Study Applying The Remainder Theorem in Algebra 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: Find the value of k so that x−2 is a factor of p(x)=x2+kx−6.
Answer: k=1. Set p(2)=0: 4+2k−6=0, so k=1.
Flashcard 2: What is the remainder when dividing p(x)=x4−16 by x+2?
Answer: p(−2)=0. Calculate p(−2)=(−2)4−16=16−16=0.
Flashcard 3: What is the remainder when dividing p(x)=3x2−12x+9 by x−1?
Answer: p(1)=0. Calculate p(1)=3(1)2−12(1)+9=3−12+9=0.
Flashcard 4: What is the remainder when dividing p(x)=x2−1 by x-rac{1}{3}?
Answer: p(31)=−98. Calculate p(31)=(31)2−1=91−1=−98.
Flashcard 5: Identify the remainder when dividing p(x)=x2+x+1 by x−1.
Answer: p(1)=3. Calculate p(1)=12+1+1=1+1+1=3.
Flashcard 6: If p(0)=5, what is the remainder when dividing p(x) by x?
Answer: Remainder =5. Dividing by x means evaluating at x=0.
Flashcard 7: What is the remainder when dividing p(x)=x3−2x2+x−2 by x−2?
Answer: p(2)=0. Calculate p(2)=8−8+2−2=0.
Flashcard 8: If the remainder on division by x−a is r, what is p(a) equal to?
Answer: p(a)=r. The remainder equals the polynomial evaluated at a.
Flashcard 9: Identify the remainder when dividing p(x)=5x2+2x−3 by x−0.
Answer: p(0)=−3. Calculate p(0)=5(0)2+2(0)−3=−3.
Flashcard 10: What is the remainder when dividing p(x)=x3−9x by x+3?
Answer: p(−3)=0. Calculate p(−3)=(−3)3−9(−3)=−27+27=0.
Flashcard 11: What is the remainder when dividing p(x)=4x3+1 by x-rac{1}{2}?
Answer: p(21)=23. Calculate p(21)=4(21)3+1=21+1=23.
Flashcard 12: If dividing p(x) by x−9 gives remainder 7, what is the value of p(9)?
Answer: p(9)=7. By the Remainder Theorem, p(a) equals the remainder.
Flashcard 13: If p(6)=−3, what is the remainder when dividing p(x) by x−6?
Answer: Remainder =−3. By the Remainder Theorem, the remainder equals p(6).
Flashcard 14: Identify the value of a used in the Remainder Theorem when the divisor is x+7.
Answer: a=−7. For divisor x+7=x−(−7), the value a=−7.
Flashcard 15: Which condition guarantees that (x−a) is a factor of p(x): p(a)=0 or p(a)=0?
Answer: p(a)=0. When p(a)=0, the remainder is zero, making (x−a) a factor.
Flashcard 16: If dividing p(x) by x+2 gives remainder 0, what is the value of p(−2)?
Answer: p(−2)=0. If remainder is 0, then p(a)=0 by the theorem.
Flashcard 17: What is the remainder when dividing p(x)=x2−2x+2 by x+1?
Answer: p(−1)=5. Calculate p(−1)=(−1)2−2(−1)+2=1+2+2=5.
Flashcard 18: What does the Factor Theorem state using p(a) and the factor (x−a)?
Answer: p(a)=0⟺(x−a) is a factor of p(x). The Factor Theorem combines remainder and factorization.
Flashcard 19: Find the remainder when dividing p(x)=x3+1 by x−1.
Answer: p(1)=2. Calculate p(1)=13+1=1+1=2.
Flashcard 20: Which divisor corresponds to evaluating p(−5) by the Remainder Theorem: x−5 or x+5?
Answer: x+5. To evaluate p(−5), divide by x−(−5)=x+5.
Flashcard 21: Which divisor corresponds to evaluating p(5) by the Remainder Theorem: x−5 or x+5?
Answer: x−5. To evaluate p(5), divide by x−5.
Flashcard 22: If p(−4)=12, what is the remainder when dividing p(x) by x+4?
Answer: Remainder =12. By the Remainder Theorem, the remainder equals p(−4).
Flashcard 23: Which statement is true if the remainder on division by x−4 is 0?
Answer: (x−4) is a factor of p(x). A zero remainder means the divisor is a factor.
Flashcard 24: If (x−a) is a factor of p(x), what must the remainder be when dividing by (x−a)?
Answer: Remainder =0. If (x−a) is a factor, then p(a)=0.
Flashcard 25: Identify the remainder when dividing p(x)=x2+x+1 by x+1.
Answer: p(−1)=1. Calculate p(−1)=(−1)2+(−1)+1=1−1+1=1.
Flashcard 26: What is the remainder when dividing p(x) by x+5 in terms of p?
