Algebra 2 Flashcards: Fundamental Theorem Of Algebra For Quadratics
Study Fundamental Theorem Of Algebra For Quadratics in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
This deck focuses on Fundamental Theorem Of Algebra For Quadratics, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
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Algebra 2 Flashcards: Fundamental Theorem Of Algebra For Quadratics
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QUESTION
Find the roots of 7x2−1=0.
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ANSWER
x=±71. Solving 7x2=1 gives x2=71.
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Flashcard 1: Find the roots of 7x2−1=0.
Answer: x=±71. Solving 7x2=1 gives x2=71.
Flashcard 2: What is the definition of the imaginary unit i?
Answer: i2=−1. Fundamental definition of the imaginary unit.
Flashcard 3: Find the complex roots of x2−8x+20=0.
Answer: x=4±2i. Using quadratic formula with Δ=−16<0.
Flashcard 4: What is the conjugate of a complex number a+bi?
Answer: a−bi. Complex conjugate changes the sign of the imaginary part.
Flashcard 5: Find the complex roots of x2−2x+2=0.
Answer: x=1±i. Using quadratic formula with Δ=−4<0.
Flashcard 6: What does the Complex Conjugate Root Theorem say for polynomials with real coefficients?
Answer: If a+bi is a root, then a−bi is a root. Real coefficients force complex roots to come in conjugate pairs.
Flashcard 7: What is the conjugate of a complex number a+bi?
Answer: a−bi. Complex conjugate changes the sign of the imaginary part.
Flashcard 8: What does the Factor Theorem state about r and the factor (x−r)?
Answer: p(r)=0⟺(x−r) is a factor of p(x). Fundamental connection between roots and linear factors.
Flashcard 9: What is the discriminant of ax2+bx+c?
Answer: Δ=b2−4ac. The discriminant determines the nature of the roots.
Flashcard 10: Which discriminant condition gives two distinct real roots for ax2+bx+c=0?
Answer: Δ>0. Positive discriminant means the square root yields two real values.
Flashcard 11: Which discriminant condition gives exactly one real root (a repeated root) for ax2+bx+c=0?
Answer: Δ=0. Zero discriminant makes the ± term disappear, giving one solution.
Flashcard 12: Which discriminant condition gives two nonreal complex roots for ax2+bx+c=0?
Answer: Δ<0. Negative discriminant requires imaginary unit for square root.
Flashcard 13: What is the definition of the imaginary unit i?
Answer: i2=−1. Fundamental definition of the imaginary unit.
Flashcard 14: How do you rewrite −k for k>0 using i?
Answer: −k=ik. Standard method to express square roots of negative numbers.
Flashcard 15: What is the quadratic formula for the solutions of ax2+bx+c=0?
Answer: x=2a−b±b2−4ac. Standard formula derived from completing the square method.
Flashcard 16: What is the degree of a quadratic polynomial written as ax2+bx+c with a=0?
Answer: Degree 2. The highest power term ax2 determines the degree is 2.
Flashcard 17: What does it mean for a complex number to be a root of p(x)?
Answer: p(r)=0. A root makes the polynomial evaluate to zero.
Flashcard 18: What does the Fundamental Theorem of Algebra guarantee for any nonconstant polynomial with complex coefficients?
Answer: It has at least one complex root. FTA guarantees at least one complex root for any nonconstant polynomial.
Flashcard 19: What does the Fundamental Theorem of Algebra say about the number of complex roots of a degree n polynomial (counting multiplicity)?
Answer: Exactly n complex roots, counting multiplicity. FTA states degree n polynomial has exactly n complex roots when counting multiplicity.
Flashcard 20: What does the Fundamental Theorem of Algebra imply about the total number of complex zeros of a quadratic (counting multiplicity)?
Answer: It has 2 complex zeros, counting multiplicity. Since degree is 2, FTA guarantees exactly 2 complex zeros.
Flashcard 21: Write the monic quadratic with roots 2+3i and 2−3i.
Answer: x2−4x+13. Using Vieta's formulas: sum=4, product=13.
Flashcard 22: Find the roots of x2−6x+13=0 in a±bi form.
Answer: x=3±2i. Using quadratic formula with discriminant Δ=−16<0.
Flashcard 23: Factor x2−2x+5 over the complex numbers.
Answer: (x−(1+2i))(x−(1−2i)). Using roots 1+2i and 1−2i to form linear factors.
Flashcard 24: If a real-coefficient quadratic has root −1+2i, what is the other root?
Answer: −1−2i. Complex Conjugate Root Theorem for real coefficients.
Flashcard 25: Identify the conjugate of the complex root 3−5i.
Answer: 3+5i. Complex conjugate of 3−5i flips the imaginary sign.
Flashcard 26: Find the complex roots of x2−2x+2=0.
Answer: x=1±i. Using quadratic formula with Δ=−4<0.
Flashcard 27: Write x2+6x+9 in factored form showing multiplicity.
Answer: (x+3)2. Perfect square trinomial factors as (x+3)2.
Flashcard 28: What is the repeated root of x2+6x+9=0?
Answer: x=−3. Since Δ=0, there's one repeated root.
Flashcard 29: Find the discriminant Δ of x2+6x+9=0.
Answer: Δ=0. Using Δ=b2−4ac with a=1,b=6,c=9.
Flashcard 30: Find the solutions of 2x2+3x−2=0.
Answer: x=21 and x=−2. Using quadratic formula with Δ=25>0.