ACT Math Flashcards: Function Definitions And Notation

Study Function Definitions And Notation in ACT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

ACT Math

Function Definitions And Notation

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QUESTION
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Identify the function that is constant for all inputs.

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ANSWER

f(x)=cf(x) = c, where cc is a constant. A constant function outputs the same value regardless of input.

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What this deck covers

This deck focuses on Function Definitions And Notation, giving you a quick way to review the definitions, rules, and examples that matter most for ACT Math.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: Identify the function that is constant for all inputs.

Answer: f(x)=cf(x) = c, where cc is a constant. A constant function outputs the same value regardless of input.

Flashcard 2: For f(x)=xx+1f(x) = \frac{x}{x+1}, what is the vertical asymptote?

Answer: Vertical asymptote is x=1x = -1. Vertical asymptotes occur where the denominator equals zero.

Flashcard 3: Simplify f(x+1)f(x+1) if f(x)=x2f(x)=x^2.

Answer: f(x+1)=(x+1)2f(x+1)=(x+1)^2. Replace xx with (x+1)(x+1) in the function: f(x+1)=(x+1)2f(x+1)=(x+1)^2.

Flashcard 4: What is the x-intercept condition for y=f(x)y=f(x) in function notation?

Answer: An x-intercept occurs where f(x)=0f(x)=0. Solve for values where the function equals zero to find x-axis intersections.

Flashcard 5: What does the notation xdomain(f)x\in\text{domain}(f) mean?

Answer: xx is an allowable input for ff. The symbol \in means 'is an element of' or 'belongs to' the domain set.

Flashcard 6: What is f(0)f(0) for f(x)=3x32xf(x) = 3x^3 - 2x?

Answer: f(0)=0f(0) = 0. Substitute x=0x = 0: 3(0)32(0)=03(0)^3 - 2(0) = 0.

Flashcard 7: What does the notation f1(x)f^{-1}(x) represent when it exists?

Answer: The inverse function of ff. The inverse function reverses the input-output relationship of the original function.

Flashcard 8: What is f(0)f(0) for f(x)=5x7f(x) = 5x - 7?

Answer: f(0)=7f(0) = -7. Substitute x=0x = 0: 5(0)7=75(0) - 7 = -7.

Flashcard 9: For f(x)=x3xf(x) = x^3 - x, find f(2)f(-2).

Answer: f(2)=6f(-2) = -6. Substitute x=2x = -2: (2)3(2)=8+2=6(-2)^3 - (-2) = -8 + 2 = -6.

Flashcard 10: What does the notation f(x)f(a)f(x)-f(a) represent?

Answer: The difference between outputs at inputs xx and aa. This calculates the change in function values between two different input points.

Flashcard 11: If f(x)=2x+1f(x)=2x+1 and g(x)=x2g(x)=x^2, find (fg)(x)(f\circ g)(x).

Answer: (fg)(x)=2x2+1(f\circ g)(x)=2x^2+1. Substitute g(x)=x2g(x)=x^2 into ff: f(g(x))=f(x2)=2(x2)+1=2x2+1f(g(x))=f(x^2)=2(x^2)+1=2x^2+1.

Flashcard 12: For f(x)=1xf(x) = \frac{1}{x}, what is f(3)f(3)?

Answer: f(3)=13f(3) = \frac{1}{3}. Substitute x=3x = 3 into the reciprocal function.

Flashcard 13: Define the zero of a function f(x)f(x).

Answer: Value of xx where f(x)=0f(x) = 0. A zero is an x-value that makes the function equal to zero.

Flashcard 14: Define the range of the function f(x)=x2f(x) = x^2.

Answer: Non-negative real numbers. Squaring any real number produces a non-negative result.

Flashcard 15: If f(x)=3xf(x)=3-x and g(x)=x2g(x)=x^2, find (gf)(x)(g\circ f)(x).

Answer: (gf)(x)=(3x)2(g\circ f)(x)=(3-x)^2. Substitute f(x)=3xf(x)=3-x into gg: g(f(x))=g(3x)=(3x)2g(f(x))=g(3-x)=(3-x)^2.

