Prokaryotic Growth, Metabolism, and Adaptation (2B)
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MCAT Biological and Biochemical Foundations of Living Systems › Prokaryotic Growth, Metabolism, and Adaptation (2B)
A researcher grows a neutrophilic bacterium in buffered media at 37°C with identical glucose and nitrogen sources but different pH values. After 6 hours, OD600 is measured.
Which condition best supports the observed growth pattern?
Table 1. Growth after 6 hours (pH vs OD600)
- pH 5.5: 0.10
- pH 6.5: 0.55
- pH 7.0: 0.85
- pH 8.0: 0.40
Maximal growth near neutral pH is consistent with optimal enzyme activity and membrane transport in a neutrophile
Maximal growth at pH 5.5 is expected because acidic conditions increase proton motive force in all bacteria
Similar growth at all pH values is expected because buffering eliminates effects of extracellular pH
The lowest growth at pH 7.0 is expected because glycolysis is inhibited at neutral pH
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic growth is strongly influenced by environmental pH, which affects enzyme activity, membrane transport, and cellular processes. In this experiment, a neutrophilic bacterium showed maximal growth at pH 7.0 with reduced growth at both acidic and alkaline conditions. Choice A is correct because neutrophiles are adapted to grow optimally near neutral pH (6.5-7.5), where their enzymes function best and membrane transport systems operate efficiently, explaining the growth pattern with peak OD600 at pH 7.0. Choice B is incorrect because while proton motive force may increase at lower pH, this doesn't benefit neutrophiles whose enzymes and transporters are optimized for neutral conditions. To tackle similar questions, match the organism's classification (neutrophile, acidophile, alkaliphile) with its expected optimal pH range and understand how pH affects cellular processes.
A gene expression study evaluates a knockout of ackA (acetate kinase), which converts acetyl phosphate to acetate while generating ATP (substrate-level phosphorylation). Wild-type and knockout strains are grown anaerobically at 37°C, pH 7.0 on 20 mM glucose. After 1 hour, extracellular acetate and culture ATP are measured.
Which conclusion is most supported by the experimental results?
Table 1. Measurements at 1 hour
- Wild-type: acetate 6.0 mM; ATP 2.2 mM
- $\Delta ackA$: acetate 1.5 mM; ATP 1.4 mM
- Wild-type + empty vector: acetate 5.8 mM; ATP 2.1 mM
- $\Delta ackA$ + complemented ackA: acetate 5.5 mM; ATP 2.0 mM
The rescue is most consistent with pH changes in the complemented strain rather than restoration of the metabolic step
Loss of acetate kinase reduces acetate production and decreases ATP yield from substrate-level phosphorylation under anaerobic growth
The knockout primarily impairs oxidative phosphorylation, explaining lower ATP despite anaerobic conditions
Loss of acetate kinase increases acetate secretion because acetyl phosphate cannot be consumed and must be exported as acetate
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Substrate-level phosphorylation provides ATP during fermentation, and acetate kinase catalyzes one such reaction in mixed-acid fermentation. In this experiment, the ackA knockout showed reduced acetate production and lower ATP levels compared to wild-type. Choice A is correct because acetate kinase converts acetyl-phosphate to acetate while generating ATP, so its loss reduces both acetate secretion (6.0 to 1.5 mM) and ATP production (2.2 to 1.4 mM) under anaerobic conditions where substrate-level phosphorylation is crucial. Choice B is incorrect because without acetate kinase, less acetate is produced, not more, as the data clearly show. To tackle similar questions, understand the role of specific enzymes in fermentation pathways and how their loss affects both product formation and energy generation.
A lab tests the effect of an inhibitor of glyceraldehyde-3-phosphate dehydrogenase (GAPDH) on anaerobic glycolysis in a facultative anaerobe at 37°C, pH 7.2. Cultures are supplied 10 mM glucose; after 10 minutes, intracellular metabolites are quantified.
Which metabolic change is most consistent with the data?
