Phylogeny
Help Questions
AP Biology › Phylogeny
A word-described phylogeny for four plant species is: (A,B) form a clade; that clade is sister to C; the clade containing A, B, and C is sister to D. No timing information is given. Based on this branching pattern, which statement is best supported?
A is equally related to C and D because A branches first
C is more closely related to A than to D
C and D are sister taxa because both branch after (A,B)
B is ancestral to A because they are in the same clade
D is more closely related to A than B is to A
Explanation
This question assesses the skill of inferring phylogenetic relatedness from a described branching pattern in plants. The topology shows ((A,B),C) as a clade sister to D, meaning C shares a more recent common ancestor with A (at the node uniting (A,B,C)) than with D (at the root). A and B are sisters, with C as their outgroup within the larger clade excluding D, and no timing data alters this hierarchical inference. This supports that divergence between C and A occurred after the split from D. A tempting distractor is D, claiming A equally related to C and D due to A's basal position, a misconception of equating branching order with equal genetic distance, a level-of-organization error in tree reading. A transferable strategy for this question type is to identify the most recent shared node for pairs and compare node depths to determine relative closeness without assuming branch lengths.
A biologist compares five vertebrate taxa using shared derived traits relative to a jawless fish outgroup. All five taxa have jaws. Only taxa M, N, and O have a bony skeleton. Only taxa N and O have four limbs. Only taxon O has an amniotic egg. Assume each derived trait evolved once and was not lost. Which pair of taxa shares the most recent common ancestor?
N and O
M and O
M and the outgroup
M and N
All pairs are equally related because all have jaws
Explanation
This question assesses the skill of inferring phylogenetic relatedness using shared derived traits in vertebrates. Taxa N and O both possess four limbs and a bony skeleton, with O additionally having an amniotic egg, indicating N and O share a more recent common ancestor defined by the limb synapomorphy relative to the outgroup. All taxa share jaws, a basal trait, while M shares only the bony skeleton with N and O but lacks limbs, placing it outside the N-O clade. This assumes each trait evolved once without loss, supporting a parsimonious tree with (N,O) as sisters. A tempting distractor is A (M and N), which might appeal because both have bony skeletons, but this ignores the more exclusive limb trait, a level-of-organization error in clade hierarchy. A transferable strategy for this question type is to map traits onto a tree by grouping taxa with the most nested shared derived characters to identify closest relatives.
A cladogram is described in words: The root splits into lineage P and a second lineage. That second lineage splits into Q and a third lineage. The third lineage splits into R and S. No other branching occurs. All taxa are extant tips. Using this branching order, determine relatedness among the lineages. Which inference about most recent common ancestry is best supported?
P and Q share a more recent common ancestor than Q and R
P and S share a more recent common ancestor than R and S
R and S share a more recent common ancestor than Q and R
P is most closely related to S because it branches first
Q and S share a more recent common ancestor than R and S
Explanation
This question assesses the skill of inferring phylogenetic relatedness from a described cladogram structure. The branching order shows the root splitting to P and a lineage that then splits to Q and another that splits to R and S, meaning R and S are the last to diverge, sharing the most recent common ancestor. This aligns with AP Biology principles of cladogram interpretation, where branch points represent common ancestors, and closer branch points indicate more recent shared ancestry. P branches first, then Q, leaving R and S as sister taxa at the final split. A tempting distractor is choice A (P and Q share a more recent common ancestor than Q and R), but this is incorrect due to a misconception of branch order, specifically a structure-function confusion where earlier branches are mistakenly seen as closer than later sister pairs. For similar questions, trace the branching sequence from the root and identify the pair with the shortest path back to their shared node as most closely related.
Five lineages (A–E) were scored for derived traits (1 = present, 0 = absent). Trait 1 is present in all five. Trait 2: A0 B1 C1 D1 E1. Trait 3: A0 B0 C1 D1 E1. Trait 4: A0 B0 C0 D1 E1. Trait 5: A0 B0 C0 D0 E1. Assume each trait evolved once and was not lost. Based on shared derived traits, infer the closest relationship. Which pair shares the most recent common ancestor?
