Regulation of Gene Expression in Eukaryotes (1B)

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MCAT Biological and Biochemical Foundations of Living Systems › Regulation of Gene Expression in Eukaryotes (1B)

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1

A lab tests whether a putative silencer element (S) represses transcription of the eukaryotic gene GATA4. A luciferase reporter is driven by the GATA4 minimal promoter (P) alone or by P plus S cloned upstream. Cells are transfected with either an empty vector or a plasmid expressing the transcription factor REST. Results after 24 hours are shown:

Condition 1: P only + empty vector → 100% luciferase

Condition 2: P+S + empty vector → 95% luciferase

Condition 3: P only + REST → 90% luciferase

Condition 4: P+S + REST → 25% luciferase

Based on the setup, which outcome is most likely if S is mutated so that REST can no longer bind, while all other sequences remain unchanged?

Condition 1 would drop to ~25% because mutating S would reduce translation efficiency of luciferase mRNA

Condition 4 would remain ~25% because REST represses transcription by binding only the minimal promoter, not S

Condition 4 would increase toward ~90–100% because REST-mediated repression requires binding to S

Condition 2 would drop to ~25% because S intrinsically blocks RNA polymerase II elongation even without REST

Explanation

This question tests understanding of silencer elements and their requirement for transcriptional repression in eukaryotes. Gene regulation involves both positive elements (enhancers) and negative elements (silencers) that recruit specific transcription factors to modulate gene expression. The data shows that element S only represses transcription when REST is present (condition 4 shows 25% activity), while S alone has minimal effect (condition 2 shows 95% activity). The correct answer (B) logically follows because mutating S to prevent REST binding would eliminate the repression seen in condition 4, returning activity to the ~90-100% range seen when REST cannot act through S. Answer A incorrectly assumes REST acts at the minimal promoter rather than through S, contradicting the experimental design. When analyzing silencer function, remember that silencers typically require specific transcription factor binding to exert their repressive effects, distinguishing them from intrinsic negative elements.

2

A gene MET1 has a CpG-rich promoter. In cancer cells, bisulfite sequencing shows heavy methylation at this promoter and MET1 mRNA is low. Treatment with a DNA methyltransferase inhibitor decreases promoter methylation and increases MET1 mRNA. Which mechanism best explains the regulation observed?

Promoter methylation increases RNA polymerase II affinity, so demethylation should decrease MET1 transcription

Promoter CpG methylation recruits methyl-binding proteins and corepressors that reduce transcription initiation; demethylation relieves repression

Promoter methylation primarily blocks DNA replication, so demethylation increases MET1 copy number and mRNA proportionally

DNA methyltransferase inhibition increases MET1 mRNA by directly stabilizing the transcript at the poly(A) tail

Explanation

This question explores DNA methylation in eukaryotic gene regulation. Methylation at promoters in eukaryotes recruits repressors to silence genes, and demethylation can activate them, which is key in development and disease like cancer. For MET1, heavy promoter methylation correlates with low mRNA, and inhibitor-induced demethylation increases it. Choice D explains this as relief from repression via methyl-binding proteins. Choice B incorrectly states methylation activates, a misconception confusing it with histone modifications. In similar cases, check methylation status and expression correlation. Additionally, use inhibitors to confirm epigenetic mechanisms.

3

In immune cells, stimulus S activates gene TNFA. A mutation deletes an insulator element between an upstream enhancer and the TNFA promoter. After deletion, basal TNFA expression increases even without stimulus S, and a neighboring gene NEIGH also shows increased expression. Which mechanism best explains the regulation observed?

Deleting the insulator increases translation of TNFA mRNA and NEIGH mRNA by shortening their 5' UTRs

The insulator normally serves as a promoter; deleting it reduces transcription factor binding and therefore increases expression

The insulator normally blocks enhancer spillover; deleting it allows the enhancer to contact and activate the TNFA promoter and nearby promoters more frequently

Insulators recruit RNA polymerase III to transcribe TNFA; deletion forces RNA polymerase II to transcribe NEIGH

Explanation

This question tests insulator functions in eukaryotic genomes. Insulators in eukaryotes block enhancer-promoter interactions to prevent misregulation, maintaining specificity. For TNFA, insulator deletion increases basal expression and affects neighbor NEIGH, suggesting blocked spillover. Choice D explains enhanced contacts post-deletion. Choice B misidentifies insulators as promoters, a role mismatch. In mutation studies, monitor adjacent gene effects. Additionally, use looping assays to confirm interactions.

