Ratios and Comparisons
Help Questions
ISEE Upper Level: Quantitative Reasoning › Ratios and Comparisons
A recipe calls for flour and sugar in the ratio $$5:2$$. If Maria uses 15 cups of flour, how much sugar should she use to maintain the same ratio?
6 cups of sugar
10 cups of sugar
7.5 cups of sugar
37.5 cups of sugar
Explanation
When you see ratio problems, you're working with proportional relationships where quantities maintain a constant relationship to each other. The key is setting up a proportion to find the unknown value.
The recipe uses flour and sugar in a $$5:2$$ ratio, meaning for every 5 parts flour, you need 2 parts sugar. Since Maria uses 15 cups of flour, you need to find how many "parts" this represents: $$15 ÷ 5 = 3$$ parts. If the flour is 3 times the base amount, the sugar must also be 3 times its base amount: $$2 × 3 = 6$$ cups of sugar.
You can also solve this using cross-multiplication: $$\frac{5}{2} = \frac{15}{x}$$, which gives you $$5x = 30$$, so $$x = 6$$.
Looking at the wrong answers: Choice B (7.5 cups) comes from incorrectly thinking you multiply the flour amount by the sugar ratio: $$15 × \frac{2}{5} = 6$$, but then making an arithmetic error. Choice C (10 cups) results from confusing the ratios and thinking it's $$2:1$$ instead of $$5:2$$. Choice D (37.5 cups) comes from mistakenly multiplying $$15 × 2.5$$ (which would be $$15 × \frac{5}{2}$$), completely reversing the relationship.
The answer is A: 6 cups of sugar.
Strategy tip: In ratio problems, always identify what one "part" equals by dividing the known quantity by its ratio number, then multiply by the unknown quantity's ratio number. This two-step approach prevents most ratio errors.
In a mixture, the ratio of water to orange juice is $$2:3$$. If 10 liters of water and 5 liters of orange juice are added to 40 liters of this mixture, what is the new ratio of water to orange juice?
$$26:29$$
$$22:23$$
$$1:1$$
$$3:4$$
Explanation
When you encounter ratio problems involving mixtures, the key is to track each component separately through all changes, then form the new ratio at the end.
Start by finding how much water and orange juice are in the original 40-liter mixture. With a $$2:3$$ ratio of water to orange juice, the mixture contains $$\frac{2}{2+3} = \frac{2}{5}$$ water and $$\frac{3}{5}$$ orange juice. So there are $$40 \times \frac{2}{5} = 16$$ liters of water and $$40 \times \frac{3}{5} = 24$$ liters of orange juice initially.
After adding 10 liters of water and 5 liters of orange juice, you have:
- Water: $$16 + 10 = 26$$ liters
- Orange juice: $$24 + 5 = 29$$ liters
The new ratio is $$26:29$$, which is answer choice B.
Let's examine why the other answers are incorrect. Choice A ($$1:1$$) would require equal amounts of water and orange juice, but we have 26 and 29 liters respectively. Choice C ($$3:4$$) might tempt you if you mistakenly thought the original ratio would be preserved after adding equal proportions, but we're adding different amounts (10 vs 5 liters). Choice D ($$22:23$$) could result from calculation errors, perhaps incorrectly determining the original mixture contents.
Remember: in mixture problems, always break down the original mixture into its components first, then add the new quantities to each component separately. Don't try to work with ratios directly when adding different amounts to each part.
Two numbers are in the ratio $$5:7$$. If the sum of the numbers is 96, what is the ratio of the smaller number to the difference between the larger and smaller numbers?
$$2:5$$
$$5:12$$
$$40:16$$
$$5:2$$
Explanation
When you encounter ratio problems with given sums, set up the problem using variables that maintain the ratio relationship. Since the numbers are in the ratio $$5:7$$, you can represent them as $$5x$$ and $$7x$$ for some value $$x$$.
