ACT Math Flashcards: Complex Numbers

Study Complex Numbers in ACT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

ACT Math

Complex Numbers

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QUESTION
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Calculate the modulus of 512i-5 - 12i.

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ANSWER

1313. Use z=25+144=169=13|z| = \sqrt{25 + 144} = \sqrt{169} = 13.

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This deck focuses on Complex Numbers, giving you a quick way to review the definitions, rules, and examples that matter most for ACT Math.

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Flashcard 1: Calculate the modulus of 512i-5 - 12i.

Answer: 1313. Use z=25+144=169=13|z| = \sqrt{25 + 144} = \sqrt{169} = 13.

Flashcard 2: Divide 4i4i by 2i2i. What is the result?

Answer: 22. Division of complex numbers: 4i2i=2\frac{4i}{2i} = 2.

Flashcard 3: What is z\overline{\overline{z}} equal to for any complex number zz?

Answer: zz. Taking conjugate twice returns original number.

Flashcard 4: What is z1z2\overline{z_1z_2} in terms of z1\overline{z_1} and z2\overline{z_2}?

Answer: z1z2\overline{z_1}\,\overline{z_2}. Conjugate of product equals product of conjugates.

Flashcard 5: What is the sum of 3+4i3 + 4i and 5+2i5 + 2i?

Answer: 8+6i8 + 6i. Add real parts and imaginary parts separately.

Flashcard 6: What is the result of dividing 3+4i3 + 4i by 1+i1 + i?

Answer: 72+12i\frac{7}{2} + \frac{1}{2}i. Multiply by conjugate of denominator and simplify.

Flashcard 7: What is the sum of 3+4i3 + 4i and 5+2i5 + 2i?

Answer: 8+6i8 + 6i. Add real parts and imaginary parts separately.

Flashcard 8: What is the standard form of a complex number?

Answer: a+bia + bi where a,ba, b are real numbers. This is the general form where aa is real part and bb is imaginary coefficient.

Flashcard 9: What is (a+bi)(abi)(a+bi)(a-bi) equal to?

Answer: a2+b2a^2+b^2. Multiplying by conjugate eliminates imaginary terms.

Flashcard 10: If z=7iz = 7i, what is zz^*?

Answer: 7i-7i. The conjugate of 7i7i is 7i-7i.

Flashcard 11: Express 2i-2i as a complex number in standard form.

Answer: 02i0 - 2i. Pure imaginary numbers have real part 0.

Flashcard 12: What is the point in the complex plane corresponding to 2+5i-2+5i?

Answer: (2,5)(-2,5). Plot as (real part,imaginary part)(\text{real part}, \text{imaginary part}).

Flashcard 13: What is 50\sqrt{-50} written in simplest form using ii?

Answer: 52i5\sqrt{2}\,i. 50=252i=52i\sqrt{-50} = \sqrt{25 \cdot 2} \cdot i = 5\sqrt{2}i.

Flashcard 14: What is the result of (2+3i)2(2 + 3i)^2?

Answer: 5+12i-5 + 12i. Expand: 4+12i+9i2=4+12i9=5+12i4 + 12i + 9i^2 = 4 + 12i - 9 = -5 + 12i.

Flashcard 15: What is the inverse of the complex number 1+i1 + i in standard form?

Answer: 1212i\frac{1}{2} - \frac{1}{2}i. Multiply by conjugate: 1+i(1+i)(1i)=1i2\frac{1+i}{(1+i)(1-i)} = \frac{1-i}{2}.

Flashcard 16: Add the complex numbers 7+2i7 + 2i and 43i-4 - 3i.

Answer: 3i3 - i. Add real parts and imaginary parts separately.

Flashcard 17: Identify the real part of the complex number 7+3i7 + 3i.

Answer:

  1. The real part is the term without ii.

Flashcard 18: What is the complex conjugate of 6+2i6 + 2i?

Answer: 62i6 - 2i. Change the sign of the imaginary part to get the conjugate.

Flashcard 19: What is the result of (2+3i)2(2 + 3i)^2?

