Algebra 2 Flashcards: Constructing Linear And Exponential Functions

Study Constructing Linear And Exponential Functions in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Algebra 2

Constructing Linear And Exponential Functions

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QUESTION
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What is the linear function for "starts at 3030 and decreases by 22 each hour"?

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ANSWER

y=2x+30y=-2x+30. Linear with slope 2-2 and yy-intercept 3030.

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What this deck covers

This deck focuses on Constructing Linear And Exponential Functions, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: What is the linear function for "starts at 3030 and decreases by 22 each hour"?

Answer: y=2x+30y=-2x+30. Linear with slope 2-2 and yy-intercept 3030.

Flashcard 2: What is the slope of the line 5x10y=205x-10y=20?

Answer: m=12m=\frac{1}{2}. Rewrite as y=12x2y = \frac{1}{2}x - 2, so slope is 12\frac{1}{2}.

Flashcard 3: What is the decay factor bb if an exponential model keeps 80%80\% each time xx increases by 11?

Answer: b=0.8b=0.8. Keeping 80%80\% means multiplying by 0.80.8 each step.

Flashcard 4: What is the common difference dd for the arithmetic sequence 5,9,13,17,5,9,13,17,\dots?

Answer: d=4d=4. Each term increases by 95=49-5 = 4.

Flashcard 5: What is aa in y=abxy=a\cdot b^x if the function passes through (0,8)(0,-8)?

Answer: a=8a=-8. The initial value when x=0x = 0 is aa.

Flashcard 6: What is the standard form of a linear equation (with integer coefficients)?

Answer: Ax+By=CAx+By=C. Linear equation with integer coefficients AA, BB, CC.

Flashcard 7: What is a5a_5 for the geometric sequence with a1=7a_1=7 and r=2r=2?

Answer: a5=112a_5=112. a5=7251=716=112a_5 = 7 \cdot 2^{5-1} = 7 \cdot 16 = 112.

Flashcard 8: What is the exponential function through (1,12)(1,12) and (3,48)(3,48) in the form y=abxy=a\cdot b^x?

Answer: y=62xy=6\cdot 2^x. From ratio 4812=4=22\frac{48}{12} = 4 = 2^2, so b=2b = 2, a=6a = 6.

Flashcard 9: What is the linear function through points (0,3)(0,-3) and (4,5)(4,5) in slope-intercept form?

Answer: y=2x3y=2x-3. Initial value 3-3, slope 5(3)40=2\frac{5-(-3)}{4-0} = 2.

Flashcard 10: What is the initial value in y=mx+by=mx+b?

Answer: bb (the yy-intercept, value when x=0x=0). Where the line crosses the yy-axis.

Flashcard 11: What is bb if y=abxy=a\cdot b^x passes through (0,2)(0,2) and (3,16)(3,16)?

Answer: b=2b=2. a=2a = 2, 16=2b316 = 2 \cdot b^3, so b3=8b^3 = 8 and b=2b = 2.

Flashcard 12: What is the explicit formula for a geometric sequence with first term a1a_1 and ratio rr?

Answer: an=a1rn1a_n=a_1\cdot r^{n-1}. Start with a1a_1, multiply by rr raised to (n1)(n-1) power.

Flashcard 13: What is the slope of the line through (2,5)(2,5) and (6,13)(6,13)?

Answer: m=2m=2. m=13562=84=2m = \frac{13-5}{6-2} = \frac{8}{4} = 2.

Flashcard 14: What is the recursive formula for an arithmetic sequence with difference dd?

Answer: an=an1+da_n=a_{n-1}+d (with a given a1a_1). Each term equals the previous term plus constant dd.

Flashcard 15: What is bb in y=abxy=a\cdot b^x if the function passes through (0,9)(0,9) and (1,3)(1,3)?

Answer: b=13b=\frac{1}{3}. At (1,3)(1,3): 3=9b3 = 9 \cdot b, so b=13b = \frac{1}{3}.

Flashcard 16: What is the slope of the line passing through (0,4)(0,4) and (5,4)(5,4)?