4

During differentiation, gene ALB becomes activated. ChIP shows increased binding of pioneer factor PF at a previously nucleosome-occupied enhancer upstream of ALB, followed by increased chromatin accessibility and then increased ALB transcription. Which sequence of events is most consistent with the data?

DNA replication at the enhancer increases → PF binds only after replication → transcription decreases due to promoter looping

Chromatin accessibility increases due to ribosome binding → PF binds the enhancer → ALB translation increases → ALB mRNA increases

ALB transcription increases → PF binds the enhancer → chromatin accessibility decreases → coactivators are recruited

PF binds compacted chromatin at the enhancer → chromatin accessibility increases → transcription factors/coactivators assemble → ALB transcription increases

Explanation

This question examines pioneer factors in eukaryotic chromatin remodeling. Pioneer factors in eukaryotes bind closed chromatin to initiate accessibility, paving the way for transcription during differentiation. For ALB, PF binding precedes accessibility and transcription increases. Choice C sequences events correctly: PF binding opens chromatin for activation. Choice B reverses causality, putting transcription first. In differentiation studies, order binding and accessibility data. Additionally, use ChIP to track temporal changes.

5

In a human hepatocyte cell line, researchers study the eukaryotic gene G6PC. A distal DNA element located ~12 kb upstream increases G6PC mRNA when cells are treated with hormone H. Chromatin conformation capture shows that hormone H increases physical contact between this distal element and the G6PC promoter. Inserting this distal element upstream of a minimal promoter driving luciferase increases luciferase expression regardless of whether the element is inserted in the forward or reverse orientation. Which mechanism best explains the regulation observed?

Hormone H recruits an activator that binds a distal enhancer and promotes mediator-dependent looping to the promoter to increase transcription initiation

Hormone H activates a repressor that binds a silencer in the promoter and increases transcription by preventing nucleosome eviction

Hormone H increases translation efficiency by binding the 5' cap and recruiting additional ribosomes to G6PC mRNA

Hormone H causes promoter methylation that blocks RNA polymerase II binding, thereby increasing G6PC transcription

Explanation

This question tests understanding of enhancers in eukaryotic gene regulation. Gene regulation in eukaryotes involves distal elements like enhancers that can increase transcription by interacting with promoters over long distances, often via looping, which is crucial for precise control of gene expression in response to signals. In this hepatocyte system, hormone H induces G6PC mRNA via a distal element 12 kb upstream that contacts the promoter, and the element functions bidirectionally like a classic enhancer. The correct answer D follows because hormone H likely recruits an activator to the enhancer, promoting looping and transcription initiation, consistent with the observed physical interaction and orientation independence. In contrast, choice C is incorrect as promoter methylation typically represses transcription by blocking polymerase binding, a common misconception that methylation can activate genes. When evaluating similar questions, always consider whether the regulatory element acts at the transcriptional or post-transcriptional level. Additionally, check if the mechanism involves chromatin looping or direct promoter modifications for distal regulation.

6

In a cell-type specificity study, gene KRT14 is highly expressed in basal epithelial cells but low in fibroblasts. DNase I hypersensitivity mapping shows an open chromatin site at an upstream enhancer in basal cells but not in fibroblasts. Both cell types have the same enhancer DNA sequence. Which mechanism best explains the regulation observed?

Basal cells express lineage-specific transcription factors that bind the enhancer and maintain accessible chromatin, enabling high transcription

Fibroblasts translate KRT14 mRNA inefficiently, which directly decreases KRT14 mRNA levels

Basal cells have increased DNA replication at the enhancer, creating more enhancer copies and higher transcription

Fibroblasts lack RNA polymerase II genes, preventing transcription of KRT14

Explanation

This question addresses cell-type-specific enhancer accessibility in eukaryotes. Eukaryotic gene regulation uses lineage-specific factors to maintain open chromatin at enhancers, enabling high expression in certain cells. For KRT14, basal cells show open enhancer chromatin and high expression, unlike fibroblasts, despite identical sequences. Choice A explains this via specific factors promoting accessibility. Choice B exaggerates by claiming fibroblasts lack polymerase, ignoring selective regulation. In cell-type studies, compare accessibility assays. Additionally, verify sequence identity to rule out mutations.

7

A CRISPR interference (CRISPRi) system is targeted to a distal enhancer of gene VEGFA using dCas9-KRAB, which recruits corepressors. After targeting, enhancer-associated histone acetylation decreases and VEGFA mRNA decreases, while the promoter sequence is unchanged. Which mechanism best explains the regulation observed?

