Biodiversity
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AP Biology › Biodiversity
A community survey recorded tree species in two forest plots. Plot 1 had 12 species; each species represented about 8% of individuals. Plot 2 had 12 species; one species represented 70% of individuals and the remaining 11 species shared 30%. Which explanation best accounts for the difference in diversity between plots?
Plot 1 has greater evenness, increasing its diversity compared with Plot 2
Plot 2 has greater diversity because it contains a higher proportion of the most common species
Plot 2 has greater richness because a single species dominates the community
The plots have equal diversity because they have the same number of species
Plot 1 has lower diversity because it lacks a dominant species to stabilize the community
Explanation
Biodiversity analysis is the skill of assessing species richness and evenness to understand differences in community diversity across habitats. Here, both plots have the same richness of 12 tree species, but Plot 1 has higher evenness with each species at about 8% of individuals, unlike Plot 2 where one species dominates at 70%. This greater evenness in Plot 1 increases its overall diversity by ensuring no single species overwhelmingly dominates the community. The evidence from abundance distributions highlights how evenness contributes to diversity when richness is equal. A tempting distractor is choice A, which claims Plot 2 has greater richness due to a dominant species, but this misconceives that dominance increases richness, when in fact richness is simply the species count and dominance reduces evenness. In biodiversity questions, remember to evaluate evenness alongside richness, as equal species counts do not guarantee equal diversity if abundances are uneven.
A lake was surveyed at two depths. Shallow water contained 16 zooplankton species with relatively even abundances. Deep water contained 16 species, but two species comprised 90% of individuals. Sampling volume and methods were identical. Which inference is best supported about biodiversity across depths?
Deep water has higher richness because most individuals belong to two species
Shallow water has lower diversity because no species dominates the community
Shallow water has higher diversity because species are more evenly represented there
Both depths have equal diversity because richness is identical and abundance is irrelevant
Deep water has higher diversity because it contains the same number of species as shallow water
Explanation
Biodiversity analysis is the skill of assessing species richness and evenness to compare diversity across environmental gradients like lake depths. Both depths have equal richness of 16 zooplankton species, but shallow water has higher evenness with even abundances compared to deep water's two species at 90%. This leads to shallow water having higher diversity, supported by the abundance distributions under identical sampling methods. The evidence emphasizes evenness's impact when richness is the same. A tempting distractor is choice C, claiming deep water has higher richness due to most individuals in two species, but this misconceives that dominance increases richness, when richness is the species count independent of abundance. For biodiversity questions, prioritize evenness in equal-richness scenarios, ensuring sampling consistency for accurate comparisons.
After a wildfire, ecologists compared plant communities in two grassland sites one year later. Site 1 had 15 plant species with relatively even cover across species. Site 2 had 15 plant species, but one grass species accounted for 80% of total cover. Which conclusion is best supported about biodiversity at the community level?
Site 2 has higher biodiversity because dominance indicates successful adaptation.
Site 2 has higher biodiversity because it has the same richness and more total cover.
Biodiversity cannot be compared because both sites are grasslands.
Site 1 has higher biodiversity because evenness is greater with the same richness.
Both sites have equal biodiversity because species richness is identical.
Explanation
This question requires analyzing biodiversity by comparing communities with identical species richness but different evenness patterns. Site 1 has higher biodiversity because, with the same number of species (15), it shows relatively even cover across species compared to Site 2 where one grass species dominates with 80% cover. When species richness is equal, evenness becomes the determining factor for biodiversity—more even distribution of individuals among species indicates higher biodiversity. The misconception in choice C is that species richness alone determines biodiversity, ignoring the critical role of evenness in community structure. To assess biodiversity comprehensively, examine both richness and evenness, understanding that when richness is equal, the community with more even species distribution has higher biodiversity.
Two desert shrubland sites were surveyed for lizard communities. Site M had 5 species and 500 total individuals, with one species making up 92% of individuals. Site N had 5 species and 120 total individuals, with each species 15–25% of individuals. Which statement is best supported about community biodiversity?
Site N is more biodiverse because evenness is higher despite lower abundance.
