Study Zeros Of Polynomials To Construct Graphs in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: For f(x)=x2(x−3)(x+1), does the graph cross or bounce at x=0?
Answer: It bounces at x=0 (even multiplicity 2). Even multiplicity causes bouncing behavior.
Flashcard 2: How do you determine end behavior from a polynomial written in standard form anxn+⋯?
Answer: Use the degree n and leading coefficient an. These determine the polynomial's long-term behavior.
Flashcard 3: For f(x)=(x−1)2(x+3), does the graph cross or bounce at x=−3?
Answer: It crosses at x=−3. Odd multiplicity 1 causes crossing behavior.
Flashcard 4: What does the multiplicity of a zero tell you about the factorization of f(x)?
Answer: It is the exponent on the factor (x−r). Higher exponents indicate repeated roots.
Flashcard 5: For f(x)=−3(x−2)2(x+1), what is the end behavior as x→−∞?
Answer: As x→−∞, f(x)→∞. Odd degree with negative leading coefficient.
Flashcard 6: If f(x) has even degree and leading coefficient an>0, what is the end behavior?
Answer: As x→±∞, f(x)→∞. Both ends go up for positive even-degree polynomials.
Flashcard 7: Identify the multiplicity of the zero x=5 in f(x)=(x−5)3(x+1).
Answer: Multiplicity 3. The exponent on (x−5) is 3.
Flashcard 8: For f(x)=2(x−1)(x+4)2, what is the end behavior as x→∞?
Answer: As x→∞, f(x)→∞. Degree 3 with positive leading coefficient.
Flashcard 9: What is f(0) for f(x)=−2(x+1)2(x−3)?
Answer: f(0)=6. Substitute x=0: −2(1)2(−3)=6.
Flashcard 10: What is the factored form of x2+6x+9 useful for finding zeros?
Answer: (x+3)2. Perfect square trinomial formula.
Flashcard 11: What are the zeros of f(x)=(x2+5x)(x−2)?
Answer: x=0, x=−5, and x=2. Factor x2+5x=x(x+5) first.
Flashcard 12: Identify the multiplicity of the zero x=−2 in f(x)=−7(x+2)2(x−4).
Answer: Multiplicity 2. The exponent on (x+2) is 2.
Flashcard 13: What is a zero of a polynomial function f(x)?
Answer: A value r such that f(r)=0. The zero is where the polynomial equals zero.
Flashcard 14: For f(x)=(x+4)2(x−2)2, does the graph cross the x-axis at x=2?
Answer: No; it touches and turns at x=2. Even multiplicity 2 causes bouncing.
Flashcard 15: If f(x) has odd degree and leading coefficient an<0, what is the end behavior?
Answer: As x→−∞, f(x)→∞; x→∞, f(x)→−∞. Negative odd-degree polynomials fall from left to right.
Flashcard 16: What is the x-intercept on the graph of y=f(x) that corresponds to a zero r?
Answer: The point (r,0). Where the graph crosses the x-axis at zero r.
Flashcard 17: What are the zeros of f(x)=(x2−4x+4)(x+5)?
Answer: x=2 (mult. 2) and x=−5. Recognize x2−4x+4=(x−2)2.
Flashcard 18: What are the zeros of f(x)=(x−4)(x+1)?
Answer: x=4 and x=−1. Set each factor equal to zero and solve.
Flashcard 19: How does multiplying f(x) by a nonzero constant k affect its zeros?
Answer: It does not change the zeros. Constants multiply the output, not the input.
Flashcard 20: If f(x) has a zero r with even multiplicity, how does the graph behave at x=r?
Answer: It touches and turns at the x-axis at x=r. Even multiplicity means the graph stays on same side.
Flashcard 21: What is the maximum number of turning points of a degree n polynomial?
Answer: At most n−1 turning points. Turning points occur between consecutive zeros.
Flashcard 22: What are the zeros of f(x)=x(x−1)(x+2)?
Answer: x=0, x=1, and x=−2. Set each factor equal to zero.
Flashcard 23: For f(x)=(x+4)2(x−2)2, what is the end behavior as x→±∞?
Answer: As x→±∞, f(x)→∞. Degree 4 with positive leading coefficient.
Flashcard 24: For f(x)=(x+3)4(x−1), which zero has odd multiplicity and what is it?
Answer: x=1 has odd multiplicity 1. The exponent 1 is odd.
Flashcard 25: What are the zeros of f(x)=(x−3)(x2+2x+1)?
Answer: x=3 and x=−1 (mult. 2). Recognize x2+2x+1=(x+1)2.
