All flashcards
Flashcard 1: Find the value of (49).
Answer: 126. Using (49)=4!5!9!=126.
Flashcard 2: Expand (x+y)3.
Answer: x3+3x2y+3xy2+y3. Using coefficients 1,3,3,1 from Pascal's triangle.
Flashcard 3: Expand (x−y)3.
Answer: x3−3x2y+3xy2−y3. Alternating signs from (−y)k with coefficients 1,3,3,1.
Flashcard 4: What is the coefficient of x5y3 in (x−y)8?
Answer: −(38)=−56. Coefficient is (38)=56 with negative sign from (−y)3.
Flashcard 5: Find the value of (110).
Answer: 10. Using (110)=10.
Flashcard 6: What is the factorial definition of the binomial coefficient (kn)?
Answer: (kn)=k!(n−k)!n!. Uses factorial formula to calculate combinations.
Flashcard 7: State the Binomial Theorem formula for expanding (x+y)n using binomial coefficients.
Answer: (x+y)n=∑k=0n(kn)xn−kyk. The general formula for binomial expansion with coefficients and powers.
Flashcard 8: Expand (x−y)3.
Answer: x3−3x2y+3xy2−y3. Alternating signs from (−y)k with coefficients 1,3,3,1.
Flashcard 9: Expand (x−y)4.
Answer: x4−4x3y+6x2y2−4xy3+y4. Alternating signs from (−y)k with coefficients 1,4,6,4,1.
Flashcard 10: What is the coefficient of x7y2 in (x+y)9?
Answer: (29)=36. The coefficient of x7y2 is (29)=36.
Flashcard 11: What is the coefficient of x3y5 in (x+y)8?
Answer: (58)=56. The coefficient of x3y5 is (58)=56.
Flashcard 12: What is the coefficient of x6y4 in (x+y)10?
Answer: (410)=210. The coefficient of x6y4 is (410)=210.
Flashcard 13: What is the coefficient of x5y3 in (x−y)8?
Answer: −(38)=−56. Coefficient is (38)=56 with negative sign from (−y)3.
Flashcard 14: What is the coefficient of x4y4 in (x−y)8?
Answer: (48)=70. Coefficient is (48)=70 with positive sign from (−y)4.
Flashcard 15: Identify the coefficient of the x2y3 term in (x+y)5.
Answer: (35)=10. The coefficient of x2y3 is (35)=10.
Flashcard 16: What is the coefficient of a4b2 in (a+b)6?
Answer: (26)=15. The coefficient of a4b2 is (26)=15.
Flashcard 17: What is the coefficient of a2b4 in (a+b)6?
Answer: (46)=15. The coefficient of a2b4 is (46)=15.
Flashcard 18: What is the coefficient pattern (Pascal row) for expanding (x+y)3?
Answer: 1,3,3,1. Row 3 of Pascal's triangle.
Flashcard 19: Find the value of (28).
Answer: 28. Using (28)=2!6!8!=28⋅7=28.
Flashcard 20: Find the value of (68).
Answer: 28. Using symmetry: (68)=(28)=28.
Flashcard 21: Find the value of (110).
Answer: 10. Using (110)=10.
Flashcard 22: Find the value of (210).
Answer: 45. Using (210)=210⋅9=45.
Flashcard 23: Find the value of (310).
Answer: 120. Using (310)=610⋅9⋅8=120.
Flashcard 24: What is the coefficient sum of (x−y)n (equivalently, evaluate at x=1,y=1)?
Answer: 0 if n is odd; 2n if n is even. Substitute x=1 and y=−1 into (x−y)n.
Flashcard 25: In (x+y)n, what is the general term (the kth term) written in powers of x and y?
Answer: (kn)xn−kyk. The (k+1)th term in the binomial expansion.
Flashcard 26: Find the value of (49).
Answer: 126. Using (49)=4!5!9!=126.
Flashcard 27: Expand (x+y)2.
Answer: x2+2xy+y2. Using coefficients 1,2,1 from Pascal's triangle.
Flashcard 28: Expand (x+y)3.
Answer: x3+3x2y+3xy2+y3. Using coefficients 1,3,3,1 from Pascal's triangle.
Flashcard 29: Expand (x+y)4.
Answer: x4+4x3y+6x2y2+4xy3+y4. Using coefficients 1,4,6,4,1 from Pascal's triangle.
Flashcard 30: In (x+y)n, what is the exponent of x in the term containing yk?
Answer: n−k. Exponents of x and y must sum to n.