Algebra 2 Flashcards: Using Intersections To Solve Equivalent Functions
Study Using Intersections To Solve Equivalent Functions in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
Algebra 2
Using Intersections To Solve Equivalent Functions
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QUESTION
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Identify the intersection x-value: f(x)=−x+5 and g(x)=2x−1.
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ANSWER
x=2. Set −x+5=2x−1 and solve: 6=3x, so x=2.
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What this deck covers
This deck focuses on Using Intersections To Solve Equivalent Functions, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
How to use these flashcards
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
All flashcards
Flashcard 1: Identify the intersection x-value: f(x)=−x+5 and g(x)=2x−1.
Answer: x=2. Set −x+5=2x−1 and solve: 6=3x, so x=2.
Flashcard 2: Find the intersection x-values: f(x)=x−11 and g(x)=1.
Answer: x=2. Set x−11=1 and solve: 1=x−1, so x=2.
Flashcard 3: What is the domain restriction when solving log(x) equations by intersections?
Answer: Require x>0 (argument must be positive). Logarithms are undefined for non-positive arguments.
Flashcard 4: Identify the intersection x-value: f(x)=3x−2 and g(x)=x+6.
Answer: x=4. Set 3x−2=x+6 and solve: 2x=8, so x=4.
Flashcard 5: Identify the intersection x-value: f(x)=2x+1 and g(x)=7.
Answer: x=3. Set 2x+1=7 and solve: 2x=6, so x=3.
Flashcard 6: What does a tangent intersection point correspond to for h(x)=f(x)−g(x)?
Answer: A zero where h(x) touches 0 without sign change. The difference function touches zero but doesn't cross.
Flashcard 7: Find the intersection x-value: f(x)=ex and g(x)=1.
Answer: x=0. Set ex=1=e0, so x=0.
Flashcard 8: What does it mean if y=f(x) and y=g(x) overlap completely?
Answer: Infinitely many solutions (all x in the domain). Identical graphs mean every x satisfies the equation.
Flashcard 9: What does it mean if f(x)−g(x)>0 at a given x?
Answer: f(x)>g(x) at that x. Positive difference means f is above g.
Flashcard 10: Find the intersection x-value: f(x)=ln(x) and g(x)=ln(5).
Answer: x=5. Set ln(x)=ln(5): x=5.
Flashcard 11: Find the intersection x-value: f(x)=ln(x) and g(x)=1.
Answer: x=e. Set ln(x)=1: x=e1=e.
Flashcard 12: What does it mean if f(x)−g(x)<0 at a given x?
Answer: f(x)<g(x) at that x. Negative difference means f is below g.
Flashcard 13: Identify the valid solution of ln(x−2)=0: x=2 or x=3?
Answer: x=3. Only x=3 makes the argument x−2=1>0 valid.
Flashcard 14: Find the intersection x-value: f(x)=log2(x) and g(x)=5.
Answer: x=32. Set log2(x)=5: x=25=32.
Flashcard 15: Find the intersection x-value: f(x)=ln(x−2) and g(x)=0.
Answer: x=3. Set ln(x−2)=0: x−2=1, so x=3.
Flashcard 16: Which x-values are solutions of f(x)=g(x): the intersection x-coordinates or y-coordinates?
Answer: The intersection x-coordinates. Solutions are x-values where graphs meet, not y-values.
Flashcard 17: What is the key step after solving an equation formed by a rational intersection?
Answer: Check for extraneous solutions from 0 denominators. Solutions making denominators zero are invalid.
Flashcard 18: Find the intersection x-values: f(x)=x1 and g(x)=−1.
Answer: x=−1. Set x1=−1 and solve: 1=−x, so x=−1.
Flashcard 19: Find the intersection x-values: f(x)=x2+2x and g(x)=0.
Answer: x=−2 and x=0. Set x2+2x=0 and factor: x(x+2)=0.
Flashcard 20: What approximate method uses repeated narrowing of an interval where a sign change occurs?