Site M is more biodiverse because it has more individuals overall.
Both sites are equally biodiverse because richness is identical.
Site M is more biodiverse because dominance indicates better adaptation.
Biodiversity cannot be compared because the sites are different sizes.
Explanation
This question requires analyzing biodiversity when total abundance differs dramatically between sites. Site N is more biodiverse because, despite having the same species richness (5 species each), it shows much higher evenness with each species comprising 15-25% of individuals, compared to Site M where one species makes up 92%. The extreme dominance in Site M indicates very low evenness, which reduces biodiversity regardless of higher total abundance. The misconception in choice A is that total number of individuals relates to biodiversity, when biodiversity actually depends on species richness and evenness, not total abundance. When comparing communities, focus on richness and evenness patterns rather than total counts, as biodiversity measures community structure, not population size.
A wetland was sampled at its edge and center. The edge community had 13 amphibian species with moderate evenness. The center had 13 amphibian species but two species accounted for 85% of individuals. Total individuals counted were similar. Which conclusion is best supported about biodiversity patterns within the wetland?
The center has lower biodiversity because amphibians avoid the edge.
The center has higher biodiversity because two species are very abundant.
The edge has lower biodiversity because dominance increases stability.
Both areas have equal biodiversity because richness is the same.
The edge has higher biodiversity because evenness is greater with equal richness.
Explanation
This question tests biodiversity analysis within a single wetland comparing edge and center habitats. The edge has higher biodiversity because, with equal species richness (13 species each), it shows moderate evenness compared to the center where two species account for 85% of individuals. When species richness is identical, the community with more even distribution of individuals among species (higher evenness) has greater biodiversity. The misconception in choice C is assuming equal richness means equal biodiversity, overlooking how dominance patterns reduce diversity even with the same number of species. To assess biodiversity within habitats, examine both richness and evenness, recognizing that spatial variation in dominance patterns can create biodiversity gradients even when species richness remains constant.
Researchers compared two kelp forest communities after a storm. Community R had 11 invertebrate species; Community S had 7 species. In both communities, individuals were similarly distributed among species (no strong dominance). Sampling area and effort were identical. Which conclusion is best supported about biodiversity differences?
Biodiversity cannot be compared because both are kelp forests.
Community S has higher biodiversity because storms select for fewer species.
Community R has higher biodiversity because species richness is greater.
Community S has higher biodiversity because fewer species reduces competition.
Both communities have equal biodiversity because evenness is similar.
Explanation
This question assesses biodiversity comparison after disturbance when evenness is similar. Community R has higher biodiversity because it contains 11 invertebrate species compared to Community S's 7 species, representing greater species richness. Since both communities show similar evenness (no strong dominance), species richness becomes the sole differentiating factor for biodiversity. The storm's impact reduced species richness in Community S without creating dominance patterns in either community. The misconception in choice A is that fewer species somehow increases biodiversity by reducing competition, when species richness is a fundamental component of biodiversity. When comparing post-disturbance communities with similar evenness, the community with more species has higher biodiversity, as disturbances often act as filters reducing species richness.
A coral reef and a nearby seagrass meadow were surveyed for reef-associated fishes. The reef had 22 species, but 3 species accounted for 75% of individuals. The seagrass meadow had 16 species, with no species exceeding 15% of individuals. Total fish abundance was similar. Which conclusion is best supported about biodiversity across these ecosystems?
Both ecosystems have equal biodiversity because total abundance is similar.
The reef has lower biodiversity because dominant species are more evolved.
The reef has higher biodiversity because it has greater species richness.
The seagrass meadow has lower biodiversity because it has fewer species.
The seagrass meadow has higher biodiversity because it has greater evenness.
Explanation
This question requires comparing biodiversity between different marine ecosystems with varying richness and evenness. The coral reef has higher biodiversity because it contains 22 species compared to the seagrass meadow's 16 species, representing significantly greater species richness. Although the reef has lower evenness (3 species account for 75% of individuals), the substantial difference in species richness (22 vs 16) outweighs the evenness advantage of the seagrass meadow. The misconception in choice B is overvaluing evenness when there's a significant difference in species richness between communities. When comparing biodiversity across ecosystems, recognize that a notable difference in species richness typically determines overall biodiversity, even when evenness patterns differ.
