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This deck focuses on Comparing Functions Represented In Different Ways, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
Study Comparing Functions Represented In Different Ways in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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For f(x)=a(x−h)2+k, when does the quadratic have a minimum value?
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When a>0, minimum value is k. When the parabola opens upward, the vertex gives the lowest point.
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This deck focuses on Comparing Functions Represented In Different Ways, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: When a>0, minimum value is k. When the parabola opens upward, the vertex gives the lowest point.
Answer: f(−1)=3 is greater than g(−1)=−2. Substitute x=−1 into each function and compare results.
Answer: They are equal; both minima are 0. Horizontal shifts don't change the minimum value, only its location.
Answer: Maximum value is 9. Negative a means downward opening, so vertex gives maximum at y=k.
Answer: f(3)= rac{1}{2} is larger than g(3)= rac{1}{4}. Substitute x=3 into each function and compare the results.
Answer: f(x)=a(x−h)2+k. Standard form that directly shows the vertex coordinates.
Answer: Relative size: compare outputs f(x) and g(x) for the same x. Compare function values at the same input to see which produces larger outputs.
Answer: An x-intercept is an x where f(x)=0. Where the graph crosses the x-axis; solve for when the output equals zero.
Answer: x=4. Read the h-value directly from the vertex form.
Answer: f is constant on [1,3]. All function values are identical, so the function is constant.
Answer: As x→±∞, f(x)→−∞. Negative leading coefficient means the parabola opens downward at both ends.
Answer: f(0)=3 is larger than g(0)=1. Evaluate both functions at x=0 and compare the outputs.
Answer: y=2x+3. Linear function with slope 2 and y-intercept 3.
Answer: Minimum value is −2. Positive a means upward opening, so vertex gives minimum at y=k.
Answer: Range: y≤8. Downward-opening parabola with vertex at y=8 gives range y≤8.
Answer: As x→±∞, f(x)→∞. Positive leading coefficient means the parabola opens upward at both ends.
Answer: g has the larger maximum (5>3). Compare the k-values from vertex form; 5>3.
Answer: b−af(b)−f(a). The slope of the secant line between two points on the function.
Answer: (3,−5). Read the vertex coordinates directly from the vertex form.
Answer: x=1 and x=−3. Set each factor equal to zero and solve for the x-values.
Answer: The first line, since slope = 2−09−1=4. Calculate the slope and compare with the given slope of 3.
Answer: They are equal; both maxima are 1. Both have the same vertex y-coordinate despite different shapes.
Answer: Axis of symmetry is x=h. The vertical line through the vertex that divides the parabola symmetrically.
Answer: f(0)=4. Substitute x=0 into the function to find where it crosses the y-axis.
Answer: f is larger (2>−1). Compare the computed rates directly; 2>−1.
Answer: Maximum of g is 5 more than maximum of f. Vertical shifts add the same amount to all function values.
Answer: f(x)→−∞. Negative leading coefficient causes the parabola to go down as x increases.
Answer: As x increases, f(x) increases on that interval. The function's output values rise as the input values increase.
Answer: The y-intercept is f(0), the point (0,f(0)). Where the graph crosses the y-axis; substitute x=0 into the function.
Answer: Reflection across the x-axis. Negating the output flips the graph over the horizontal axis.
Answer: f(3)=21 is larger than g(3)=41. Substitute x=3 into each function and compare the results.
Answer: As x increases, f(x) decreases on that interval. The function's output values fall as the input values increase.
Answer: Vertex is (h,k). The turning point where the parabola changes direction.
Answer: When a<0, maximum value is k. When the parabola opens downward, the vertex gives the highest point.
Answer: g is steeper because ∣−5∣>∣3∣. Compare absolute values of slopes; steeper means larger absolute slope.
Answer: Range: y≥5. Upward-opening parabola with vertex at y=5 gives range y≥5.
Answer: g has more zeros (2 zeros; f has 0 real zeros). Count real solutions; f has no real zeros, g has two.
Answer: m= rac{y_2-y_1}{x_2-x_1}. Rise over run; the change in y divided by the change in x.
Answer: g has the larger y-intercept (4>−1). Find each y-intercept by setting x=0 and compare.
Answer: f(−2) is larger. On decreasing intervals, smaller x-values produce larger function values.
Answer: f(5) is larger. On increasing intervals, larger x-values produce larger function values.
Answer: Horizontal shift right c units (left if c<0). Subtracting from the input moves the graph horizontally opposite direction.
Answer: f(2) is larger. Compare the function values directly to determine which is greater.
Answer: Minimum of g is 6 less than minimum of f. Vertical shifts change the minimum by the same amount as the shift.
Answer: Minimum value is −1. For upward-opening parabolas, the vertex y-coordinate is the minimum.
Answer: Reflection across the y-axis. Negating the input flips the graph over the vertical axis.
Answer: Vertical shift up c units (down if c<0). Adding to the output moves the graph vertically.
Answer: Domain: all real x with x=3. The denominator cannot be zero, so exclude x=3.
Answer: g has the larger minimum ( −1>−4 ). Compare the k-values from vertex form; −1>−4.
Answer: m is slope; b is y-intercept. Slope-intercept form where m determines steepness and b is the starting value.
Answer: m=5−110−2=2. Use the slope formula with the two given points.
Answer: Key points shift right 2 units (add 2 to x). Horizontal shifts move all points the same distance along the x-axis.
Answer: f has the larger maximum (4>2). Compare the k-values from vertex form; 4>2.
Answer: m=5−110−2=2. Use the slope formula with the two given points.
Answer: The set of all allowed input values (all x-values). All x-values for which the function is defined.
Answer: The set of all possible output values (all y-values). All y-values that the function can produce as outputs.
Answer: rac{11-2}{3-0}=3. Use the average rate formula with the table values over the interval.
Answer: Maximum value is 7. For downward-opening parabolas, the vertex y-coordinate is the maximum.
Answer: Maximum value is 6. For downward-opening parabolas, the vertex gives the maximum value.
Answer: 4−115−3=4. Apply the average rate of change formula with the given values.