Given that their sum is 96, you have: $$5x + 7x = 96$$, which simplifies to $$12x = 96$$, so $$x = 8$$. Therefore, the two numbers are $$5(8) = 40$$ and $$7(8) = 56$$.
The question asks for the ratio of the smaller number to the difference between the larger and smaller numbers. The smaller number is 40, and the difference is $$56 - 40 = 16$$. So the ratio is $$40:16$$, which simplifies to $$5:2$$ by dividing both terms by 8.
Looking at the wrong answers: Choice B ($$40:16$$) represents the unsimplified form of the correct ratio—always reduce ratios to lowest terms. Choice C ($$2:5$$) reverses the correct ratio, giving you the difference to the smaller number instead of smaller number to difference. Choice D ($$5:12$$) incorrectly uses the sum of both numbers (which relates to the $$12x$$ from our equation) instead of their difference.
Strategy tip: In multi-step ratio problems, work systematically: first find the actual numbers using the given constraint, then calculate what the question specifically asks for. Always check that your final answer addresses exactly what was requested, and remember to simplify ratios to lowest terms.
In a parking lot, the ratio of cars to motorcycles to bicycles is $$12:3:2$$. If there are 34 total vehicles and each bicycle is replaced with a car, what will be the new ratio of cars to motorcycles?
$$7:1$$
$$26:6$$
$$8:2$$
$$14:3$$
Explanation
When you encounter ratio problems with multiple changes, break them down step by step. First, determine the actual quantities, then apply the changes, and finally calculate the new ratio.
Start by finding how many of each vehicle type exists initially. The ratio $$12:3:2$$ means for every 17 parts total ($$12+3+2=17$$), there are 34 vehicles. So each part equals $$34÷17=2$$ vehicles. This gives us: 12 parts × 2 = 24 cars, 3 parts × 2 = 6 motorcycles, and 2 parts × 2 = 4 bicycles.
Next, apply the change: each bicycle becomes a car. The 4 bicycles are replaced with 4 cars, giving us $$24+4=28$$ cars and still 6 motorcycles. The new ratio is $$28:6$$, which simplifies to $$14:3$$ by dividing both terms by 2.
Looking at the wrong answers: Choice A ($$7:1$$) incorrectly reduces $$14:3$$ further, perhaps by mistakenly dividing by different numbers. Choice C ($$26:6$$) likely comes from adding only 2 cars instead of 4, missing that all 4 bicycles become cars. Choice D ($$8:2$$) appears to be a random simplification that doesn't match the actual numbers.
Remember that in ratio problems involving changes, always work with actual quantities first rather than trying to manipulate the ratios directly. Convert ratios to real numbers, make the specified changes, then create your new ratio and simplify if possible.
Two machines produce widgets in the ratio $$5:3$$. If Machine A produces 15 widgets per hour, what is the ratio of Machine B's hourly production to the total hourly production of both machines?
$$9:24$$
$$3:8$$
$$1:3$$
$$9:15$$
Explanation
When you encounter ratio problems involving multiple machines or workers, focus on finding the actual production rates first, then use those to calculate any requested ratios.
Given that the machines produce widgets in a $$5:3$$ ratio and Machine A produces 15 widgets per hour, you can find Machine B's rate. Since Machine A corresponds to the "5" part of the ratio, each ratio unit represents $$15 ÷ 5 = 3$$ widgets per hour. Therefore, Machine B produces $$3 × 3 = 9$$ widgets per hour.
The total hourly production is $$15 + 9 = 24$$ widgets. The ratio of Machine B's production to total production is $$9:24$$, which simplifies to $$3:8$$ by dividing both terms by 3.
Looking at the wrong answers: Choice A gives $$9:24$$, which is the unsimplified form of the correct ratio—always simplify ratios to lowest terms. Choice C shows $$1:3$$, which incorrectly suggests Machine B produces only one-third of the total, when it actually produces three-eighths. Choice D presents $$9:15$$, which compares Machine B's production to only Machine A's production rather than the total production of both machines.
