Membrane Potential and Electrochemical Gradients (2A)

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MCAT Biological and Biochemical Foundations of Living Systems › Membrane Potential and Electrochemical Gradients (2A)

Questions 1 - 10
1

In a patch-clamp experiment, a neuron is initially at rest (−70 mV). A toxin that selectively blocks voltage-gated K\(^+\) channels is applied. When an action potential is triggered by a brief current injection, the repolarization phase becomes slower and the after-hyperpolarization is reduced.

Which statement best explains the changes in membrane potential observed?

Blocking K\(^+\) channels increases K\(^+\) efflux by trapping K\(^+\) outside the cell, accelerating repolarization

Blocking K\(^+\) channels prevents Na\(^+\) channel inactivation, eliminating the action potential threshold

Blocking K\(^+\) channels reduces outward K\(^+\) current, slowing repolarization and limiting hyperpolarization after the spike

Blocking K\(^+\) channels hyperpolarizes the resting potential by increasing K\(^+\) permeability at baseline

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Membrane potential arises from the differential distribution of ions across a cell membrane, influenced by permeability and concentration gradients. In this scenario, the described changes in ion permeability directly affect membrane potential, illustrating the principle. Choice D is correct because it accurately reflects the ion movement described, consistent with the membrane potential concept. Choice B is incorrect because it assumes ion movement that contradicts the passage details, a common error when misapplying gradient principles. To avoid similar errors, ensure understanding of how ion gradients influence membrane potential and verify predictions align with passage data.

2

A neuron has intracellular K\(^+\) 140 mM and extracellular K\(^+\) 4 mM. A researcher injects KCl into the cytosol, increasing intracellular Cl\(^−\) substantially while leaving K\(^+\) nearly unchanged. Opening GABA\(_A\) receptors (Cl\(^−\) channels) now produces depolarizing responses instead of hyperpolarizing responses.

Which statement best explains the change in response polarity?

Depolarization occurs because GABA\(_A\) receptors are voltage-gated Na\(^+\) channels that open when intracellular Cl\(^−\) is high

Increasing intracellular Cl\(^−\) shifts the Cl\(^−\) equilibrium potential to a more positive value, so opening Cl\(^−\) channels can depolarize the membrane

Depolarization occurs because Cl\(^−\) always leaves cells when Cl\(^−\) channels open, regardless of concentration gradients

Increasing intracellular Cl\(^−\) shifts the K\(^+\) equilibrium potential to a more positive value, so Cl\(^−\) channels indirectly depolarize

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Membrane potential arises from the differential distribution of ions across a cell membrane, influenced by permeability and concentration gradients. In this scenario, the described changes in ion permeability directly affect membrane potential, illustrating the principle. Choice A is correct because it accurately reflects the ion movement described, consistent with the membrane potential concept. Choice B is incorrect because it assumes ion movement that contradicts the passage details, a common error when misapplying gradient principles. To avoid similar errors, ensure understanding of how ion gradients influence membrane potential and verify predictions align with passage data.

3

A neuron is voltage-clamped at −40 mV. A brief pulse opens K\(^+\)-selective channels, producing an outward current. When the holding potential is changed to −90 mV, opening the same channels produces a much smaller outward current.

Which statement best explains the change in current magnitude with membrane voltage?

At more negative voltages, K\(^+\) channels conduct fewer ions because K\(^+\) becomes electrically neutral

At more negative voltages, the K\(^+\) concentration gradient reverses direction, so K\(^+\) influx cancels efflux completely

Current decreases because changing holding potential reduces extracellular K\(^+\) concentration during the protocol

As $V_m$ approaches the K\(^+\) equilibrium potential, the electrochemical driving force for K\(^+\) decreases, reducing current

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Membrane potential arises from the differential distribution of ions across a cell membrane, influenced by permeability and concentration gradients. In this scenario, the described changes in ion permeability directly affect membrane potential, illustrating the principle. Choice D is correct because it accurately reflects the ion movement described, consistent with the membrane potential concept. Choice B is incorrect because it assumes ion movement that contradicts the passage details, a common error when misapplying gradient principles. To avoid similar errors, ensure understanding of how ion gradients influence membrane potential and verify predictions align with passage data.

