Amino Acid Structure and Classification (1A)

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MCAT Biological and Biochemical Foundations of Living Systems › Amino Acid Structure and Classification (1A)

Questions 1 - 10
1

A mutation replaces a residue involved in a salt bridge with a partner carboxylate (–COO$^-$) at pH 7.4. Which new residue is most likely to preserve the electrostatic interaction by remaining positively charged at pH 7.4?

General amino acid: $\mathrm{H_3N^+-CH(R)-COO^-}$

Tyrosine

Glutamine

Glycine

Lysine

Explanation

This question tests the understanding of amino acid structure and classification, focusing on charged side chains in electrostatic interactions. Basic amino acids like lysine have high pKa amine groups (~10.5), remaining protonated and positively charged at pH 7.4 to form salt bridges with anions. The mutation replaces a residue in a salt bridge with a carboxylate, requiring a new positive charge to preserve the interaction. Lysine (choice C) suits this as its side chain stays +1 at pH 7.4, maintaining the bridge. Glutamine (choice A) fails being polar uncharged, lacking charge for electrostatics, reflecting a misconception equating polarity with ionicity. Verify by comparing side chain pKa to ensure charge state. This underscores salt bridges' role in protein stability.

2

A folded protein is exposed to increasing pH from 7.0 to 11.0, and a surface patch becomes more negatively charged, increasing electrostatic repulsion. Which residue type on the surface is most consistent with gaining negative charge over this pH range due to side-chain deprotonation?

General amino acid: $\mathrm{H_3N^+-CH(R)-COO^-}$

Tyrosine (phenolic –OH side chain)

Lysine (basic amine side chain)

Leucine (aliphatic side chain)

Arginine (guanidinium side chain)

Explanation

This question tests the understanding of amino acid structure and classification, examining pH-dependent deprotonation and charge effects on protein surfaces. Amino acids with ionizable side chains change charge with pH; tyrosine's phenolic OH (pKa ~10) deprotonates to negative in the 7-11 range, unlike basics that neutralize. The protein surface becomes more negatively charged from pH 7 to 11, increasing repulsion via side-chain deprotonation. Tyrosine (choice B) fits as it shifts from neutral to -1, gaining negative charge and boosting repulsion. Lysine (choice A) fails by neutralizing from +1 to 0, reducing positive repulsion not increasing negative, a misconception about charge gain. Check pKa ranges for deprotonation windows. This illustrates pH-induced unfolding via electrostatics.

3

A peptide containing a single histidine is analyzed by isoelectric focusing in a buffer that is stepped from pH 5.5 to pH 8.5. The residue of interest has an imidazole side chain (p$K_a$ near 6). Which conclusion about the histidine side chain is most consistent with its predominant charge state at pH 8.5?

General amino acid: $\mathrm{H_3N^+-CH(R)-COO^-}$

It is predominantly protonated and positively charged

It is predominantly deprotonated and neutral

It is predominantly zwitterionic with a +1 net charge on the side chain

It is predominantly deprotonated and negatively charged

Explanation

This question tests the understanding of amino acid structure and classification, particularly the ionization behavior of side chains in response to pH changes. Amino acids have side chains with varying pKa values that determine their protonation state and charge at a given pH, with histidine's imidazole group having a pKa around 6, allowing it to switch between charged and neutral forms near physiological pH. In this isoelectric focusing experiment, the histidine side chain is examined at pH 8.5, which is above its pKa, leading to deprotonation. This state is predominantly deprotonated and neutral (choice B) because at pH > pKa, the imidazole loses its proton, resulting in a net zero charge on the side chain. Conversely, choice A fails by assuming it remains protonated and positive, a misconception ignoring the Henderson-Hasselbalch equation where pH >> pKa favors deprotonation. A transferable check is to calculate the fraction deprotonated using 10^(pH - pKa)/(1 + 10^(pH - pKa)). This clarifies how histidine acts as a pH-sensitive switch in proteins.

4

A researcher compares two peptides that differ at one position: one has an R-group of –CH$_2$–OH and the other has –CH$_2$–CH$_2$–S–CH$_3$. In an aqueous buffer at pH 7.4, which conclusion about that position is most consistent with amino acid classification?

