Study Creating Solving One Variable Equations Inequalities in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: What is the solution to the absolute value equation ∣ 2 x + 1 ∣ = 7 |2x+1|=7 ∣2 x + 1∣ = 7 ? Answer: x = 3 x=3 x = 3 or x = − 4 x=-4 x = − 4 . Solve 2 x + 1 = 7 2x+1=7 2 x + 1 = 7 and 2 x + 1 = − 7 2x+1=-7 2 x + 1 = − 7 separately.
Flashcard 2: What value must be excluded from solutions of x + 5 x 2 − 9 = 1 \frac{x+5}{x^2-9}=1 x 2 − 9 x + 5 = 1 ? Answer: x ≠ 3 x\ne 3 x = 3 and x ≠ − 3 x\ne -3 x = − 3 . Denominator x 2 − 9 = ( x − 3 ) ( x + 3 ) x^2-9=(x-3)(x+3) x 2 − 9 = ( x − 3 ) ( x + 3 ) cannot equal zero.
Flashcard 3: What is the solution to x x − 1 = 2 \frac{x}{x-1}=2 x − 1 x = 2 , with restrictions stated? Answer: x = 2 x=2 x = 2 , with x ≠ 1 x\ne 1 x = 1 . Multiply by ( x − 1 ) (x-1) ( x − 1 ) to get x = 2 ( x − 1 ) x=2(x-1) x = 2 ( x − 1 ) .
Flashcard 4: What is the axis of symmetry for y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k ? Answer: x = h x=h x = h . Vertical line through the vertex of any parabola.
Flashcard 5: What are the solutions to the quadratic equation x 2 − 6 x + 9 = 0 x^2-6x+9=0 x 2 − 6 x + 9 = 0 ? Answer: x = 3 x=3 x = 3 . Perfect square trinomial ( x − 3 ) 2 = 0 (x-3)^2=0 ( x − 3 ) 2 = 0 gives double root.
Flashcard 6: What is the solution to the linear equation x 4 + 3 = 8 \frac{x}{4}+3=8 4 x + 3 = 8 ? Answer: x = 20 x=20 x = 20 . Subtract 3 3 3 , then multiply both sides by 4 4 4 .
Flashcard 7: What is the interval notation for the solution set of x < − 2 x< -2 x < − 2 ? Answer: ( − ∞ , − 2 ) (-\infty,-2) ( − ∞ , − 2 ) . Parenthesis excludes − 2 -2 − 2 , extends from negative infinity.
Flashcard 8: What is the key restriction to state when solving 1 x − 3 = 5 \frac{1}{x-3}=5 x − 3 1 = 5 ? Answer: x ≠ 3 x\ne 3 x = 3 . Denominator cannot equal zero in rational equations.
Flashcard 9: What is the solution set for the inequality 5 − 2 x ≤ 9 5-2x\le 9 5 − 2 x ≤ 9 in interval notation? Answer: [ − 2 , ∞ ) [-2,\infty) [ − 2 , ∞ ) . Subtract 5 5 5 , divide by − 2 -2 − 2 , flip inequality sign.
Flashcard 10: What inequality models "no more than 12 12 12 tickets" if t t t is the number of tickets? Answer: t ≤ 12 t\le 12 t ≤ 12 . "No more than" means less than or equal to.
Flashcard 11: What equation models perimeter 24 24 24 of a square with side length s s s ? Answer: 4 s = 24 4s=24 4 s = 24 . Square perimeter is 4 4 4 times the side length.
Flashcard 12: What is the standard approach to solve ∣ x − 4 ∣ < 9 |x-4|<9 ∣ x − 4∣ < 9 ? Answer: Write − 9 < x − 4 < 9 -9<x-4<9 − 9 < x − 4 < 9 . Absolute value less than positive creates compound inequality.
