Algebra 2 Flashcards: Using Conjugates With Complex Numbers

Study Using Conjugates With Complex Numbers in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Algebra 2

Using Conjugates With Complex Numbers

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QUESTION
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What is 413i\frac{4}{1-3i} written as a+bia+bi?

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ANSWER

25+65i\frac{2}{5}+\frac{6}{5}i. Multiply by conjugate 1+3i1+3i: 4(1+3i)(13i)(1+3i)=4+12i10\frac{4(1+3i)}{(1-3i)(1+3i)}=\frac{4+12i}{10}

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Flashcard 1: What is 413i\frac{4}{1-3i} written as a+bia+bi?

Answer: 25+65i\frac{2}{5}+\frac{6}{5}i. Multiply by conjugate 1+3i1+3i: 4(1+3i)(13i)(1+3i)=4+12i10\frac{4(1+3i)}{(1-3i)(1+3i)}=\frac{4+12i}{10}

Flashcard 2: What is 3+4i12i\left|\frac{3+4i}{1-2i}\right|?

Answer: 5\sqrt{5}. Use zw=zw|\frac{z}{w}|=\frac{|z|}{|w|}: 3+4i12i=55=5\frac{|3+4i|}{|1-2i|}=\frac{5}{\sqrt{5}}=\sqrt{5}

Flashcard 3: State the formula for the modulus of z=a+biz=a+bi.

Answer: z=a2+b2|z|=\sqrt{a^2+b^2}. Distance from origin in the complex plane.

Flashcard 4: State the quotient formula for a+bic+di\frac{a+bi}{c+di} using a conjugate in the denominator.

Answer: a+bic+di=(a+bi)(cdi)c2+d2\frac{a+bi}{c+di}=\frac{(a+bi)(c-di)}{c^2+d^2}. Multiply numerator and denominator by the conjugate of the denominator.

Flashcard 5: What is 22i2+2i\frac{2-2i}{2+2i} written as a+bia+bi?

Answer: i-i. Factor and simplify: 2(1i)2(1+i)=1i1+i=i\frac{2(1-i)}{2(1+i)}=\frac{1-i}{1+i}=-i

Flashcard 6: What is i1+i\frac{i}{1+i} written as a+bia+bi?

Answer: 12+12i\frac{1}{2}+\frac{1}{2}i. Multiply by conjugate 1i1-i: i(1i)(1+i)(1i)=i+12\frac{i(1-i)}{(1+i)(1-i)}=\frac{i+1}{2}

Flashcard 7: What is 9i|-9i|?

Answer: 99. For pure imaginary numbers, bi=b|bi|=|b|.

Flashcard 8: What is the complex conjugate of z=73iz=7-3i?

Answer: 7+3i7+3i. Change the sign of the imaginary part from negative to positive.

Flashcard 9: What is 8+6i|-8+6i|?

Answer: 1010. (8)2+62=100=10\sqrt{(-8)^2+6^2}=\sqrt{100}=10

Flashcard 10: What is z|\overline{z}| in terms of z|z|?

Answer: z=z|\overline{z}|=|z|. Taking the conjugate doesn't change the modulus.

Flashcard 11: What is (25i)(2+5i)(2-5i)(2+5i)?

Answer: 2929. (a+bi)(abi)=a2b2i2=a2+b2=4+25=29(a+bi)(a-bi)=a^2-b^2i^2=a^2+b^2=4+25=29

Flashcard 12: What is 12+i\frac{1}{2+i} written as a+bia+bi?

Answer: 2515i\frac{2}{5}-\frac{1}{5}i. Multiply by conjugate 2i2-i: 1(2i)(2+i)(2i)=2i5\frac{1(2-i)}{(2+i)(2-i)}=\frac{2-i}{5}

Flashcard 13: What is 34i2+i\frac{3-4i}{2+i} written as a+bia+bi?

Answer: 25115i\frac{2}{5}-\frac{11}{5}i. Multiply by conjugate 2i2-i: (34i)(2i)(2+i)(2i)=211i5\frac{(3-4i)(2-i)}{(2+i)(2-i)}=\frac{2-11i}{5}

Flashcard 14: What is 3+4i|3+4i|?

Answer: 55. 32+42=25=5\sqrt{3^2+4^2}=\sqrt{25}=5

Flashcard 15: What is 132i\frac{1}{3-2i} written as a+bia+bi?

Answer: 313+213i\frac{3}{13}+\frac{2}{13}i. Multiply by conjugate 3+2i3+2i: 1(3+2i)(32i)(3+2i)=3+2i13\frac{1(3+2i)}{(3-2i)(3+2i)}=\frac{3+2i}{13}

Flashcard 16: State the property of conjugation for products: zw=?\overline{zw}=?

Answer: zw=zw\overline{zw}=\overline{z}\,\overline{w}. The conjugate distributes over multiplication.

Flashcard 17: State the modulus product rule: zw=?|zw|=?

Answer: zw=zw|zw|=|z||w|. The modulus of a product equals the product of moduli.

Flashcard 18: What is (a+bi)(abi)(a+bi)(a-bi) written in terms of aa and bb?

Answer: a2+b2a^2+b^2. Using the difference of squares pattern with i2=1i^2=-1.

Flashcard 19: State the value of zz\frac{z}{\overline{z}} for z=2+iz=2+i written as a+bia+bi.

Answer: 35+45i\frac{3}{5}+\frac{4}{5}i. zz=2+i2i=3+4i5\frac{z}{\overline{z}}=\frac{2+i}{2-i}=\frac{3+4i}{5} after rationalizing.

Flashcard 20: Find z|z| if zz=49z\overline{z}=49 and z0|z|\ge 0.

Answer: 77. Since z2=zz=49|z|^2=z\overline{z}=49, we have z=7|z|=7.