Flashcard 26: What are the zeros of f(x)=(x−2)2(x+7)?
Answer: x=2 (mult. 2) and x=−7. The squared factor gives multiplicity 2.
Flashcard 27: What are the zeros of f(x)=(x−1)(x2−16)?
Answer: x=1, x=−4, and x=4. Factor x2−16=(x−4)(x+4) first.
Flashcard 28: What are the zeros of f(x)=(x2−9)(x−4)?
Answer: x=−3, x=3, and x=4. Factor x2−9=(x−3)(x+3) first.
Flashcard 29: Identify the zeros of f(x)=x2(x−3)(x+1) and state the multiplicity of x=0.
Answer: Zeros x=0 (mult. 2), x=3, x=−1. The factor x2 gives multiplicity 2 at x=0.
Flashcard 30: For f(x)=(x+3)4(x−1), which zero has even multiplicity and what is it?
Answer: x=−3 has even multiplicity 4. The exponent 4 is even.
Flashcard 31: If f(x) has even degree and leading coefficient an<0, what is the end behavior?
Answer: As x→±∞, f(x)→−∞. Both ends go down for negative even-degree polynomials.
Flashcard 32: What are the zeros of f(x)=(2x−3)(x+5)?
Answer: x=23 and x=−5. Set each factor equal to zero and solve.
Flashcard 33: What is the factored form of x2−9 useful for finding zeros?
Answer: (x−3)(x+3). Difference of squares formula.
Flashcard 34: What are the zeros of f(x)=(3x+6)(x2−1)?
Answer: x=−2, x=−1, and x=1. Factor 3x+6=3(x+2) and x2−1=(x−1)(x+1).
Flashcard 35: What is the y-intercept of y=f(x) in terms of f?
Answer: The y-intercept is (0,f(0)). Substitute x=0 into the function.
Flashcard 36: What does the Factor Theorem state about x−r and a polynomial f(x)?
Answer: f(r)=0 if and only if (x−r) is a factor of f(x). Connects zeros and factors of polynomials.
Flashcard 37: What is the leading coefficient of f(x)=2(x−1)(x+4)2?
Answer: Leading coefficient 2. The coefficient 2 multiplies the entire expression.
Flashcard 38: Identify the zeros of f(x)=(x+4)2(x−2)2.
Answer: x=−4 (mult. 2) and x=2 (mult. 2). Both zeros have even multiplicity 2.
Flashcard 39: What is the maximum possible number of real zeros of a degree n polynomial?
Answer: At most n real zeros. A polynomial can have complex zeros too.
Flashcard 40: For f(x)=(x−1)2(x+3), does the graph cross or bounce at x=1?
Answer: It bounces (touches and turns) at x=1. Even multiplicity 2 causes bouncing behavior.
Flashcard 41: How does multiplying f(x) by −1 affect its zeros?
Answer: It does not change the zeros. Multiplying by constants doesn't change zero locations.
Flashcard 42: If f(x) has odd degree and leading coefficient an>0, what is the end behavior?
Answer: As x→−∞, f(x)→−∞; x→∞, f(x)→∞. Positive odd-degree polynomials rise from left to right.
Flashcard 43: What is f(0) for f(x)=(x−2)(x+5)?
Answer: f(0)=−10. Substitute x=0: (0−2)(0+5)=−10.
Flashcard 44: For f(x)=(x+2)(x2+4x+4), does the graph cross or bounce at x=−2?
Answer: It crosses at x=−2 (odd multiplicity 3). Odd multiplicity means crossing behavior.
Flashcard 45: What is the factored form of x2−4x+4 useful for finding zeros?
Answer: (x−2)2. Perfect square trinomial formula.
Flashcard 46: What is the degree and leading coefficient of f(x)=−3(x−2)2(x+1)?
Answer: Degree 3, leading coefficient −3. Multiply exponents to get degree 3, coefficient is −3.
Flashcard 47: For f(x)=−3(x−2)2(x+1), what is the end behavior as x→∞?
Answer: As x→∞, f(x)→−∞. Odd degree with negative leading coefficient.
Flashcard 48: What are the zeros of f(x)=(x+2)(x2+4x+4)?
Answer: x=−2 (mult. 3). Recognize x2+4x+4=(x+2)2, so total multiplicity is 3.
Flashcard 49: What are the zeros of f(x)=−(x+2)(x−2)(x−6)?
Answer: x=−2, x=2, and x=6. Set each factor equal to zero.
Flashcard 50: If f(x) has a zero r with odd multiplicity, how does the graph behave at x=r?
Answer: It crosses the x-axis at x=r. Odd multiplicity means the graph changes sides.