Flashcard 16: If f(x)=x+12f(x)=\frac{x+1}{2}, what is f1(x)f^{-1}(x)?

Answer: f1(x)=2x1f^{-1}(x)=2x-1. Swap xx and yy, then solve for yy: x=y+12x=\frac{y+1}{2} gives y=2x1y=2x-1.

Flashcard 17: Find f(a)f(a) if f(x)=3x22xf(x)=3x^2-2x.

Answer: f(a)=3a22af(a)=3a^2-2a. Replace every occurrence of xx with aa in the function expression.

Flashcard 18: For f(x)=1x1f(x) = \frac{1}{x-1}, what is the domain?

Answer: All real numbers except x=1x = 1. Division by zero occurs when x=1x = 1.

Flashcard 19: Define the range of the function f(x)=x2f(x) = x^2.

Answer: Non-negative real numbers. Squaring any real number produces a non-negative result.

Flashcard 20: Identify the range of f(x)=1xf(x) = \frac{1}{x}.

Answer: All real numbers except 00. The reciprocal function cannot equal zero for any real input.

Flashcard 21: What does the notation f(x)f(x) represent in a function?

Answer: f(x)f(x) is the output value of ff when the input is xx. This defines function notation where ff is the function name and xx is the input variable.

Flashcard 22: What does the notation f(x)+g(x)f(x)+g(x) mean?

Answer: A new function whose output is f(x)+g(x)f(x)+g(x). Function addition creates a new function by adding corresponding outputs pointwise.

Flashcard 23: Evaluate f(2)f(-2) if f(x)=x2+4f(x)=x^2+4.

Answer: f(2)=8f(-2)=8. Substitute x=2x=-2: f(2)=(2)2+4=4+4=8f(-2)=(-2)^2+4=4+4=8.

Flashcard 24: What is the range of a function, in words?

Answer: The set of all possible output values. Range consists of all yy-values that the function can actually produce as outputs.

Flashcard 25: What is the correct interpretation of f1(x)f^{-1}(x) (not a power)?

Answer: f1(x)f^{-1}(x) is the inverse function, not 1f(x)\frac{1}{f(x)}. The superscript 1-1 denotes inverse function, not reciprocal or negative exponent.

Flashcard 26: What is the domain of a function, in words?

Answer: The set of all allowable input values. Domain consists of all xx-values where the function is defined and produces real outputs.

Flashcard 27: What is the domain of f(x)=1x24f(x) = \frac{1}{x^2 - 4}?

Answer: All real numbers except x=±2x = \text{±}2. Denominator equals zero when x2=4x^2 = 4, so x=±2x = ±2.

Flashcard 28: What is f(3)f(-3) for f(x)=2x+1f(x) = 2x + 1?

Answer: f(3)=5f(-3) = -5. Substitute x=3x = -3: 2(3)+1=6+1=52(-3) + 1 = -6 + 1 = -5.

Flashcard 29: What does the notation f(x)f(a)f(x)-f(a) represent?

Answer: The difference between outputs at inputs xx and aa. This calculates the change in function values between two different input points.

Flashcard 30: What is the defining relationship between a function and its inverse?

Answer: f(f1(x))=xf(f^{-1}(x))=x and f1(f(x))=xf^{-1}(f(x))=x. These compositions demonstrate that inverse functions undo each other's operations.

Flashcard 31: What is the meaning of the equation f(x)=0f(x)=0?

Answer: The input values xx for which the output equals 00. These are the zeros or roots of the function, where the graph crosses the x-axis.

Flashcard 32: What does the notation f(2)=7f(2) = 7 indicate?

Answer: The output is 77 when input is 22. Function notation shows the input-output relationship.

Flashcard 33: What is the domain of a function, in words?

Answer: The set of all allowable input values. Domain consists of all xx-values where the function is defined and produces real outputs.

Flashcard 34: What is the meaning of the equation f(x)=0f(x)=0?

Answer: The input values xx for which the output equals 00. These are the zeros or roots of the function, where the graph crosses the x-axis.

