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Algebra 2 Flashcards: Graph Polynomial Functions And End Behavior

Study Graph Polynomial Functions And End Behavior in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Graph Polynomial Functions And End Behavior, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Graph Polynomial Functions And End Behavior

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QUESTION

Identify the zeros of f(x)=x3−4x2=x2(x−4)f(x)=x^3-4x^2=x^2(x-4)f(x)=x3−4x2=x2(x−4).

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ANSWER

x=0x=0x=0 (mult. 222) and x=4x=4x=4 (mult. 111). Factor out x2x^2x2 to reveal the zeros and their multiplicities.

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Flashcard 1: Identify the zeros of f(x)=x3−4x2=x2(x−4)f(x)=x^3-4x^2=x^2(x-4)f(x)=x3−4x2=x2(x−4).

Answer: x=0x=0x=0 (mult. 222) and x=4x=4x=4 (mult. 111). Factor out x2x^2x2 to reveal the zeros and their multiplicities.

Flashcard 2: What is the zero of the factor (x+7)(x+7)(x+7)?

Answer: x=−7x=-7x=−7. Set x+7=0x+7=0x+7=0 and solve for xxx.

Flashcard 3: Identify the zeros of f(x)=(x2−9)(x−1)f(x)=(x^2-9)(x-1)f(x)=(x2−9)(x−1) using factoring.

Answer: x=−3x=-3x=−3, x=3x=3x=3, and x=1x=1x=1. Factor x2−9=(x−3)(x+3)x^2-9=(x-3)(x+3)x2−9=(x−3)(x+3) then set each factor to zero.

Flashcard 4: Which end behavior matches f(x)=x4−7x2+1f(x)=x^4-7x^2+1f(x)=x4−7x2+1?

Answer: As x→±∞x\to\pm\inftyx→±∞, f(x)→∞f(x)\to\inftyf(x)→∞. Even degree 444 with positive leading coefficient 111.

Flashcard 5: What is the yyy-intercept of f(x)=−3(x+1)2(x−2)f(x)=-3(x+1)^2(x-2)f(x)=−3(x+1)2(x−2)?

Answer: (0,6)(0,6)(0,6). Evaluate f(0)=−3(0+1)2(0−2)=−3(1)(−2)=6f(0)=-3(0+1)^2(0-2)=-3(1)(-2)=6f(0)=−3(0+1)2(0−2)=−3(1)(−2)=6.

Flashcard 6: What is the yyy-intercept of f(x)=(x−2)(x+3)f(x)=(x-2)(x+3)f(x)=(x−2)(x+3)?

Answer: (0,−6)(0,-6)(0,−6). Evaluate f(0)=(0−2)(0+3)=(−2)(3)=−6f(0)=(0-2)(0+3)=(-2)(3)=-6f(0)=(0−2)(0+3)=(−2)(3)=−6.

Flashcard 7: Identify the xxx-intercepts of f(x)=2(x−4)(x+1)f(x)=2(x-4)(x+1)f(x)=2(x−4)(x+1).

Answer: (4,0)(4,0)(4,0) and (−1,0)(-1,0)(−1,0). The zeros x=4x=4x=4 and x=−1x=-1x=−1 correspond to xxx-intercepts.

Flashcard 8: Identify the zeros of f(x)=(x+5)2(x−1)f(x)=(x+5)^2(x-1)f(x)=(x+5)2(x−1).

Answer: x=−5x=-5x=−5 (mult. 222) and x=1x=1x=1 (mult. 111). The squared factor gives multiplicity 222, the linear factor gives multiplicity 111.

Flashcard 9: What is the multiplicity of a zero rrr if (x−r)m(x-r)^m(x−r)m is a factor of f(x)f(x)f(x)?

Answer: Multiplicity is mmm. The exponent on the factor (x−r)(x-r)(x−r) equals the multiplicity.

Flashcard 10: What is the end behavior of f(x)=anxn+…f(x)=a_nx^n+\dotsf(x)=an​xn+… determined by?

Answer: The leading term anxna_nx^nan​xn. The highest degree term dominates behavior as xxx approaches infinity.

Flashcard 11: What are the real zeros of f(x)=x(x−7)(x+2)f(x)=x(x-7)(x+2)f(x)=x(x−7)(x+2)?

Answer: x=0x=0x=0, x=7x=7x=7, and x=−2x=-2x=−2. Set each factor equal to zero and solve.

Flashcard 12: Identify the zeros of f(x)=(2x−6)(x+4)f(x)=(2x-6)(x+4)f(x)=(2x−6)(x+4).

Answer: x=3x=3x=3 and x=−4x=-4x=−4. From 2x−6=02x-6=02x−6=0, solve x=3x=3x=3; from x+4=0x+4=0x+4=0, solve x=−4x=-4x=−4.

Flashcard 13: What is the zero of f(x)=(5−x)(x+1)f(x)=(5-x)(x+1)f(x)=(5−x)(x+1) coming from the factor (5−x)(5-x)(5−x)?

Answer: x=5x=5x=5. Set 5−x=05-x=05−x=0 to get x=5x=5x=5.

Flashcard 14: Identify the end behavior of f(x)=−(x−1)(x+2)(x−3)(x+4)f(x)=-(x-1)(x+2)(x-3)(x+4)f(x)=−(x−1)(x+2)(x−3)(x+4).

