ISEE Upper Level Quantitative Reasoning · Question of the Day

ISEE Upper Level Quantitative Reasoning Question of the Day

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Friday, August 14, 2026

Question of the Day

Answer today's ISEE Upper Level Quantitative Reasoning question, reveal the full explanation, then keep the streak going with a new question every day.

In an arithmetic sequence, the 3rd term is 17 and the 8th term is 42. What is the 15th term?

  1. 77 (correct answer)
  2. 79
  3. 81
  4. 83

Explanation: When you encounter arithmetic sequence problems, you're working with patterns where each term increases by the same constant difference. The key is finding that common difference and using the arithmetic sequence formula. In an arithmetic sequence, any term can be found using an=a1+(n1)da_n = a_1 + (n-1)d, where a1a_1 is the first term and dd is the common difference. Since you know the 3rd term is 17 and the 8th term is 42, you can set up equations: a3=a1+2d=17a_3 = a_1 + 2d = 17 and a8=a1+7d=42a_8 = a_1 + 7d = 42. To find the common difference, subtract the first equation from the second: (a1+7d)(a1+2d)=4217(a_1 + 7d) - (a_1 + 2d) = 42 - 17, which gives you 5d=255d = 25, so d=5d = 5. Now find the first term by substituting back: a1+2(5)=17a_1 + 2(5) = 17, so a1=7a_1 = 7. For the 15th term: a15=7+(151)(5)=7+70=77a_{15} = 7 + (15-1)(5) = 7 + 70 = 77. Looking at the wrong answers: B) 79 results from miscalculating the common difference as 6 instead of 5. C) 81 comes from incorrectly using d=5d = 5 but making an arithmetic error in the final calculation. D) 83 typically results from finding the wrong first term, perhaps using a1=9a_1 = 9 instead of 7. Remember this pattern: when given two terms in an arithmetic sequence, always subtract to find the common difference first. The difference between the terms divided by the difference between their positions gives you dd.