4

A neuron is exposed to a drug that increases permeability to K\(^+\) only during the falling phase of the action potential (e.g., by prolonging K\(^+\) channel opening). Experimentally, the action potential duration shortens.

Which statement best explains the changes in membrane potential observed?

Greater K\(^+\) permeability increases outward K\(^+\) current during repolarization, accelerating return toward negative potentials and shortening the spike

Greater K\(^+\) permeability increases Na\(^+\) influx during the upstroke, which shortens the spike by reaching threshold faster

Greater K\(^+\) permeability increases inward K\(^+\) current during repolarization, prolonging depolarization and shortening the spike

Action potential duration shortens because resting membrane potential becomes more positive when K\(^+\) permeability increases

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Membrane potential arises from the differential distribution of ions across a cell membrane, influenced by permeability and concentration gradients. In this scenario, the drug selectively increases K⁺ permeability during the falling phase of the action potential, affecting repolarization dynamics. Choice A is correct because it accurately describes how enhanced outward K⁺ current speeds up repolarization, shortening the action potential duration. Choice B is incorrect because it assumes inward K⁺ current, which contradicts the electrochemical driving force during repolarization and misapplies gradient principles. To avoid similar errors, ensure understanding of ion flow directions based on driving forces during different action potential phases. Always verify predictions align with passage data on permeability changes and their timing.

5

A researcher studies a cell type with a resting membrane potential near −30 mV. Ion gradients are typical (high K\(^+\) inside, high Na\(^+\) outside), but the membrane expresses a large resting Na\(^+\) conductance in addition to K\(^+\) leak.

Which statement best explains why the resting membrane potential is relatively depolarized compared with neurons?

High resting Na\(^+\) permeability shifts $V_m$ toward $E_{Na}$, making the resting potential less negative despite normal gradients

A depolarized resting potential indicates the cell is continuously firing action potentials at rest

A depolarized resting potential indicates the cell cannot maintain ion gradients and therefore has no membrane potential

High resting Na\(^+\) permeability shifts $V_m$ toward $E_K$, making the resting potential less negative because K\(^+\) is more concentrated inside

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Membrane potential arises from the differential distribution of ions across a cell membrane, influenced by permeability and concentration gradients. In this scenario, the cell has typical ion gradients but unusually high resting Na⁺ permeability alongside K⁺ leak, which alters the resting potential compared to neurons. Choice D is correct because it accurately reflects how increased Na⁺ influx pulls the membrane potential toward the positive ENa, resulting in a less negative (depolarized) resting potential. Choice B is incorrect because it mistakenly attributes the shift to EK and confuses the concentration gradient of K⁺, a common error when overlooking the role of Na⁺ conductance. To avoid similar errors, ensure understanding of how relative ion permeabilities weight the resting potential toward specific equilibrium potentials. Always verify predictions align with passage data on ion conductances and gradients.

6

In an epithelial monolayer, apical application of a CFTR potentiator increased $\text{Cl}^-$ conductance across the apical membrane. Intracellular $\text{Cl}^-$ was measured at $30\ \text{mM}$ and extracellular (luminal) $\text{Cl}^-$ at $110\ \text{mM}$. The apical membrane potential (cell interior relative to lumen) was approximately $-40\ \text{mV}$. After potentiator treatment, transepithelial fluid secretion increased. Which statement best explains the principle linking increased $\text{Cl}^-$ permeability to fluid movement in this setup?

Enhanced $\text{Cl}^-$ permeability eliminates the resting potential, preventing any ion flux and forcing water to move out of the lumen.