Table 1. Intracellular metabolite levels (mM) Condition: No inhibitor vs +GAPDH inhibitor
- G3P: 1.2 vs 4.8
- 1,3-BPG: 0.9 vs 0.1
- Pyruvate: 2.5 vs 0.6
- Lactate: 3.0 vs 0.7
Inhibition increases flux through pyruvate dehydrogenase, raising pyruvate and lactate under anaerobic conditions
Inhibition primarily blocks conversion of pyruvate to lactate, causing pyruvate accumulation and lactate depletion
Inhibition activates the pentose phosphate pathway, increasing 1,3-BPG and decreasing G3P
Inhibition blocks conversion of G3P to 1,3-BPG, causing upstream accumulation and reduced downstream fermentation products
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic metabolism involves sequential enzymatic reactions where inhibition at one step affects upstream and downstream metabolites. In this experiment, GAPDH inhibition blocks the conversion of G3P to 1,3-BPG in glycolysis, causing predictable metabolic changes. Choice D is correct because GAPDH catalyzes G3P → 1,3-BPG, so its inhibition causes G3P accumulation (1.2 → 4.8 mM) and 1,3-BPG depletion (0.9 → 0.1 mM), with reduced flux to downstream products like pyruvate and lactate. Choice B is incorrect because pyruvate dehydrogenase is irrelevant under anaerobic conditions, and the data show decreased, not increased, pyruvate and lactate. To tackle similar questions, trace the metabolic pathway step-by-step and predict how blocking one enzyme affects metabolites before and after that step.
A study examines temperature effects on growth of a mesophilic bacterium in rich medium at pH 7.0. Cultures are incubated at different temperatures, and specific growth rate ($\mu$, h$^{-1}$) is estimated during exponential phase.
Which conclusion is most supported by the experimental results?
Table 1. Temperature vs growth rate
- 25°C: $\mu=0.30$
- 30°C: $\mu=0.55$
- 37°C: $\mu=0.90$
- 45°C: $\mu=0.20$
The organism is most consistent with a thermophile because growth increases monotonically with temperature
The temperature effect is most consistent with inhibition of the pentose phosphate pathway specifically at 37°C
The reduced growth at 45°C is most consistent with increased nutrient availability at high temperature
The organism is most consistent with a mesophile showing an optimum near 37°C and reduced growth at higher temperatures due to protein destabilization
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Temperature profoundly affects prokaryotic growth by influencing enzyme kinetics, membrane fluidity, and protein stability. In this experiment, the mesophilic bacterium showed optimal growth at 37°C with reduced rates at both lower and higher temperatures. Choice D is correct because mesophiles typically grow optimally between 20-45°C, with peak growth often near 37°C, and the sharp decline at 45°C indicates protein denaturation and enzyme inactivation at elevated temperatures. Choice B is incorrect because the growth does not increase monotonically - it peaks at 37°C then decreases at 45°C, which is inconsistent with thermophile behavior. To tackle similar questions, recognize temperature classifications (psychrophile, mesophile, thermophile) and understand that growth rates follow a characteristic curve with an optimum flanked by reduced growth at temperature extremes.
A study tests phosphate limitation. A bacterium is grown aerobically at 37°C, pH 7.2, with excess glucose but either 5 mM phosphate or 0.05 mM phosphate. After 5 hours, OD600 is measured.
Table (OD600 at 5 h):
5 mM phosphate: 1.00
0.05 mM phosphate: 0.28
Which conclusion is most supported by the experimental results?
