Cell Structure and Function

Help Questions

AP Biology › Cell Structure and Function

Questions 1 - 10
1

A plant cell is placed in a concentrated salt solution. The plasma membrane pulls away from the cell wall, and the cytoplasm shrinks inward. The cell wall remains rigid and retains its shape. Which feature best explains why the wall does not shrink with the cytoplasm?

The cell wall is made of phospholipids that dissolve in hypertonic solutions

The cell wall is a lipid bilayer that collapses when water exits the cell

The cell wall is a rigid extracellular structure that resists changes in volume

The cell wall is composed of microtubules that depolymerize in salt solutions

The cell wall is a nuclear membrane that detaches during osmotic stress

Explanation

This question assesses the skill of analyzing cell structure-function relationships. The rigid cell wall, composed of cellulose and other polysaccharides, resists deformation and maintains its shape even as the plasma membrane pulls away in the hypertonic salt solution. This extracellular structure prevents the wall from shrinking with the cytoplasm, as observed in the stimulus during plasmolysis. In AP Biology, the cell wall's rigidity counters osmotic pressures in plant cells. A tempting distractor is B, claiming the wall is a lipid bilayer, but this is incorrect due to structure-function confusion, as cell walls are carbohydrate-based, not lipid membranes. When assessing osmotic responses, distinguish between intracellular and extracellular components' behaviors.

2

A cell is exposed to a toxin that disrupts actin filament polymerization. The cell can still synthesize proteins normally, but it shows reduced formation of membrane protrusions and slower engulfment of large particles. Which outcome is most likely due to the disrupted structure?

Decreased water transport because actin filaments create aquaporin channels in membranes

Decreased DNA replication because actin filaments unwind the double helix in the nucleus

Decreased phagocytosis because actin supports changes in cell shape and membrane movement

Decreased ATP production because actin filaments form the inner mitochondrial membrane

Decreased protein translation because actin filaments are the catalytic core of ribosomes

Explanation

This question assesses the skill of analyzing cell structure-function relationships. Disrupting actin filament polymerization impairs phagocytosis, as actin supports membrane protrusions and shape changes needed to engulf particles, while protein synthesis continues unaffected since it occurs on ribosomes. This highlights actin's role in the cytoskeleton for AP Biology, enabling dynamic processes like cell motility and endocytosis through polymerization-driven force generation. Reduced protrusions and slower engulfment directly result from the inability to form actin networks at the membrane. A tempting distractor is choice B, which is incorrect due to structure-function confusion, as actin does not form mitochondrial membranes; those are lipid bilayers with embedded proteins. To approach similar questions, link specific cytoskeletal components to their primary functions and exclude unrelated cellular processes.

3

In a lab, a cell type shows abundant rough ER membranes studded with ribosomes and a large Golgi apparatus. When these cells are treated with a drug that prevents vesicles from fusing with the Golgi, newly made proteins accumulate in small transport vesicles near the ER, and very little protein appears outside the cell. Which feature best explains why secretion decreases when Golgi fusion is blocked?

Golgi cisternae modify and sort proteins from ER vesicles into secretory vesicles for exocytosis

Lysosomes synthesize secreted proteins and release them by fusing with the plasma membrane

Chloroplast thylakoids fold secreted proteins and deliver them to the cell surface

Mitochondria package proteins into vesicles that bud directly from the outer membrane

Ribosomes inside the nucleus translate secreted proteins and export them through nuclear pores

Explanation

This question assesses the skill of analyzing cell structure-function relationships. The abundant rough ER studded with ribosomes indicates active protein synthesis for secretion, and the large Golgi apparatus suggests its role in processing these proteins, as seen when the drug blocks vesicle fusion to the Golgi, causing proteins to accumulate in transport vesicles near the ER. This aligns with the endomembrane system's secretory pathway in AP Biology, where proteins synthesized in the rough ER are transported via vesicles to the Golgi for modification and sorting into secretory vesicles that fuse with the plasma membrane for exocytosis. Blocking fusion prevents this processing, reducing secretion as proteins cannot reach the cell exterior. A tempting distractor is choice B, which is incorrect due to structure-function confusion, as ribosomes are not located inside the nucleus for translating secreted proteins, and nuclear pores export mRNA, not proteins. To approach similar questions, map the sequence of organelles involved in a process and identify how disruptions affect the pathway.

4

A student compares two eukaryotic cell types. Cell X has many mitochondria and an extensive network of folded inner mitochondrial membranes (cristae). Cell Y has fewer mitochondria with less folded inner membranes. Both cell types have similar plasma membrane surface area and similar numbers of ribosomes. When provided the same amount of glucose and oxygen, Cell X produces more ATP per unit time than Cell Y. Which outcome is most likely explained by the difference in mitochondrial structure?