Answer: 5+12i-5 + 12i. Expand: 4+12i+9i2=4+12i9=5+12i4 + 12i + 9i^2 = 4 + 12i - 9 = -5 + 12i.

Flashcard 20: What is z1+z2\overline{z_1+z_2} in terms of z1\overline{z_1} and z2\overline{z_2}?

Answer: z1+z2\overline{z_1}+\overline{z_2}. Conjugate of sum equals sum of conjugates.

Flashcard 21: What is i3i^3 equal to?

Answer: i-i. i3=i2i=(1)(i)=ii^3 = i^2 \cdot i = (-1)(i) = -i.

Flashcard 22: What is i2i^2 equal to?

Answer: 1-1. Since i=1i = \sqrt{-1}, squaring gives 1-1.

Flashcard 23: Simplify the expression (2i)3(2i)^3.

Answer: 8i-8i. Evaluate: (2i)3=8i3=8(i)=8i(2i)^3 = 8i^3 = 8(-i) = -8i.

Flashcard 24: What is the difference between 7+5i7 + 5i and 4+2i4 + 2i?

Answer: 3+3i3 + 3i. Subtract real and imaginary parts: (74)+(52)i(7-4) + (5-2)i.

Flashcard 25: Identify the imaginary part of the complex number 54i5 - 4i.

Answer: -4. The imaginary part is the coefficient of ii (without the ii).

Flashcard 26: If z=43iz = 4 - 3i, what is zz^*?

Answer: 4+3i4 + 3i. The conjugate of 43i4 - 3i is 4+3i4 + 3i.

Flashcard 27: What is i4i^4 equal to?

Answer: 11. i4=(i2)2=(1)2=1i^4 = (i^2)^2 = (-1)^2 = 1.

Flashcard 28: What is i4i^4 equal to?

Answer: 11. i4=(i2)2=(1)2=1i^4 = (i^2)^2 = (-1)^2 = 1.

Flashcard 29: What is i2i^2 equal to?

Answer: -1. By definition, i2=1i^2 = -1.

Flashcard 30: Find the sum of 3+5i-3 + 5i and 47i4 - 7i.

Answer: 12i1 - 2i. Add real parts and imaginary parts separately.

Flashcard 31: What is the cycle of powers ini^n in terms of nmod4n\bmod 4?

Answer: n0:1, 1:i, 2:1, 3:in\equiv^0:1,\ 1:i,\ 2:-1,\ 3:-i. Powers of ii repeat every 4 terms: 1,i,1,i1, i, -1, -i.

Flashcard 32: What is the conjugate of 7+9i-7+9i?

Answer: 79i-7-9i. Negate the imaginary part to find conjugate.

Flashcard 33: What is the result of (3+2i)2(-3 + 2i)^2?

Answer: 512i5 - 12i. Expand: 912i+4i2=912i4=512i9 - 12i + 4i^2 = 9 - 12i - 4 = 5 - 12i.

Flashcard 34: What is i7i^7 in terms of ii?

Answer: i-i. Use i7=i4i3=1(i)=ii^7 = i^4 \cdot i^3 = 1 \cdot (-i) = -i.

Flashcard 35: What is 34i|3-4i|?

Answer: 55. 34i=32+(4)2=25=5|3-4i| = \sqrt{3^2+(-4)^2} = \sqrt{25} = 5.

Flashcard 36: Calculate the product of ii and 4i4i.

Answer: -4. Since i4i=4i2=4(1)=4i \cdot 4i = 4i^2 = 4(-1) = -4.

Flashcard 37: Identify the real part of the complex number 7+3i7 + 3i.

Answer:

  1. The real part is the term without ii.

Flashcard 38: Calculate (1i)2(1 - i)^2.

Answer: 02i0 - 2i. (1i)2=12i+i2=12i1=2i(1-i)^2 = 1 - 2i + i^2 = 1 - 2i - 1 = -2i.

Flashcard 39: What is the standard form of a complex number?

Answer: a+bia + bi where a,ba, b are real numbers. This is the general form where aa is real part and bb is imaginary coefficient.

Flashcard 40: What is the imaginary unit ii defined as?

Answer: i=1i=\sqrt{-1}. The fundamental definition of the imaginary unit.

