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Algebra 2 Flashcards: Graph Exponential Logarithmic And Trig Functions

Study Graph Exponential Logarithmic And Trig Functions in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Graph Exponential Logarithmic And Trig Functions, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Graph Exponential Logarithmic And Trig Functions

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QUESTION

What is the amplitude of y=2sin⁡(x)−5y=2\sin(x)-5y=2sin(x)−5?

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ANSWER

222. Coefficient magnitude is ∣2∣=2|2|=2∣2∣=2.

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Flashcard 1: What is the amplitude of y=2sin⁡(x)−5y=2\sin(x)-5y=2sin(x)−5?

Answer: 222. Coefficient magnitude is ∣2∣=2|2|=2∣2∣=2.

Flashcard 2: State the five key points for one cycle of y=cos⁡(x)y=\cos(x)y=cos(x) on [0,2π][0,2\pi][0,2π].

Answer: (0,1),(π2,0),(π,−1),(3π2,0),(2π,1)(0,1),(\frac{\pi}{2},0),(\pi,-1),(\frac{3\pi}{2},0),(2\pi,1)(0,1),(2π​,0),(π,−1),(23π​,0),(2π,1). Cosine starts at maximum, crosses axis, reaches minimum, returns.

Flashcard 3: Identify the end behavior of f(x)=−2⋅4x+1f(x)= -2\cdot 4^x+1f(x)=−2⋅4x+1 as x→∞x\to\inftyx→∞.

Answer: As x→∞x\to\inftyx→∞, f(x)→−∞f(x)\to-\inftyf(x)→−∞. Negative coefficient with growing base: approaches negative infinity.

Flashcard 4: Find the xxx-intercept of f(x)=2x−8f(x)=2^x-8f(x)=2x−8.

Answer: (3,0)(3,0)(3,0). Set f(x)=0f(x)=0f(x)=0: 2x=8=232^x=8=2^32x=8=23 gives x=3x=3x=3.

Flashcard 5: What is the midline of y=−3sin⁡(2x)+4y=-3\sin(2x)+4y=−3sin(2x)+4?

Answer: y=4y=4y=4. Vertical shift parameter is k=4k=4k=4.

Flashcard 6: What is the period of y=sin⁡(Bx)y=\sin(Bx)y=sin(Bx) if BBB is negative?

Answer: Period: 2π∣B∣\frac{2\pi}{|B|}∣B∣2π​. Absolute value of BBB gives same period regardless of sign.

Flashcard 7: Find the xxx-intercept of f(x)=log⁡2(x)−3f(x)=\log_2(x)-3f(x)=log2​(x)−3.

Answer: (8,0)(8,0)(8,0). Set f(x)=0f(x)=0f(x)=0: log⁡2(x)−3=0\log_2(x)-3=0log2​(x)−3=0 gives x=23=8x=2^3=8x=23=8.

Flashcard 8: State the five key points for one cycle of y=sin⁡(x)y=\sin(x)y=sin(x) on [0,2π][0,2\pi][0,2π].

Answer: (0,0),(π2,1),(π,0),(3π2,−1),(2π,0)(0,0),(\frac{\pi}{2},1),(\pi,0),(\frac{3\pi}{2},-1),(2\pi,0)(0,0),(2π​,1),(π,0),(23π​,−1),(2π,0). Sine starts at origin, peaks at π2\frac{\pi}{2}2π​, completes cycle.

Flashcard 9: Identify the end behavior of f(x)=−2⋅4x+1f(x)= -2\cdot 4^x+1f(x)=−2⋅4x+1 as x→−∞x\to-\inftyx→−∞.

Answer: As x→−∞x\to-\inftyx→−∞, f(x)→1f(x)\to 1f(x)→1. As xxx decreases, 4x4^x4x approaches 0, so f(x)f(x)f(x) approaches 1.

Flashcard 10: Identify the end behavior of f(x)=3log⁡2(x−5)+1f(x)=3\log_2(x-5)+1f(x)=3log2​(x−5)+1 as x→5+x\to 5^+x→5+.

Answer: As x→5+x\to 5^+x→5+, f(x)→−∞f(x)\to-\inftyf(x)→−∞. Positive coefficient: as xxx approaches 5 from right, logarithm decreases.

Flashcard 11: Identify the end behavior of f(x)=3log⁡2(x−5)+1f(x)=3\log_2(x-5)+1f(x)=3log2​(x−5)+1 as x→∞x\to\inftyx→∞.

Answer: As x→∞x\to\inftyx→∞, f(x)→∞f(x)\to\inftyf(x)→∞. Positive coefficient with increasing argument: function grows without bound.

Flashcard 12: What transformation does f(x)=log⁡b(x)+kf(x)=\log_b(x)+kf(x)=logb​(x)+k represent relative to y=log⁡b(x)y=\log_b(x)y=logb​(x)?

Answer: Vertical shift by kkk. Output transformation: adding shifts graph up.

Flashcard 13: Identify the end behavior of f(x)=bxf(x)=b^xf(x)=bx when b>1b>1b>1 as x→∞x\to\inftyx→∞ and x→−∞x\to-\inftyx→−∞.

Answer: As x→∞x\to\inftyx→∞, f(x)→∞f(x)\to\inftyf(x)→∞; as x→−∞x\to-\inftyx→−∞, f(x)→0f(x)\to 0f(x)→0. For b>1b>1b>1: grows to infinity, approaches zero from left.