Cell X will have a higher rate of ATP synthesis because cristae increase inner membrane surface area for chemiosmosis

Cell X will have a higher rate of phagocytosis because cristae provide vesicles for endocytosis

Cell Y will have a higher rate of glycolysis because fewer cristae increase cytosolic enzyme availability

Cell Y will have a higher rate of protein secretion because cristae are continuous with rough ER membranes

Cell X will have a higher rate of transcription because mitochondria contain chromatin that unwinds on cristae

Explanation

This question assesses the skill of analyzing cell structure-function relationships. The correct answer, choice A, highlights that Cell X's extensive cristae increase the inner mitochondrial membrane's surface area, enhancing chemiosmosis and ATP synthesis during oxidative phosphorylation. The stimulus notes Cell X has more mitochondria with folded cristae compared to Cell Y, enabling greater electron transport chain activity and proton gradient formation for higher ATP production from the same glucose and oxygen. This directly ties to the AP Biology concept that mitochondrial structure optimizes aerobic respiration efficiency. A tempting distractor is choice C, which wrongly claims Cell Y has higher glycolysis due to fewer cristae freeing cytosolic enzymes, embodying a level-of-organization error by confusing mitochondrial membrane folding with cytosolic metabolic capacity. For such questions, compare organelle structural differences to their functional impacts on specific metabolic pathways like respiration.

5

A plant cell’s chloroplasts and mitochondria both contain internal membranes that compartmentalize reactions. In chloroplasts, a proton gradient forms across the thylakoid membrane; in mitochondria, a gradient forms across the inner membrane. Which feature best explains how these gradients can drive ATP synthesis in both organelles?

Ribosomes in the membranes use proton gradients to assemble ATP from amino acids

Proton gradients open nuclear pores to allow ATP to diffuse into the nucleus for storage

Proton gradients increase ATP by thickening the cell wall and trapping phosphate ions

ATP synthase embedded in the membrane uses proton flow down the gradient to phosphorylate ADP

Proton gradients directly convert glucose into ATP within the membrane bilayer

Explanation

This question assesses the skill of analyzing cell structure-function relationships. The internal membranes in chloroplasts and mitochondria create proton gradients across thylakoid and inner membranes, respectively, which drive ATP synthase to phosphorylate ADP into ATP via chemiosmosis. This shared mechanism explains ATP synthesis in both organelles, as compartmentalization isolates the gradients. In AP Biology, chemiosmosis is a universal process in energy-transducing membranes. A tempting distractor is B, suggesting ribosomes use gradients, but this is incorrect due to structure-function confusion, as ribosomes synthesize proteins, not ATP. For energy production questions, identify gradient formation and its coupling to ATP synthesis.

6

A researcher compares two membrane preparations. Membrane A contains a higher proportion of unsaturated phospholipid fatty acid tails than Membrane B, while both have similar cholesterol content. At the same temperature, Membrane A shows greater lateral movement of lipids and embedded proteins. Which feature best explains the increased membrane fluidity in Membrane A?

Unsaturated tails form extra hydrogen bonds that lock phospholipids together more tightly

Unsaturated fatty acid tails have kinks that reduce packing, increasing lateral movement within the bilayer

Unsaturated tails increase the number of ribosomes attached to the membrane, raising fluidity

Higher unsaturation increases covalent cross-linking between phospholipids, decreasing viscosity

Unsaturated tails convert the membrane into a single layer, allowing proteins to float freely

Explanation

This question assesses the skill of analyzing cell structure and function by relating lipid composition to membrane properties. Unsaturated fatty acid tails introduce kinks from double bonds, preventing tight packing of phospholipids and thus increasing bilayer fluidity, which allows greater lateral movement of lipids and proteins in Membrane A. This higher unsaturation disrupts van der Waals interactions compared to saturated tails in Membrane B, explaining the difference at the same temperature without cholesterol variations. The fluid mosaic model supports how tail structure influences membrane viscosity and dynamics. A tempting distractor is choice B, which claims unsaturated tails form extra hydrogen bonds for tighter locking, embodying a misconception of chemical bonding by reversing the effect of unsaturation on packing. When comparing membranes, analyze fatty acid saturation and its impact on molecular interactions to predict fluidity differences.

7

A student compares two cell types. Cell X contains numerous mitochondria with densely folded inner membranes, while Cell Y contains fewer mitochondria with relatively smooth inner membranes. Both cells have similar sizes and similar numbers of ribosomes. Measurements show Cell X consumes oxygen at a higher rate than Cell Y under the same conditions. Which feature best explains Cell X’s higher oxygen consumption at the cellular level?

More folding of the mitochondrial inner membrane increases surface area for electron transport proteins

Additional lysosomes in Cell X break down oxygen molecules to release energy for the cell

A thicker plasma membrane in Cell X allows more oxygen to diffuse into the cytoplasm per second

More nucleoli in Cell X synthesize oxygen-binding proteins that directly generate ATP

A larger central vacuole in Cell X stores oxygen and releases it during high energy demand

Explanation

This question assesses the skill of analyzing cell structure and function by relating mitochondrial morphology to metabolic rates. The densely folded inner membranes in Cell X's mitochondria provide increased surface area for embedding electron transport chain proteins, enhancing oxidative phosphorylation and thus higher oxygen consumption as the final electron acceptor. This cristae folding compartmentalizes the proton gradient, optimizing ATP synthesis efficiency, which explains Cell X's greater oxygen use despite similar cell sizes and ribosome numbers. Similar ribosome counts suggest comparable protein synthesis rates, isolating the difference to mitochondrial structure rather than overall cellular activity. A tempting distractor is choice B, which suggests a thicker plasma membrane allows more oxygen diffusion, representing a level-of-organization error by confusing organelle-level respiration with whole-cell membrane properties unrelated to thickness. When comparing cells, focus on the organelle directly involved in the process and quantify how structural adaptations amplify function.