General amino acid: $\mathrm{H_3N^+-CH(R)-COO^-}$

The –CH$_2$–OH residue is polar uncharged and can hydrogen bond with water

The –CH$_2$–OH residue is nonpolar and tends to be buried

The thioether residue is polar and tends to be solvent-exposed

Both residues are acidic and will be negatively charged at pH 7.4

Explanation

This question tests the understanding of amino acid structure and classification, comparing polar and nonpolar side chains in aqueous environments. Amino acids are categorized by side chain properties, with polar uncharged like serine (–CH₂–OH) forming hydrogen bonds with water for solvent exposure, while nonpolar like methionine (–CH₂–CH₂–S–CH₃) prefer burial. The peptides differ at a position with these R-groups in pH 7.4 buffer, affecting solvation. Choice C correctly states the –CH₂–OH (serine) is polar uncharged and H-bonds with water, aligning with its classification. Choice B fails by calling the thioether (methionine) polar and exposed, a misconception as methionine is nonpolar despite sulfur. Assess by reviewing standard classifications and hydropathy. This clarifies how side chains dictate protein surface properties.

5

A short peptide is placed in a solution at pH 2.0. Consider a residue with a side chain containing a carboxyl group (–CH$_2$–COOH) in addition to the backbone carboxyl. Which statement is most consistent with the side-chain charge of that residue at pH 2.0?

General amino acid: $\mathrm{H_3N^+-CH(R)-COO^-}$

The side chain is predominantly zwitterionic with net 0 charge due to internal salt formation

The side chain is predominantly protonated and neutral

The side chain is predominantly protonated and carries a +1 charge

The side chain is predominantly deprotonated and carries a −1 charge

Explanation

This question tests the understanding of amino acid structure and classification, specifically the protonation states of acidic side chains at low pH. Amino acids with carboxyl side chains, like aspartate, have pKa values around 4, meaning they are protonated and neutral below this pH, while deprotonated and charged above it. In this peptide at pH 2.0, the side chain carboxyl (–CH₂–COOH) is below its pKa, favoring protonation. Thus, it is predominantly protonated and neutral (choice B), as the acidic group retains its hydrogen, yielding zero charge. Choice A fails by claiming deprotonation and negative charge, a misconception ignoring that pH < pKa promotes protonation for acids. To verify, use the Henderson-Hasselbalch equation to estimate protonated fraction. This concept extends to predicting peptide behavior in acidic cellular compartments.

6

A membrane protein segment is reconstituted into lipid vesicles. A single residue in the middle of a transmembrane helix is mutated, and the mutant shows reduced insertion efficiency into the hydrophobic bilayer core. Which replacement is most consistent with introducing an energetically unfavorable polar/charged group into the bilayer interior?

General amino acid: $\mathrm{H_3N^+-CH(R)-COO^-}$

Isoleucine $\rightarrow$ Valine

Alanine $\rightarrow$ Glycine

Phenylalanine $\rightarrow$ Leucine

Leucine $\rightarrow$ Aspartate

Explanation

This question tests the understanding of amino acid structure and classification, emphasizing the role of side chain polarity in membrane protein insertion. Amino acids are grouped by side chain hydrophobicity, with nonpolar residues favoring the lipid bilayer core, while polar or charged ones incur energetic penalties in hydrophobic environments. Here, a mutation in a transmembrane helix reduces insertion efficiency into lipid vesicles by introducing a polar or charged group into the bilayer interior. Leucine to aspartate (choice A) fits because leucine is nonpolar, but aspartate's carboxyl group is charged and polar, making insertion unfavorable. In contrast, isoleucine to valine (choice B) fails as both are nonpolar aliphatics, not introducing polarity, stemming from a misconception that all substitutions disrupt membranes equally. To check, evaluate side chain hydropathy scores for membrane compatibility. This highlights how charged residues in transmembrane segments can cause misfolding or retention in aqueous phases.

7

A soluble cytosolic protein is engineered to increase stability by strengthening its hydrophobic core. One candidate substitution introduces an amino acid with $R = \text{CH}_3$. The backbone is $\mathrm{H_3N^+-CH(R)-COO^-}$ at pH 7.4. Which outcome is most consistent with this residue’s classification in a folded, water-soluble protein?

It is acidic and forms salt bridges with lysine

It is basic and more likely to be solvent exposed

It is polar and stabilizes the surface via hydrogen bonding

It is nonpolar and more likely to be buried in the interior

Explanation

This question tests amino acid classification and its impact on protein stability through core interactions. Side chains classify amino acids as nonpolar (hydrophobic), promoting burial in protein interiors to enhance stability. The substitution introduces R = CH₃, alanine, a nonpolar residue. This nonpolar nature makes it more likely buried, strengthening the hydrophobic core for stability. Suggesting it is basic and solvent-exposed errs by ignoring the methyl group's lack of charge, misclassifying nonpolar as charged. Verify by assessing if the side chain is small and aliphatic without polar atoms. Such classifications guide engineering efforts to optimize protein folding and thermostability.

