Cell Theory and Prokaryotic Cell Structure (2B)

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MCAT Biological and Biochemical Foundations of Living Systems › Cell Theory and Prokaryotic Cell Structure (2B)

Questions 1 - 10
1

Researchers isolated two bacterial strains from a hypersaline lake. Both strains grew well at 3.5 M NaCl, but only Strain H remained viable after rapid transfer to freshwater. Chemical analysis showed Strain H produced a thick extracellular polysaccharide layer and formed compact cell aggregates. When a gene required for polysaccharide export was knocked out, the mutant lost freshwater survival despite unchanged intracellular enzyme profiles.

Which evolutionary adaptation would be expected given the described conditions and results?

Selection for a nucleus to compartmentalize DNA and prevent osmotic lysis

Selection for an extracellular capsule that slows osmotic water influx during hypoosmotic shock

Selection for chloroplasts to increase ATP production needed for salt export

Selection for reduced peptidoglycan cross-linking to increase membrane fluidity in freshwater

Explanation

This question tests understanding of prokaryotic adaptations to osmotic stress. Prokaryotes can produce extracellular structures like capsules or slime layers that provide protection against environmental stresses, including osmotic shock. In the vignette, Strain H survives transfer from hypersaline to freshwater conditions due to its thick extracellular polysaccharide layer, which forms a protective barrier that slows water influx during hypoosmotic shock. The correct answer (B) identifies selection for an extracellular capsule as the evolutionary adaptation that enables survival in fluctuating osmotic conditions. Answer choice C is incorrect because prokaryotes lack nuclei, and nuclear compartmentalization is not a mechanism for preventing osmotic lysis—the cell wall and capsule serve this function in bacteria. To verify understanding, remember that prokaryotic capsules are external to the cell wall and provide additional protection beyond what the peptidoglycan layer offers.

2

A lab compared a Gram-negative bacterium and a yeast cell after exposure to a β-lactam antibiotic that inhibits peptidoglycan cross-linking. Both were placed in hypotonic buffer for 10 minutes. The bacterium rapidly lysed, while the yeast remained intact. (Terms: peptidoglycan = bacterial cell wall polymer; hypotonic = lower solute concentration outside the cell than inside.)

Which feature best exemplifies cell theory as applied to prokaryotes in this setup?

The yeast is larger, demonstrating that cell size determines whether a cell can maintain homeostasis

The bacterium lacks membrane-bound organelles, showing that only eukaryotes are composed of cells

The bacterium lyses because its DNA is not protected by a nucleus, causing osmotic rupture

The bacterium’s survival depends on a boundary that regulates exchange with the environment, consistent with cells as basic functional units

Explanation

This question tests the application of cell theory to prokaryotic boundaries and homeostasis. Cell theory states that all living organisms are composed of cells, which are the basic functional units maintaining internal environments through boundaries like plasma membranes and cell walls. In this setup, the Gram-negative bacterium lyses in hypotonic buffer after β-lactam treatment disrupts its peptidoglycan cell wall, while the yeast, with a different wall composition, remains intact. Choice B is correct because the bacterium's survival relies on its cell envelope as a regulatory boundary, exemplifying cells as basic units in prokaryotes. Choice A is incorrect as it misconstrues cell theory; prokaryotes lacking membrane-bound organelles still qualify as cells, and eukaryotes are not the only cell type. To verify, confirm that cell theory applies universally to prokaryotes and eukaryotes by their ability to maintain homeostasis via boundaries. A transferable check is to assess if an organism's integrity depends on a plasma membrane or wall, reinforcing that all cells arise from pre-existing cells and function independently.

3

A biotechnology team introduced a plasmid encoding a metabolic enzyme into a bacterial population. After 30 generations without antibiotic selection, many cells retained the enzyme activity, but plasmid DNA became undetectable in a subset; whole-genome sequencing revealed the enzyme gene integrated into the chromosome in those cells. The researchers argued that this result supports a key idea about heredity in cellular organisms.