CRISPRi decreases VEGFA mRNA by preventing DNA replication of the VEGFA locus

Enhancer repression increases transcription by forcing RNA polymerase II to initiate at the promoter more frequently

dCas9-KRAB blocks translation elongation of VEGFA mRNA by binding the coding sequence

KRAB recruitment promotes repressive chromatin at the enhancer, reducing enhancer activity and lowering transcription from the promoter

Explanation

This question examines CRISPR-mediated repression of enhancers in eukaryotes. In eukaryotic regulation, enhancers can be repressed by recruiting corepressors like KRAB, which induce repressive chromatin to decrease transcription. For VEGFA, CRISPRi targeting the enhancer reduces acetylation and mRNA without promoter changes. Choice D correctly attributes this to repressive chromatin diminishing enhancer activity. Choice B misplaces repression to translation, a post-transcriptional error. For CRISPR studies, assess chromatin and expression effects. Also, confirm target specificity to enhancers versus promoters.

8

A lab identifies two regulatory sequences near gene GENE7: an enhancer E and a silencer S. In a reporter construct containing promoter + E + S, baseline luciferase is low. Deleting S increases baseline luciferase 6-fold, while deleting E decreases luciferase to near zero. Under stimulus U, luciferase increases 8-fold only when E is present. Which mechanism best explains the regulation observed?

E is required for activation (including stimulus responsiveness), while S recruits repressors that reduce baseline transcription in the absence of strong activation

Deleting S increases luciferase because it removes the start codon, improving translation of luciferase mRNA

S is required for activation by binding RNA polymerase II, while E blocks transcription by recruiting repressors

Deleting E decreases luciferase because enhancers encode essential splice sites needed for luciferase mRNA processing

Explanation

This question assesses interplay between enhancers and silencers in eukaryotes. Gene regulation in eukaryotes balances activators and repressors for controlled expression, with enhancers driving induction and silencers setting baselines. For GENE7, E enables stimulus response, while S represses baseline, as deletions show. Choice D explains E's activation role and S's repression. Choice B swaps functions, a common confusion in multi-element systems. When deleting elements, compare basal and induced effects. Additionally, test combinations to uncover interactions.

9

A lab uses a synthetic transcription factor that binds a unique DNA site upstream of gene X. When fused to an activation domain (AD), gene X mRNA increases. When fused to a repression domain (RD), gene X mRNA decreases. The DNA-binding domain is identical in both constructs. Which mechanism best explains the regulation observed?

DNA-binding domains determine translation rate, so identical binding domains should yield identical mRNA changes

The activation domain increases mRNA by enhancing ribosomal peptidyl transferase activity

The effector domain determines recruitment of coactivators or corepressors at the regulatory site, altering transcription initiation at the promoter

The repression domain decreases mRNA by blocking DNA replication forks at gene X

Explanation

This question probes modular transcription factor design in eukaryotes. Eukaryotic TFs have domains for DNA binding and effector functions, allowing recruitment of coactivators or corepressors to modulate transcription. For gene X, AD fusion activates while RD represses, with identical binding domains. Choice A attributes differences to effector recruitment altering initiation. Choice D ignores effector roles, assuming binding suffices. In synthetic TF experiments, compare domain effects. Furthermore, confirm binding site specificity.

10

In an experiment, an enhancer E driving gene Y contains binding sites for activator A and cofactor C. Cells express A constitutively, but C is induced by stimulus W. Reporter assays show little change with W when only A sites are present; strong induction occurs when both A and C sites are intact. Which mechanism best explains the regulation observed?

Enhancers require both A and C sites to function only because they must be transcribed into a regulatory RNA

Combinatorial control: A primes enhancer occupancy, but W-induced C provides additional activation (e.g., coactivator recruitment) needed for strong transcriptional induction

W induces C, which increases gene Y by enhancing mRNA translation, independent of enhancer binding sites

A sites are silencers, so removing them should increase induction by W

Explanation

This question assesses combinatorial regulation in eukaryotes. Combinatorial control in eukaryotes integrates multiple factors for precise, synergistic activation, crucial for complex responses. For enhancer E, A sites alone yield weak response; A and C sites together enable strong induction by W via C. Choice A explains this synergy in recruitment. Choice C mislabels sites as silencers, confusing activation requirements. For combinatorial questions, test site combinations. Also, consider constitutive versus induced factors.

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