Flashcard 13: What quadratic equation models "a rectangle has area 30 30 30 with length x + 2 x+2 x + 2 and width x − 3 x-3 x − 3 "? Answer: ( x + 2 ) ( x − 3 ) = 30 (x+2)(x-3)=30 ( x + 2 ) ( x − 3 ) = 30 . Rectangle area equals length times width.
Flashcard 14: What is the standard approach to solve ∣ x − 4 ∣ = 9 |x-4|=9 ∣ x − 4∣ = 9 ? Answer: Solve x − 4 = 9 x-4=9 x − 4 = 9 and x − 4 = − 9 x-4=-9 x − 4 = − 9 . Absolute value equals positive creates two linear equations.
Flashcard 15: What are the solutions to x 2 − 5 x = 0 x^2-5x=0 x 2 − 5 x = 0 ? Answer: x = 0 x=0 x = 0 or x = 5 x=5 x = 5 . Factor as x ( x − 5 ) = 0 x(x-5)=0 x ( x − 5 ) = 0 using zero product property.
Flashcard 16: What is the vertex x x x -coordinate of y = x 2 − 8 x + 1 y=x^2-8x+1 y = x 2 − 8 x + 1 ? Answer: x = 4 x=4 x = 4 . Use x = − b 2 a = − ( − 8 ) 2 ( 1 ) = 4 x=-\frac{b}{2a}=-\frac{(-8)}{2(1)}=4 x = − 2 a b = − 2 ( 1 ) ( − 8 ) = 4 .
Flashcard 17: What is a simple rational equation form that requires excluding values making the denominator 0 0 0 ? Answer: p ( x ) q ( x ) = k \frac{p(x)}{q(x)}=k q ( x ) p ( x ) = k with q ( x ) ≠ 0 q(x)\ne 0 q ( x ) = 0 . Fraction equals constant with domain restrictions.
Flashcard 18: What is the solution set of ∣ x − 1 ∣ ≤ 4 |x-1|\le 4 ∣ x − 1∣ ≤ 4 in interval notation? Answer: [ − 3 , 5 ] [-3,5] [ − 3 , 5 ] . Distance from 1 1 1 is at most 4 4 4 units.
Flashcard 19: What is the continuous growth formula for amount after time t t t at rate r r r ? Answer: A = P e r t A=Pe^{rt} A = P e r t . Principal P P P grows continuously at rate r r r over time t t t .
Flashcard 20: What equation models "the product of a number and 6 6 6 is 42 42 42 " using variable x x x ? Answer: 6 x = 42 6x=42 6 x = 42 . "Product" means multiplication of the number and 6 6 6 .
Flashcard 21: What are the solutions to x 2 + 3 x − 10 = 0 x^2+3x-10=0 x 2 + 3 x − 10 = 0 ? Answer: x = 2 x=2 x = 2 or x = − 5 x=-5 x = − 5 . Factor as ( x − 2 ) ( x + 5 ) = 0 (x-2)(x+5)=0 ( x − 2 ) ( x + 5 ) = 0 for two solutions.
Flashcard 22: Identify the first step to create an equation from a word problem involving a changing quantity. Answer: Define a variable for the unknown. Establishes what quantity you're solving for.
Flashcard 23: What is the solution to the inequality 2 x ≥ 8 2^{x}\ge 8 2 x ≥ 8 ? Answer: x ≥ 3 x\ge 3 x ≥ 3 . Rewrite as 2 x ≥ 2 3 2^x\ge 2^3 2 x ≥ 2 3 , so x ≥ 3 x\ge 3 x ≥ 3 .
Flashcard 24: What equation models "a number decreased by 7 7 7 is 20 20 20 " using variable x x x ? Answer: x − 7 = 20 x-7=20 x − 7 = 20 . "Decreased by" means subtract 7 7 7 from the number.
Flashcard 25: What operation clears denominators in 2 x + 1 = 5 \frac{2}{x}+1=5 x 2 + 1 = 5 to create an equivalent equation? Answer: Multiply both sides by the LCD. Eliminates fractions by multiplying by common denominator.