Low phosphate increases OD600 by increasing cell wall thickness without affecting metabolism
Phosphate limitation restricts synthesis of nucleic acids, phospholipids, and ATP, reducing growth yield
Phosphate limitation increases growth by preventing ATP hydrolysis
Phosphate affects growth only through pH changes, so buffering would eliminate the effect
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic growth and metabolism are influenced by environmental conditions and nutrient availability, affecting cellular processes. In this experiment, bacterial growth was measured under varying phosphate conditions with excess glucose, demonstrating how phosphate limitation impacts biomass accumulation as indicated by OD600 readings. Choice A is correct because it aligns with the observed decrease in growth yield under low phosphate conditions, as phosphate is essential for synthesizing nucleic acids, phospholipids, and ATP, which are critical for cell proliferation and metabolism. Choice B is incorrect as it suggests phosphate limitation increases growth by preventing ATP hydrolysis, which contradicts the data showing reduced OD600 and misunderstands the role of phosphate in ATP synthesis rather than hydrolysis prevention. To tackle similar questions, focus on direct data interpretation and avoid inferring unstated conditions or unrelated pathways. Always correlate experimental outcomes with fundamental biochemical requirements for microbial growth.
A researcher compares growth of a facultative anaerobe at 37°C in identical medium containing 20 mM glucose, but with either vigorous aeration or an anoxic chamber (no O2). pH is maintained at 7.0. OD600 is measured after 4 hours.
Table (OD600 at 4 h):
Aerobic: 0.95
Anoxic: 0.45
Which conclusion is most supported by the experimental results?
Aerobic conditions decrease growth because O2 directly inhibits glycolytic enzymes
Anoxic conditions increase ATP yield by enabling oxidative phosphorylation with O2
Aerobic conditions increase ATP yield per glucose due to oxidative phosphorylation, supporting higher biomass
Anoxic conditions increase growth because fermentation produces more ATP per glucose than respiration
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic growth and metabolism are influenced by environmental conditions and nutrient availability, affecting cellular processes. In this experiment, oxygen availability affected growth yield in a facultative anaerobe, highlighting differences in ATP production. Choice B is correct because aerobic conditions enable oxidative phosphorylation, increasing ATP per glucose and supporting higher biomass, as shown by greater OD600. Choice C is incorrect as fermentation yields less ATP than respiration, not more, contradicting the lower anoxic growth. To tackle similar questions, focus on direct data interpretation and avoid inferring unstated conditions or unrelated pathways.
To evaluate phosphate limitation, a bacterium is grown aerobically at 30°C, pH 7.0 in minimal medium with constant glucose (0.2%) but varying inorganic phosphate (Pi). After 8 hours, final OD600 is recorded.
Which condition best supports the observed growth pattern?
Table 1. Final biomass vs phosphate Pi (mM) vs Final OD600 (8 h)
- 10: 1.05
- 1: 0.92
- 0.2: 0.48
- 0.05: 0.20
Lower Pi increases glycolytic phosphorylation steps, raising ATP yield and therefore decreasing OD600 due to faster lysis
Lower Pi limits synthesis of ATP, nucleic acids, and phospholipids, reducing biomass yield despite unchanged glucose availability
Pi limitation primarily blocks beta-oxidation, which is required for glucose catabolism, lowering OD600 at low Pi
Final OD600 decreases at low Pi because oxygen becomes limiting only in high-Pi cultures, causing early stationary phase
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic growth requires phosphate for multiple essential biomolecules including ATP, nucleic acids, and phospholipids, making it a potential limiting nutrient. In this experiment, decreasing phosphate concentration from 10 mM to 0.05 mM causes a dramatic reduction in final biomass from OD600 1.05 to 0.20, despite constant glucose availability. Choice D is correct because phosphate is essential for synthesizing ATP (energy currency), nucleotides (for DNA/RNA), and phospholipids (for membranes), so limiting phosphate restricts production of these vital components and thus limits total biomass regardless of carbon source availability. Choice B is incorrect because lower phosphate would decrease, not increase, glycolytic phosphorylation steps, and would not cause cell lysis. To tackle similar questions, recognize that growth requires balanced availability of all essential nutrients, not just carbon and energy sources.
A lab measures the effect of an uncoupler (dissipates proton gradient) on aerobic bacterial metabolism at 30°C, pH 7.0, with glucose present. Oxygen consumption and ATP are measured after 30 minutes.
