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Algebra 2 Flashcards: Exponents Logarithms And Their Inverse Relationship

Study Exponents Logarithms And Their Inverse Relationship in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Exponents Logarithms And Their Inverse Relationship, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Exponents Logarithms And Their Inverse Relationship

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QUESTION

What is the inverse function of f(x)=bxf(x)=b^xf(x)=bx (with b>0b>0b>0, b≠1b\ne 1b=1) written as a log?

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ANSWER

f−1(x)=log⁡b(x)f^{-1}(x)=\log_b(x)f−1(x)=logb​(x). Exponential and logarithmic functions are inverses of each other.

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Flashcard 1: What is the inverse function of f(x)=bxf(x)=b^xf(x)=bx (with b>0b>0b>0, b≠1b\ne 1b=1) written as a log?

Answer: f−1(x)=log⁡b(x)f^{-1}(x)=\log_b(x)f−1(x)=logb​(x). Exponential and logarithmic functions are inverses of each other.

Flashcard 2: What is the inverse function of g(x)=log⁡b(x)g(x)=\log_b(x)g(x)=logb​(x) (with valid base bbb) written exponentially?

Answer: g−1(x)=bxg^{-1}(x)=b^xg−1(x)=bx. Logarithmic and exponential functions are inverses of each other.

Flashcard 3: What is the exact solution of log⁡3(x)=12\log_3(x)=\frac{1}{2}log3​(x)=21​?

Answer: x=3x=\sqrt{3}x=3​. Since 31/2=33^{1/2} = \sqrt{3}31/2=3​.

Flashcard 4: What is the exact value of log⁡8(4)\log_8(4)log8​(4)?

Answer: 23\frac{2}{3}32​. Since 82/3=(23)2/3=22=48^{2/3} = (2^3)^{2/3} = 2^2 = 482/3=(23)2/3=22=4.

Flashcard 5: What is the exact value of log⁡14(2)\log_{\frac{1}{4}}(2)log41​​(2)?

Answer: −12-\frac{1}{2}−21​. Since (14)−1/2=41/2=2(\frac{1}{4})^{-1/2} = 4^{1/2} = 2(41​)−1/2=41/2=2.

Flashcard 6: What is the exact value of log⁡16(12)\log_{16}(\frac{1}{2})log16​(21​)?

Answer: −14-\frac{1}{4}−41​. Since 16−1/4=(24)−1/4=2−1=1216^{-1/4} = (2^4)^{-1/4} = 2^{-1} = \frac{1}{2}16−1/4=(24)−1/4=2−1=21​.

Flashcard 7: What is the exact solution of ln⁡(x)=ln⁡(12)\ln(x)=\ln(12)ln(x)=ln(12)?

Answer: x=12x=12x=12. Equal natural logarithms means equal arguments.

Flashcard 8: What is the exact solution of log⁡2(x−1)=3\log_2(x-1)=3log2​(x−1)=3?

Answer: x=9x=9x=9. Since 23=82^3 = 823=8, so x−1=8x - 1 = 8x−1=8.

Flashcard 9: What is the exact solution of log⁡3(x2)=2\log_3(x^2)=2log3​(x2)=2 with x>0x>0x>0?

Answer: x=3x=3x=3. Using power rule: 2log⁡3(x)=22\log_3(x) = 22log3​(x)=2, so log⁡3(x)=1\log_3(x) = 1log3​(x)=1.

Flashcard 10: What is the exact solution of 4x=24^x=24x=2?

Answer: x=12x=\frac{1}{2}x=21​. Since 41/2=24^{1/2} = 241/2=2.

Flashcard 11: What is log⁡7(7)\log_7(7)log7​(7)?

Answer: 111. Any base raised to power 1 equals itself.

Flashcard 12: What is the exact solution of ln⁡(x)=2\ln(x)=2ln(x)=2?

Answer: x=e2x=e^2x=e2. Converting logarithmic to exponential form: e2=xe^2 = xe2=x.

Flashcard 13: What is log⁡2(8)\log_2(8)log2​(8)?

Answer: 333. Since 23=82^3 = 823=8.

Flashcard 14: What is log⁡3(19)\log_3(\frac{1}{9})log3​(91​)?

Answer: −2-2−2. Since 3−2=193^{-2} = \frac{1}{9}3−2=91​.

Flashcard 15: What is log⁡5(1)\log_5(1)log5​(1)?

Answer: 000. Any base raised to power 0 equals 1.

Flashcard 16: What is log⁡7(7)\log_7(7)log7​(7)?

Answer: 111. Any base raised to power 1 equals itself.

Flashcard 17: What is log⁡4(2)\log_4(2)log4​(2)?

Answer: 12\frac{1}{2}21​. Since 41/2=4=24^{1/2} = \sqrt{4} = 241/2=4​=2.

Flashcard 18: What is log⁡12(4)\log_{\frac{1}{2}}(4)log21​​(4)?

Answer: −2-2−2. Since (12)−2=22=4(\frac{1}{2})^{-2} = 2^2 = 4(21​)−2=22=4.

Flashcard 19: What is log⁡10(0.01)\log_{10}(0.01)log10​(0.01)?

Answer: −2-2−2. Since 10−2=0.0110^{-2} = 0.0110−2=0.01.

Flashcard 20: What is ln⁡(1)\ln(1)ln(1)?

Answer: 000. Any base raised to power 0 equals 1.

Flashcard 21: What is ln⁡(e3)\ln(e^3)ln(e3)?

Answer: 333. Natural logarithm and exponential are inverse functions.

Flashcard 22: What is eln⁡(7)e^{\ln(7)}eln(7)?

Answer: 777. Exponential and natural logarithm are inverse functions.

Flashcard 23: What is the exact solution of 2x=162^x=162x=16?

Answer: x=4x=4x=4. Since 24=162^4 = 1624=16.

Flashcard 24: What is the exact solution of 3x=1273^x=\frac{1}{27}3x=271​?

Answer: x=−3x=-3x=−3. Since 3−3=1273^{-3} = \frac{1}{27}3−3=271​.

Flashcard 25: What is the exact solution of 10x=0.00110^x=0.00110x=0.001?

Answer: x=−3x=-3x=−3. Since 10−3=0.00110^{-3} = 0.00110−3=0.001.

Flashcard 26: What is the exact solution of log⁡5(x)=3\log_5(x)=3log5​(x)=3?

Answer: x=125x=125x=125. Since 53=1255^3 = 12553=125.

Flashcard 27: What is the exact solution of log⁡2(x)=−4\log_2(x)=-4log2​(x)=−4?

Answer: x=116x=\frac{1}{16}x=161​. Since 2−4=1162^{-4} = \frac{1}{16}2−4=161​.

Flashcard 28: What is the exact solution of ln⁡(x)=2\ln(x)=2ln(x)=2?

Answer: x=e2x=e^2x=e2. Converting logarithmic to exponential form: e2=xe^2 = xe2=x.

Flashcard 29: What is the exact solution of ex=1e5e^x=\frac{1}{e^5}ex=e51​?

Answer: x=−5x=-5x=−5. Since e−5=1e5e^{-5} = \frac{1}{e^5}e−5=e51​.

Flashcard 30: What is the exact solution of 4x=24^x=24x=2?

Answer: x=12x=\frac{1}{2}x=21​. Since 41/2=24^{1/2} = 241/2=2.