Flashcard 26: What is the inequality for "at least 50 50 50 " dollars if d d d is the number of dollars? Answer: d ≥ 50 d\ge 50 d ≥ 50 . "At least" means greater than or equal to.
Flashcard 27: What is the standard form of a quadratic equation used for solving in one variable? Answer: a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 . Standard quadratic form where a ≠ 0 a\ne 0 a = 0 for solving methods.
Flashcard 28: What is the solution to the exponential equation 5 ⋅ 2 x = 40 5\cdot 2^{x}=40 5 ⋅ 2 x = 40 ? Answer: x = 3 x=3 x = 3 . Divide by 5 5 5 to get 2 x = 8 = 2 3 2^x=8=2^3 2 x = 8 = 2 3 .
Flashcard 29: What is the solution to the quadratic equation x 2 − 9 = 0 x^2-9=0 x 2 − 9 = 0 ? Answer: x = ± 3 x=\pm 3 x = ± 3 . Factor as ( x − 3 ) ( x + 3 ) = 0 (x-3)(x+3)=0 ( x − 3 ) ( x + 3 ) = 0 to get solutions.
Flashcard 30: What does b 2 − 4 a c = 0 b^2-4ac=0 b 2 − 4 a c = 0 tell you about the real solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: One real solution (double root). Zero discriminant means the parabola touches the x x x -axis once.
Flashcard 31: What is the factored form of a quadratic used to create equations from zeros? Answer: y = a ( x − r 1 ) ( x − r 2 ) y=a(x-r_1)(x-r_2) y = a ( x − r 1 ) ( x − r 2 ) . Shows zeros r 1 r_1 r 1 and r 2 r_2 r 2 directly for intercept problems.
Flashcard 32: What is the compound interest formula for amount after t t t years with n n n compounds per year? Answer: A = P ( 1 + r n ) n t A=P\left(1+\frac{r}{n}\right)^{nt} A = P ( 1 + n r ) n t . Principal P P P , rate r r r , compounds n n n times, over t t t years.
Flashcard 33: What condition on b b b in y = a b x y=ab^x y = a b x represents exponential decay? Answer: 0 < b < 1 0<b<1 0 < b < 1 . Base between 0 0 0 and 1 1 1 creates decreasing exponential function.
Flashcard 34: What is the interval notation for the compound inequality − 1 < x ≤ 4 -1<x\le 4 − 1 < x ≤ 4 ? Answer: ( − 1 , 4 ] (-1,4] ( − 1 , 4 ] . Parenthesis excludes − 1 -1 − 1 , bracket includes 4 4 4 .
Flashcard 35: What is the interval notation for the solution set of x ≥ 3 x\ge 3 x ≥ 3 ? Answer: [ 3 , ∞ ) [3,\infty) [ 3 , ∞ ) . Bracket includes 3 3 3 , parenthesis extends to infinity.
Flashcard 36: What is the solution to the exponential equation 2 x = 16 2^x=16 2 x = 16 ? Answer: x = 4 x=4 x = 4 . Rewrite as 2 x = 2 4 2^x=2^4 2 x = 2 4 , so x = 4 x=4 x = 4 .
Flashcard 37: What is the solution to the compound inequality 2 < 3 x + 2 ≤ 11 2<3x+2\le 11 2 < 3 x + 2 ≤ 11 ? Answer: 0 < x ≤ 3 0<x\le 3 0 < x ≤ 3 . Subtract 2 2 2 , then divide by 3 3 3 for both parts.
Flashcard 38: What is the slope-intercept form of a linear equation in one variable context (function form)? Answer: y = m x + b y=mx+b y = m x + b . Standard form for linear functions with slope m m m and y y y -intercept b b b .
Flashcard 39: What does b 2 − 4 a c < 0 b^2-4ac<0 b 2 − 4 a c < 0 tell you about the real solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: No real solutions (two complex). Negative discriminant means the parabola doesn't cross the x x x -axis.