Table (relative units):
Condition: Control, +Uncoupler
O2 consumption: 100, 160
ATP: 100, 40
Which conclusion is most supported by the experimental results?
The uncoupler has no effect on ATP because ATP is produced only by substrate-level phosphorylation
The uncoupler increases ATP by making oxidative phosphorylation more efficient
The uncoupler decreases electron transport rate because ATP synthase runs faster
The uncoupler increases electron transport rate while decreasing ATP synthesis by collapsing the proton motive force
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic growth and metabolism are influenced by environmental conditions and nutrient availability, affecting cellular processes. In this experiment, an uncoupler altered oxygen consumption and ATP, affecting respiration. Choice D is correct because dissipating the proton gradient increases electron transport but reduces ATP synthesis, matching the data. Choice B is incorrect as uncouplers increase, not decrease, electron transport rate. To tackle similar questions, focus on direct data interpretation and avoid inferring unstated conditions or unrelated pathways.
A metabolic pathway experiment evaluates inhibition of ATP synthase in an aerobic bacterium at 30°C, pH 7.0. Cells are treated with oligomycin-like compound (blocks $F_0$ channel). After 20 minutes, proton gradient (Δp) and oxygen consumption are measured.
Table (relative units):
Condition: Control, +ATP synthase inhibitor
Δp: 100, 150
O2 consumption: 100, 60
Which metabolic change is most consistent with the data?
Blocking ATP synthase increases Δp and increases O2 consumption because ETC becomes more efficient
Blocking proton re-entry increases Δp and slows electron transport due to backpressure, reducing O2 consumption
Blocking ATP synthase collapses Δp and increases O2 consumption to compensate
Blocking ATP synthase increases fermentation, which directly increases O2 consumption
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic growth and metabolism are influenced by environmental conditions and nutrient availability, affecting cellular processes. In this experiment, ATP synthase inhibition increased Δp and reduced O2 consumption, affecting respiration. Choice A is correct because blocking proton re-entry builds Δp, creating backpressure that slows electron transport and O2 use. Choice B is incorrect as inhibition increases, not collapses, Δp. To tackle similar questions, focus on direct data interpretation and avoid inferring unstated conditions or unrelated pathways.
Investigators test the effect of an inhibitor of ATP synthase (Compound X) on aerobic respiration in a prokaryote grown at 30°C, pH 7.2 with abundant glucose. After 20 minutes, intracellular ATP and NADH are measured.
Which metabolic change is most consistent with the data?
Table 1. Metabolite levels (relative units) Condition vs ATP vs NADH
- No inhibitor: ATP 1.0; NADH 1.0
- +Compound X: ATP 0.35; NADH 1.8
Electron transport slows due to reduced proton re-entry, causing NADH to accumulate while ATP production falls
Glycolysis is directly inhibited, decreasing NADH formation and thereby lowering ATP through substrate-level phosphorylation
ATP increases because the proton gradient is preserved, driving faster ATP synthase turnover and oxidizing NADH
The TCA cycle accelerates to compensate, consuming NADH and restoring ATP to near-baseline levels
Explanation
This question assesses understanding of prokaryotic growth, metabolism, and adaptation (Foundational Concept 2). Prokaryotic ATP production through oxidative phosphorylation depends on the electron transport chain creating a proton gradient that drives ATP synthase. In this experiment, inhibiting ATP synthase with Compound X causes ATP levels to drop to 0.35 while NADH levels increase to 1.8 relative units. Choice A is correct because blocking ATP synthase prevents protons from re-entering the cell through this enzyme, causing the proton gradient to build up and inhibit further electron transport, leading to NADH accumulation (as it cannot be oxidized) and decreased ATP production. Choice D is incorrect because inhibiting ATP synthase would decrease, not increase, ATP production regardless of the proton gradient status. To tackle similar questions, trace the flow of electrons and protons in oxidative phosphorylation and predict the effects of blocking specific steps.