Difference of Two Population Proportions (Setup)
Help Questions
AP Statistics › Difference of Two Population Proportions (Setup)
A city compares two methods for repairing potholes to see which results in fewer repairs needed within 6 months. For Method A, 19 of 85 repaired potholes needed another repair within 6 months. For Method B, 10 of 80 repaired potholes needed another repair within 6 months. The city’s research claim is that Method A has a higher proportion needing another repair than Method B. Which hypotheses are appropriate for testing this claim about the population proportions?
$H_0: p_A=0.20\quad\text{vs.}\quad H_a: p_A>0.20$
$H_0: \hat{p}_A-\hat{p}_B=0\quad\text{vs.}\quad H_a: \hat{p}_A-\hat{p}_B>0$
$H_0: p_B-p_A=0\quad\text{vs.}\quad H_a: p_B-p_A>0$
$H_0: p_A-p_B=0\quad\text{vs.}\quad H_a: p_A-p_B>0$
$H_0: p_A-p_B=0\quad\text{vs.}\quad H_a: p_A-p_B<0$
Explanation
The city claims Method A has a higher proportion needing repairs than Method B, which is a directional claim requiring a one-sided test. The alternative hypothesis should be p_A - p_B > 0. Option A incorrectly uses p_A - p_B < 0, which would mean Method A is better, contradicting the claim. Option C uses sample statistics (p̂) instead of population parameters. Option D reverses the order to p_B - p_A > 0, which is mathematically equivalent to p_A - p_B < 0, again contradicting the claim. Option E tests only Method A against a fixed value rather than comparing methods. When setting up hypotheses, carefully match the direction of the inequality to the research claim about which group has the higher proportion.
An engineer tests whether a new manufacturing process changes the proportion of parts that are defective. Under the old process, 17 of 220 randomly selected parts are defective. Under the new process, 29 of 210 randomly selected parts are defective. The engineer’s research claim is that the defect proportion is different under the new process than under the old process. Which hypotheses are appropriate for testing this claim?
$H_0: \hat{p}{new}-\hat{p}{old}=0\quad\text{vs.}\quad H_a: \hat{p}{new}-\hat{p}{old}\ne 0$
$H_0: p_{old}-p_{new}=0\quad\text{vs.}\quad H_a: p_{old}-p_{new}\ne 0$
$H_0: p_{new}-p_{old}=0\quad\text{vs.}\quad H_a: p_{new}-p_{old}>0$
$H_0: p_{new}=0.10\quad\text{vs.}\quad H_a: p_{new}\ne 0.10$
$H_0: p_{new}-p_{old}=0\quad\text{vs.}\quad H_a: p_{new}-p_{old}\ne 0$
Explanation
The engineer claims the defect proportion is different under the new process, without specifying if it's higher or lower. This requires a two-sided alternative hypothesis: p_new - p_old ≠ 0. Option A incorrectly uses a one-sided test (p_new > p_old) when no direction is specified. Option C uses sample statistics (p̂) instead of population parameters. Option D reverses the order but maintains the two-sided test, which would also be mathematically acceptable. Option E tests only the new process against a fixed proportion rather than comparing processes. When testing if a change in process affects a proportion without specifying the direction of change, use a two-sided alternative to detect differences in either direction.
A school nurse wants to know whether the proportion of students who report getting at least 8 hours of sleep on school nights differs between students who participate in after-school sports and students who do not. In a random sample, 78 of 150 sports participants reported at least 8 hours, and 64 of 160 non-participants reported at least 8 hours. The nurse’s research claim is that the true proportions are different. Which hypotheses are appropriate?
