Algebra 2 Flashcards: Fundamental Theorem Of Algebra For Quadratics

Study Fundamental Theorem Of Algebra For Quadratics in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Algebra 2

Fundamental Theorem Of Algebra For Quadratics

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QUESTION
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Given roots r1=5r_1=5 and r2=1r_2=-1, what is the monic quadratic polynomial?

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ANSWER

x24x5x^2-4x-5. Using sum=44 and product=5-5 in x2(sum)x+(product)x^2-(sum)x+(product).

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Flashcard 1: Given roots r1=5r_1=5 and r2=1r_2=-1, what is the monic quadratic polynomial?

Answer: x24x5x^2-4x-5. Using sum=44 and product=5-5 in x2(sum)x+(product)x^2-(sum)x+(product).

Flashcard 2: What are the two complex roots of x2+1=0x^2+1=0?

Answer: x=ix=i and x=ix=-i. Solving x2=1x^2=-1 gives x=±1=±ix=\pm\sqrt{-1}=\pm i.

Flashcard 3: For x2+px+q=0x^2+px+q=0, what are the sum and product of the roots?

Answer: r1+r2=pr_1+r_2=-p and r1r2=qr_1r_2=q. For monic quadratic x2+px+qx^2+px+q, coefficients relate directly to roots.

Flashcard 4: Write the monic quadratic with roots 4+i-4+i and 4i-4-i.

Answer: x2+8x+17x^2+8x+17. Using Vieta's formulas: sum=8-8, product=1717.

Flashcard 5: Factor x22x+5x^2-2x+5 over the complex numbers.

Answer: (x(1+2i))(x(12i))(x-(1+2i))(x-(1-2i)). Using roots 1+2i1+2i and 12i1-2i to form linear factors.

Flashcard 6: What is the relationship between complex roots and linear factors over C\mathbb{C} for a quadratic?

Answer: A quadratic factors into two linear factors over C\mathbb{C}. FTA guarantees complete factorization over complex numbers.

Flashcard 7: If Δ<0\Delta<0 in x=b±Δ2ax=\frac{-b\pm\sqrt{\Delta}}{2a}, what form do the two solutions take?

Answer: x=b2a±iΔ2ax=\frac{-b}{2a}\pm i\frac{\sqrt{-\Delta}}{2a}. Standard form showing complex conjugate pair structure.

Flashcard 8: If ax2+bx+cax^2+bx+c has roots r1,r2r_1,r_2, what is cc in terms of aa and r1r2r_1r_2?

Answer: c=a(r1r2)c=a(r_1r_2). From Vieta's formulas, product of roots equals ca\frac{c}{a}.

Flashcard 9: Write x2+6x+9x^2+6x+9 in factored form showing multiplicity.

Answer: (x+3)2(x+3)^2. Perfect square trinomial factors as (x+3)2(x+3)^2.

Flashcard 10: Which discriminant condition gives two distinct real roots for ax2+bx+c=0ax^2+bx+c=0?

Answer: Δ>0\Delta>0. Positive discriminant means the square root yields two real values.

Flashcard 11: What is the degree of a quadratic polynomial written as ax2+bx+cax^2+bx+c with a0a\ne 0?

Answer: Degree 22. The highest power term ax2ax^2 determines the degree is 22.

Flashcard 12: Which discriminant condition gives exactly one real root (a repeated root) for ax2+bx+c=0ax^2+bx+c=0?

Answer: Δ=0\Delta=0. Zero discriminant makes the ±\pm term disappear, giving one solution.

Flashcard 13: Find the complex roots of x22x+2=0x^2-2x+2=0.

Answer: x=1±ix=1\pm i. Using quadratic formula with Δ=4<0\Delta=-4<0.

Flashcard 14: Which discriminant condition gives two nonreal complex roots for ax2+bx+c=0ax^2+bx+c=0?

Answer: Δ<0\Delta<0. Negative discriminant requires imaginary unit for square root.

Flashcard 15: What is the repeated root of x2+6x+9=0x^2+6x+9=0?

Answer: x=3x=-3. Since Δ=0\Delta=0, there's one repeated root.

Flashcard 16: What does it mean for a root of a polynomial to have multiplicity 22?

Answer: The factor (xr)2(x-r)^2 divides the polynomial. Multiplicity 22 means the root appears twice in factorization.

Flashcard 17: What is the standard factorization form of a quadratic with roots r1r_1 and r2r_2?

Answer: a(xr1)(xr2)a(x-r_1)(x-r_2). Each root contributes a linear factor (xri)(x-r_i).