Flashcard 41: What is the complex number corresponding to the point (4,6)(4,-6)?

Answer: 46i4-6i. Convert point (x,y)(x,y) to x+yix+yi.

Flashcard 42: Find the modulus of the complex number 4+3i4 + 3i.

Answer:

  1. Use a+bi=a2+b2=16+9=5|a + bi| = \sqrt{a^2 + b^2} = \sqrt{16 + 9} = 5.

Flashcard 43: What is the modulus of 68i6 - 8i?

Answer: Modulus=10\text{Modulus} = 10. Use z=a2+b2=36+64=10|z| = \sqrt{a^2 + b^2} = \sqrt{36 + 64} = 10.

Flashcard 44: Find the imaginary part of 57i5 - 7i.

Answer: 7-7. The imaginary part is the coefficient of ii.

Flashcard 45: What is the standard form of a complex number?

Answer: a+bia+bi. Where aa is real and bb is the coefficient of ii.

Flashcard 46: What is 2i1+2i\frac{2-i}{1+2i} in standard form?

Answer: 1545i-\frac{1}{5}-\frac{4}{5}i. Multiply by conjugate: (2i)(12i)(1+2i)(12i)=4i5\frac{(2-i)(1-2i)}{(1+2i)(1-2i)} = \frac{-4i}{5}.

Flashcard 47: What is the distance between 00 and a+bia+bi in the complex plane?

Answer: a2+b2\sqrt{a^2+b^2}. Same as the modulus formula.

Flashcard 48: What is (52i)(1+3i)(5-2i)(1+3i) in standard form?

Answer: 11+13i11+13i. (52i)(1+3i)=5+15i2i6i2=5+13i+6(5-2i)(1+3i) = 5+15i-2i-6i^2 = 5+13i+6.

Flashcard 49: Find the real part of the complex number 9+4i9 + 4i.

Answer: 99. The real part is the coefficient of the non-imaginary term.

Flashcard 50: What is (3+2i)+(45i)(3+2i)+(4-5i) in standard form?

Answer: 73i7-3i. Add real parts: 3+4=73+4=7, imaginary: 2+(5)=32+(-5)=-3.

Flashcard 51: What is i22i^{22} equal to?

Answer: 1-1. 22=45+222 = 4 \cdot 5 + 2, so i22=i2=1i^{22} = i^2 = -1.

Flashcard 52: Calculate the modulus of 512i-5 - 12i.

Answer: 1313. Use z=25+144=169=13|z| = \sqrt{25 + 144} = \sqrt{169} = 13.

Flashcard 53: What is (1+i)2(1+i)^2 in standard form?

Answer: 2i2i. (1+i)2=1+2i+i2=1+2i1=2i(1+i)^2 = 1+2i+i^2 = 1+2i-1 = 2i.

Flashcard 54: What is the complex number corresponding to the point (4,6)(4,-6)?

Answer: 46i4-6i. Convert point (x,y)(x,y) to x+yix+yi.

Flashcard 55: What is the result of multiplying (3+2i)(32i)(3 + 2i)(3 - 2i)?

Answer:

  1. Multiplying conjugates gives a2+b2=9+4=13a^2 + b^2 = 9 + 4 = 13.

Flashcard 56: Find the magnitude of the complex number 34i-3 - 4i.

Answer:

  1. Magnitude is (3)2+(4)2=25=5\sqrt{(-3)^2 + (-4)^2} = \sqrt{25} = 5.

Flashcard 57: What is the imaginary part of a+bia+bi?

Answer: Im(a+bi)=b\operatorname{Im}(a+bi)=b. The coefficient of the imaginary unit ii.

Flashcard 58: What is the condition for two complex numbers a+bia+bi and c+dic+di to be equal?

Answer: a=ca=c and b=db=d. Real and imaginary parts must match separately.

Flashcard 59: Identify the modulus of 0+7i0 + 7i.

Answer: 77. For pure imaginary bibi, modulus is b|b|.

Flashcard 60: What is the difference between 7+5i7 + 5i and 4+2i4 + 2i?