Answer: m=0m=0. Horizontal line has zero slope (no rise).

Flashcard 17: What is the point-slope form of a line through (x1,y1)(x_1,y_1) with slope mm?

Answer: yy1=m(xx1)y-y_1=m(x-x_1). Uses a known point and slope to build the equation.

Flashcard 18: What is the slope of a line that falls 1010 units when xx increases by 55?

Answer: m=2m=-2. Slope equals rise over run: 105=2\frac{-10}{5} = -2.

Flashcard 19: What is the recursive formula for a geometric sequence with ratio rr?

Answer: an=ran1a_n=r\cdot a_{n-1} (with a given a1a_1). Each term equals the previous term times constant rr.

Flashcard 20: What condition on bb gives exponential growth in y=abxy=a\cdot b^x (assuming a>0a>0)?

Answer: b>1b>1. Base greater than 1 means increasing exponential function.

Flashcard 21: What is the exponential function through (0,6)(0,6) and (1,15)(1,15) in the form y=abxy=a\cdot b^x?

Answer: y=6(52)xy=6\cdot\left(\frac{5}{2}\right)^x. a=6a = 6 from (0,6)(0,6), b=156=52b = \frac{15}{6} = \frac{5}{2}.

Flashcard 22: In y=abxy=a\cdot b^x, what does bb represent?

Answer: bb is the growth/decay factor per 11 unit of xx. How much the output multiplies for each unit increase in xx.

Flashcard 23: What is the slope of the line passing through (2,1)(2,-1) and (2,6)(2,6)?

Answer: Undefined slope (vertical line x=2x=2). Vertical lines have undefined slope (zero run).

Flashcard 24: What is the yy-intercept of the line 3x+2y=83x+2y=8?

Answer: b=4b=4. Solve 3(0)+2y=83(0) + 2y = 8 to get y=4y = 4.

Flashcard 25: What is the exponential function for "starts at 200200 and decreases by 5%5\% per month"?

Answer: y=200(0.95)xy=200\cdot(0.95)^x. Initial 200200, decay factor 10.05=0.951 - 0.05 = 0.95.

Flashcard 26: What is the exponential function through (0,4)(0,4) and (2,36)(2,36) in the form y=abxy=a\cdot b^x?

Answer: y=43xy=4\cdot 3^x. a=4a = 4, 36=4b236 = 4 \cdot b^2, so b2=9b^2 = 9 and b=3b = 3.

Flashcard 27: What is the linear function with slope m=4m=-4 and passing through (2,1)(2,1)?

Answer: y=4x+9y=-4x+9. Using point-slope form with (2,1)(2,1) and m=4m=-4.

Flashcard 28: What is the slope of a line that rises 66 units when xx increases by 22?

Answer: m=3m=3. Slope equals rise over run: 62=3\frac{6}{2} = 3.

Flashcard 29: What is the slope-intercept form of a linear function?

Answer: y=mx+by=mx+b. Standard linear form with slope mm and yy-intercept bb.

Flashcard 30: In y=abxy=a\cdot b^x, what does aa represent?

Answer: aa is the initial value y(0)y(0). The output value when x=0x = 0.

Flashcard 31: Identify the function type if the table has a constant ratio yk+1yk\frac{y_{k+1}}{y_k} for equal steps in xx.

Answer: Exponential. Constant ratios indicate exponential relationship.

Flashcard 32: What condition on bb gives exponential decay in y=abxy=a\cdot b^x (assuming a>0a>0)?

Answer: 0<b<10<b<1. Base between 0 and 1 means decreasing exponential function.

Flashcard 33: What is the linear equation of the vertical line passing through (3,0)(3,0)?

Answer: x=3x=3. Vertical lines have form x=constantx = \text{constant}.

Flashcard 34: What is the linear function through points (1,7)(1,7) and (3,11)(3,11) in slope-intercept form?

Answer: y=2x+5y=2x+5. Slope 11731=2\frac{11-7}{3-1} = 2, yy-intercept when x=0x=0 is 55.

Flashcard 35: What is a6a_6 for the arithmetic sequence with a1=2a_1=2 and d=5d=5?

