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Algebra 2 Flashcards: Constructing Linear And Exponential Functions

Study Constructing Linear And Exponential Functions in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Constructing Linear And Exponential Functions, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Constructing Linear And Exponential Functions

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QUESTION

Identify the function type if the table has a constant ratio yk+1yk\frac{y_{k+1}}{y_k}yk​yk+1​​ for equal steps in xxx.

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ANSWER

Exponential. Constant ratios indicate exponential relationship.

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All flashcards

Flashcard 1: Identify the function type if the table has a constant ratio yk+1yk\frac{y_{k+1}}{y_k}yk​yk+1​​ for equal steps in xxx.

Answer: Exponential. Constant ratios indicate exponential relationship.

Flashcard 2: What is the linear function through points (0,−3)(0,-3)(0,−3) and (4,5)(4,5)(4,5) in slope-intercept form?

Answer: y=2x−3y=2x-3y=2x−3. Initial value −3-3−3, slope 5−(−3)4−0=2\frac{5-(-3)}{4-0} = 24−05−(−3)​=2.

Flashcard 3: What is the linear function through points (1,7)(1,7)(1,7) and (3,11)(3,11)(3,11) in slope-intercept form?

Answer: y=2x+5y=2x+5y=2x+5. Slope 11−73−1=2\frac{11-7}{3-1} = 23−111−7​=2, yyy-intercept when x=0x=0x=0 is 555.

Flashcard 4: What is the exponential function for “starts at 505050 and increases by 3%3\%3% per year”?

Answer: y=50⋅(1.03)xy=50\cdot(1.03)^xy=50⋅(1.03)x. Initial 505050, growth factor 1+0.03=1.031 + 0.03 = 1.031+0.03=1.03.

Flashcard 5: What is the exponential function for “starts at 200200200 and decreases by 5%5\%5% per month”?

Answer: y=200⋅(0.95)xy=200\cdot(0.95)^xy=200⋅(0.95)x. Initial 200200200, decay factor 1−0.05=0.951 - 0.05 = 0.951−0.05=0.95.

Flashcard 6: What is the linear function for “starts at 121212 and increases by 444 each step”?

Answer: y=4x+12y=4x+12y=4x+12. Linear with slope 444 and yyy-intercept 121212.

Flashcard 7: What is the linear function for “starts at 303030 and decreases by 222 each hour”?

Answer: y=−2x+30y=-2x+30y=−2x+30. Linear with slope −2-2−2 and yyy-intercept 303030.

Flashcard 8: What is the common ratio rrr for the geometric sequence 3,12,48,192,…3,12,48,192,\dots3,12,48,192,…?

Answer: r=4r=4r=4. Each term multiplies by 123=4\frac{12}{3} = 4312​=4.

Flashcard 9: What is a6a_6a6​ for the arithmetic sequence with a1=2a_1=2a1​=2 and d=5d=5d=5?

Answer: a6=27a_6=27a6​=27. a6=2+(6−1)⋅5=2+25=27a_6 = 2 + (6-1) \cdot 5 = 2 + 25 = 27a6​=2+(6−1)⋅5=2+25=27.

Flashcard 10: What is a5a_5a5​ for the geometric sequence with a1=7a_1=7a1​=7 and r=2r=2r=2?

Answer: a5=112a_5=112a5​=112. a5=7⋅25−1=7⋅16=112a_5 = 7 \cdot 2^{5-1} = 7 \cdot 16 = 112a5​=7⋅25−1=7⋅16=112.

Flashcard 11: What is the linear function through points (1,7)(1,7)(1,7) and (3,11)(3,11)(3,11) in slope-intercept form?

Answer: y=2x+5y=2x+5y=2x+5. Slope 11−73−1=2\frac{11-7}{3-1} = 23−111−7​=2, yyy-intercept when x=0x=0x=0 is 555.

Flashcard 12: What is the constant ratio property of a geometric sequence?

Answer: an+1an=r\frac{a_{n+1}}{a_n}=ran​an+1​​=r (constant, an≠0a_n\neq 0an​=0). Consecutive terms have the same ratio rrr.

Flashcard 13: What is the explicit formula for an arithmetic sequence with first term a1a_1a1​ and difference ddd?

Answer: an=a1+(n−1)da_n=a_1+(n-1)dan​=a1​+(n−1)d. Start with a1a_1a1​, add ddd for each step to term nnn.

Flashcard 14: Identify the function type if the graph is a straight line with constant slope.

Answer: Linear. Straight lines have constant slope (linear functions).

Flashcard 15: Identify the function type if the graph curves and multiplies by a constant factor each 111 step in xxx.

Answer: Exponential. Curved growth by constant factors indicates exponential.