B and C
C and D
D and E
A and E
A and B
Explanation
This question assesses the skill of inferring phylogenetic relatedness using shared derived traits in cladistic analysis. The lineages D and E share all five derived traits, including the most nested one (trait 5 present only in E), but since trait 4 is present in D and E while absent in C, and trait 5 distinguishes E further, D and E share the most recent common ancestor as they are the last to diverge in this nested pattern. Traits are assumed to evolve once without loss, following parsimony in AP Biology phylogeny construction, where shared derived traits (synapomorphies) group clades. For example, A lacks all but trait 1, B shares up to trait 2, C up to trait 3, but D and E extend to trait 4, with E having trait 5, confirming their close relationship. A tempting distractor is choice B (B and C), which share traits up to 2 and 3 respectively but not as many as D and E, reflecting a misconception of counting total traits rather than identifying the most nested shared ancestor (clade nesting error). When facing such questions, construct a mental cladogram by nesting groups based on progressively shared derived traits to pinpoint the closest pairs.
Three island bird lineages (U, V, W) and a mainland outgroup (O) were compared at a neutral locus. Pairwise nucleotide differences are: O–U = 12, O–V = 12, O–W = 12; U–V = 2, U–W = 6, V–W = 6. Assume the outgroup indicates the ancestral state and that fewer differences reflect more recent divergence among the island lineages. Which statement is best supported?
W is the outgroup because it differs most from U and V
U is ancestral to V because U has fewer differences from O
U and V share a more recent common ancestor than either does with W
V and W are most closely related because both differ equally from U
All three island lineages diverged at the same time because O differs equally
Explanation
This question assesses the skill of inferring phylogenetic relatedness from nucleotide differences with an outgroup. Among island lineages, U and V differ by only 2 nucleotides, fewer than U-W=6 or V-W=6, indicating U and V diverged most recently from a common ancestor, while all differ equally from outgroup O at 12, establishing ancestral state. This uses the AP Biology concept of molecular divergence, where fewer differences post-colonization reflect recency under neutral evolution. W differs more from both, suggesting earlier split. A tempting distractor is choice E (V and W most closely related because both differ equally from U), but equal differences from a third don't imply closeness, a misconception of teleology assuming symmetry indicates relation. Compare intra-group differences against the outgroup to find the minimal pair for closest island relatedness.
A set of taxa (L, M, N, O) was scored for derived characters relative to an outgroup. Character A is present in all four taxa. Character B is present in M, N, and O. Character C is present in N and O. Character D is present only in N. Assume each character evolved once and was not lost. Which inference about relatedness is best supported?
N and O share a more recent common ancestor than either shares with M
O is ancestral to N because O lacks character D
N is least related to the outgroup because it has character D
L and M are sister taxa because both have character A
M and N share the most recent common ancestor because both have B
Explanation
This question assesses the skill of inferring phylogenetic relatedness from derived character distributions. Character C is present only in N and O, indicating they share a more recent common ancestor than either does with M, as this synapomorphy defines their subclade. Character A is basal to all, B groups M, N, O, and D is unique to N, supporting a tree with (N,O) nested within (M,N,O). Assumptions of single evolution and no loss ensure parsimony in interpreting these patterns. A tempting distractor is B (M and N sharing B), which overlooks the more exclusive C, a structure-function confusion mistaking broader shared traits for closer relatedness. A transferable strategy for this question type is to construct a cladogram by progressively grouping taxa based on increasingly exclusive shared characters to reveal nested hierarchies.
Four species (W, X, Y, Z) were compared using a 12–amino acid protein segment. Species W and X differ at 1 position. Species Y differs from W at 4 positions and from X at 4 positions. Species Z differs from W at 6 positions and from X at 6 positions, and differs from Y at 5 positions. Assume substitutions accumulate at a roughly constant rate in this protein segment and that fewer differences indicate a more recent common ancestor. Which pair of species is most closely related based on the data?