Flashcard 35: If f(x)=x2f(x)=x^2 and g(x)=x1g(x)=x-1, find (gf)(2)(g\circ f)(2).

Answer: (gf)(2)=3(g\circ f)(2)=3. First find f(2)=4f(2)=4, then g(4)=41=3g(4)=4-1=3.

Flashcard 36: For f(x)=x2f(x) = x^2, what is the vertex of the parabola?

Answer: Vertex is (0,0)(0, 0). The vertex of x2x^2 occurs at the origin where the derivative is zero.

Flashcard 37: What is the y-intercept of a function y=f(x)y=f(x) in function notation?

Answer: The y-intercept is f(0)f(0). Set x=0x=0 and evaluate the function to find where the graph crosses the y-axis.

Flashcard 38: What is the standard meaning of the statement y=f(x)y=f(x)?

Answer: yy equals the output of function ff for input xx. This is the standard function equation format relating dependent and independent variables.

Flashcard 39: What does the notation yrange(f)y\in\text{range}(f) mean?

Answer: yy is a possible output value of ff. The symbol \in means the output value exists within the function's range set.

Flashcard 40: If f(x)=x2f(x) = x^2 and g(x)=2xg(x) = 2x, find (fg)(x)(f \, \text{∘} \, g)(x).

Answer: (fg)(x)=4x2(f \, \text{∘} \, g)(x) = 4x^2. First apply gg, then ff: f(g(x))=f(2x)=(2x)2=4x2f(g(x)) = f(2x) = (2x)^2 = 4x^2.

Flashcard 41: What does the notation f(2)=7f(2) = 7 indicate?

Answer: The output is 77 when input is 22. Function notation shows the input-output relationship.

Flashcard 42: What is the domain restriction for f(x)=x+5f(x)=\sqrt{x+5} (real numbers)?

Answer: Domain: x5x\ge -5. The radicand x+5x+5 must be non-negative for real square root values.

Flashcard 43: What does the notation xdomain(f)x\in\text{domain}(f) mean?

Answer: xx is an allowable input for ff. The symbol \in means 'is an element of' or 'belongs to' the domain set.

Flashcard 44: What does the notation f(x+h)f(x+h) indicate compared with f(x)f(x)?

Answer: The output when the input is shifted to x+hx+h. The input is horizontally shifted by hh units, affecting the function's evaluation point.

Flashcard 45: What is the defining relationship between a function and its inverse?

Answer: f(f1(x))=xf(f^{-1}(x))=x and f1(f(x))=xf^{-1}(f(x))=x. These compositions demonstrate that inverse functions undo each other's operations.

Flashcard 46: Find xx if f(x)=x29f(x)=x^2-9 and f(x)=0f(x)=0.

Answer: x=3x=3 or x=3x=-3. Set x29=0x^2-9=0, so x2=9x^2=9, giving x=±3x=\pm 3.

Flashcard 47: What does it mean if f(a)f(b)f(a)\neq f(b)?

Answer: Inputs aa and bb produce different outputs. This indicates the function produces distinct outputs for these different inputs.

Flashcard 48: What is f(1)f(1) for f(x)=3x+5f(x) = 3x + 5?

Answer: f(1)=8f(1) = 8. Substitute x=1x = 1: 3(1)+5=83(1) + 5 = 8.

Flashcard 49: If f(x)=x+12f(x)=\frac{x+1}{2}, what is f1(x)f^{-1}(x)?

Answer: f1(x)=2x1f^{-1}(x)=2x-1. Swap xx and yy, then solve for yy: x=y+12x=\frac{y+1}{2} gives y=2x1y=2x-1.

Flashcard 50: Evaluate f(0)f(0) if f(x)=x1x+2f(x)=\frac{x-1}{x+2}.

Answer: f(0)=12f(0)=-\frac{1}{2}. Substitute x=0x=0: f(0)=010+2=12=12f(0)=\frac{0-1}{0+2}=\frac{-1}{2}=-\frac{1}{2}.

Flashcard 51: If f(x)=3xf(x)=3-x and g(x)=x2g(x)=x^2, find (gf)(x)(g\circ f)(x).