$H_0: p_{\text{sports}}=p_{\text{no sports}}$; $H_a: p_{\text{sports}}\ne p_{\text{no sports}}$
$H_0: \hat{p}{\text{sports}}-\hat{p}{\text{no sports}}=0$; $H_a: \hat{p}{\text{sports}}-\hat{p}{\text{no sports}}\ne 0$
$H_0: p_{\text{sports}}=0.50$; $H_a: p_{\text{sports}}\ne 0.50$
$H_0: p_{\text{sports}}-p_{\text{no sports}}=0$; $H_a: p_{\text{sports}}-p_{\text{no sports}}\ne 0$
$H_0: p_{\text{no sports}}-p_{\text{sports}}=0$; $H_a: p_{\text{no sports}}-p_{\text{sports}}>0$
Explanation
This question tests your ability to set up hypotheses for comparing two population proportions. The nurse wants to test if the proportion of students getting at least 8 hours of sleep differs between sports participants and non-participants, which requires a two-tailed test. The common mistake (option A) is using sample proportions ($\hat{p}$) in the hypotheses instead of population proportions ($p$). When writing hypotheses, we always use population parameters ($p$), not sample statistics ($\hat{p}$). The correct setup uses $p_1 - p_2 = 0$ for $H_0$ and $p_1 - p_2 \ne 0$ for $H_a$, which is mathematically equivalent to option B but option C follows the standard format for difference tests.
A company compares two website designs to see which leads to a higher purchase rate. Of 200 randomly selected visitors shown Design 1, 34 made a purchase. Of 180 randomly selected visitors shown Design 2, 18 made a purchase. The company’s research claim is that Design 1 has a higher purchase proportion than Design 2. Which hypotheses are appropriate for a test of the company’s claim about the population proportions?
$H_0: p_1=0.17\quad\text{vs.}\quad H_a: p_1>0.17$
$H_0: p_1-p_2=0\quad\text{vs.}\quad H_a: p_1-p_2\ne 0$
$H_0: p_1-p_2=0\quad\text{vs.}\quad H_a: p_1-p_2>0$
$H_0: p_2-p_1=0\quad\text{vs.}\quad H_a: p_2-p_1>0$
$H_0: \hat{p}_1-\hat{p}_2=0\quad\text{vs.}\quad H_a: \hat{p}_1-\hat{p}_2>0$
Explanation
This problem requires setting up hypotheses to test if Design 1 has a higher purchase rate than Design 2. The research claim is directional (Design 1 > Design 2), so we need a one-sided alternative hypothesis with p_1 - p_2 > 0. Option B incorrectly uses sample statistics (p̂) instead of population parameters. Option C reverses the order, testing if Design 2 > Design 1, which contradicts the claim. Option D tests only one proportion against a fixed value rather than comparing two populations. Option E uses a two-sided alternative when the claim specifies a direction. Remember that hypothesis tests always use population parameters (p) not sample statistics (p̂), and the alternative hypothesis must match the direction of the research claim.
A public health team is investigating whether the proportion of residents who regularly wear a seat belt differs between residents in rural counties and residents in urban counties. In a survey, 162 of 200 rural residents reported regularly wearing a seat belt, and 190 of 220 urban residents reported regularly wearing a seat belt. The research claim is that the proportions differ. Which hypotheses are appropriate?
$H_0: p_{\text{urban}}-p_{\text{rural}}=0$; $H_a: p_{\text{urban}}-p_{\text{rural}}<0$
$H_0: \hat{p}{\text{rural}}=\hat{p}{\text{urban}}$; $H_a: \hat{p}{\text{rural}}\ne \hat{p}{\text{urban}}$
$H_0: p_{\text{rural}}-p_{\text{urban}}=0$; $H_a: p_{\text{rural}}-p_{\text{urban}}\ne 0$
$H_0: p_{\text{rural}}=0.80$; $H_a: p_{\text{rural}}\ne 0.80$
$H_0: p_{\text{rural}}=p_{\text{urban}}$; $H_a: p_{\text{rural}}>p_{\text{urban}}$
Explanation
The public health team wants to test if seat belt usage proportions differ between rural and urban residents, requiring a two-tailed test. The research claim is that proportions differ (not which is higher), so we use ≠ in the alternative hypothesis. Option B incorrectly uses a one-tailed test with a specific direction. Option C uses sample proportions (p̂) instead of population proportions. Option D also uses a one-tailed test when no direction is specified. When the research question asks if proportions 'differ' without specifying a direction, always use a two-tailed test with p₁ - p₂ ≠ 0 in the alternative hypothesis.