Answer: Remainder =p(−5). Since x+5=x−(−5), we have a=−5.
Flashcard 27: Identify the value of a used in the Remainder Theorem when the divisor is x−7.
Answer: a=7. For divisor x−7, the value a=7.
Flashcard 28: Find the value of k so that x−1 is a factor of p(x)=x3−4x2+kx+3.
Answer: k=0. Set p(1)=0: 1−4+k+3=0, so k=0.
Flashcard 29: What is the remainder when dividing p(x)=x4−16 by x−2?
Answer: p(2)=0. Calculate p(2)=24−16=16−16=0.
Flashcard 30: Find the remainder when dividing p(x)=x3−1 by x+1.
Answer: p(−1)=−2. Calculate p(−1)=(−1)3−1=−1−1=−2.
Flashcard 31: If p(−2)=0, which linear factor must divide p(x): x−2 or x+2?
Answer: x+2. If p(−2)=0, then (x+2) is a factor.
Flashcard 32: What is the remainder when dividing p(x)=x3−4x+1 by x−2?
Answer: p(2)=1. Calculate p(2)=23−4(2)+1=8−8+1=1.
Flashcard 33: What is the remainder when dividing p(x)=x3−2x2+x−2 by x+1?
Answer: p(−1)=−6. Calculate p(−1)=−1−2−1−2=−6.
Flashcard 34: What is the remainder when dividing p(x)=x4+x3−x−1 by x+1?
Answer: p(−1)=0. Calculate p(−1)=(−1)4+(−1)3−(−1)−1=1−1+1−1=0.
Flashcard 35: What is the remainder when dividing p(x)=2x3−x2+5 by x−1?
Answer: p(1)=6. Calculate p(1)=2(1)3−(1)2+5=2−1+5=6.
Flashcard 36: What is the remainder when dividing p(x)=x3−9x by x−3?
Answer: p(3)=0. Calculate p(3)=33−9(3)=27−27=0.
Flashcard 37: If p(2)=0, which linear factor must divide p(x): x−2 or x+2?
Answer: x−2. If p(2)=0, then (x−2) is a factor.
Flashcard 38: What is the remainder when dividing p(x)=3x2−12x+9 by x−3?
Answer: p(3)=0. Calculate p(3)=3(3)2−12(3)+9=27−36+9=0.
Flashcard 39: Find the value of k so that x+3 is a factor of p(x)=2x2+kx−9.
Answer: k=3. Set p(−3)=0: 18−3k−9=0, so k=3.
Flashcard 40: Find the value of k so that x+2 is a factor of p(x)=x3+kx2−4x+8.
Answer: k=0. Set p(−2)=0: −8+4k+8+8=0, so k=0.
Flashcard 41: Find the remainder when dividing p(x)=x3+1 by x+1.
Answer: p(−1)=0. Calculate p(−1)=(−1)3+1=−1+1=0.
Flashcard 42: What is the remainder when dividing p(x)=x4+x3−x−1 by x−1?
Answer: p(1)=0. Calculate p(1)=14+13−1−1=1+1−1−1=0.
Flashcard 43: What does the Remainder Theorem state for the remainder when dividing p(x) by x−a?
Answer: Remainder =p(a). This is the core statement of the Remainder Theorem.
Flashcard 44: What is the remainder when dividing p(x)=x2+3x−10 by x−2?
Answer: p(2)=0. Calculate p(2)=22+3(2)−10=4+6−10=0.
Flashcard 45: What is the remainder when dividing p(x)=x3+2x2−x−2 by x+2?
Answer: p(−2)=0. Calculate p(−2)=(−2)3+2(−2)2−(−2)−2=−8+8+2−2=0.
Flashcard 46: What is the remainder when dividing p(x)=2x3−x2+5 by x+1?
Answer: p(−1)=2. Calculate p(−1)=2(−1)3−(−1)2+5=−2−1+5=2.
Flashcard 47: What is the remainder when dividing p(x)=x2−2x+2 by x−1?
Answer: p(1)=1. Calculate p(1)=12−2(1)+2=1−2+2=1.
Flashcard 48: What is the remainder when dividing p(x) by x−3 in terms of p?
Answer: Remainder =p(3). By the Remainder Theorem, substitute a=3.
Flashcard 49: Find the remainder when dividing p(x)=x3−1 by x−1.
Answer: p(1)=0. Calculate p(1)=13−1=1−1=0.
Flashcard 50: What is the remainder when dividing p(x)=x2+3x−10 by x+5?
Answer: p(−5)=0. Calculate p(−5)=(−5)2+3(−5)−10=25−15−10=0.
Flashcard 51: What is the remainder when dividing p(x)=x3+2x2−x−2 by x−1?
Answer: p(1)=0. Calculate p(1)=13+2(1)2−1−2=1+2−1−2=0.