8

Two epithelial cell samples are compared. Sample 1 has many membrane proteins with attached carbohydrate chains projecting into the extracellular space, forming a dense surface coat. Sample 2 has far fewer of these carbohydrate-bearing proteins, but similar phospholipid composition. When mixed, cells from Sample 1 clump together more strongly than cells from Sample 2. Which feature best explains the increased cell-to-cell adhesion in Sample 1?

Additional nuclear pores in Sample 1 export adhesion molecules straight into the extracellular matrix

More smooth ER in Sample 1 secretes adhesive lipids directly into neighboring cell membranes

Extra cholesterol forms covalent bonds between adjacent cells, permanently fusing their membranes

Higher cytosolic ribosome density increases membrane thickness, causing cells to stick together

Carbohydrate chains on glycoproteins enable specific extracellular interactions that increase adhesion between cells

Explanation

This question assesses the skill of analyzing cell structure and function by linking surface modifications to intercellular interactions. The carbohydrate chains on glycoproteins in Sample 1 form a glycocalyx that facilitates specific recognition and binding between cells, enhancing adhesion through extracellular matrix interactions or direct cell-cell contacts like in tissues. This dense surface coat increases clumping compared to Sample 2, despite similar phospholipid compositions, highlighting the functional role of glycosylation in cell signaling and adhesion. The membrane proteins' projections into the extracellular space enable these interactions without altering lipid bilayers. A tempting distractor is choice E, which suggests nuclear pores export adhesion molecules directly, embodying a level-of-organization error by bypassing the endomembrane system's processing pathway. In adhesion-related questions, evaluate extracellular components and their modifications to explain binding behaviors.

9

A secretory gland cell is observed to have abundant rough endoplasmic reticulum (RER) with ribosomes attached, a prominent Golgi apparatus, and many small vesicles near the plasma membrane. Shortly after stimulation, the cell releases a burst of protein into the extracellular fluid without losing cytoplasm. Which outcome is most likely enabled by the arrangement of these cellular structures?​​

Proteins are copied from DNA in the Golgi and transported out through microtubules.

Proteins are assembled in the smooth ER and released by rupture of the plasma membrane.

Proteins are degraded in lysosomes and diffuse through the membrane to the outside.

Proteins are synthesized on RER ribosomes and exported by vesicles that fuse with the membrane.

Proteins are produced in mitochondria and exit through channels in the nuclear envelope.

Explanation

This question tests analysis of cell structure-function relationships in protein secretion pathways. The abundant rough endoplasmic reticulum with ribosomes, prominent Golgi apparatus, and vesicles near the plasma membrane form the classic secretory pathway where proteins are synthesized on RER ribosomes, modified in the Golgi, packaged into vesicles, and released by exocytosis when vesicles fuse with the plasma membrane. This mechanism allows protein release without cytoplasm loss, as observed in the stimulus. Option C incorrectly places protein production in mitochondria and suggests exit through nuclear pores, demonstrating a level-of-organization error since mitochondria produce ATP, not secreted proteins, and nuclear pores regulate nucleus-cytoplasm transport, not cell-exterior transport. To solve secretory pathway questions, trace the flow from RER synthesis through Golgi processing to vesicle-mediated exocytosis.

10

A secretory cell produces a large amount of digestive enzyme that is exported from the cell. Electron micrographs show abundant rough endoplasmic reticulum (RER) with ribosomes attached and an extensive Golgi apparatus with many budding vesicles. When cells are treated with a chemical that disrupts Golgi function, enzyme accumulates in intracellular vesicles and little is detected outside the cell. Which feature best explains the role of the Golgi apparatus in enzyme export?

The Golgi forms the cell wall, which creates pores through which enzymes exit the cell

The Golgi generates ATP that powers ribosomes on the RER to synthesize secreted proteins

The Golgi modifies and sorts proteins into vesicles that fuse with the plasma membrane for secretion

The Golgi is the site of transcription, producing mRNA needed to build digestive enzymes

The Golgi degrades misfolded proteins using hydrolytic enzymes at neutral pH in its lumen

Explanation

This question assesses the analysis of cell structure and function, specifically the Golgi apparatus's role in protein processing and secretion. The correct answer is A because the stimulus depicts abundant RER and Golgi with budding vesicles, and Golgi disruption causes intracellular enzyme accumulation, aligning with AP Biology principles where the Golgi modifies, sorts, and packages proteins into secretory vesicles for exocytosis. This explains the export pathway for digestive enzymes. The chemical's effect confirms the Golgi's essential post-RER processing step. A tempting distractor is B, which reflects a level-of-organization error by confusing the Golgi with the nucleus's transcriptional role instead of its modification function. For such questions, trace the secretory pathway and identify bottlenecks when organelles are disrupted.

Page 1 of 8