A researcher is studying whether the proportion of adults who have received a flu shot this year is lower among adults who work from home than among adults who work primarily on-site. In a random sample, 55 of 130 work-from-home adults had a flu shot, and 78 of 150 on-site adults had a flu shot. The research claim is that the work-from-home proportion is lower. Which hypotheses are appropriate?
$H_0: p_{\text{WFH}}=p_{\text{on-site}}$; $H_a: p_{\text{WFH}}\ne p_{\text{on-site}}$
$H_0: p_{\text{on-site}}-p_{\text{WFH}}=0$; $H_a: p_{\text{on-site}}-p_{\text{WFH}}<0$
$H_0: p_{\text{WFH}}=0.50$; $H_a: p_{\text{WFH}}<0.50$
$H_0: p_{\text{WFH}}-p_{\text{on-site}}=0$; $H_a: p_{\text{WFH}}-p_{\text{on-site}}<0$
$H_0: \hat{p}{\text{WFH}}-\hat{p}{\text{on-site}}=0$; $H_a: \hat{p}{\text{WFH}}-\hat{p}{\text{on-site}}<0$
Explanation
This problem tests understanding of left-tailed hypothesis tests for two proportions. The researcher claims that the work-from-home proportion is lower than the on-site proportion, which translates to p_WFH < p_on-site. Rewriting this as p_WFH - p_on-site < 0 gives us the correct alternative hypothesis. Option B incorrectly uses sample proportions (p̂) in the hypotheses. Option C reverses the order, testing if on-site is lower than WFH. Remember that hypotheses always involve population parameters, and the order matters in one-tailed tests: the group claimed to be smaller comes first when using '<' in the alternative.
A retailer is comparing two email subject lines to see which leads to a higher proportion of customers making a purchase within 24 hours. Of 500 customers emailed subject line A, 62 made a purchase; of 480 customers emailed subject line B, 45 made a purchase. The research claim is that subject line A has a higher purchase proportion. Which hypotheses are appropriate?
$H_0: \hat{p}_A-\hat{p}_B=0$; $H_a: \hat{p}_A-\hat{p}_B>0$
$H_0: p_A-p_B=0$; $H_a: p_A-p_B>0$
$H_0: p_A=p_B$; $H_a: p_A\ne p_B$
$H_0: p_B-p_A=0$; $H_a: p_B-p_A>0$
$H_0: p_A=0.10$; $H_a: p_A>0.10$
Explanation
This question tests setting up a one-tailed hypothesis for comparing email subject line effectiveness. The retailer claims subject line A has a higher purchase proportion than B, making this a right-tailed test with p_A - p_B > 0 in the alternative hypothesis. Option B reverses the order, which would test if B is higher than A. Option C uses a two-tailed test when the claim specifies a direction. Option D incorrectly uses sample proportions (p̂) in the hypotheses. Remember that when a claim states one group is 'higher' or 'greater,' use a one-tailed test with the supposedly larger group first in the subtraction.
A teacher wants to know whether offering optional review sessions increases the proportion of students who pass the final exam. In one class section with review sessions, 52 of 80 students passed. In another section without review sessions, 61 of 100 students passed. The teacher’s research claim is that the review sessions increase the pass rate. Which hypotheses are appropriate for testing the teacher’s claim about the population proportions?