Y and Z
X and Y
W and Z
W and X
W and Y
Explanation
This question assesses the skill of inferring phylogenetic relatedness from molecular sequence differences. The data show that species W and X differ at only 1 amino acid position, which is the fewest differences among all pairs, indicating they share a more recent common ancestor under the assumption of a roughly constant substitution rate. Species Y differs from both W and X at 4 positions, while Z differs from them at 6 positions, supporting that W and X diverged most recently. In contrast, Y and Z differ at 5 positions, which is more than W and X, confirming W and X as the closest pair. A tempting distractor is B (Y and Z), which might appeal due to a misconception of averaging differences instead of identifying the minimal pairwise difference, a structure-function confusion in interpreting molecular clocks. A transferable strategy for this question type is to systematically compare all pairwise differences and select the pair with the smallest number as the most closely related, assuming constant evolutionary rates.
A cladistic analysis of five reptile species uses derived characters: Character 1 (temporal fenestra) is present in B, C, D, and E; Character 2 (diapsid skull) is present in C, D, and E; Character 3 (feather-like filaments) is present in D and E only. Species A lacks all three characters. Each character evolved once and was retained. Which pair shares the most recent common ancestor?
B and C
C and D
A and E
A and B
D and E
Explanation
This question tests the skill of inferring phylogenetic relationships using cladistic analysis of derived characters. The characters show a nested pattern where Character 3 (feather-like filaments) is the most derived, present only in species D and E, indicating these two species share the most recent common ancestor. This follows the principle that species sharing the most recently evolved traits diverged most recently from their common ancestor. A common misconception is to group species by total character count rather than identifying which species share the most derived (recently evolved) character. When analyzing cladistic data, identify the most restricted character distribution, as species sharing the most exclusive derived trait are sister taxa.
Five insect species (P–T) were assessed for derived traits. Trait 1 is present in Q, R, S, and T. Trait 2 is present in R, S, and T. Trait 3 is present only in S and T. Trait 4 is present only in T. Traits evolved once and were retained. Which pair shares the most recent common ancestor?
P and Q
P and T
S and T
Q and R
R and S
Explanation
This question tests the skill of inferring phylogenetic relationships from nested sets of derived characters. The traits show a clear nested pattern where Trait 3 is the most derived, present only in species S and T, indicating these two species are sister taxa sharing the most recent common ancestor. This follows the cladistic principle that species sharing the most recently evolved trait diverged most recently from their exclusive common ancestor. A common misconception is to pair species based on having different numbers of traits rather than identifying which species uniquely share the most derived character. When analyzing nested character data, the most restricted trait distribution identifies the most closely related species pair.
A biologist compares a 12–amino acid protein segment among five species. Species W and X differ at 1 position; W and Y differ at 4; W and Z differ at 5; W and V differ at 6. X and Y differ at 4; X and Z differ at 5; X and V differ at 6. Y and Z differ at 2; Y and V differ at 5; Z and V differ at 5. Assuming substitutions accumulate over time and no reversals, fewer differences indicate a more recent common ancestor. Which pair of species is most closely related?
W and Y
Y and Z
X and V
W and V
W and Z
Explanation
This question tests the skill of inferring phylogenetic relationships from molecular sequence differences. The data shows pairwise amino acid differences between five species, where fewer differences indicate more recent divergence according to the molecular clock hypothesis. Species Y and Z differ at only 2 positions, which is the smallest difference among all pairwise comparisons, indicating they share the most recent common ancestor. A common misconception is to focus on the reference species (W) and choose the pair with the smallest difference from W (like W and X with 1 difference), but phylogenetic relatedness requires comparing all species pairs directly. When analyzing molecular data for phylogeny, always create a complete pairwise difference matrix and identify the species pair with the fewest differences.