Answer: (gf)(x)=(3x)2(g\circ f)(x)=(3-x)^2. Substitute f(x)=3xf(x)=3-x into gg: g(f(x))=g(3x)=(3x)2g(f(x))=g(3-x)=(3-x)^2.

Flashcard 52: What is f(3)f(3) if f(x)=x24x+4f(x) = x^2 - 4x + 4?

Answer: f(3)=1f(3) = 1. Substitute x=3x = 3: (3)24(3)+4=912+4=1(3)^2 - 4(3) + 4 = 9 - 12 + 4 = 1.

Flashcard 53: What does the notation yrange(f)y\in\text{range}(f) mean?

Answer: yy is a possible output value of ff. The symbol \in means the output value exists within the function's range set.

Flashcard 54: For f(x)=3x+2f(x) = 3x + 2, what is f(4)f(4)?

Answer: f(4)=14f(4) = 14. Substitute x=4x = 4 into the function: 3(4)+2=143(4) + 2 = 14.

Flashcard 55: What does it mean if f(a)f(b)f(a)\neq f(b)?

Answer: Inputs aa and bb produce different outputs. This indicates the function produces distinct outputs for these different inputs.

Flashcard 56: Evaluate f(0)f(0) if f(x)=x1x+2f(x)=\frac{x-1}{x+2}.

Answer: f(0)=12f(0)=-\frac{1}{2}. Substitute x=0x=0: f(0)=010+2=12=12f(0)=\frac{0-1}{0+2}=\frac{-1}{2}=-\frac{1}{2}.

Flashcard 57: Simplify f(x)f(1)f(x)-f(1) if f(x)=x2+2xf(x)=x^2+2x.

Answer: f(x)f(1)=x2+2x3f(x)-f(1)=x^2+2x-3. Calculate f(x)=(x2+2x)f(x)=(x^2+2x) and f(1)=3f(1)=3, so the difference is x2+2x3x^2+2x-3.

Flashcard 58: What does f(a)f(a) represent if f(x)f(x) is a function?

Answer: Value of f(x)f(x) at x=ax = a. Function notation indicates the output when input is aa.

Flashcard 59: What is the slope of f(x)=7x4f(x) = 7x - 4?

Answer: Slope is 77. Linear functions have the form mx+bmx + b where mm is the slope.

Flashcard 60: Evaluate f(3)f(3) if f(x)=2x5f(x)=2x-5.

Answer: f(3)=1f(3)=1. Substitute x=3x=3: f(3)=2(3)5=65=1f(3)=2(3)-5=6-5=1.

Flashcard 61: Identify the notation for the reciprocal of a function output.

Answer: 1f(x)\frac{1}{f(x)}. This represents one divided by the function output, the multiplicative inverse.

Flashcard 62: Simplify f(x)f(1)f(x)-f(1) if f(x)=x2+2xf(x)=x^2+2x.

Answer: f(x)f(1)=x2+2x3f(x)-f(1)=x^2+2x-3. Calculate f(x)=(x2+2x)f(x)=(x^2+2x) and f(1)=3f(1)=3, so the difference is x2+2x3x^2+2x-3.

Flashcard 63: What does the notation f(x)|f(x)| mean?

Answer: The absolute value of the output f(x)f(x). Takes the absolute value of whatever the function outputs for input xx.

Flashcard 64: What does the notation (fg)(x)(f\circ g)(x) mean?

Answer: (fg)(x)=f(g(x))(f\circ g)(x)=f(g(x)). Composition means applying gg first, then applying ff to that result.

Flashcard 65: Find the y-intercept of f(x)=x2+3x+2f(x) = x^2 + 3x + 2.

Answer: The point (0,2)(0, 2). Set x=0x = 0 to find where the graph crosses the y-axis.

Flashcard 66: For f(x)=1x1f(x) = \frac{1}{x-1}, what is the domain?

Answer: All real numbers except x=1x = 1. Division by zero occurs when x=1x = 1.

Flashcard 67: What is f(0)f(0) for f(x)=3x32xf(x) = 3x^3 - 2x?