Which conclusion most directly applies cell theory to the prokaryotic observations?

Cells arise spontaneously from nonliving material when selection is removed

Inheritance requires meiotic segregation of homologous chromosomes within a nucleus

Only eukaryotic cells can stably integrate foreign DNA into their genomes

Genetic information can be maintained and transmitted within cells even without membrane-bound organelles

Explanation

This question tests understanding of genetic inheritance in prokaryotes within the context of cell theory. Cell theory encompasses the principle that cells can maintain and transmit genetic information, which applies to both prokaryotes and eukaryotes despite their structural differences. The vignette demonstrates that bacterial cells can stably integrate foreign DNA into their chromosomes and pass this genetic information to daughter cells through binary fission, showing that membrane-bound organelles are not required for heredity. The correct answer (C) states that genetic information can be maintained and transmitted within cells even without membrane-bound organelles, directly supporting cell theory's application to prokaryotes. Answer choice A is incorrect because prokaryotes undergo binary fission rather than meiosis, and they lack the nuclear organization required for meiotic chromosome segregation. To verify understanding, remember that cell theory's hereditary principle requires only that cells can reproduce and pass genetic information, not that they must use specific mechanisms like meiosis.

4

A lab evolved E. coli in the presence of a lytic bacteriophage that adsorbs to a specific outer-membrane porin. After 200 generations, a dominant bacterial lineage carried mutations that eliminated expression of that porin. The lineage showed reduced phage adsorption but also slower growth in minimal medium where that porin normally facilitates nutrient uptake. (Terms: porin = outer-membrane channel protein in Gram-negative bacteria; adsorption = virus binding to cell surface.)

Which evolutionary adaptation would be expected given the described conditions?

Evolution of endocytosis to internalize and digest phage particles before infection

Increased expression of the porin to outcompete phage binding through higher nutrient uptake

Loss or modification of the porin receptor, reducing phage attachment despite a tradeoff in nutrient transport

Acquisition of a nuclear envelope to physically block phage entry through the plasma membrane

Explanation

This question tests evolutionary adaptations in prokaryotic surface structures against phage pressure. Prokaryotes like E. coli have outer-membrane porins that serve as channels but can be phage receptors, leading to selection for modifications under viral pressure. In the vignette, evolved E. coli mutants lose porin expression, reducing phage adsorption but slowing growth in minimal medium due to impaired nutrient uptake. Loss or modification of the porin is expected as it reduces phage attachment with a nutrient tradeoff, as in choice B. Choice C fails because prokaryotes lack nuclear envelopes; this misconstrues eukaryotic compartmentalization as a prokaryotic defense. To verify understanding, note that porin mutations balance survival against efficiency in prokaryotes. A transferable check is to assess tradeoffs in adaptations: if surface changes reduce infection but impair function, it exemplifies prokaryotic evolution without organelles.

5

A researcher cultured a Gram-negative bacterium in the presence of a hydrophobic antibiotic. A mutant strain with a disrupted gene for lipopolysaccharide (LPS) core synthesis showed increased antibiotic sensitivity but unchanged cytosolic enzyme activity. Complementation restored resistance. No changes were observed in peptidoglycan thickness.

Based on the findings, which prokaryotic structure is most critical for the observed change in antibiotic sensitivity?

