Cancer Biology and Loss of Cell Cycle Control (2C)

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MCAT Biological and Biochemical Foundations of Living Systems › Cancer Biology and Loss of Cell Cycle Control (2C)

Questions 1 - 10
1

A lab studied the Rb–E2F pathway in a cancer cell line. In normal cells, hypophosphorylated Rb binds E2F and limits transcription of S-phase genes; phosphorylation of Rb by cyclin D–CDK4/6 releases E2F. The cancer line expresses an Rb truncation that cannot bind E2F. When treated with a CDK4/6 inhibitor, the cancer cells show little change in S-phase gene expression, while a control line with intact Rb shows decreased S-phase gene expression and reduced proliferation. Which outcome is most consistent with these findings?

CDK4/6 inhibition increases S-phase gene expression in the control cells because Rb becomes more phosphorylated and releases E2F.

CDK4/6 inhibition reduces S-phase gene expression in both lines because E2F is a kinase that is directly inhibited by CDK4/6 drugs.

CDK4/6 inhibition fails to reduce S-phase gene expression in the Rb-truncated cancer cells because E2F is constitutively unrestrained.

CDK4/6 inhibition reduces S-phase gene expression in the Rb-truncated cancer cells because cyclin D is a tumor suppressor that blocks E2F.

Explanation

This question assesses knowledge of the Rb-E2F pathway and its deregulation in cancer. Cancer often involves loss of Rb function, which normally represses E2F to control S-phase gene expression, leading to uncontrolled proliferation when mutated. The experiment shows CDK4/6 inhibition reduces S-phase genes in control cells with intact Rb but not in Rb-truncated cancer cells. Choice D is correct as Rb truncation allows constitutive E2F activity, rendering CDK4/6 inhibition ineffective since Rb is needed to bind and repress E2F. Choice B fails by reversing the mechanism; CDK4/6 inhibition decreases Rb phosphorylation, enhancing E2F repression in controls, not increasing it. For similar problems, confirm if the pathway requires the mutated protein for drug efficacy. Also, evaluate whether the outcome matches expected deregulation, like persistent gene expression despite treatment.

2

Researchers compared a healthy epithelial cell line to a tumor-derived line. Both were exposed to ionizing radiation (IR) to induce DNA double-strand breaks. In healthy cells, IR caused a strong accumulation of p53 protein and a marked decrease in S-phase entry 12 hours later. In the tumor-derived line, IR did not increase p53 levels, and S-phase entry remained high. Sequencing revealed a missense mutation in the tumor line’s p53 DNA-binding domain. Based on these results, which conclusion is most consistent with the data regarding cell cycle regulation in cancer?

The p53 mutation likely hyperactivates Rb, strengthening E2F repression and reducing S-phase entry after IR.

The p53 mutation likely blocks cyclin synthesis in G1, which would explain why the tumor cells fail to arrest and instead stop dividing.

The p53 mutation likely prevents transcriptional activation of genes that enforce the G1/S checkpoint after DNA damage, allowing continued S-phase entry.

The p53 mutation likely increases cyclin-dependent kinase (CDK) catalytic activity directly, accelerating progression through mitosis after IR.

Explanation

This question tests understanding of cell cycle checkpoints and tumor suppressor genes in cancer. In cancer, mutations in genes like p53 disrupt cell cycle control, allowing cells to proliferate despite DNA damage by failing to activate checkpoints that halt progression. The data show that ionizing radiation induces p53 accumulation and reduces S-phase entry in healthy cells, but not in tumor cells with a p53 DNA-binding domain mutation. Choice A is correct because the mutation impairs p53's ability to transcribe checkpoint genes, such as p21, preventing G1/S arrest and permitting S-phase entry post-damage. Choice B is incorrect as it misrepresents p53's role; p53 does not directly increase CDK activity but rather inhibits it through downstream effectors, and the effect is on G1/S, not mitosis. To verify similar questions, check if the mutation aligns with loss of checkpoint function leading to unchecked progression. Additionally, ensure the explanation matches the specific checkpoint affected, here G1/S rather than others like G2/M.

3

A cancer cell line was engineered to overexpress a nondegradable cyclin B variant (cyclin B cannot be ubiquitinated). Normally, cyclin B–CDK1 activity rises to drive entry into mitosis and then falls when cyclin B is degraded, allowing mitotic exit. After induction of nondegradable cyclin B, cells accumulate with condensed chromosomes and fail to complete cytokinesis. Which outcome is most consistent with this manipulation?