Flashcard 16: What is the slope of the line passing through (0,4)(0,4)(0,4) and (5,4)(5,4)(5,4)?

Answer: m=0m=0m=0. Horizontal line has zero slope (no rise).

Flashcard 17: What is aaa in y=a⋅bxy=a\cdot b^xy=a⋅bx if the function passes through (0,−8)(0,-8)(0,−8)?

Answer: a=−8a=-8a=−8. The initial value when x=0x = 0x=0 is aaa.

Flashcard 18: What is bbb if y=a⋅bxy=a\cdot b^xy=a⋅bx passes through (0,2)(0,2)(0,2) and (3,16)(3,16)(3,16)?

Answer: b=2b=2b=2. a=2a = 2a=2, 16=2⋅b316 = 2 \cdot b^316=2⋅b3, so b3=8b^3 = 8b3=8 and b=2b = 2b=2.

Flashcard 19: What is the linear function through (2,0)(2,0)(2,0) and (0,6)(0,6)(0,6) in slope-intercept form?

Answer: y=−3x+6y=-3x+6y=−3x+6. Slope 0−62−0=−3\frac{0-6}{2-0} = -32−00−6​=−3, yyy-intercept 666.

Flashcard 20: What is the exponential function through (0,4)(0,4)(0,4) and (2,36)(2,36)(2,36) in the form y=a⋅bxy=a\cdot b^xy=a⋅bx?

Answer: y=4⋅3xy=4\cdot 3^xy=4⋅3x. a=4a = 4a=4, 36=4⋅b236 = 4 \cdot b^236=4⋅b2, so b2=9b^2 = 9b2=9 and b=3b = 3b=3.

Flashcard 21: What is the slope of a line that rises 666 units when xxx increases by 222?

Answer: m=3m=3m=3. Slope equals rise over run: 62=3\frac{6}{2} = 326​=3.

Flashcard 22: What is the slope of a line that falls 101010 units when xxx increases by 555?

Answer: m=−2m=-2m=−2. Slope equals rise over run: −105=−2\frac{-10}{5} = -25−10​=−2.

Flashcard 23: Identify the function type if the table has a constant first difference in yyy for equal steps in xxx.

Answer: Linear. Constant differences indicate linear relationship.

Flashcard 24: What is the slope of the line through (2,5)(2,5)(2,5) and (6,13)(6,13)(6,13)?

Answer: m=2m=2m=2. m=13−56−2=84=2m = \frac{13-5}{6-2} = \frac{8}{4} = 2m=6−213−5​=48​=2.

Flashcard 25: What is the linear function with slope m=−4m=-4m=−4 and passing through (2,1)(2,1)(2,1)?

Answer: y=−4x+9y=-4x+9y=−4x+9. Using point-slope form with (2,1)(2,1)(2,1) and m=−4m=-4m=−4.

Flashcard 26: What is the yyy-intercept of the line 3x+2y=83x+2y=83x+2y=8?

Answer: b=4b=4b=4. Solve 3(0)+2y=83(0) + 2y = 83(0)+2y=8 to get y=4y = 4y=4.

Flashcard 27: What is the slope of the line 5x−10y=205x-10y=205x−10y=20?

Answer: m=12m=\frac{1}{2}m=21​. Rewrite as y=12x−2y = \frac{1}{2}x - 2y=21​x−2, so slope is 12\frac{1}{2}21​.

Flashcard 28: What is the exponential function through (0,6)(0,6)(0,6) and (1,15)(1,15)(1,15) in the form y=a⋅bxy=a\cdot b^xy=a⋅bx?

Answer: y=6⋅(52)xy=6\cdot\left(\frac{5}{2}\right)^xy=6⋅(25​)x. a=6a = 6a=6 from (0,6)(0,6)(0,6), b=156=52b = \frac{15}{6} = \frac{5}{2}b=615​=25​.

Flashcard 29: What is the exponential function through (0,10)(0,10)(0,10) and (2,40)(2,40)(2,40) in the form y=a⋅bxy=a\cdot b^xy=a⋅bx?

Answer: y=10⋅2xy=10\cdot 2^xy=10⋅2x. a=10a = 10a=10, b2=4b^2 = 4b2=4 so b=2b = 2b=2.

Flashcard 30: What is the exponential function through (1,12)(1,12)(1,12) and (3,48)(3,48)(3,48) in the form y=a⋅bxy=a\cdot b^xy=a⋅bx?

Answer: y=6⋅2xy=6\cdot 2^xy=6⋅2x. From ratio 4812=4=22\frac{48}{12} = 4 = 2^21248​=4=22, so b=2b = 2b=2, a=6a = 6a=6.