$H_0: \hat{p}_R-\hat{p}_N=0\quad\text{vs.}\quad H_a: \hat{p}_R-\hat{p}_N>0$
$H_0: p_R=0.65\quad\text{vs.}\quad H_a: p_R>0.65$
$H_0: p_R-p_N=0\quad\text{vs.}\quad H_a: p_R-p_N>0$
$H_0: p_N-p_R=0\quad\text{vs.}\quad H_a: p_N-p_R>0$
$H_0: p_R-p_N=0\quad\text{vs.}\quad H_a: p_R-p_N\ne 0$
Explanation
The teacher claims that review sessions increase the pass rate, so we need a one-sided test with the review group (R) having a higher proportion than the no-review group (N). The alternative hypothesis should be p_R - p_N > 0. Option B incorrectly uses a two-sided alternative when the claim is directional. Option C uses sample statistics (p̂) instead of population parameters. Option D reverses the order, testing if no-review is better than review, which contradicts the claim. Option E tests only the review group against a fixed value rather than comparing two groups. When testing if one treatment increases a proportion compared to another, the alternative hypothesis should reflect that directional claim with the appropriate inequality.
A public health researcher compares smoking rates in two cities. In a random sample of 160 adults from City X, 44 are current smokers. In a random sample of 140 adults from City Y, 54 are current smokers. The researcher’s claim is that the proportion of smokers differs between the two cities. Which hypotheses are appropriate for testing this claim using a difference in two population proportions?
$H_0: p_X=0.275\quad\text{vs.}\quad H_a: p_X\ne 0.275$
$H_0: p_X-p_Y=0\quad\text{vs.}\quad H_a: p_X-p_Y\ne 0$
$H_0: \hat{p}_X-\hat{p}_Y=0\quad\text{vs.}\quad H_a: \hat{p}_X-\hat{p}_Y\ne 0$
$H_0: p_X-p_Y=0\quad\text{vs.}\quad H_a: p_X-p_Y>0$
$H_0: p_Y-p_X=0\quad\text{vs.}\quad H_a: p_Y-p_X>0$
Explanation
The researcher claims that smoking rates differ between the two cities, which requires a two-sided alternative hypothesis. The correct setup tests if p_X - p_Y ≠ 0, allowing for either city to have a higher rate. Option A incorrectly uses a one-sided test (p_X > p_Y) when no direction is specified. Option C uses sample statistics (p̂) instead of population parameters. Option D tests only City X's proportion against a specific value, not comparing two populations. Option E reverses the order and uses a one-sided test. When a research claim states that proportions "differ" without specifying which is larger, always use a two-sided alternative hypothesis (≠) to test for any difference in either direction.
A restaurant chain wants to know whether changing its menu layout affects the proportion of customers who order a dessert. At 40 randomly selected locations using the old menu, 92 of 400 customers ordered dessert ($\hat{p}_O=0.23$). At 35 independently selected locations using the new menu, 126 of 420 customers ordered dessert ($\hat{p}_N=0.30$). The research claim is that the new menu changes (not necessarily increases) the dessert-ordering rate. Which hypotheses are appropriate?
$H_0: p_N=0.30$; $H_a: p_N\neq 0.30$
$H_0: p_N-p_O=0$; $H_a: p_N-p_O\neq 0$
$H_0: \hat{p}_N-\hat{p}_O=0$; $H_a: \hat{p}_N-\hat{p}_O\neq 0$
$H_0: p_N-p_O=0$; $H_a: p_N-p_O>0$
$H_0: p_O-p_N=0$; $H_a: p_O-p_N>0$
Explanation
This question assesses hypothesis setup for two population proportions in AP Statistics, emphasizing a change without direction. Null H0: p_N - p_O = 0, no difference in dessert rates. Alternative Ha: p_N - p_O ≠ 0, rates differ, per choice A. Distractor B assumes a one-sided increase not stated in the claim. Choice C uses samples incorrectly. Mini-lesson: For 'changes' claims implying any difference, use two-sided ≠; define p_new and p_old; null always =0; avoid directional alternatives unless specified; hypotheses concern populations, not observed samples.