Flashcard 40: What does b 2 − 4 a c > 0 b^2-4ac>0 b 2 − 4 a c > 0 tell you about the real solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: Two distinct real solutions. Positive discriminant means two x x x -intercepts exist.
Flashcard 41: What condition on b b b in y = a b x y=ab^x y = a b x represents exponential growth? Answer: b > 1 b>1 b > 1 . Base greater than 1 1 1 creates increasing exponential function.
Flashcard 42: What is the discriminant of 2 x 2 − 4 x + 7 = 0 2x^2-4x+7=0 2 x 2 − 4 x + 7 = 0 ? Answer: − 40 -40 − 40 . b 2 − 4 a c = ( − 4 ) 2 − 4 ( 2 ) ( 7 ) = 16 − 56 = − 40 b^2-4ac=(-4)^2-4(2)(7)=16-56=-40 b 2 − 4 a c = ( − 4 ) 2 − 4 ( 2 ) ( 7 ) = 16 − 56 = − 40 .
Flashcard 43: What is the solution to the rational equation 1 x − 2 = 3 \frac{1}{x-2}=3 x − 2 1 = 3 ? Answer: x = 7 3 x=\frac{7}{3} x = 3 7 . Multiply both sides by ( x − 2 ) (x-2) ( x − 2 ) , then solve.
Flashcard 44: What equation models "a population starts at 500 500 500 and grows by 6 % 6\% 6% per year for t t t years"? Answer: P = 500 ( 1.06 ) t P=500(1.06)^{t} P = 500 ( 1.06 ) t . 6 % 6\% 6% growth means multiply by 1.06 1.06 1.06 each year.
Flashcard 45: What is the discriminant of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 that determines the number of real solutions? Answer: b 2 − 4 a c b^2-4ac b 2 − 4 a c . Expression under the square root in the quadratic formula.
Flashcard 46: What is the quadratic formula for solutions of a x 2 + b x + c = 0 ax^2+bx+c=0 a x 2 + b x + c = 0 ? Answer: x = − b ± b 2 − 4 a c 2 a x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} x = 2 a − b ± b 2 − 4 a c . Derives solutions when factoring or completing the square fails.
Flashcard 47: What is the solution to the linear equation 3 x − 7 = 11 3x-7=11 3 x − 7 = 11 ? Answer: x = 6 x=6 x = 6 . Add 7 7 7 to both sides, then divide by 3 3 3 .
Flashcard 48: What is the general exponential function form used to model growth or decay in one variable? Answer: y = a b x y=ab^x y = a b x . Base b b b and initial value a a a for exponential modeling.
Flashcard 49: What is the vertex form of a quadratic function often used when creating equations from a maximum or minimum? Answer: y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k . Shows vertex at ( h , k ) (h,k) ( h , k ) directly for optimization problems.
Flashcard 50: What inequality symbol results after multiplying both sides of an inequality by a negative number? Answer: The inequality sign reverses. Multiplying by negative flips the inequality direction.
Flashcard 51: What is the minimum value of y = ( x − 2 ) 2 − 5 y=(x-2)^2-5 y = ( x − 2 ) 2 − 5 ? Answer: − 5 -5 − 5 . Vertex form shows minimum value k = − 5 k=-5 k = − 5 directly.
Flashcard 52: What is the solution set for the inequality − 3 x > 12 -3x>12 − 3 x > 12 in interval notation? Answer: ( − ∞ , − 4 ) (-\infty,-4) ( − ∞ , − 4 ) . Divide by − 3 -3 − 3 and flip the inequality direction.
Flashcard 53: What is the solution to the exponential equation 3 x = 1 9 3^{x}=\frac{1}{9} 3 x = 9 1 ? Answer: x = − 2 x=-2 x = − 2 . Rewrite as 3 x = 3 − 2 3^x=3^{-2} 3 x = 3 − 2 , so x = − 2 x=-2 x = − 2 .