Algebra 2 Flashcards: Fundamental Theorem Of Algebra For Quadratics
Study Fundamental Theorem Of Algebra For Quadratics in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
Algebra 2
Fundamental Theorem Of Algebra For Quadratics
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QUESTION
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Given roots r1=5 and r2=−1, what is the monic quadratic polynomial?
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ANSWER
x2−4x−5. Using sum=4 and product=−5 in x2−(sum)x+(product).
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This deck focuses on Fundamental Theorem Of Algebra For Quadratics, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
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Flashcard 1: Given roots r1=5 and r2=−1, what is the monic quadratic polynomial?
Answer: x2−4x−5. Using sum=4 and product=−5 in x2−(sum)x+(product).
Flashcard 2: What are the two complex roots of x2+1=0?
Answer: x=i and x=−i. Solving x2=−1 gives x=±−1=±i.
Flashcard 3: For x2+px+q=0, what are the sum and product of the roots?
Answer: r1+r2=−p and r1r2=q. For monic quadratic x2+px+q, coefficients relate directly to roots.
Flashcard 4: Write the monic quadratic with roots −4+i and −4−i.
Answer: x2+8x+17. Using Vieta's formulas: sum=−8, product=17.
Flashcard 5: Factor x2−2x+5 over the complex numbers.
Answer: (x−(1+2i))(x−(1−2i)). Using roots 1+2i and 1−2i to form linear factors.
Flashcard 6: What is the relationship between complex roots and linear factors over C for a quadratic?
Answer: A quadratic factors into two linear factors over C. FTA guarantees complete factorization over complex numbers.
Flashcard 7: If Δ<0 in x=2a−b±Δ, what form do the two solutions take?
Answer: x=2a−b±i2a−Δ. Standard form showing complex conjugate pair structure.
Flashcard 8: If ax2+bx+c has roots r1,r2, what is c in terms of a and r1r2?
Answer: c=a(r1r2). From Vieta's formulas, product of roots equals ac.
Flashcard 9: Write x2+6x+9 in factored form showing multiplicity.
Answer: (x+3)2. Perfect square trinomial factors as (x+3)2.
Flashcard 10: Which discriminant condition gives two distinct real roots for ax2+bx+c=0?
Answer: Δ>0. Positive discriminant means the square root yields two real values.
Flashcard 11: What is the degree of a quadratic polynomial written as ax2+bx+c with a=0?
Answer: Degree 2. The highest power term ax2 determines the degree is 2.
Flashcard 12: Which discriminant condition gives exactly one real root (a repeated root) for ax2+bx+c=0?
Answer: Δ=0. Zero discriminant makes the ± term disappear, giving one solution.
Flashcard 13: Find the complex roots of x2−2x+2=0.
Answer: x=1±i. Using quadratic formula with Δ=−4<0.
Flashcard 14: Which discriminant condition gives two nonreal complex roots for ax2+bx+c=0?
Answer: Δ<0. Negative discriminant requires imaginary unit for square root.
Flashcard 15: What is the repeated root of x2+6x+9=0?
Answer: x=−3. Since Δ=0, there's one repeated root.
Flashcard 16: What does it mean for a root of a polynomial to have multiplicity 2?
Answer: The factor (x−r)2 divides the polynomial. Multiplicity 2 means the root appears twice in factorization.
Flashcard 17: What is the standard factorization form of a quadratic with roots r1 and r2?
Answer: a(x−r1)(x−r2). Each root contributes a linear factor (x−ri).
Flashcard 18: Find the complex roots of x2+10x+34=0.
Answer: x=−5±3i. Using quadratic formula with Δ=−36<0.
Flashcard 19: Find the discriminant Δ of x2+6x+9=0.
Answer: Δ=0. Using Δ=b2−4ac with a=1,b=6,c=9.
Flashcard 20: Factor x2+2x+5 over the complex numbers.
Answer: (x−(−1+2i))(x−(−1−2i)). Using roots −1+2i and −1−2i to form linear factors.
Flashcard 21: Find the roots of 7x2−1=0.
Answer: x=±71. Solving 7x2=1 gives x2=71.
Flashcard 22: How many real roots does x2−4x+7=0 have, based on Δ?
Answer: 0 real roots. Since Δ<0, there are no real roots.
Flashcard 23: If ax2+bx+c has roots r1,r2, what is b in terms of a and r1+r2?
Answer: b=−a(r1+r2). From Vieta's formulas, sum of roots equals −ab.
Flashcard 24: Find r1+r2 for 3x2−12x+1=0 without solving.
Answer: r1+r2=4. Sum formula: r1+r2=−ab=−3−12=4.
Flashcard 25: What is the factored form of x2−2ax+(a2+b2) over complex numbers?
Answer: (x−(a+bi))(x−(a−bi)). Linear factors corresponding to conjugate pair roots.
Flashcard 26: What does the Complex Conjugate Root Theorem say for polynomials with real coefficients?
Answer: If a+bi is a root, then a−bi is a root. Real coefficients force complex roots to come in conjugate pairs.
Flashcard 27: Find the roots of 4x2+4x+5=0 in a±bi form.
Answer: x=−21±i. Using quadratic formula with Δ=−64<0.
Flashcard 28: Find the complex solutions of x2−4x+7=0 in a±bi form.
Answer: x=2±i3. Using quadratic formula with Δ=−12<0.
Flashcard 29: Identify the complex roots of x2+9=0.
Answer: x=3i and x=−3i. Solving x2=−9 gives x=±−9=±3i.
Flashcard 30: Find the solutions of 2x2+3x−2=0.
Answer: x=21 and x=−2. Using quadratic formula with Δ=25>0.
Flashcard 31: What does it mean to count roots "with multiplicity" for a quadratic?
Answer: A double root counts as 2 roots total. Repeated roots are counted multiple times in the total.
Flashcard 32: Find r1r2 for 3x2−12x+1=0 without solving.