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Algebra 2 Flashcards: Compare Linear And Exponential Growth

Study Compare Linear And Exponential Growth in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

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What this deck covers

This deck focuses on Compare Linear And Exponential Growth, giving you a quick way to review the definitions, rules, and examples that matter most for Algebra 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Algebra 2 Flashcards: Compare Linear And Exponential Growth

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QUESTION

Find the constant difference over 444 units if m=−2m=-2m=−2 for a linear function.

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ANSWER

−8-8−8. Difference over 4 units is 4×(−2)=−84 \times (-2) = -84×(−2)=−8.

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Flashcard 1: Find the constant difference over 444 units if m=−2m=-2m=−2 for a linear function.

Answer: −8-8−8. Difference over 4 units is 4×(−2)=−84 \times (-2) = -84×(−2)=−8.

Flashcard 2: Identify the interval length hhh used in f(x+h)−f(x)f(x+h)-f(x)f(x+h)−f(x) when comparing x=2x=2x=2 to x=7x=7x=7.

Answer: 555. Distance from 2 to 7 is 7−2=57-2 = 57−2=5 units.

Flashcard 3: Find mmm if f(10)−f(6)=20f(10)-f(6)=20f(10)−f(6)=20 for a linear function.

Answer: 555. Using differenceinterval=204=5\frac{\text{difference}}{\text{interval}} = \frac{20}{4} = 5intervaldifference​=420​=5.

Flashcard 4: Identify the function type if outputs increase by +6+6+6 each time xxx increases by 111.

Answer: Linear. Adding constant amounts indicates linear growth pattern.

Flashcard 5: Identify the function type if outputs are multiplied by 1.251.251.25 each time xxx increases by 111.

Answer: Exponential. Multiplying by constant factors indicates exponential growth pattern.

Flashcard 6: Find the constant factor over 222 units if b=3b=3b=3 for an exponential function.

Answer: 999. Factor over 2 units is b2=32=9b^2 = 3^2 = 9b2=32=9.

Flashcard 7: Which value is constant for linear functions: ΔyΔx\frac{\Delta y}{\Delta x}ΔxΔy​ or y2y1\frac{y_2}{y_1}y1​y2​​?

Answer: ΔyΔx\frac{\Delta y}{\Delta x}ΔxΔy​. Linear functions have constant slope (rate of change).

Flashcard 8: What is the general form of a linear function used to show equal differences?

Answer: f(x)=mx+bf(x)=mx+bf(x)=mx+b. Standard linear form where mmm is the slope (constant difference).

Flashcard 9: Identify the constant factor for f(x)=5⋅2xf(x)=5\cdot 2^xf(x)=5⋅2x over a 111-unit interval.

Answer: 222. The base 222 is the constant factor per unit interval.

Flashcard 10: What expression gives the constant change over 111 unit for f(x)=mx+bf(x)=mx+bf(x)=mx+b?

Answer: f(x+1)−f(x)=mf(x+1)-f(x)=mf(x+1)−f(x)=m. Shows the slope mmm as the constant difference per unit.

Flashcard 11: What is f(x+1)−f(x)f(x+1)-f(x)f(x+1)−f(x) for f(x)=mx+bf(x)=mx+bf(x)=mx+b after simplification?

Answer: mmm. Expanding (mx+m+b)−(mx+b)(mx+m+b)-(mx+b)(mx+m+b)−(mx+b) gives mmm.

Flashcard 12: Identify the constant difference for f(x)=−4x+10f(x)=-4x+10f(x)=−4x+10 over a 1-unit interval.

Answer: −4-4−4. The coefficient −4-4−4 is the slope, giving constant difference −4-4−4.

Flashcard 13: Which test identifies exponential growth in a table: constant f(x+1)−f(x)f(x+1)-f(x)f(x+1)−f(x) or constant f(x+1)f(x)\frac{f(x+1)}{f(x)}f(x)f(x+1)​?

Answer: Constant f(x+1)f(x)\frac{f(x+1)}{f(x)}f(x)f(x+1)​. Exponential functions have constant ratios between consecutive outputs.

Flashcard 14: Choose the correct statement for linear functions: constant difference or constant ratio?

Answer: Constant difference. Linear functions add the same amount over equal intervals.

Flashcard 15: Find the slope mmm if f(x+1)−f(x)=12f(x+1)-f(x)=12f(x+1)−f(x)=12 for all xxx.