Answer: As x→±∞x\to\pm\inftyx→±∞, f(x)→−∞f(x)\to-\inftyf(x)→−∞. Even degree 444 with negative leading coefficient −1-1−1.

Flashcard 15: Identify the end behavior of f(x)=2(x−1)2(x+3)f(x)=2(x-1)^2(x+3)f(x)=2(x−1)2(x+3).

Answer: As x→−∞x\to-\inftyx→−∞, f(x)→−∞f(x)\to-\inftyf(x)→−∞; x→∞x\to\inftyx→∞, f(x)→∞f(x)\to\inftyf(x)→∞. Odd degree 333 with positive leading coefficient 222.

Flashcard 16: What happens at x=rx=rx=r if rrr is a zero of odd multiplicity?

Answer: The graph crosses the xxx-axis at x=rx=rx=r. Odd multiplicities cause the graph to pass through the xxx-axis.

Flashcard 17: What is the sign of f(x)=−(x−2)2(x+1)f(x)=-(x-2)^2(x+1)f(x)=−(x−2)2(x+1) for very large positive xxx?

Answer: f(x)<0f(x)<0f(x)<0 for large positive xxx. The negative leading coefficient dominates for large positive xxx.

Flashcard 18: Which factor gives the zero x=−32x=-\frac{3}{2}x=−23​ in factored form?

Answer: (2x+3)(2x+3)(2x+3). Set 2x+3=02x+3=02x+3=0 to find the zero x=−32x=-\frac{3}{2}x=−23​.

Flashcard 19: What is the zero of the factor (x−13)(x-\frac{1}{3})(x−31​)?

Answer: x=13x=\frac{1}{3}x=31​. Set x−13=0x-\frac{1}{3}=0x−31​=0 and solve for xxx.

Flashcard 20: Identify the zeros of f(x)=(x−3)(x+2)f(x)=(x-3)(x+2)f(x)=(x−3)(x+2).

Answer: x=3x=3x=3 and x=−2x=-2x=−2. Set each factor equal to zero: x−3=0x-3=0x−3=0 and x+2=0x+2=0x+2=0.

Flashcard 21: What is the end behavior when nnn is even and an<0a_n<0an​<0?

Answer: As x→±∞x\to\pm\inftyx→±∞, f(x)→−∞f(x)\to-\inftyf(x)→−∞. Even degree with negative leading coefficient creates downward parabola-like ends.

Flashcard 22: What does it indicate if f(x)f(x)f(x) is written as a∏(x−ri)mia\prod (x-r_i)^{m_i}a∏(x−ri​)mi​?

Answer: Zeros are rir_iri​ with multiplicities mim_imi​. Factored form reveals each zero rir_iri​ and its multiplicity mim_imi​.

Flashcard 23: What is the maximum number of turning points a degree nnn polynomial can have?

Answer: At most n−1n-1n−1 turning points. Turning points occur where the derivative equals zero, limited by degree.

Flashcard 24: What is the maximum number of real zeros a degree nnn polynomial can have?

Answer: At most nnn real zeros. The Fundamental Theorem of Algebra limits real zeros to the degree.

Flashcard 25: What is the yyy-intercept of a polynomial function f(x)f(x)f(x) in terms of fff?

Answer: (0,f(0))(0,f(0))(0,f(0)). Set x=0x=0x=0 and evaluate the function to find where it crosses the yyy-axis.

Flashcard 26: What is the end behavior when nnn is odd and an<0a_n<0an​<0?

Answer: As x→−∞x\to-\inftyx→−∞, f(x)→∞f(x)\to\inftyf(x)→∞; x→∞x\to\inftyx→∞, f(x)→−∞f(x)\to-\inftyf(x)→−∞. Odd degree with negative leading coefficient falls from left to right.

Flashcard 27: What is the zero of the factor (4x−1)(4x-1)(4x−1)?

Answer: x=14x=\frac{1}{4}x=41​. Set 4x−1=04x-1=04x−1=0 to get 4x=14x=14x=1, so x=14x=\frac{1}{4}x=41​.

Flashcard 28: Identify the zeros of f(x)=(x2+5x)(x−2)f(x)=(x^2+5x)(x-2)f(x)=(x2+5x)(x−2) using factoring.

Answer: x=0x=0x=0, x=−5x=-5x=−5, and x=2x=2x=2. Factor x2+5x=x(x+5)x^2+5x=x(x+5)x2+5x=x(x+5) then set factors equal to zero.

Flashcard 29: Identify the zeros of f(x)=(x2−4x+4)(x+1)f(x)=(x^2-4x+4)(x+1)f(x)=(x2−4x+4)(x+1).

Answer: x=2x=2x=2 (mult. 222) and x=−1x=-1x=−1 (mult. 111). Factor x2−4x+4=(x−2)2x^2-4x+4=(x-2)^2x2−4x+4=(x−2)2 to identify the repeated zero.

Flashcard 30: Identify the zeros of f(x)=(x2−16)(x2−1)f(x)=(x^2-16)(x^2-1)f(x)=(x2−16)(x2−1).

Answer: x=−4x=-4x=−4, x=4x=4x=4, x=−1x=-1x=−1, and x=1x=1x=1. Factor each quadratic: (x−4)(x+4)(x−1)(x+1)(x-4)(x+4)(x-1)(x+1)(x−4)(x+4)(x−1)(x+1).