All flashcards
Flashcard 1: Which part of Qigl(1+rac{r}{n}igr)^{nt} is independent of Q?
Answer: igl(1+rac{r}{n}igr)^{nt}. The compound interest factor doesn't depend on principal Q.
Flashcard 2: Which part of 2xigl(x^2+3x+1igr) is best viewed as one entity multiplied by 2x?
Answer: igl(x^2+3x+1igr). The polynomial is treated as one factor of 2x.
Flashcard 3: In Aigl(1-rac{d}{100}igr)^k, what factor represents repeated percent decrease?
Answer: igl(1-rac{d}{100}igr)^k. This represents the decay factor applied k times.
Flashcard 4: In f(x)=−(x+4)2+9, what single entity is being squared?
Answer: (x+4). The shifted variable is squared with negative coefficient.
Flashcard 5: Identify u so that (x−4)2−16 can be viewed as u2−42.
Answer: u=x−4. Setting u=x−4 transforms this into u2−16.
Flashcard 6: In 21(h+7), what single entity is scaled by 21?
Answer: (h+7). The binomial is multiplied by the fractional coefficient.
Flashcard 7: Which part of P(1+r)n can be viewed as a single factor independent of P?
Answer: (1+r)n. This is the growth factor that doesn't contain P.
Flashcard 8: In igl(2(x-3)igr)^2, what single entity is being squared as a whole?
Answer: 2(x−3). The entire product is treated as one unit being squared.
Flashcard 9: In x2−6x+9, which single entity makes it recognizable as a perfect square?
Answer: Treat it as (x−3)2 with entity (x−3). Recognizing the perfect square trinomial pattern.
Flashcard 10: Identify u so that 4x2+12x+9 can be viewed as u2.
Answer: u=2x+3. This makes the expression (2x+3)2.
Flashcard 11: In (x2−1)(x2+1), what single entity can replace x2 to simplify viewing the product?
Answer: Let u=x2. Substitution simplifies the product structure.
Flashcard 12: If u=x2, how does x4−5x2+6 rewrite in terms of u?
Answer: u2−5u+6. Substituting transforms this into a quadratic in u.
Flashcard 13: If u=x+1, how does (x+1)2+3(x+1) rewrite in terms of u?
Answer: u2+3u. Direct substitution creates a simpler expression in u.
Flashcard 14: Identify u so that igl(3x-4igr)^2+2igl(3x-4igr) rewrites as u2+2u.
Answer: u=3x−4. This substitution creates the standard quadratic form.
Flashcard 15: In kigl(rac{1}{2}igr)^t, what is the factor independent of k?
Answer: igl(rac{1}{2}igr)^t. The exponential decay factor independent of the coefficient.
Flashcard 16: What does the expression P(1+r)n represent in words if r is a growth rate?
Answer: Initial amount P times growth factor (1+r)n. Standard compound growth formula interpretation.
Flashcard 17: What does the expression P(1−r)n represent in words if 0<r<1?
Answer: Initial amount P times decay factor (1−r)n. Standard exponential decay formula interpretation.
Flashcard 18: Identify the single entity in 3igl(2x^2-5x+1igr) that is multiplied by 3.
Answer: 2x2−5x+1. The polynomial expression is scaled by the coefficient 3.
Flashcard 19: Identify the single entity in rac{(x-1)^2}{9} that is being divided by 9.
Answer: (x−1)2. The squared binomial is the numerator being divided.
Flashcard 20: Which subexpression acts as one unit in igl(rac{x+1}{x-2}igr)^3?
Answer: rac{x+1}{x-2}. The rational expression is raised to the third power.
Flashcard 21: In a(bc+d), which part is best viewed as a single entity multiplied by a?
Answer: (bc+d). The sum is treated as a single factor of a.
Flashcard 22: Identify the single entity in (m+n)(m−n) that suggests a product of two units.
Answer: (m+n) and (m−n). Two separate binomial entities multiplied together.
Flashcard 23: In (x2+1)2−4, what subexpression is most natural to treat as one unit?
Answer: (x2+1). The quadratic expression is the base of operations.
Flashcard 24: What single entity makes u2−9 recognizable as a difference of squares?
Answer: Treat u as one unit: u2−32. Substituting u reveals the difference of squares pattern.
Flashcard 25: Identify u so that (x−4)2−16 can be viewed as u2−42.
Answer: u=x−4. Setting u=x−4 transforms this into u2−16.
Flashcard 26: Identify u so that (2x+1)2−25 can be viewed as u2−52.
Answer: u=2x+1. This substitution reveals the difference of squares structure.
Flashcard 27: Identify u so that (x2+3)2−1 can be viewed as u2−12.
Answer: u=x2+3. The quadratic plus constant becomes the single entity.
Flashcard 28: In (x+2)3+(x+2)2, what common single entity should be factored out?
Answer: (x+2)2. The squared binomial can be factored from both terms.
Flashcard 29: In 5(3t−1)+2(3t−1), what single entity is common to both terms?
Answer: (3t−1). The binomial appears in both terms as a common factor.
Flashcard 30: What is the shared single entity in a(x−7)−b(x−7)?
Answer: (x−7). The binomial is multiplied by different coefficients.