Enhanced $\text{Cl}^-$ permeability increases $\text{Cl}^-$ flux, promoting osmotic water movement that follows the net movement of solute.

Enhanced $\text{Cl}^-$ permeability decreases $\text{Na}^+$ entry, hyperpolarizing the membrane and thereby pulling water into the cell.

Enhanced $\text{Cl}^-$ permeability directly pumps water through CFTR, increasing secretion independent of electrochemical gradients.

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Epithelial fluid secretion depends on transepithelial ion transport creating osmotic gradients that drive water movement. With intracellular [Cl⁻] = 30 mM and luminal [Cl⁻] = 110 mM, ECl is approximately -35 mV. At an apical membrane potential of -40 mV, Cl⁻ experiences an outward electrochemical gradient and will exit the cell into the lumen. Choice D is correct because Cl⁻ efflux increases luminal osmolarity, drawing water transcellularly or paracellularly into the lumen. Choice B is incorrect because CFTR is a Cl⁻ channel, not a water pump. To understand epithelial transport, consider how ion movement creates osmotic gradients that secondarily drive water flow.

7

In a ventricular myocyte, a pharmacologic agent selectively inhibits the Na$^+$/K$^+$-ATPase without directly affecting ion channels. Over several minutes, intracellular Na$^+$ increases and intracellular K$^+$ decreases, while extracellular concentrations remain approximately constant (Na$^+$ out high, K$^+$ out low). Resting membrane potential is recorded to become less negative. Which statement best explains the changes in membrane potential observed?

The membrane becomes less negative because extracellular Na$^+$ decreases substantially, reversing the Na$^+$ gradient

Reduced Na$^+$/K$^+$ pumping decreases the K$^+$ gradient, reducing K$^+$ efflux at rest and shifting $V_m$ toward depolarization

Inhibition of the pump directly opens voltage-gated Na$^+$ channels, producing an action potential upstroke at rest

Reduced pumping increases the K$^+$ gradient, enhancing K$^+$ efflux and making the membrane more negative

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). The Na+/K+-ATPase maintains ion gradients by pumping 3 Na+ out and 2 K+ in, consuming ATP. In this scenario, inhibiting the pump allows gradients to dissipate: intracellular K+ decreases and intracellular Na+ increases. Choice D is correct because the reduced K+ gradient (smaller concentration difference) decreases the driving force for K+ efflux, causing less negative membrane potential (depolarization). Choice B is incorrect because it suggests the K+ gradient increases, which is opposite to what occurs when the pump is inhibited. To understand pump inhibition effects, remember that ion gradients will dissipate toward equilibrium, reducing the concentration differences that normally maintain the resting potential.

8

In a patch-clamp experiment, a neuron was stepped from $-70\ \text{mV}$ to $+20\ \text{mV}$. A fast inward current was observed that inactivated within milliseconds. Tetrodotoxin (TTX) eliminated this transient inward current without affecting a delayed outward current. The bath and pipette solutions maintained physiological gradients (high extracellular $\text{Na}^+$, high intracellular $\text{K}^+$). Which statement best explains the changes in membrane potential observed during the initial rapid phase of an action potential in this neuron?

Opening voltage-gated $\text{Na}^+$ channels increases $\text{Na}^+$ permeability, and $\text{Na}^+$ influx drives $V_m$ toward $E_{\text{Na}}$ (depolarization).

The transient inward current reflects the resting membrane potential, which is generated by $\text{Cl}^-$ efflux through leak channels.

Opening voltage-gated $\text{K}^+$ channels increases $\text{K}^+$ permeability, and $\text{K}^+$ influx drives $V_m$ toward $E_{\text{K}}$ (depolarization).

TTX eliminates the delayed outward current by blocking $\text{K}^+$ channels, preventing repolarization and thereby abolishing the inward current.