Mitochondrial outer membrane that exports antibiotics via porins

Outer membrane containing LPS that limits entry of certain hydrophobic compounds

Nuclear pore complex that prevents diffusion of hydrophobic molecules into the nucleus

Contractile vacuole that actively pumps antibiotics out of the cytoplasm

Explanation

This question tests knowledge of Gram-negative bacterial cell envelope structure and antibiotic resistance. Gram-negative bacteria possess an outer membrane containing lipopolysaccharide (LPS) that serves as a permeability barrier, particularly against hydrophobic compounds including many antibiotics. The vignette describes increased antibiotic sensitivity in a mutant with disrupted LPS core synthesis, which compromises outer membrane integrity and allows greater antibiotic penetration without affecting the peptidoglycan layer. The correct answer (D) identifies the outer membrane containing LPS as the critical structure for limiting antibiotic entry. Answer choice B is incorrect because bacteria lack mitochondria—the outer membrane referenced in choice D is a prokaryotic structure unique to Gram-negative bacteria, not a mitochondrial membrane. To verify understanding, remember that Gram-negative bacteria have two membranes (inner plasma membrane and outer membrane with LPS), while Gram-positive bacteria have only one membrane.

6

To compare information storage in prokaryotes and eukaryotes, researchers treated a bacterial culture and a mammalian cell line with a DNA gyrase inhibitor. In bacteria, DNA supercoiling decreased and replication slowed markedly. In mammalian cells, nuclear DNA replication was minimally affected at the same inhibitor concentration. (Terms: DNA gyrase = bacterial type II topoisomerase that introduces negative supercoils; supercoiling affects DNA compaction and replication.)

Based on the vignette, which structure is most directly implicated in the prokaryote-specific sensitivity to the inhibitor?

The nucleolus, because ribosomal RNA synthesis is the primary target of gyrase inhibitors

The nucleoid, because bacterial chromosomal DNA organization relies on gyrase-mediated supercoiling

The mitochondrial matrix, because mitochondrial DNA replication uses DNA gyrase in mammalian cells

The Golgi apparatus, because protein trafficking determines replication rate in bacteria

Explanation

This question tests prokaryotic genetic organization and its distinction from eukaryotes. Prokaryotes store genetic information in a nucleoid, a region of compacted chromosomal DNA reliant on supercoiling by enzymes like DNA gyrase for replication and compaction. In the vignette, the gyrase inhibitor slows bacterial replication by reducing supercoiling, with minimal effect on mammalian nuclear DNA. The nucleoid is implicated as gyrase-mediated supercoiling is essential for bacterial DNA organization, explaining prokaryote-specific sensitivity in choice D. Choice B is incorrect because the Golgi apparatus is eukaryotic for protein trafficking, absent in prokaryotes; this highlights the misconception of shared organelles. To verify, recall gyrase is bacterial-specific, unlike eukaryotic topoisomerases. A transferable check is to compare DNA compaction: supercoiling-dependent in prokaryotic nucleoids versus histone-based in eukaryotic nuclei.

7

A clinician cultured a bacterium from a urinary tract infection. In Gram stain, cells appeared pink and were sensitive to an antibiotic that disrupts peptidoglycan crosslinking. Electron microscopy showed two membranes surrounding a thin cell wall layer.

Core cell theory idea: all cells are bounded by membranes and contain internal components necessary for life. Based on the vignette, which prokaryotic structure most directly explains the staining and envelope observations?

Cellulose wall external to a plasma membrane and internal chloroplast envelope

Thick peptidoglycan layer containing teichoic acids external to a single membrane

Chitin wall supported by an underlying nuclear envelope

Outer membrane surrounding a thin peptidoglycan layer in the periplasm

Explanation

The skill being tested is identifying prokaryotic envelope structures aligning with cell theory. Cell theory states all cells are membrane-bound with internal components for life. In the vignette, the pink Gram stain and thin wall indicate Gram-negative structure. Choice D is correct because Gram-negative bacteria have an outer membrane and thin peptidoglycan, explaining staining and antibiotic sensitivity. Choice C fails as it describes plant cell walls with chloroplasts, misconstruing prokaryotic envelopes which lack such features. To verify understanding, recall Gram staining basis in envelope architecture. A transferable check is to distinguish prokaryotic wall compositions from eukaryotic ones.