Answer: a6=27a_6=27. a6=2+(61)5=2+25=27a_6 = 2 + (6-1) \cdot 5 = 2 + 25 = 27.

Flashcard 36: What is the constant ratio property of a geometric sequence?

Answer: an+1an=r\frac{a_{n+1}}{a_n}=r (constant, an0a_n\neq 0). Consecutive terms have the same ratio rr.

Flashcard 37: Identify the function type if the graph is a straight line with constant slope.

Answer: Linear. Straight lines have constant slope (linear functions).

Flashcard 38: What is the linear function for "starts at 1212 and increases by 44 each step"?

Answer: y=4x+12y=4x+12. Linear with slope 44 and yy-intercept 1212.

Flashcard 39: Identify the function type if the table has a constant first difference in yy for equal steps in xx.

Answer: Linear. Constant differences indicate linear relationship.

Flashcard 40: What is the growth factor bb if an exponential model doubles each time xx increases by 11?

Answer: b=2b=2. Doubling means multiplying by 22 each step.

Flashcard 41: What is the exponential function through (0,81)(0,81) and (4,9)(4,9) in the form y=abxy=a\cdot b^x?

Answer: y=81(13)xy=81\cdot\left(\frac{1}{\sqrt{3}}\right)^x. a=81a = 81, b4=981=19b^4 = \frac{9}{81} = \frac{1}{9}, so b=13b = \frac{1}{\sqrt{3}}.

Flashcard 42: What is the constant difference property of an arithmetic sequence?

Answer: an+1an=da_{n+1}-a_n=d (constant). Consecutive terms have the same difference dd.

Flashcard 43: What is the exponential function for "starts at 5050 and increases by 3%3\% per year"?

Answer: y=50(1.03)xy=50\cdot(1.03)^x. Initial 5050, growth factor 1+0.03=1.031 + 0.03 = 1.03.

Flashcard 44: What is the slope formula mm using two points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?

Answer: m=y2y1x2x1m=\frac{y_2-y_1}{x_2-x_1}. The rise over run formula using coordinate differences.

Flashcard 45: Identify the function type if the graph curves and multiplies by a constant factor each 11 step in xx.

Answer: Exponential. Curved growth by constant factors indicates exponential.

Flashcard 46: What is the general form of an exponential function showing initial value and growth factor?

Answer: y=abxy=a\cdot b^x. Initial value aa times growth factor bb raised to power xx.

Flashcard 47: What is the linear equation of the horizontal line passing through (0,7)(0,-7)?

Answer: y=7y=-7. Horizontal lines have form y=constanty = \text{constant}.

Flashcard 48: What is the exponential function through (0,10)(0,10) and (2,40)(2,40) in the form y=abxy=a\cdot b^x?

Answer: y=102xy=10\cdot 2^x. a=10a = 10, b2=4b^2 = 4 so b=2b = 2.

Flashcard 49: What is the explicit formula for the geometric sequence with a1=5a_1=5 and r=13r=\frac{1}{3}?

Answer: an=5(13)n1a_n=5\cdot\left(\frac{1}{3}\right)^{n-1}. Using the explicit geometric sequence formula.

Flashcard 50: What is the linear function through (2,0)(2,0) and (0,6)(0,6) in slope-intercept form?

Answer: y=3x+6y=-3x+6. Slope 0620=3\frac{0-6}{2-0} = -3, yy-intercept 66.

Flashcard 51: What is the explicit formula for an arithmetic sequence with first term a1a_1 and difference dd?

Answer: an=a1+(n1)da_n=a_1+(n-1)d. Start with a1a_1, add dd for each step to term nn.

Flashcard 52: What is the explicit formula for the arithmetic sequence with a1=3a_1=-3 and d=2d=2?

Answer: an=3+2(n1)a_n=-3+2(n-1). Using the explicit arithmetic sequence formula.

Flashcard 53: What is the common ratio rr for the geometric sequence 3,12,48,192,3,12,48,192,\dots?

Answer: r=4r=4. Each term multiplies by 123=4\frac{12}{3} = 4.