Answer: f(0)=0f(0) = 0. Substitute x=0x = 0: 3(0)32(0)=03(0)^3 - 2(0) = 0.

Flashcard 68: Find the inverse of f(x)=2x+3f(x) = 2x + 3.

Answer: f1(x)=x32f^{-1}(x) = \frac{x-3}{2}. Solve y=2x+3y = 2x + 3 for xx, then swap variables.

Flashcard 69: What is the range of f(x)=abs(x)f(x) = \text{abs}(x)?

Answer: Non-negative real numbers. Absolute value function always produces non-negative outputs.

Flashcard 70: Find f(2)f(2) if f(x)=2x23x+1f(x) = 2x^2 - 3x + 1.

Answer: f(2)=3f(2) = 3. Substitute x=2x = 2: 2(4)3(2)+1=86+1=32(4) - 3(2) + 1 = 8 - 6 + 1 = 3.

Flashcard 71: What is the value of f(5)f(-5) if f(x)=x+6f(x) = -x + 6?

Answer: f(5)=11f(-5) = 11. Substitute x=5x = -5: (5)+6=5+6=11-(-5) + 6 = 5 + 6 = 11.

Flashcard 72: What is the notation for the composition of ff and gg?

Answer: (fg)(x)(f \, \text{∘} \, g)(x). This symbol represents function composition, where one function is applied to another.

Flashcard 73: What is the notation for the composition of ff and gg?

Answer: (fg)(x)(f \, \text{∘} \, g)(x). This symbol represents function composition, where one function is applied to another.

Flashcard 74: What does the notation f(x)=xf(x)=\sqrt{x} imply about the domain (real numbers)?

Answer: Domain: x0x\ge 0. Square root requires non-negative inputs to produce real number outputs.

Flashcard 75: Express f(x)=x2+2x+1f(x) = x^2 + 2x + 1 in vertex form.

Answer: f(x)=(x+1)2f(x) = (x+1)^2. Factor the perfect square trinomial to vertex form.

Flashcard 76: What does the notation f(x)f(x) represent in a function?

Answer: f(x)f(x) is the output value of ff when the input is xx. This defines function notation where ff is the function name and xx is the input variable.

Flashcard 77: Identify the range of f(x)=1xf(x) = \frac{1}{x}.

Answer: All real numbers except 00. The reciprocal function cannot equal zero for any real input.

Flashcard 78: If f(x)=x5f(x)=x-5, what is f1(x)f^{-1}(x)?

Answer: f1(x)=x+5f^{-1}(x)=x+5. For linear functions, the inverse reverses the operation: subtract becomes add.

Flashcard 79: What is f(3)f(3) if f(x)=x24x+4f(x) = x^2 - 4x + 4?

Answer: f(3)=1f(3) = 1. Substitute x=3x = 3: (3)24(3)+4=912+4=1(3)^2 - 4(3) + 4 = 9 - 12 + 4 = 1.

Flashcard 80: For f(x)=xx+1f(x) = \frac{x}{x+1}, what is the vertical asymptote?

Answer: Vertical asymptote is x=1x = -1. Vertical asymptotes occur where the denominator equals zero.

Flashcard 81: Simplify f(2x)f(2x) if f(x)=x23f(x)=x^2-3.

Answer: f(2x)=4x23f(2x)=4x^2-3. Replace xx with 2x2x: f(2x)=(2x)23=4x23f(2x)=(2x)^2-3=4x^2-3.

Flashcard 82: Find f(2)f(2) if f(x)=2x23x+1f(x) = 2x^2 - 3x + 1.

Answer: f(2)=3f(2) = 3. Substitute x=2x = 2: 2(4)3(2)+1=86+1=32(4) - 3(2) + 1 = 8 - 6 + 1 = 3.

Flashcard 83: Simplify f(x)=x21x1f(x) = \frac{x^2 - 1}{x - 1}.

Answer: f(x)=x+1f(x) = x + 1, x1x \neq 1. Factor and cancel, but note the domain restriction.

Flashcard 84: What is the slope of f(x)=7x4f(x) = 7x - 4?

