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This deck focuses on Modeling With Equation Inequalityconstraints, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
Study Modeling With Equation Inequalityconstraints in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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A storage limit allows at most 200 liters: container x is 10 L and y is 25 L. What constraint?
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10x+25y≤200. Total volume equals container sizes times quantities, within limit.
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This deck focuses on Modeling With Equation Inequalityconstraints, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: 10x+25y≤200. Total volume equals container sizes times quantities, within limit.
Answer: >. Strict inequality excludes the boundary value.
Answer: x∈Z and y∈Z (often with x,y≥0). Discrete quantities require integer domain restrictions.
Answer: y≥2x. At least twice means greater than or equal to 2x.
Answer: Dashed boundary line. Dashed lines show the boundary is not included in solutions.
Answer: 6x+3y≥30. Total protein equals grams per food times amounts, meeting minimum.
Answer: ≥. Greater than or equal to includes the minimum value.
Answer: An intersection point of boundary lines that is often a candidate optimum. Corner points are where constraint boundaries intersect.
Answer: Nonviable; 2(4)+5=13 is not less than 13. Strict inequality requires the value be less than, not equal to 13.
Answer: 3x+5y≤50. Total cost equals unit costs times quantities, bounded by budget.
Answer: The inequality uses < or >, so equality is not allowed. Strict inequalities exclude the boundary from valid solutions.
Answer: 15x+25y≥200. Total spending equals prices times quantities, meeting minimum.
Answer: y≤2x. No more than twice means less than or equal to 2x.
Answer: The set of all viable (x,y) satisfying every constraint. The solution set includes all points meeting every constraint.
Answer: s<20. Fewer than means strictly less than the given number.
Answer: The equation 2x+y=10 (where equality holds). The boundary shows where the inequality becomes an equality.
Answer: The constraints are inconsistent; there are no viable options. Conflicting constraints create an empty feasible region.
Answer: Substitute a test point (often (0,0)) into the inequality. Test points determine which side of the boundary satisfies the inequality.
Answer: 8x+5y≤100. Weight constraint limits total mass within capacity.
Answer: x−y≤5 and x−y≥−5. Absolute value inequalities split into two linear constraints.
Answer: The inequality uses ≤ or ≥, so equality is allowed. Non-strict inequalities include the boundary as valid solutions.
Answer: An inequality such as cost≤budget. Budget constraints limit total spending to available funds.
Answer: C≤500. Cost constraints ensure spending stays within budget.
Answer: ≤. Less than or equal to includes the maximum value.
Answer: <. Strict inequality excludes the boundary value.
Answer: x≤12. No more than means less than or equal to the limit.
Answer: a+c=120. Exact totals require equality constraints, not inequalities.
Answer: It violates at least one constraint or is unrealistic in context. Nonviable solutions fail either mathematical or practical tests.
Answer: x≥4 and x∈Z. Integer constraints model discrete counting situations.
Answer: Nonviable; 3+2=5 violates x+y≤4. The sum 3+2=5 exceeds the maximum allowed total of 4.
Answer: x+y≤10. Combined quantities cannot exceed the maximum total.
Answer: Viable; 1+3=4 and both are nonnegative. All constraints are satisfied: 1≥0, 3≥0, and 4≤4.
Answer: All points that satisfy every inequality in the system. The overlap region contains all points meeting every constraint.
Answer: A condition that limits allowable values of variables. Constraints establish boundaries for what's mathematically and practically possible.
Answer: R≥500. Revenue constraints ensure minimum income requirements.
Answer: x≥0 (nonnegativity constraint). Physical quantities like time, distance, or count cannot be negative.
Answer: ∣x−y∣≤5. Absolute value constraints capture differences in either direction.
Answer: x+y≥10. Combined quantities must meet or exceed the minimum total.
Answer: h≥5. At least means greater than or equal to the minimum.
Answer: The set of points satisfying both inequalities simultaneously. The intersection shows points satisfying multiple constraints simultaneously.
Answer: s≥18 and s≤30. Compound inequalities split into separate minimum and maximum constraints.
Answer: There are many viable options; the feasible region has area/length. Multiple solutions form a region rather than discrete points.
Answer: 120x+80y≤300. Total calories equals calories per food times amounts, staying within limit.
Answer: 2x+y≤40. Total time equals hours per unit times quantities, bounded by limit.
Answer: 18≤s≤30. Compound inequalities capture both minimum and maximum bounds.
Answer: m>8. More than means strictly greater than the given value.
Answer: It satisfies all constraints and matches the real-world context. A viable solution meets all mathematical and practical requirements.
Answer: "Exactly" (models with =). Exact amounts require equality rather than inequality constraints.
Answer: Solid boundary line. Solid lines show the boundary is included in solutions.
Answer: Substitute into every inequality and verify all are true. A solution must satisfy every constraint in the system.
Answer: x≥0 and y≥0. Both variables must be non-negative in most real contexts.
Answer: 2x+5y≥20 and 50x+80y≤400. Multiple constraints model complex nutritional requirements simultaneously.
Answer: A nonviable option because it breaks one or more constraints. Points outside violate constraints and are impractical solutions.