Flashcard 18: Find the complex roots of x2+10x+34=0x^2+10x+34=0.

Answer: x=5±3ix=-5\pm 3i. Using quadratic formula with Δ=36<0\Delta=-36<0.

Flashcard 19: Find the discriminant Δ\Delta of x2+6x+9=0x^2+6x+9=0.

Answer: Δ=0\Delta=0. Using Δ=b24ac\Delta=b^2-4ac with a=1,b=6,c=9a=1,b=6,c=9.

Flashcard 20: Factor x2+2x+5x^2+2x+5 over the complex numbers.

Answer: (x(1+2i))(x(12i))(x-(-1+2i))(x-(-1-2i)). Using roots 1+2i-1+2i and 12i-1-2i to form linear factors.

Flashcard 21: Find the roots of 7x21=07x^2-1=0.

Answer: x=±17x=\pm\frac{1}{\sqrt{7}}. Solving 7x2=17x^2=1 gives x2=17x^2=\frac{1}{7}.

Flashcard 22: How many real roots does x24x+7=0x^2-4x+7=0 have, based on Δ\Delta?

Answer: 00 real roots. Since Δ<0\Delta<0, there are no real roots.

Flashcard 23: If ax2+bx+cax^2+bx+c has roots r1,r2r_1,r_2, what is bb in terms of aa and r1+r2r_1+r_2?

Answer: b=a(r1+r2)b=-a(r_1+r_2). From Vieta's formulas, sum of roots equals ba-\frac{b}{a}.

Flashcard 24: Find r1+r2r_1+r_2 for 3x212x+1=03x^2-12x+1=0 without solving.

Answer: r1+r2=4r_1+r_2=4. Sum formula: r1+r2=ba=123=4r_1+r_2=-\frac{b}{a}=-\frac{-12}{3}=4.

Flashcard 25: What is the factored form of x22ax+(a2+b2)x^2-2ax+(a^2+b^2) over complex numbers?

Answer: (x(a+bi))(x(abi))(x-(a+bi))(x-(a-bi)). Linear factors corresponding to conjugate pair roots.

Flashcard 26: What does the Complex Conjugate Root Theorem say for polynomials with real coefficients?

Answer: If a+bia+bi is a root, then abia-bi is a root. Real coefficients force complex roots to come in conjugate pairs.

Flashcard 27: Find the roots of 4x2+4x+5=04x^2+4x+5=0 in a±bia\pm bi form.

Answer: x=12±ix=-\frac{1}{2}\pm i. Using quadratic formula with Δ=64<0\Delta=-64<0.

Flashcard 28: Find the complex solutions of x24x+7=0x^2-4x+7=0 in a±bia\pm bi form.

Answer: x=2±i3x=2\pm i\sqrt{3}. Using quadratic formula with Δ=12<0\Delta=-12<0.

Flashcard 29: Identify the complex roots of x2+9=0x^2+9=0.

Answer: x=3ix=3i and x=3ix=-3i. Solving x2=9x^2=-9 gives x=±9=±3ix=\pm\sqrt{-9}=\pm 3i.

Flashcard 30: Find the solutions of 2x2+3x2=02x^2+3x-2=0.

Answer: x=12x=\frac{1}{2} and x=2x=-2. Using quadratic formula with Δ=25>0\Delta=25>0.

Flashcard 31: What does it mean to count roots "with multiplicity" for a quadratic?

Answer: A double root counts as 22 roots total. Repeated roots are counted multiple times in the total.

Flashcard 32: Find r1r2r_1r_2 for 3x212x+1=03x^2-12x+1=0 without solving.

Answer: r1r2=13r_1r_2=\frac{1}{3}. Product formula: r1r2=ca=13r_1r_2=\frac{c}{a}=\frac{1}{3}.

Flashcard 33: What is the quadratic formula for the solutions of ax2+bx+c=0ax^2+bx+c=0?

Answer: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Standard formula derived from completing the square method.

Flashcard 34: What does the Fundamental Theorem of Algebra say about the number of complex roots of a degree nn polynomial (counting multiplicity)?

Answer: Exactly nn complex roots, counting multiplicity. FTA states degree nn polynomial has exactly nn complex roots when counting multiplicity.

Flashcard 35: Identify the missing statement to show FTA for quadratics: Δ<0Δ=iΔ\Delta<0\Rightarrow\sqrt{\Delta}=i\sqrt{-\Delta}.

Answer: Δ=iΔ\sqrt{\Delta}=i\sqrt{-\Delta}. When discriminant is negative, square root becomes imaginary.