A stream was sampled upstream and downstream of a wastewater outflow using the same effort. Upstream, macroinvertebrates included 14 taxa with no single taxon exceeding 20% of individuals. Downstream, 6 taxa were found and one taxon made up 75% of individuals. Which conclusion is best supported about biodiversity and community structure downstream?
Downstream biodiversity is lower because richness and evenness are both reduced.
Downstream biodiversity is higher because one taxon is very abundant.
Downstream biodiversity is unchanged because both sites contain macroinvertebrates.
Biodiversity cannot be compared because taxa are not the same as species.
Downstream biodiversity is higher because fewer taxa increases community stability.
Explanation
This question assesses the skill of analyzing biodiversity by comparing species richness and evenness in different ecosystems. Downstream biodiversity is lower because both richness drops to 6 taxa from 14 upstream and evenness decreases with one taxon at 75% dominance, compared to no taxon exceeding 20% upstream. The same sampling effort reveals how pollution likely reduces community complexity downstream. This is supported by the data showing fewer taxa and increased dominance, indicating disrupted structure. A tempting distractor is choice A, which claims higher diversity from abundance, falling for the misconception that dominance enhances rather than reduces biodiversity. A transferable strategy for biodiversity questions is to always evaluate both species richness and evenness, especially when richness is identical, to determine overall diversity.
A stream segment upstream of a wastewater outfall contained 18 fish species, including 6 species each contributing 10–15% of individuals. A downstream segment contained 10 fish species, with one species making up 70% of individuals. Sampling effort and total fish counted were similar. Which inference about biodiversity patterns is best supported?
Downstream biodiversity is higher because one species is very abundant.
Upstream biodiversity is higher due to greater richness and greater evenness.
Biodiversity is equal because both segments are in the same stream.
Upstream biodiversity is lower because no single species dominates the community.
Downstream biodiversity is higher because fewer species reduces competition.
Explanation
This question tests biodiversity analysis in the context of environmental disturbance (wastewater outfall). The upstream segment has higher biodiversity due to both greater species richness (18 vs 10 species) and greater evenness (6 species each contributing 10-15% vs one species making up 70% downstream). The wastewater outfall has reduced both components of biodiversity downstream, creating a community dominated by pollution-tolerant species. The misconception in choice A is that high abundance of one species indicates high biodiversity, when actually dominance by a single species indicates low evenness and reduced biodiversity. When analyzing biodiversity patterns, consider how environmental stressors often reduce both species richness and evenness, creating communities dominated by tolerant species.
Two adjacent ponds were surveyed using identical effort. Pond X contained 12 macroinvertebrate species; 4 species made up 90% of individuals. Pond Y contained 8 macroinvertebrate species; individuals were spread more evenly across species. Both ponds had similar total macroinvertebrate abundance. Which conclusion is best supported about community biodiversity in the two ponds?
Pond Y has lower biodiversity because it contains fewer species than Pond X.
Pond X has higher biodiversity because it contains more species, despite low evenness.
Both ponds have equal biodiversity because total abundance is similar.
Pond Y has higher biodiversity because species abundances are more evenly distributed.
Pond X has lower biodiversity because its dominant species are better adapted.
Explanation
This question tests your ability to analyze biodiversity by considering both species richness (number of species) and evenness (distribution of individuals among species). Pond X has higher biodiversity because it contains 12 species compared to Pond Y's 8 species, giving it greater species richness. While Pond X has low evenness (4 species make up 90% of individuals), species richness is the primary determinant of biodiversity when the difference is substantial (12 vs 8 species). The misconception in choice B is that evenness alone determines biodiversity, but biodiversity encompasses both richness and evenness, with richness often being the stronger factor. When comparing biodiversity between communities, always evaluate both species richness and evenness, recognizing that a community with significantly more species typically has higher biodiversity even if evenness is lower.