Answer: 121212. If constant difference is 12, then slope m=12m = 12m=12.

Flashcard 16: Find the base bbb if f(x+1)f(x)=0.8\frac{f(x+1)}{f(x)}=0.8f(x)f(x+1)​=0.8 for all xxx and f(x)≠0f(x)\neq 0f(x)=0.

Answer: 0.80.80.8. If constant ratio is 0.8, then base b=0.8b = 0.8b=0.8.

Flashcard 17: What expression gives the constant factor over 111 unit for f(x)=abxf(x)=ab^xf(x)=abx?

Answer: f(x+1)f(x)=b\frac{f(x+1)}{f(x)}=bf(x)f(x+1)​=b. Shows the base bbb as the constant multiplicative factor per unit.

Flashcard 18: What is the key condition needed to use f(x+h)f(x)\frac{f(x+h)}{f(x)}f(x)f(x+h)​ as a test?

Answer: f(x)≠0f(x)\neq 0f(x)=0. Division by zero is undefined, so f(x)≠0f(x) \neq 0f(x)=0 is required.

Flashcard 19: Find bbb if f(4)f(1)=18\frac{f(4)}{f(1)}=\frac{1}{8}f(1)f(4)​=81​ for an exponential function.

Answer: 12\frac{1}{2}21​. Since b3=18b^3 = \frac{1}{8}b3=81​ and (12)3=18(\frac{1}{2})^3 = \frac{1}{8}(21​)3=81​, base is 12\frac{1}{2}21​.

Flashcard 20: Choose the correct statement for exponential functions: constant difference or constant ratio?

Answer: Constant ratio. Exponential functions multiply by the same factor over equal intervals.

Flashcard 21: Identify the base bbb if an exponential function doubles each time xxx increases by 111.

Answer: 222. Doubling means multiplying by 2, so base b=2b = 2b=2.

Flashcard 22: Identify the base bbb if an exponential function is halved each time xxx increases by 111.

Answer: 12\frac{1}{2}21​. Halving means multiplying by 12\frac{1}{2}21​, so base b=12b = \frac{1}{2}b=21​.

Flashcard 23: What is the common ratio bbb using two exponential values f(x)f(x)f(x) and f(x+1)f(x+1)f(x+1)?

Answer: b=f(x+1)f(x)b=\frac{f(x+1)}{f(x)}b=f(x)f(x+1)​. Consecutive exponential values have ratio equal to the base.

Flashcard 24: What is the constant difference over hhh units for f(x)=mx+bf(x)=mx+bf(x)=mx+b?

Answer: f(x+h)−f(x)=mhf(x+h)-f(x)=mhf(x+h)−f(x)=mh. Generalizes to any interval hhh with difference mhmhmh.

Flashcard 25: Identify the constant difference for f(x)=12x+6f(x)=\frac{1}{2}x+6f(x)=21​x+6 over a 111-unit interval.

Answer: 12\frac{1}{2}21​. The coefficient 12\frac{1}{2}21​ is the slope.

Flashcard 26: What is the general form of an exponential function used to show equal factors?

Answer: f(x)=abxf(x)=ab^xf(x)=abx. Standard exponential form where bbb is the base (constant factor).

Flashcard 27: Find f(x+3)−f(x)f(x+3)-f(x)f(x+3)−f(x) for f(x)=−6x+4f(x)=-6x+4f(x)=−6x+4.

Answer: −18-18−18. Difference over 3 units is 3×(−6)=−183 \times (-6) = -183×(−6)=−18.

Flashcard 28: What expression gives the constant change over 111 unit for f(x)=mx+bf(x)=mx+bf(x)=mx+b?

Answer: f(x+1)−f(x)=mf(x+1)-f(x)=mf(x+1)−f(x)=m. Shows the slope mmm as the constant difference per unit.

Flashcard 29: Identify the constant factor for f(x)=3⋅(14)xf(x)=3\cdot \left(\frac{1}{4}\right)^xf(x)=3⋅(41​)x over 111 unit.

Answer: 14\frac{1}{4}41​. The base 14\frac{1}{4}41​ is the constant factor per unit.

Flashcard 30: What is the general form of a linear function used to show equal differences?

Answer: f(x)=mx+bf(x)=mx+bf(x)=mx+b. Standard linear form where mmm is the slope (constant difference).