Flashcard 36: Find the complex roots of x28x+20=0x^2-8x+20=0.

Answer: x=4±2ix=4\pm 2i. Using quadratic formula with Δ=16<0\Delta=-16<0.

Flashcard 37: What does the Fundamental Theorem of Algebra guarantee for any nonconstant polynomial with complex coefficients?

Answer: It has at least one complex root. FTA guarantees at least one complex root for any nonconstant polynomial.

Flashcard 38: What is the definition of the imaginary unit ii?

Answer: i2=1i^2=-1. Fundamental definition of the imaginary unit.

Flashcard 39: How do you rewrite k\sqrt{-k} for k>0k>0 using ii?

Answer: k=ik\sqrt{-k}=i\sqrt{k}. Standard method to express square roots of negative numbers.

Flashcard 40: Identify the conjugate of the complex root 35i3-5i.

Answer: 3+5i3+5i. Complex conjugate of 35i3-5i flips the imaginary sign.

Flashcard 41: What is the conjugate of a complex number a+bia+bi?

Answer: abia-bi. Complex conjugate changes the sign of the imaginary part.

Flashcard 42: What are the sum and product of roots for ax2+bx+c=0ax^2+bx+c=0 in terms of a,b,ca,b,c?

Answer: r1+r2=bar_1+r_2=-\frac{b}{a} and r1r2=car_1r_2=\frac{c}{a}. Vieta's formulas relate coefficients to root combinations.

Flashcard 43: If a real-coefficient quadratic has root 1+2i-1+2i, what is the other root?

Answer: 12i-1-2i. Complex Conjugate Root Theorem for real coefficients.

Flashcard 44: Find the discriminant Δ\Delta of 2x2+3x2=02x^2+3x-2=0.

Answer: Δ=25\Delta=25. Using Δ=b24ac\Delta=b^2-4ac with a=2,b=3,c=2a=2,b=3,c=-2.

Flashcard 45: What does the Fundamental Theorem of Algebra imply about the total number of complex zeros of a quadratic (counting multiplicity)?

Answer: It has 22 complex zeros, counting multiplicity. Since degree is 22, FTA guarantees exactly 22 complex zeros.

Flashcard 46: Identify the number of complex roots (counting multiplicity) of p(x)=7x21p(x)=7x^2-1.

Answer: 22. Degree 22 polynomial always has exactly 22 complex roots.

Flashcard 47: What does the Factor Theorem state about rr and the factor (xr)(x-r)?

Answer: p(r)=0    (xr)p(r)=0\iff(x-r) is a factor of p(x)p(x). Fundamental connection between roots and linear factors.

Flashcard 48: What is the discriminant of ax2+bx+cax^2+bx+c?

Answer: Δ=b24ac\Delta=b^2-4ac. The discriminant determines the nature of the roots.

Flashcard 49: For x22ax+(a2+b2)=0x^2-2ax+(a^2+b^2)=0, what are the roots in terms of aa and bb?

Answer: x=a±bix=a\pm bi. Standard form for conjugate pair roots a±bia\pm bi.

Flashcard 50: Find the roots of x26x+13=0x^2-6x+13=0 in a±bia\pm bi form.

Answer: x=3±2ix=3\pm 2i. Using quadratic formula with discriminant Δ=16<0\Delta=-16<0.

Flashcard 51: Find the discriminant Δ\Delta of x24x+7=0x^2-4x+7=0.

Answer: Δ=12\Delta=-12. Using Δ=b24ac\Delta=b^2-4ac with a=1,b=4,c=7a=1,b=-4,c=7.

Flashcard 52: Write the monic quadratic with roots 2+3i2+3i and 23i2-3i.

Answer: x24x+13x^2-4x+13. Using Vieta's formulas: sum=44, product=1313.

Flashcard 53: Find the complex roots of x2+2x+2=0x^2+2x+2=0.

Answer: x=1±ix=-1\pm i. Using quadratic formula with Δ=4<0\Delta=-4<0.

Flashcard 54: Find the complex solutions of x2+4x+8=0x^2+4x+8=0 in a±bia\pm bi form.

Answer: x=2±2ix=-2\pm 2i. Using quadratic formula with negative discriminant.

Flashcard 55: What is the key conclusion that verifies the Fundamental Theorem of Algebra for quadratics?

Answer: Every quadratic has 22 complex roots, counting multiplicity. This confirms FTA applies to all degree 22 polynomials.

Flashcard 56: What does it mean for a complex number to be a root of p(x)p(x)?

Answer: p(r)=0p(r)=0. A root makes the polynomial evaluate to zero.