Strategy tip: In ratio problems, always identify what each number in the original ratio represents in real units, calculate the actual values, then build your final ratio step by step. Watch out for answer choices that give correct intermediate calculations but don't answer the specific question asked.
The ages of three siblings are in the ratio $$2:3:5$$. In 4 years, the sum of their ages will be 46. What is the current ratio of the youngest sibling's age to the oldest sibling's age?
$$10:25$$
$$4:10$$
$$2:5$$
$$6:15$$
Explanation
When you encounter ratio problems with age changes over time, the key insight is that ratios change as people age, but you can use the given information to find the actual current ages first.
Since the current ages are in the ratio $$2:3:5$$, you can represent them as $$2x$$, $$3x$$, and $$5x$$ for some value $$x$$. In 4 years, these ages become $$(2x+4)$$, $$(3x+4)$$, and $$(5x+4)$$. Their sum will be 46, so:
$$(2x+4) + (3x+4) + (5x+4) = 46$$
$$10x + 12 = 46$$
$$10x = 34$$
$$x = 3.4$$
Therefore, the current ages are $$2(3.4) = 6.8$$, $$3(3.4) = 10.2$$, and $$5(3.4) = 17$$ years old. The ratio of youngest to oldest is $$6.8:17$$, which simplifies to $$2:5$$.
Choice A ($$6:15$$) incorrectly assumes $$x = 3$$ and creates a ratio that doesn't match the original $$2:5$$ relationship. Choice C ($$10:25$$) appears to multiply the correct ratio by 5, perhaps confusing the sum with individual terms. Choice D ($$4:10$$) doubles the original ratio values, possibly from incorrectly adding the 4-year age increase to the ratio itself rather than solving for actual ages first.
The correct answer is B.
Remember: in ratio problems involving changes over time, always solve for the actual values first, then create the new ratio from those concrete numbers. Don't try to manipulate the ratios directly.
A factory produces red, blue, and green widgets in the ratio $$6:4:5$$. If production increases such that red widget output doubles, blue widget output increases by 50%, and green widget output remains constant, what is the new ratio of red to blue to green widgets?
$$12:8:5$$
$$8:3:5$$
$$6:2:5$$
$$12:6:5$$
Explanation
Ratio problems involving changes require you to apply percentage increases to each component separately, then express the results in simplest form.
Start with the original ratio of red:blue:green widgets at $$6:4:5$$. Now apply each change:
- Red widgets double: $$6 \times 2 = 12$$
- Blue widgets increase by 50%: $$4 \times 1.5 = 6$$
- Green widgets remain constant: $$5$$
This gives you the new ratio $$12:6:5$$, which is already in simplest form since 12, 6, and 5 share no common factors other than 1.
Looking at the wrong answers: Choice B ($$8:3:5$$) appears to come from incorrectly calculating the blue increase as 25% instead of 50%, giving $$4 \times 1.25 = 5$$, then somehow arriving at different values entirely. Choice C ($$6:2:5$$) suggests someone misunderstood "doubles" as "increases by 100%" but applied it incorrectly, and severely miscalculated the blue increase. Choice D ($$12:8:5$$) correctly doubles the red widgets but incorrectly doubles the blue widgets too, instead of applying the 50% increase.
The correct answer is A: $$12:6:5$$.
Remember that "increases by X%" means you multiply by $$(1 + \frac{X}{100})$$, while "doubles" means you multiply by 2. Always double-check that you're applying the right operation to each component, and verify your final ratio is in simplest form by checking for common factors.
A concrete mixture contains cement, sand, and gravel in the ratio $$1:3:4$$. If a construction project uses 24 cubic yards of this mixture and requires an additional 6 cubic yards of sand to be added separately, what is the ratio of sand to the total volume of materials?
$$9:30$$
$$15:30$$
$$3:10$$
$$1:2$$
Explanation
When you encounter ratio problems that involve adding materials, you need to carefully track both the original components and any additions to find the new total.