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Action potentials involve sequential changes in membrane permeability to different ions, with voltage-gated channels responding to depolarization. The fast inward current blocked by TTX is characteristic of voltage-gated Na⁺ channels, which open rapidly upon depolarization. With high extracellular Na⁺, opening these channels allows Na⁺ influx down its electrochemical gradient, driving the membrane toward ENa (+60 mV). Choice D is correct because it accurately describes the Na⁺ influx that causes the rapid depolarization phase of the action potential. Choice B is incorrect because K⁺ channels produce outward current and K⁺ efflux, not influx. To identify ion currents, consider the direction of current flow and the specific blockers used.

9

A myotube preparation is voltage-clamped at $-80\ \text{mV}$ while a drug is applied that selectively increases sarcolemmal permeability to Cl$^-$. During the recording, measured intracellular and extracellular chloride concentrations are 10 mM and 110 mM, respectively, and other permeabilities are unchanged. The membrane potential shifts from $-80\ \text{mV}$ toward $-60\ \text{mV}$ after drug application. Which statement best explains the changes in membrane potential observed?

The shift reflects initiation of an action potential, which requires opening of voltage-gated Na$^+$ channels rather than Cl$^-$ channels

The shift occurs because Cl$^-$ efflux makes the cytosol more negative, producing hyperpolarization toward $-90\ \text{mV}$

Increased Cl$^-$ permeability drives the membrane toward the Cl$^-$ equilibrium potential, consistent with a depolarizing shift from $-80$ to $-60\ \text{mV}$

Increased Cl$^-$ permeability drives the membrane toward the Na$^+$ equilibrium potential because anions follow cation gradients

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). Membrane potential is determined by the relative permeabilities and equilibrium potentials of permeant ions. In this scenario, the Cl- equilibrium potential can be calculated using the Nernst equation: ECl = -61 log(10/110) ≈ -64 mV. Choice A is correct because increasing Cl- permeability drives the membrane potential from -80 mV toward the Cl- equilibrium potential of approximately -64 mV, explaining the observed shift to -60 mV. Choice D is incorrect because it suggests Cl- efflux, but the concentration gradient (10 mM inside, 110 mM outside) favors Cl- influx, not efflux. To avoid confusion, always calculate the equilibrium potential for the ion in question and determine whether the membrane will depolarize or hyperpolarize based on the starting potential.

10

A researcher expresses a mutated nonselective cation channel in a cell line. In whole-cell recordings, opening the channel increases permeability equally to Na$^+$ and K$^+$, with negligible permeability to Cl$^-$. Under control conditions, the membrane potential is $-65\ \text{mV}$. Ion concentrations (mM) are Na$^+$ in/out = 15/145 and K$^+$ in/out = 140/5. Based on the scenario, what effect would increasing this channel’s permeability have on the membrane potential?

It will hyperpolarize toward the K$^+$ equilibrium potential because K$^+$ concentration is higher inside than outside

It will remain at $-65\ \text{mV}$ because equal permeability to Na$^+$ and K$^+$ causes no net ionic current at any voltage

It will depolarize toward a value between the Na$^+$ and K$^+$ equilibrium potentials because both cations contribute to $V_m$

It will depolarize toward the Cl$^-$ equilibrium potential because anions determine membrane potential when cation channels open

Explanation

This question tests understanding of membrane potential and electrochemical gradients (Foundational Concept 2: Cells and Cellular Organization). When a membrane becomes equally permeable to multiple ions, the membrane potential moves toward a weighted average of their equilibrium potentials. In this scenario, the Na+ equilibrium potential is approximately +60 mV and the K+ equilibrium potential is approximately -90 mV. Choice B is correct because equal permeability to Na+ and K+ drives the membrane potential toward a value between these two equilibrium potentials, resulting in depolarization from -65 mV. Choice D is incorrect because equal permeability does not mean no net current; rather, it means the membrane potential will settle where Na+ influx equals K+ efflux. To solve such problems, recognize that the membrane potential will be influenced by all permeant ions according to their relative permeabilities.

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