Nondegradable cyclin B increases p53 transcriptional activity, which triggers apoptosis and eliminates mitotic cells before chromosome condensation.

Persistent cyclin B–CDK1 activity strengthens the G1/S checkpoint, causing cells to arrest in G1 with low DNA content.

Nondegradable cyclin B directly inhibits CDK1, preventing chromosome condensation and blocking entry into mitosis.

Persistent cyclin B–CDK1 activity prevents mitotic exit, leading to arrest in M phase with failure to complete cytokinesis.

Explanation

This question probes understanding of mitotic regulation and cyclin degradation in cell cycle control. Cancer can arise from failures in cyclin B degradation, which normally allows mitotic exit after CDK1 activation drives mitosis entry. The manipulation with nondegradable cyclin B leads to cells stuck with condensed chromosomes and incomplete cytokinesis. Choice D is correct as persistent cyclin B-CDK1 activity blocks mitotic exit, causing M-phase arrest without cytokinesis completion. Choice C is incorrect because nondegradable cyclin B sustains CDK1 activity, promoting chromosome condensation, not inhibiting it. For related scenarios, check if the defect prevents progression beyond the affected phase, like mitosis here. Additionally, confirm the role of ubiquitin-mediated degradation in cycle advancement.

4

A cancer cell line displays high levels of aneuploidy. Microscopy shows frequent chromosome mis-segregation during mitosis. Sequencing identifies a loss-of-function mutation in a kinetochore-associated checkpoint protein that normally delays anaphase until all chromosomes are properly attached to the spindle. Which outcome would be expected from this mutation?

Failure to enter mitosis due to inability of cyclin B to bind CDK1, resulting in accumulation of cells in G1.

Premature anaphase onset despite unattached chromosomes, increasing mis-segregation and aneuploidy.

Reduced cyclin D–CDK4/6 activity, leading to hypophosphorylated Rb and decreased E2F target gene expression.

Enhanced G1/S arrest after DNA damage due to increased p53 stabilization, decreasing aneuploidy.

Explanation

This question investigates mitotic checkpoints and aneuploidy in cancer. Loss of spindle assembly checkpoint proteins allows premature anaphase, causing chromosome mis-segregation and aneuploidy, a cancer hallmark. The cell line exhibits aneuploidy, mis-segregation, and mutation in a kinetochore checkpoint protein. Choice A is correct because the mutation permits anaphase without full attachment, increasing errors. Choice B is incorrect as it confuses checkpoints; spindle defects do not enhance G1/S arrest or reduce aneuploidy but promote it. To solve similar items, identify if the mutation weakens fidelity at the affected stage, like mitosis. Also, link the phenotype to consequences like genomic instability.

5

Investigators measured cyclin levels in paired samples from patients: adjacent non-tumor tissue vs. tumor tissue. They found that cyclin E protein was markedly elevated in tumors, while cyclin D was unchanged. In a functional assay, tumor cells entered S phase even under low growth factor conditions that normally keep cells in G1. Based on the data and known checkpoint logic, which conclusion is most consistent with cell cycle regulation in these tumors?

Elevated cyclin E is consistent with enhanced spindle assembly checkpoint activity, delaying anaphase and reducing proliferation.

Elevated cyclin E is most consistent with increased degradation of cyclins, which would prevent entry into S phase in low growth factor conditions.

Unchanged cyclin D indicates that CDK2 cannot be activated, so the tumor cells should arrest in G2 under low growth factor conditions.

Elevated cyclin E is consistent with increased G1/S transition by promoting CDK2 activity and S-phase entry despite weak mitogenic signaling.

Explanation

This question evaluates comprehension of cyclin roles in cell cycle progression and their dysregulation in tumors. In cancer, elevated cyclins like cyclin E can bypass growth factor requirements, driving inappropriate G1/S transition through CDK activation. The data indicate elevated cyclin E in tumors, with unchanged cyclin D, and S-phase entry under low growth factors that arrest normal cells. Choice C is correct because high cyclin E activates CDK2, promoting Rb phosphorylation and E2F release for S-phase genes, enabling proliferation without mitogens. Choice B is wrong as it confuses cyclin E with mitotic functions; cyclin E acts at G1/S, not the spindle checkpoint, and would increase, not decrease, proliferation. In analogous questions, verify if the cyclin matches the checkpoint deregulated, here G1/S. Moreover, assess if the data support bypass of normal regulatory signals like growth factors.

