All flashcards
Flashcard 1: What is the amplitude of y=2sin(x)−5?
Answer: 2. Coefficient magnitude is ∣2∣=2.
Flashcard 2: State the five key points for one cycle of y=cos(x) on [0,2π].
Answer: (0,1),(2π,0),(π,−1),(23π,0),(2π,1). Cosine starts at maximum, crosses axis, reaches minimum, returns.
Flashcard 3: Identify the end behavior of f(x)=−2⋅4x+1 as x→∞.
Answer: As x→∞, f(x)→−∞. Negative coefficient with growing base: approaches negative infinity.
Flashcard 4: Find the x-intercept of f(x)=2x−8.
Answer: (3,0). Set f(x)=0: 2x=8=23 gives x=3.
Flashcard 5: What is the midline of y=−3sin(2x)+4?
Answer: y=4. Vertical shift parameter is k=4.
Flashcard 6: What is the period of y=sin(Bx) if B is negative?
Answer: Period: ∣B∣2π. Absolute value of B gives same period regardless of sign.
Flashcard 7: Find the x-intercept of f(x)=log2(x)−3.
Answer: (8,0). Set f(x)=0: log2(x)−3=0 gives x=23=8.
Flashcard 8: State the five key points for one cycle of y=sin(x) on [0,2π].
Answer: (0,0),(2π,1),(π,0),(23π,−1),(2π,0). Sine starts at origin, peaks at 2π, completes cycle.
Flashcard 9: Identify the end behavior of f(x)=−2⋅4x+1 as x→−∞.
Answer: As x→−∞, f(x)→1. As x decreases, 4x approaches 0, so f(x) approaches 1.
Flashcard 10: Identify the end behavior of f(x)=3log2(x−5)+1 as x→5+.
Answer: As x→5+, f(x)→−∞. Positive coefficient: as x approaches 5 from right, logarithm decreases.
Flashcard 11: Identify the end behavior of f(x)=3log2(x−5)+1 as x→∞.
Answer: As x→∞, f(x)→∞. Positive coefficient with increasing argument: function grows without bound.
Flashcard 12: What transformation does f(x)=logb(x)+k represent relative to y=logb(x)?
Answer: Vertical shift by k. Output transformation: adding shifts graph up.
Flashcard 13: Identify the end behavior of f(x)=bx when b>1 as x→∞ and x→−∞.
Answer: As x→∞, f(x)→∞; as x→−∞, f(x)→0. For b>1: grows to infinity, approaches zero from left.
Flashcard 14: What is the x-intercept of f(x)=logb(x)?
Answer: (1,0). When x=1, logb(1)=0, giving point (1,0).
Flashcard 15: What is the y-intercept of f(x)=bx?
Answer: (0,1). When x=0, b0=1, giving point (0,1).
Flashcard 16: What is the range of f(x)=alogb(x−h)+k if a=0?
Answer: Range: (−∞,∞). Logarithmic functions have unrestricted output values.
Flashcard 17: What is the range of f(x)=ab(x−h)+k if a=0?
Answer: Range: (k,∞) if a>0; (−∞,k) if a<0. Sign of a determines if range extends above or below asymptote.
Flashcard 18: What is the domain of f(x)=alogb(x−h)+k?
Answer: Domain: (h,∞). Argument must be positive, so x>h.
Flashcard 19: What is the inverse relationship between y=bx and y=logb(x)?
Answer: They are inverses; their graphs reflect across y=x. Exponential and log functions undo each other.
Flashcard 20: Find the horizontal asymptote of f(x)=3⋅2x−5.
Answer: y=−5. Vertical shift parameter k=−5 gives asymptote.
Flashcard 21: Find the vertical asymptote of f(x)=2log3(x+4)−1.
Answer: x=−4. Horizontal shift parameter: x+4=0 gives x=−4.
Flashcard 22: Identify whether f(x)=(31)x shows growth or decay.
Answer: Decay. Base 31<1 causes exponential decay.
Flashcard 23: Identify whether f(x)=5⋅1.2x shows growth or decay.
Answer: Growth. Base 1.2>1 causes exponential growth.
Flashcard 24: Find the y-intercept of f(x)=4⋅3x−7.
Answer: (0,−3). At x=0: f(0)=4(1)−7=−3.
Flashcard 25: What is the domain of f(x)=ab(x−h)+k?
Answer: Domain: (−∞,∞). Exponential functions are defined for all real numbers.
Flashcard 26: What is the vertical asymptote of f(x)=alogb(x−h)+k?
Answer: x=h. Horizontal shift parameter h determines vertical asymptote.
Flashcard 27: What is the horizontal asymptote of f(x)=ab(x−h)+k?
Answer: y=k. Vertical shift parameter k determines horizontal asymptote.
Flashcard 28: What is the general form of a logarithmic function used for graphing transformations?
Answer: f(x)=alogb(x−h)+k with b>0 and b=1. Standard form showing all transformations with base restrictions.
Flashcard 29: What is the general form of an exponential function used for graphing transformations?
Answer: f(x)=ab(x−h)+k with b>0 and b=1. Standard form showing all transformations with base restrictions.
Flashcard 30: Find the y-intercept of f(x)=log5(x+1).
Answer: (0,0). At x=0: f(0)=log5(1)=0.