Flashcard 14: What is the xxx-intercept of f(x)=log⁡b(x)f(x)=\log_b(x)f(x)=logb​(x)?

Answer: (1,0)(1,0)(1,0). When x=1x=1x=1, log⁡b(1)=0\log_b(1)=0logb​(1)=0, giving point (1,0)(1,0)(1,0).

Flashcard 15: What is the yyy-intercept of f(x)=bxf(x)=b^xf(x)=bx?

Answer: (0,1)(0,1)(0,1). When x=0x=0x=0, b0=1b^0=1b0=1, giving point (0,1)(0,1)(0,1).

Flashcard 16: What is the range of f(x)=alog⁡b(x−h)+kf(x)=a\log_b(x-h)+kf(x)=alogb​(x−h)+k if a≠0a\neq 0a=0?

Answer: Range: (−∞,∞)(-\infty,\infty)(−∞,∞). Logarithmic functions have unrestricted output values.

Flashcard 17: What is the range of f(x)=a b(x−h)+kf(x)=a\,b^{(x-h)}+kf(x)=ab(x−h)+k if a≠0a\neq 0a=0?

Answer: Range: (k,∞)(k,\infty)(k,∞) if a>0a>0a>0; (−∞,k)( -\infty,k)(−∞,k) if a<0a<0a<0. Sign of aaa determines if range extends above or below asymptote.

Flashcard 18: What is the domain of f(x)=alog⁡b(x−h)+kf(x)=a\log_b(x-h)+kf(x)=alogb​(x−h)+k?

Answer: Domain: (h,∞)(h,\infty)(h,∞). Argument must be positive, so x>hx>hx>h.

Flashcard 19: What is the inverse relationship between y=bxy=b^xy=bx and y=log⁡b(x)y=\log_b(x)y=logb​(x)?

Answer: They are inverses; their graphs reflect across y=xy=xy=x. Exponential and log functions undo each other.

Flashcard 20: Find the horizontal asymptote of f(x)=3⋅2x−5f(x)=3\cdot 2^{x}-5f(x)=3⋅2x−5.

Answer: y=−5y=-5y=−5. Vertical shift parameter k=−5k=-5k=−5 gives asymptote.

Flashcard 21: Find the vertical asymptote of f(x)=2log⁡3(x+4)−1f(x)=2\log_3(x+4)-1f(x)=2log3​(x+4)−1.

Answer: x=−4x=-4x=−4. Horizontal shift parameter: x+4=0x+4=0x+4=0 gives x=−4x=-4x=−4.

Flashcard 22: Identify whether f(x)=(13)xf(x)=\left(\frac{1}{3}\right)^xf(x)=(31​)x shows growth or decay.

Answer: Decay. Base 13<1\frac{1}{3}<131​<1 causes exponential decay.

Flashcard 23: Identify whether f(x)=5⋅1.2xf(x)=5\cdot 1.2^xf(x)=5⋅1.2x shows growth or decay.

Answer: Growth. Base 1.2>11.2>11.2>1 causes exponential growth.

Flashcard 24: Find the yyy-intercept of f(x)=4⋅3x−7f(x)=4\cdot 3^x-7f(x)=4⋅3x−7.

Answer: (0,−3)(0,-3)(0,−3). At x=0x=0x=0: f(0)=4(1)−7=−3f(0)=4(1)-7=-3f(0)=4(1)−7=−3.

Flashcard 25: What is the domain of f(x)=a b(x−h)+kf(x)=a\,b^{(x-h)}+kf(x)=ab(x−h)+k?

Answer: Domain: (−∞,∞)(-\infty,\infty)(−∞,∞). Exponential functions are defined for all real numbers.

Flashcard 26: What is the vertical asymptote of f(x)=alog⁡b(x−h)+kf(x)=a\log_b(x-h)+kf(x)=alogb​(x−h)+k?

Answer: x=hx=hx=h. Horizontal shift parameter hhh determines vertical asymptote.

Flashcard 27: What is the horizontal asymptote of f(x)=a b(x−h)+kf(x)=a\,b^{(x-h)}+kf(x)=ab(x−h)+k?

Answer: y=ky=ky=k. Vertical shift parameter kkk determines horizontal asymptote.

Flashcard 28: What is the general form of a logarithmic function used for graphing transformations?

Answer: f(x)=alog⁡b(x−h)+kf(x)=a\log_b(x-h)+kf(x)=alogb​(x−h)+k with b>0b>0b>0 and b≠1b\neq 1b=1. Standard form showing all transformations with base restrictions.

Flashcard 29: What is the general form of an exponential function used for graphing transformations?

Answer: f(x)=a b(x−h)+kf(x)=a\,b^{(x-h)}+kf(x)=ab(x−h)+k with b>0b>0b>0 and b≠1b\neq 1b=1. Standard form showing all transformations with base restrictions.

Flashcard 30: Find the yyy-intercept of f(x)=log⁡5(x+1)f(x)=\log_5(x+1)f(x)=log5​(x+1).

Answer: (0,0)(0,0)(0,0). At x=0x=0x=0: f(0)=log⁡5(1)=0f(0)=\log_5(1)=0f(0)=log5​(1)=0.