8

An enzyme active site contains a residue that must act as a nucleophile at pH 7.0 by presenting a deprotonated heteroatom on its side chain. A point mutation replaces this residue with one that is usually protonated (positively charged) at pH 7.0, reducing catalysis. Which substitution is most consistent with this loss of nucleophilicity due to side-chain classification?

Asn  Gln

Cys  Lys

Asp  Glu

Ser  Thr

Explanation

This question tests understanding of amino acid side chain properties and their roles in enzyme catalysis. Nucleophiles are electron-rich species that can attack electrophilic centers, requiring a deprotonated heteroatom (like O, N, or S) at physiological pH. Cysteine has a thiol group (pKa ~8) that can be deprotonated to form a nucleophilic thiolate anion at pH 7.0. The substitution Cys → Lys (choice B) replaces this potential nucleophile with lysine, which has a primary amine side chain (pKa ~10.5) that remains protonated and positively charged at pH 7.0, eliminating nucleophilicity. Options A (Ser → Thr), C (Asp → Glu), and D (Asn → Gln) involve substitutions between similar amino acids that would not dramatically change nucleophilic character. A common misconception is confusing basicity with nucleophilicity; while lysine is basic, its protonated state at pH 7 prevents it from acting as a nucleophile.

9

An enzyme active site requires a residue that can accept a proton near physiological pH and often participates in acid–base catalysis. A mutation replaces this residue with one whose side chain is $R = \text{CH}_2\text{-CH}_2\text{-COO}^-$. Which substitution is most likely to preserve the original residue’s basic classification and catalytic role?

Replace with serine ($R = \text{CH}_2\text{-OH$)

Replace with aspartate ($R = \text{CH}_2\text{-COO}^-$)

Replace with lysine ($R = (\text{CH}_2)_4\text{-NH}_3^+$ at pH 7)

Replace with leucine ($R = \text{CH}_2\text{-CH(CH}_3)_2$)

Explanation

This question tests understanding of amino acid classifications and their roles in enzyme catalysis, particularly acid-base functions. Amino acids are classified by side chains: basic ones like lysine can accept protons due to their amine groups. The original residue is basic for proton acceptance in catalysis, but mutation to R = CH₂-CH₂-COO⁻ (glutamate, acidic) disrupts this. Replacing with lysine (R = (CH₂)₄-NH₃⁺) preserves the basic classification and catalytic role via its protonatable amine. A distractor suggesting leucine fails as it is nonpolar, lacking charge for acid-base catalysis, confusing hydrophobicity with basicity. Check by confirming side chain pKa allows proton acceptance near pH 7. This clarifies how basic residues facilitate catalysis in active sites.

10

A peptide (10 residues) is analyzed by isoelectric focusing. At pH 3.0 the peptide migrates toward the cathode, but at pH 10.0 it migrates toward the anode. The investigator suspects a single side chain with a p$K_a$ near physiological pH contributes substantially to the charge change. Which residue is most consistent with this behavior based on its side-chain functional group?

Lysine (primary amine side chain)

Leucine (aliphatic side chain)

Histidine (imidazole side chain)

Aspartate (carboxylate side chain)

Explanation

This question tests understanding of amino acid ionization states and their pH-dependent behavior. Amino acids have characteristic pKa values for their ionizable groups: carboxyl groups (~2-4), amino groups (~9-10), and certain side chains. At pH 3.0, the peptide migrates toward the cathode (negative electrode), indicating a net positive charge, while at pH 10.0 it migrates toward the anode (positive electrode), indicating a net negative charge. Histidine (choice A) has an imidazole side chain with a pKa around 6.0, meaning it transitions from protonated (positive) to deprotonated (neutral) near physiological pH. Leucine (B) has no ionizable side chain, aspartate (C) has a carboxylate with pKa ~3.8 that would already be deprotonated at pH 3, and lysine (D) has a primary amine with pKa ~10.5 that would remain protonated even at pH 10. The dramatic charge change between pH 3 and 10 is best explained by histidine's unique pKa near the middle of this range.

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