8

A lab investigated plasmid inheritance in a bacterium carrying an antibiotic-resistance plasmid. When plasmid partitioning proteins were inhibited, daughter cells frequently lost resistance after several generations, despite normal chromosomal replication and cell division rate. No nuclear membrane was present.

Core cell theory idea: hereditary information is passed from cell to cell. Based on the vignette, which conclusion is most supported?

Nonchromosomal DNA requires dedicated segregation machinery to be reliably transmitted during division

Loss of resistance indicates that DNA replication cannot occur in prokaryotes

Plasmids are proteins that must be translated on the rough ER before inheritance

Plasmids are replicated only in the nucleus, so inhibition blocks nuclear entry

Explanation

The skill being tested is understanding hereditary transmission in prokaryotes per cell theory. Cell theory emphasizes passing hereditary information, including extrachromosomal elements, during division. In the vignette, inhibiting partitioning leads to plasmid loss despite normal division. Choice D is correct because plasmids require specific machinery for segregation in prokaryotes. Choice B fails as prokaryotes lack a nucleus, misconstruing plasmid replication sites. To verify understanding, compare plasmid and chromosome inheritance. A transferable check is to evaluate mechanisms ensuring non-chromosomal DNA transmission without organelles.

9

To test whether a newly discovered microbe follows cell theory, researchers measured whether it can generate offspring without pre-existing cells. Under sterile conditions with only inorganic salts and carbon source, no new cells appeared unless a small inoculum was added. Once inoculated, the population increased by binary fission. The organism lacked a nucleus.

Core cell theory idea: cells arise from pre-existing cells. Which feature best exemplifies this principle as applied to the microbe?

Ability to assemble ribosomes de novo from free amino acids in the medium

Formation of multicellular tissues that bud off independent daughter organisms

Presence of membrane-bound organelles enabling spontaneous cell formation

Population growth occurring only after inoculation with existing cells

Explanation

The skill being tested is applying cell theory's origin principle to microbes. Cell theory asserts that cells arise only from pre-existing cells, refuting spontaneous generation. In the vignette, no growth occurs without inoculum, but binary fission follows addition. Choice A is correct because it demonstrates dependence on existing cells for population growth. Choice B fails by suggesting organelles enable spontaneous formation, misconstruing that prokaryotes lack organelles yet follow cell theory. To verify understanding, consider historical experiments disproving abiogenesis. A transferable check is to test if an organism requires pre-existing cells for propagation.

10

In a structural comparison study, investigators treated bacterial cells and cultured mammalian cells with a translation inhibitor that binds the small ribosomal subunit. Protein synthesis in bacteria dropped sharply, while mammalian cytosolic protein synthesis was minimally affected, though mitochondrial protein synthesis decreased. The bacterial cells were confirmed to lack a nucleus and endomembrane system.

Core cell theory idea: cells carry out essential life processes, including protein synthesis. Based on these data, which conclusion best applies cell theory to prokaryotic structure?

Bacterial protein synthesis requires trafficking through the Golgi apparatus before translation can begin

Bacterial ribosomes are membrane-bound to the endoplasmic reticulum for co-translational import

Bacterial protein synthesis occurs on ribosomes that are structurally distinct from eukaryotic cytosolic ribosomes

Bacterial translation is confined to the nucleus to protect DNA from ribosomal enzymes

Explanation

The skill being tested is understanding prokaryotic protein synthesis in light of cell theory. Cell theory asserts that cells perform essential processes like protein synthesis using ribosomes. In the vignette, the inhibitor affects bacterial and mitochondrial ribosomes but not eukaryotic cytosolic ones, highlighting structural differences. Choice C is correct because bacterial ribosomes are distinct, allowing selective inhibition without an endomembrane system. Choice B fails as bacteria lack a Golgi, misconstruing that prokaryotic translation requires eukaryotic trafficking. To verify understanding, compare ribosomal structures across domains. A transferable check is to note that prokaryotic translation occurs freely in the cytosol without nuclear separation.

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