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Algebra 2 Flashcards: Rewrite Exponential Expressions Using Exponents

Study Rewrite Exponential Expressions Using Exponents in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Rewrite Exponential Expressions Using Exponents, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Rewrite Exponential Expressions Using Exponents

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QUESTION

Rewrite ((1+r)12)t\left(\left(1+r\right)^{12}\right)^t((1+r)12)t as a single exponent on 1+r1+r1+r.

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ANSWER

(1+r)12t\left(1+r\right)^{12t}(1+r)12t. Power of a power rule: (am)n=amn(a^m)^n = a^{mn}(am)n=amn.

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Flashcard 1: Rewrite ((1+r)12)t\left(\left(1+r\right)^{12}\right)^t((1+r)12)t as a single exponent on 1+r1+r1+r.

Answer: (1+r)12t\left(1+r\right)^{12t}(1+r)12t. Power of a power rule: (am)n=amn(a^m)^n = a^{mn}(am)n=amn.

Flashcard 2: Identify the base after rewriting btb^tbt as (b1n)nt\left(b^{\frac{1}{n}}\right)^{nt}(bn1​)nt.

Answer: b1nb^{\frac{1}{n}}bn1​. The new base after transformation.

Flashcard 3: Rewrite b2tb^{2t}b2t to show 6t6t6t in the exponent: b2t=(?)6tb^{2t} = (?)^{6t}b2t=(?)6t.

Answer: (b13)6t\left(b^{\frac{1}{3}}\right)^{6t}(b31​)6t. Rewrite using fractional exponent of 13\frac{1}{3}31​.

Flashcard 4: Identify the exponent property used to justify bt=(b1n)ntb^t=\left(b^{\frac{1}{n}}\right)^{nt}bt=(bn1​)nt.

Answer: (am)n=amn(a^m)^n=a^{mn}(am)n=amn. This property allows rewriting for multiple periods.

Flashcard 5: State the exponent rule that rewrites amna^{mn}amn using a power raised to a power.

Answer: amn=(am)na^{mn}=(a^m)^namn=(am)n. Power of a power rule: multiply the exponents.

Flashcard 6: State the exponent rule that rewrites (am)n(a^m)^n(am)n as a single power of aaa.

Answer: (am)n=amn(a^m)^n=a^{mn}(am)n=amn. Power of a power rule: multiply the exponents.

Flashcard 7: State the rule for multiplying same-base powers: am⋅ana^m\cdot a^nam⋅an.

Answer: am⋅an=am+na^m\cdot a^n=a^{m+n}am⋅an=am+n. Product of powers rule: add the exponents.

Flashcard 8: State the rule for dividing same-base powers: aman\frac{a^m}{a^n}anam​ for a≠0a\ne 0a=0.

Answer: aman=am−n\frac{a^m}{a^n}=a^{m-n}anam​=am−n. Quotient of powers rule: subtract the exponents.

Flashcard 9: State the meaning of a zero exponent for a≠0a\ne 0a=0.

Answer: a0=1a^0=1a0=1. Any nonzero number to the zero power equals 1.

Flashcard 10: State the meaning of a negative exponent for a≠0a\ne 0a=0.

Answer: a−n=1ana^{-n}=\frac{1}{a^n}a−n=an1​. Negative exponent means reciprocal of positive power.

Flashcard 11: State the meaning of a fractional exponent a1na^{\frac{1}{n}}an1​ for a≥0a\ge 0a≥0.

Answer: a1n=ana^{\frac{1}{n}}=\sqrt[n]{a}an1​=na​. Fractional exponent means nth root.

Flashcard 12: State the meaning of amna^{\frac{m}{n}}anm​ for a≥0a\ge 0a≥0 and integers m,n>0m,n>0m,n>0.

Answer: amn=amna^{\frac{m}{n}}=\sqrt[n]{a^m}anm​=nam​. Fractional exponent: raise to m, then take nth root.

Flashcard 13: What is the standard form for an exponential function with initial value aaa and factor bbb?

Answer: f(t)=abtf(t)=ab^tf(t)=abt. Standard exponential form with base bbb and coefficient aaa.

Flashcard 14: What base bbb corresponds to exponential growth in abtab^tabt?

Answer: b>1b>1b>1. Base greater than 1 causes exponential growth.

Flashcard 15: What base bbb corresponds to exponential decay in abtab^tabt?