Start by finding how much of each material is in the original 24 cubic yards of concrete. The ratio $$1:3:4$$ means for every 8 parts total ($$1+3+4=8$$), cement gets 1 part, sand gets 3 parts, and gravel gets 4 parts. So the original mixture contains: $$\frac{3}{8} \times 24 = 9$$ cubic yards of sand, along with 3 cubic yards of cement and 12 cubic yards of gravel.
After adding 6 cubic yards of sand separately, you have $$9 + 6 = 15$$ cubic yards of sand total. The total volume of all materials is now $$24 + 6 = 30$$ cubic yards. Therefore, the ratio of sand to total volume is $$15:30$$, which simplifies to $$1:2$$.
Choice A ($$15:30$$) represents the unsimplified form of the correct ratio, but ratios should always be reduced to lowest terms. Choice C ($$9:30$$) incorrectly uses only the original sand amount, forgetting to include the 6 cubic yards added separately. Choice D ($$3:10$$) appears to use the original ratio of sand to total concrete ($$3:8$$) but incorrectly adjusted.
Always remember to simplify ratios to their lowest terms, and when materials are added to an existing mixture, update both the component amounts and the total volume before calculating your final ratio.
In a chess tournament, the ratio of wins to losses to draws for Player A is $$4:1:2$$. Player A has played 21 games total. If Player A wins the next 3 games, what will be the new ratio of wins to total games played?
$$15:24$$
$$5:8$$
$$4:7$$
$$12:21$$
Explanation
Ratio problems require you to work with parts and wholes systematically. When you see a ratio like $$4:1:2$$, these numbers represent relative parts, not actual quantities.
First, find the actual number of wins, losses, and draws. The ratio $$4:1:2$$ means for every 7 total parts ($$4+1+2=7$$), Player A has 4 wins, 1 loss, and 2 draws. Since Player A played 21 games total, each part represents $$21 \div 7 = 3$$ games. Therefore: wins = $$4 \times 3 = 12$$, losses = $$1 \times 3 = 3$$, draws = $$2 \times 3 = 6$$.
After winning the next 3 games, Player A will have $$12 + 3 = 15$$ wins out of $$21 + 3 = 24$$ total games. The ratio of wins to total games is $$15:24$$. To simplify, divide both numbers by their greatest common factor of 3: $$15:24 = 5:8$$.
Choice A ($$15:24$$) represents the unsimplified ratio - a common trap since this is the correct relationship but not in simplest form. Choice C ($$12:21$$) uses the original wins and games before the additional 3 victories. Choice D ($$4:7$$) incorrectly applies the original win ratio (4 parts out of 7 total parts) without accounting for the changed situation.
The correct answer is B.
Strategy tip: Always check whether ratios need to be simplified on the ISEE. Calculate the actual quantities first, then form your new ratio, and finally reduce to lowest terms by finding the greatest common factor.
A theater budget is sets:costumes $=7:5$; if costumes increase $50%$, what is the new ratio?
7:7.5
7:10
10.5:5
5:7
Explanation
This question tests ISEE Upper Level quantitative reasoning skills, specifically calculating new ratios when one quantity changes by a percentage. The theater budget starts with sets:costumes = 7:5, and when costumes increase by 50%, the costume budget becomes 5 × 1.5 = 7.5, while sets remain at 7. The new ratio is therefore 7:7.5, which can also be expressed as 14:15 when both terms are multiplied by 2 to eliminate the decimal. Choice A is correct because it accurately represents the new ratio with sets at 7 and costumes at 7.5. Choice B incorrectly calculates the 50% increase, choice C reverses and miscalculates the ratio, and choice D shows the original ratio reversed. To master this concept, students should practice calculating percentage increases first, then form the new ratio, being comfortable with decimal values in ratios when appropriate.