Answer: 3+3i3 + 3i. Subtract real and imaginary parts: (74)+(52)i(7-4) + (5-2)i.

Flashcard 61: Identify the imaginary part of the complex number 54i5 - 4i.

Answer: -4. The imaginary part is the coefficient of ii (without the ii).

Flashcard 62: What is the distance between 00 and a+bia+bi in the complex plane?

Answer: a2+b2\sqrt{a^2+b^2}. Same as the modulus formula.

Flashcard 63: Find the real part of the complex number 9+4i9 + 4i.

Answer: 99. The real part is the coefficient of the non-imaginary term.

Flashcard 64: What is the square of the complex number 1+i1 + i?

Answer: 2i. (1+i)2=1+2i+i2=1+2i1=2i(1+i)^2 = 1 + 2i + i^2 = 1 + 2i - 1 = 2i.

Flashcard 65: What is (52i)(1+3i)(5-2i)(1+3i) in standard form?

Answer: 11+13i11+13i. (52i)(1+3i)=5+15i2i6i2=5+13i+6(5-2i)(1+3i) = 5+15i-2i-6i^2 = 5+13i+6.

Flashcard 66: What is the rule for adding complex numbers (a+bi)+(c+di)(a+bi)+(c+di)?

Answer: (a+c)+(b+d)i(a+c)+(b+d)i. Add real parts and imaginary parts separately.

Flashcard 67: Express 2i-2i as a complex number in standard form.

Answer: 02i0 - 2i. Pure imaginary numbers have real part 0.

Flashcard 68: Find the imaginary part of 57i5 - 7i.

Answer: 7-7. The imaginary part is the coefficient of ii.

Flashcard 69: Find the magnitude of the complex number 34i-3 - 4i.

Answer:

  1. Magnitude is (3)2+(4)2=25=5\sqrt{(-3)^2 + (-4)^2} = \sqrt{25} = 5.

Flashcard 70: What is the complex conjugate of a+bia+bi?

Answer: abia-bi. Change the sign of the imaginary part.

Flashcard 71: Subtract 23i2 - 3i from 4+i4 + i.

Answer: 2+4i2 + 4i. Subtract real parts and imaginary parts separately.

Flashcard 72: State the complex conjugate of 75i7 - 5i.

Answer: 7+5i7 + 5i. Change the sign of the imaginary part.

Flashcard 73: What is (3+2i)+(45i)(3+2i)+(4-5i) in standard form?

Answer: 73i7-3i. Add real parts: 3+4=73+4=7, imaginary: 2+(5)=32+(-5)=-3.

Flashcard 74: Express i2i^2 in terms of real numbers.

Answer: i2=1i^2 = -1. By definition, i2=1i^2 = -1 since i=1i = \sqrt{-1}.

Flashcard 75: What is i3i^3 in terms of ii?

Answer: i-i. Use i3=i2i=1i=ii^3 = i^2 \cdot i = -1 \cdot i = -i.

Flashcard 76: What is z1z2\overline{\frac{z_1}{z_2}} in terms of z1\overline{z_1} and z2\overline{z_2}?

Answer: z1z2\frac{\overline{z_1}}{\overline{z_2}}. Conjugate of quotient equals quotient of conjugates.

Flashcard 77: What is 9\sqrt{-9} written using ii?

Answer: 3i3i. 9=91=3i\sqrt{-9} = \sqrt{9} \cdot \sqrt{-1} = 3i.

Flashcard 78: What is 9\sqrt{-9} written using ii?

Answer: 3i3i. 9=91=3i\sqrt{-9} = \sqrt{9} \cdot \sqrt{-1} = 3i.

Flashcard 79: Multiply the complex numbers 1+i1 + i and 1i1 - i.

Answer: 22. Use (1+i)(1i)=1i2=1(1)=2(1+i)(1-i) = 1 - i^2 = 1 - (-1) = 2.

Flashcard 80: What is the rule for subtracting complex numbers (a+bi)(c+di)(a+bi)-(c+di)?

Answer: (ac)+(bd)i(a-c)+(b-d)i. Subtract real parts and imaginary parts separately.

Flashcard 81: What is 34i|3-4i|?