Answer: 0<b<10<b<10<b<1. Base between 0 and 1 causes exponential decay.

Flashcard 16: State the transformation that converts btb^tbt into a form with nnn periods per unit: bt=( ? )ntb^t=(\,?\,)^{nt}bt=(?)nt.

Answer: bt=(b1n)ntb^t=\left(b^{\frac{1}{n}}\right)^{nt}bt=(bn1​)nt. Power of a power rule applied to create nnn periods.

Flashcard 17: Identify the per-period growth factor if the annual factor is bbb and there are nnn compounding periods per year.

Answer: b1nb^{\frac{1}{n}}bn1​. nth root of annual factor gives per-period factor.

Flashcard 18: Identify the per-period rate rrr if the per-period factor is kkk.

Answer: r=k−1r=k-1r=k−1. Rate is factor minus 1.

Flashcard 19: Identify the per-period factor kkk if the per-period rate is rrr.

Answer: k=1+rk=1+rk=1+r. Factor is 1 plus the rate.

Flashcard 20: What is the monthly factor equivalent to an annual factor of 1.151.151.15 (symbolic form only)?

Answer: 1.151121.15^{\frac{1}{12}}1.15121​. 12th root of annual factor gives monthly factor.

Flashcard 21: Rewrite 1.15t1.15^t1.15t to show 121212 equal growth periods per year using exponent properties.

Answer: 1.15t=(1.15112)12t1.15^t=\left(1.15^{\frac{1}{12}}\right)^{12t}1.15t=(1.15121​)12t. Power of a power rule creates monthly compounding.

Flashcard 22: Rewrite b3tb^{3t}b3t as a power with exponent ttt (single-step rewrite).

Answer: b3t=(b3)tb^{3t}=(b^3)^tb3t=(b3)t. Power of a power rule: (am)n=amn(a^m)^n = a^{mn}(am)n=amn.

Flashcard 23: Rewrite (b3)t(b^3)^t(b3)t as a single exponential expression in the form b ? b^{\,?\,}b?.

Answer: b3tb^{3t}b3t. Power of a power rule: (am)n=amn(a^m)^n = a^{mn}(am)n=amn.

Flashcard 24: Rewrite bt5b^{\frac{t}{5}}b5t​ in the form ( ? )t(\,?\,)^{t}(?)t using exponent properties.

Answer: (b15)t\left(b^{\frac{1}{5}}\right)^t(b51​)t. Fractional exponent becomes root in the base.

Flashcard 25: Rewrite (b15)t(b^{\frac{1}{5}})^t(b51​)t as a single power of bbb.

Answer: bt5b^{\frac{t}{5}}b5t​. Power of a power rule: (am)n=amn(a^m)^n = a^{mn}(am)n=amn.

Flashcard 26: Rewrite bt+7b^{t+7}bt+7 as a product involving btb^tbt using exponent properties.

Answer: bt+7=bt⋅b7b^{t+7}=b^t\cdot b^7bt+7=bt⋅b7. Product rule: am⋅an=am+na^m \cdot a^n = a^{m+n}am⋅an=am+n.

Flashcard 27: Rewrite bt−4b^{t-4}bt−4 as a quotient involving btb^tbt using exponent properties.

Answer: bt−4=btb4b^{t-4}=\frac{b^t}{b^4}bt−4=b4bt​. Quotient rule: aman=am−n\frac{a^m}{a^n} = a^{m-n}anam​=am−n.

Flashcard 28: Rewrite btb2t\frac{b^{t}}{b^{2t}}b2tbt​ as a single power of bbb.

Answer: b−tb^{-t}b−t. Quotient rule: btb2t=bt−2t=b−t\frac{b^t}{b^{2t}} = b^{t-2t} = b^{-t}b2tbt​=bt−2t=b−t.

Flashcard 29: Rewrite b−tb^{-t}b−t without negative exponents.

Answer: 1bt\frac{1}{b^t}bt1​. Negative exponent becomes reciprocal.

Flashcard 30: Find the equivalent expression for (1+r)12t\left(1+r\right)^{12t}(1+r)12t written as ( ? )t\left(\,?\,\right)^t(?)t.

Answer: (1+r)12t=((1+r)12)t\left(1+r\right)^{12t}=\left(\left(1+r\right)^{12}\right)^t(1+r)12t=((1+r)12)t. Power of a power rule applied in reverse.