Answer: Slope is 77. Linear functions have the form mx+bmx + b where mm is the slope.

Flashcard 85: If f(x)=x+4f(x)=x+4 and g(x)=2xg(x)=2x, find (fg)(3)(f\circ g)(3).

Answer: (fg)(3)=10(f\circ g)(3)=10. First find g(3)=6g(3)=6, then f(6)=6+4=10f(6)=6+4=10.

Flashcard 86: Find f(x+1)f(x+1) for f(x)=x2xf(x) = x^2 - x.

Answer: f(x+1)=x2+xf(x+1) = x^2 + x. Replace xx with x+1x+1 in the function: (x+1)2(x+1)(x+1)^2 - (x+1).

Flashcard 87: What is the notation for the absolute value of xx?

Answer: x|x|. Vertical bars around a variable indicate absolute value.

Flashcard 88: What does the notation f1(x)f^{-1}(x) represent when it exists?

Answer: The inverse function of ff. The inverse function reverses the input-output relationship of the original function.

Flashcard 89: What does it mean if f(a)=f(b)f(a)=f(b)?

Answer: Inputs aa and bb produce the same output. Different inputs can map to the same output value in many-to-one relationships.

Flashcard 90: What is f(3)f(-3) for f(x)=2x+1f(x) = 2x + 1?

Answer: f(3)=5f(-3) = -5. Substitute x=3x = -3: 2(3)+1=6+1=52(-3) + 1 = -6 + 1 = -5.

Flashcard 91: What is the domain restriction for f(x)=x+5f(x)=\sqrt{x+5} (real numbers)?

Answer: Domain: x5x\ge -5. The radicand x+5x+5 must be non-negative for real square root values.

Flashcard 92: What is the domain of f(x)=1x24f(x) = \frac{1}{x^2 - 4}?

Answer: All real numbers except x=±2x = \text{±}2. Denominator equals zero when x2=4x^2 = 4, so x=±2x = ±2.

Flashcard 93: Find xx if f(x)=x29f(x)=x^2-9 and f(x)=0f(x)=0.

Answer: x=3x=3 or x=3x=-3. Set x29=0x^2-9=0, so x2=9x^2=9, giving x=±3x=\pm 3.

Flashcard 94: What is the domain restriction for f(x)=1x3f(x)=\frac{1}{x-3} (real numbers)?

Answer: Domain: x3x\ne 3. Set the denominator x30x-3\neq 0 to avoid division by zero.

Flashcard 95: What is the domain restriction for f(x)=1x3f(x)=\frac{1}{x-3} (real numbers)?

Answer: Domain: x3x\ne 3. Set the denominator x30x-3\neq 0 to avoid division by zero.

Flashcard 96: What is the correct interpretation of f1(x)f^{-1}(x) (not a power)?

Answer: f1(x)f^{-1}(x) is the inverse function, not 1f(x)\frac{1}{f(x)}. The superscript 1-1 denotes inverse function, not reciprocal or negative exponent.

Flashcard 97: Identify the notation for the reciprocal of a function output.

Answer: 1f(x)\frac{1}{f(x)}. This represents one divided by the function output, the multiplicative inverse.

Flashcard 98: Simplify f(x+1)f(x+1) if f(x)=x2f(x)=x^2.

Answer: f(x+1)=(x+1)2f(x+1)=(x+1)^2. Replace xx with (x+1)(x+1) in the function: f(x+1)=(x+1)2f(x+1)=(x+1)^2.

Flashcard 99: Find f(x+1)f(x+1) for f(x)=x2xf(x) = x^2 - x.

Answer: f(x+1)=x2+xf(x+1) = x^2 + x. Replace xx with x+1x+1 in the function: (x+1)2(x+1)(x+1)^2 - (x+1).

Flashcard 100: Evaluate f(2)f(-2) if f(x)=x2+4f(x)=x^2+4.

Answer: f(2)=8f(-2)=8. Substitute x=2x=-2: f(2)=(2)2+4=4+4=8f(-2)=(-2)^2+4=4+4=8.