Answer: 55. 34i=32+(4)2=25=5|3-4i| = \sqrt{3^2+(-4)^2} = \sqrt{25} = 5.

Flashcard 82: Determine the modulus of 3+4i3 + 4i.

Answer: 55. Use z=32+42=9+16=5|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = 5.

Flashcard 83: What is the complex conjugate of 0+6i0 + 6i?

Answer: 06i0 - 6i. Change the sign of the imaginary part.

Flashcard 84: What is the real part of (83i)(8-3i)?

Answer: 88. The real part is the coefficient without ii.

Flashcard 85: What is the complex conjugate of 6+2i6 + 2i?

Answer: 62i6 - 2i. Change the sign of the imaginary part to get the conjugate.

Flashcard 86: If z=2+3iz = 2 + 3i, what is Re(zˉ)\text{Re}(\bar{z})?

Answer: 22. The real part of zˉ=23i\bar{z} = 2 - 3i is 2.

Flashcard 87: What is the result of subtracting 6+i6 + i from 23i2 - 3i?

Answer: 44i-4 - 4i. Subtract: (23i)(6+i)=44i(2 - 3i) - (6 + i) = -4 - 4i.

Flashcard 88: What is the point in the complex plane corresponding to 2+5i-2+5i?

Answer: (2,5)(-2,5). Plot as (real part,imaginary part)(\text{real part}, \text{imaginary part}).

Flashcard 89: What is the result of subtracting 6+i6 + i from 23i2 - 3i?

Answer: 44i-4 - 4i. Subtract: (23i)(6+i)=44i(2 - 3i) - (6 + i) = -4 - 4i.

Flashcard 90: What is the result of i3i^3?

Answer: -i. Since i3=i2i=(1)i=ii^3 = i^2 \cdot i = (-1) \cdot i = -i.

Flashcard 91: What is (67i)(2+3i)(6-7i)-(2+3i) in standard form?

Answer: 410i4-10i. Subtract real: 62=46-2=4, imaginary: 73=10-7-3=-10.

Flashcard 92: What is the cycle of powers ini^n in terms of nmod4n\bmod 4?

Answer: n0:1, 1:i, 2:1, 3:in\equiv^0:1,\ 1:i,\ 2:-1,\ 3:-i. Powers of ii repeat every 4 terms: 1,i,1,i1, i, -1, -i.

Flashcard 93: What is i0i^0?

Answer: 11. Any number to the power of 0 equals 1.

Flashcard 94: Express i5i^5 in terms of ii.

Answer: ii. Use i5=i4i=1i=ii^5 = i^4 \cdot i = 1 \cdot i = i.

Flashcard 95: What is zzz-\overline{z} for z=a+biz=a+bi?

Answer: 2bi2bi. (a+bi)(abi)=2bi(a+bi)-(a-bi) = 2bi.

Flashcard 96: What is i4i^4 in terms of real numbers?

Answer: 11. Powers of ii cycle every 4: i4=(i2)2=(1)2=1i^4 = (i^2)^2 = (-1)^2 = 1.

Flashcard 97: What is i3i^3 in terms of ii?

Answer: i-i. Use i3=i2i=1i=ii^3 = i^2 \cdot i = -1 \cdot i = -i.

Flashcard 98: What is (2+i)(34i)(2+i)(3-4i) in standard form?

Answer: 105i10-5i. (2+i)(34i)=68i+3i4i2=65i+4=105i(2+i)(3-4i) = 6-8i+3i-4i^2 = 6-5i+4 = 10-5i.

Flashcard 99: What is the rule for adding complex numbers (a+bi)+(c+di)(a+bi)+(c+di)?

Answer: (a+c)+(b+d)i(a+c)+(b+d)i. Add real parts and imaginary parts separately.

Flashcard 100: What is 1a+bi\frac{1}{a+bi} in standard form (with a,bRa,b\in\mathbb{R})?

Answer: abia2+b2\frac{a-bi}{a^2+b^2}. Multiply by conjugate: 1a+biabiabi\frac{1}{a+bi} \cdot \frac{a-bi}{a-bi}.