6

A study tested whether a tumor suppressor pathway is intact by treating cells with a DNA replication inhibitor that causes replication stress. In normal cells, replication stress activates a kinase cascade that stabilizes p53 and increases transcription of a CDK inhibitor, resulting in reduced CDK2 activity and G1/S arrest. In a cancer cell line, replication stress does not reduce CDK2 activity, and cells continue DNA synthesis with elevated DNA damage markers. Which mutation is most likely to produce this phenotype?

Gain-of-function mutation in Rb that increases binding to E2F, preventing S-phase gene transcription.

Loss-of-function mutation in cyclin B that prevents CDK1 activation and blocks mitotic entry.

Loss-of-function mutation in a p53-regulated CDK inhibitor gene that normally suppresses CDK2 at the G1/S checkpoint.

Gain-of-function mutation in a spindle checkpoint protein that delays anaphase until all kinetochores attach.

Explanation

This question tests insight into DNA damage responses and tumor suppressor pathways in cancer. Mutations in p53 or its effectors allow cancer cells to ignore replication stress, evading G1/S arrest and accumulating damage. The cancer cells fail to reduce CDK2 activity or arrest at G1/S despite replication stress, continuing DNA synthesis with damage. Choice A is correct as a loss-of-function in a p53-induced CDK inhibitor like p21 would prevent CDK2 suppression, bypassing the checkpoint. Choice B is flawed by inverting Rb's role; gain-of-function Rb would enhance E2F repression, promoting arrest, not the observed progression. To approach similar questions, identify if the mutation disables a checkpoint response to stress. Furthermore, ensure the phenotype matches unchecked activity at the specific CDK and phase involved.

7

A tumor sample shows amplification of a gene encoding cyclin D, with high cyclin D protein and increased phosphorylation of Rb. In cell culture, reducing cyclin D expression decreases proliferation and lowers expression of S-phase genes. Based on cell cycle control principles, which statement best explains how cyclin D amplification promotes tumor growth?

Cyclin D amplification increases CDK4/6-mediated phosphorylation of Rb, releasing E2F to drive transcription of genes required for S phase.

Cyclin D amplification directly repairs DNA lesions, reducing p53 activation and thereby slowing the cell cycle.

Cyclin D amplification inhibits CDK4/6, keeping Rb hypophosphorylated and preventing E2F from activating S-phase genes.

Cyclin D amplification activates the spindle assembly checkpoint, preventing chromosome segregation and reducing proliferation.

Explanation

This question assesses how cyclin amplifications drive oncogenic cell cycle progression. Cyclin D overexpression in cancer hyperactivates CDK4/6, phosphorylating Rb to release E2F and promote S-phase genes, fueling growth. The tumor shows cyclin D amplification, high Rb phosphorylation, and proliferation decrease upon cyclin D reduction. Choice A is correct as amplified cyclin D enhances CDK4/6 activity, freeing E2F for S-phase transcription and tumor proliferation. Choice C is incorrect because cyclin D activates, not inhibits, CDK4/6, leading to Rb hyperphosphorylation, not hypophosphorylation. In similar cases, confirm if the alteration accelerates the specific transition, like G1/S here. Additionally, evaluate if reversing the change restores normal control, as with cyclin D reduction.

8

A researcher compares gene edits in a pancreatic cancer model. Cells are engineered with either (i) a loss-of-function mutation in a tumor suppressor that normally restrains cell-cycle progression at the G1/S checkpoint, or (ii) a gain-of-function mutation in an oncogene that increases cyclin expression. Both edits increase proliferation. When a CDK2 inhibitor is added, only the oncogene-mutant cells show a marked decrease in S-phase entry; the tumor-suppressor–mutant cells show little change.

Which explanation is most consistent with the data?

Tumor suppressor loss increases reliance on CDK2, so CDK2 inhibition should selectively block the tumor-suppressor–mutant cells.

CDK2 inhibitors act by restoring tumor suppressor gene transcription, so they should only affect tumor-suppressor–mutant cells.

Oncogene-driven proliferation in this model depends on cyclin–CDK2 activity for S-phase entry, whereas the tumor-suppressor loss bypasses this control point.

The oncogene mutation decreases cyclin levels, making CDK2 inhibition unnecessary to reduce S-phase entry.