Flashcard 21: What is the conjugate you multiply by to rationalize 132i\frac{1}{3-2i}?

Answer: 3+2i3+2i. Multiply by the conjugate to eliminate the imaginary part in the denominator.

Flashcard 22: What is 1+i1i\frac{1+i}{1-i} written as a+bia+bi?

Answer: ii. Multiply by conjugate 1+i1+i: (1+i)(1+i)(1i)(1+i)=2i2\frac{(1+i)(1+i)}{(1-i)(1+i)}=\frac{2i}{2}

Flashcard 23: What is (2+i)(34i)\overline{(2+i)(3-4i)}?

Answer: 2+5i2+5i. (2+i)(34i)=25i(2+i)(3-4i)=2-5i, so 25i=2+5i\overline{2-5i}=2+5i

Flashcard 24: What is z\overline{\overline{z}} in terms of zz?

Answer: z=z\overline{\overline{z}}=z. Taking the conjugate twice returns the original number.

Flashcard 25: State the identity relating zzz\overline{z} and the modulus z|z|.

Answer: zz=z2z\overline{z}=|z|^2. Multiplying a complex number by its conjugate gives the square of its modulus.

Flashcard 26: What is the complex conjugate of z=abiz=a-bi?

Answer: z=a+bi\overline{z}=a+bi. Change the sign of the imaginary part.

Flashcard 27: Identify the value of z+zz+\overline{z} for z=a+biz=a+bi.

Answer: 2a2a. Adding a complex number to its conjugate gives twice the real part.

Flashcard 28: State the property of conjugation for sums: z+w=?\overline{z+w}=?

Answer: z+w=z+w\overline{z+w}=\overline{z}+\overline{w}. The conjugate distributes over addition.

Flashcard 29: State the formula for the complex conjugate of z=a+biz=a+bi.

Answer: z=abi\overline{z}=a-bi. Change the sign of the imaginary part.

Flashcard 30: Identify 1a+bi\frac{1}{a+bi} written using a conjugate, assuming aa and bb are real and not both 00.

Answer: 1a+bi=abia2+b2\frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}. Multiply numerator and denominator by the conjugate abia-bi.

Flashcard 31: What is 1+2i3i\overline{\frac{1+2i}{3-i}} written as a+bia+bi?

Answer: 1212i\frac{1}{2}-\frac{1}{2}i. 1+2i3i=12+12i\frac{1+2i}{3-i}=\frac{1}{2}+\frac{1}{2}i, so its conjugate is 1212i\frac{1}{2}-\frac{1}{2}i

Flashcard 32: Identify the value of zzz-\overline{z} for z=a+biz=a+bi.

Answer: 2bi2bi. Subtracting the conjugate gives twice the imaginary part.

Flashcard 33: What is 7|7| when z=7z=7 is viewed as a complex number?

Answer: 77. For real numbers, the modulus equals the absolute value.

Flashcard 34: What is 512i|5-12i|?

Answer: 1313. 52+(12)2=169=13\sqrt{5^2+(-12)^2}=\sqrt{169}=13

Flashcard 35: What is the complex conjugate of the real number z=11z=11?

Answer: 1111. Real numbers are their own conjugates.

Flashcard 36: What is the complex conjugate of z=4+9iz=-4+9i?

Answer: 49i-4-9i. Change the sign of the imaginary part from positive to negative.

Flashcard 37: What is the complex conjugate of the pure imaginary number z=6iz=-6i?

Answer: 6i6i. For pure imaginary numbers, change the sign of the imaginary part.

Flashcard 38: State the property of conjugation for quotients: zw=?\overline{\frac{z}{w}}=? for w0w\neq 0.

Answer: zw=zw\overline{\frac{z}{w}}=\frac{\overline{z}}{\overline{w}}. The conjugate distributes over division.

Flashcard 39: What is 6πi\overline{6-\pi i}?

Answer: 6+πi6+\pi i. Change the sign of the imaginary part from πi-\pi i to +πi+\pi i.

Flashcard 40: What is 1i\frac{1}{i} written as a real number?

Answer: i-i. Multiply by i-i: 1iii=ii2=i1=i\frac{1}{i}\cdot\frac{-i}{-i}=\frac{-i}{-i^2}=\frac{-i}{1}=-i

Flashcard 41: What is the complex conjugate of z=1253iz=\frac{1}{2}-\frac{5}{3}i?

Answer: 12+53i\frac{1}{2}+\frac{5}{3}i. Change the sign of the imaginary part from negative to positive.

Flashcard 42: What is 1+i2|1+i|^2?

Answer: 22. 1+i2=12+12=2|1+i|^2=1^2+1^2=2

Flashcard 43: State the modulus quotient rule for nonzero ww: zw=?\left|\frac{z}{w}\right|=?

Answer: zw=zw\left|\frac{z}{w}\right|=\frac{|z|}{|w|}. The modulus of a quotient equals the quotient of moduli.

Flashcard 44: What is zz\overline{z}\,z if z=43iz=4-3i?

Answer: 2525. zz=z2=42+(3)2=25z\overline{z}=|z|^2=4^2+(-3)^2=25

Flashcard 45: What is zzz-\overline{z} if z=3+7iz=-3+7i?

Answer: 14i14i. zz=(3+7i)(37i)=14iz-\overline{z}=(-3+7i)-(-3-7i)=14i

Flashcard 46: What is z+zz+\overline{z} if z=3+7iz=-3+7i?

Answer: 6-6. z+z=(3+7i)+(37i)=6z+\overline{z}=(-3+7i)+(-3-7i)=-6

Flashcard 47: What is 25i2|2-5i|^2?

Answer: 2929. z2=zz=(25i)(2+5i)=29|z|^2=z\overline{z}=(2-5i)(2+5i)=29