Explanation

This question tests understanding of how different genetic alterations create distinct dependencies on cell cycle regulators. The oncogene mutation increases cyclin expression, making cells dependent on cyclin-CDK2 activity for S-phase entry, so CDK2 inhibition effectively blocks their proliferation. The tumor suppressor loss likely removes a checkpoint that normally restrains S-phase entry upstream of or parallel to CDK2, allowing cells to bypass the need for CDK2 activity through alternative pathways. The correct answer (A) accurately explains that oncogene-driven proliferation depends on CDK2 for S-phase entry while tumor suppressor loss bypasses this control point. Choice B reverses the logic by suggesting tumor suppressor loss increases CDK2 reliance, choice C incorrectly proposes CDK2 inhibitors restore tumor suppressor transcription, and choice D contradicts the experimental setup. To understand synthetic lethality and targeted therapy, recognize that different mutations create different vulnerabilities - oncogene addiction often creates targetable dependencies while loss of tumor suppressors may eliminate those same dependencies.

9

An experimental therapy aims to restore checkpoint control in a cancer line with intact p53 but low p21 expression due to promoter methylation. Treatment with a DNA-demethylating agent increases p21 mRNA and decreases CDK2 activity. After treatment, cells show a larger G1 population and reduced colony formation.

Which conclusion is most consistent with these results about cell-cycle regulation in cancer?

Demethylation increases cyclin E stability, which decreases CDK2 activity and causes G1 arrest.

Demethylation likely reactivates p21 transcription, enabling p21-mediated inhibition of cyclin–CDK complexes and promoting G1 arrest.

Demethylation likely silences p53, preventing apoptosis and thereby reducing colony formation.

Demethylation activates telomerase, which directly inhibits CDK2 and reduces colony formation by shortening S phase.

Explanation

This question tests understanding of epigenetic silencing in cancer and how reversing promoter methylation can restore tumor suppressor function. DNA methylation of CpG islands in gene promoters silences transcription, a common mechanism for inactivating tumor suppressors like p21 without genetic mutation. The demethylating agent removes methyl groups from the p21 promoter, reactivating transcription and restoring p21 protein expression, which then inhibits CDK2 to enforce G1 arrest and reduce proliferation. The correct answer (A) accurately describes demethylation reactivating p21 transcription, enabling CDK inhibition and G1 arrest. Choice B incorrectly suggests demethylation silences p53 and confuses reduced proliferation with reduced apoptosis, choice C proposes an illogical mechanism where cyclin E stability decreases CDK2 activity, and choice D invokes telomerase in an unrelated context. When analyzing epigenetic therapies, remember that demethylating agents can reactivate silenced tumor suppressors, potentially restoring checkpoint control without requiring gene therapy.

10

A clinical trial evaluates a small-molecule MDM2 inhibitor in tumors that retain wild-type p53. Biopsies taken 48 hours after treatment show increased p53 protein levels and increased transcription of p21 and pro-apoptotic genes. Tumor cells show reduced proliferation markers. Which outcome is most consistent with the drug’s mechanism in cell cycle control?

Core concept: MDM2 targets p53 for degradation; inhibiting MDM2 stabilizes p53, promoting cell cycle arrest and/or apoptosis.

Inhibition of E2F DNA binding, which decreases p53 levels because E2F is required for p53 translation.

Decreased p53 levels due to enhanced ubiquitination, leading to increased cyclin-CDK activity and faster G1/S progression.

Stabilized p53 leading to increased p21, which inhibits cyclin-CDK complexes and slows cell cycle progression.

Direct activation of CDK4/6, leading to increased Rb phosphorylation and reduced p21 transcription.

Explanation

This question assesses MDM2's regulation of p53 in cell cycle arrest and apoptosis in cancer. In cancer, MDM2 degrades p53; inhibitors stabilize p53 to induce p21 for arrest and pro-apoptotic genes. Here, MDM2 inhibition increases p53, p21, apoptotic transcripts, and reduces proliferation. The correct answer (B) follows because stabilized p53 activates p21 to inhibit cyclin-CDKs, slowing progression. A distractor like (A) fails by proposing decreased p53 from enhanced ubiquitination, predicting opposite effects and misconceiving the inhibitor's stabilizing role. For comparable questions, trace from regulator (MDM2) to effector (p53-p21) and verify downstream outcomes like arrest. Also, correlate protein levels with transcriptional changes.

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