Add and Subtract Within 100
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2nd Grade Math › Add and Subtract Within 100
Calculate $67 - 19$.
38
48
49
58
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: 47 + 28 → $7 + 8 = 15$, write 5 and carry 1 → $4 + 2 + 1 = 7$ → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: 63 - 27 → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → $13 - 7 = 6$, $5 - 2 = 3$ → answer is 36). Describe strategies: Place value strategy: Break numbers into tens and ones, add or subtract separately, combine ($47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75$). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, student must calculate $67 - 19$. To solve, can't do 7 - 9, so regroup 67 to 5 tens 17 ones, subtract $17 - 9 = 8$ and $5 - 1 = 4$, answer 48. Choice B is correct because subtracting $67 - 19$ correctly—regroup to 5 tens 17 ones, $17 - 9 = 8$, $5 - 1 = 4$, giving 48. This correctly applies subtraction with regrouping. Choice C represents a basic fact error ($17 - 9 = 9$ instead of 8, giving 49) or didn't regroup correctly. This error typically happens when students regroup incorrectly or make arithmetic mistakes. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones ($7 + 8 = 15$ ones = 1 ten + 5 ones), combine tens ($4 + 2 + 1 = 7$ tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
Use the number line to add $27 + 36$.
53
62
63
73
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: 47 + 28 → 7 + 8 = 15, write 5 and carry 1 → 4 + 2 + 1 = 7 → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: 63 - 27 → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → 13 - 7 = 6, 5 - 2 = 3 → answer is 36). Describe strategies: Place value strategy: Break numbers into tens and ones, add or subtract separately, combine (47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, use the number line to add 27 + 36. To solve, start at 27, jump 30 to 57, then 6 to 63, or add ones: 7 + 6 = 13 (write 3, carry 1), tens: 2 + 3 + 1 = 6, answer 63. Choice C is correct because adding 27 + 36 correctly—7 + 6 = 13 (write 3, carry 1), 2 + 3 + 1 = 6, giving 63. This correctly applies addition with regrouping using number line strategy. Choice D represents not carrying when regrouping in addition (7 + 6 = 13 but wrote 53 instead of carrying to get 63, or basic fact error 7 + 6 = 12, giving 62). This error typically happens when students forget to regroup or misjump on the number line. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones (7 + 8 = 15 ones = 1 ten + 5 ones), combine tens (4 + 2 + 1 = 7 tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
Calculate $90 - 48$.
38
42
48
52
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: 47 + 28 → 7 + 8 = 15, write 5 and carry 1 → 4 + 2 + 1 = 7 → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: 63 - 27 → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → 13 - 7 = 6, 5 - 2 = 3 → answer is 36). Place value strategy: Break numbers into tens and ones, add or subtract separately, combine (47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, the student must calculate 90 - 48. To solve, subtract with regrouping: can't do 0 - 8, so regroup 9 tens 0 ones to 8 tens 10 ones, 10 - 8 = 2, 8 - 4 = 4, answer 42, or use place value: 90 - 40 = 50, 50 - 8 = 42. Choice C is correct because subtracting 90 - 48 correctly—regroup to 8 tens 10 ones, 10 - 8 = 2, 8 - 4 = 4, giving 42. This correctly applies subtraction with regrouping. Choice A represents not regrouping or wrong borrow (perhaps 90 - 48 as 90 - 40 = 50, then 50 + 2 or miscalculated as 52). This error typically happens when students forget to regroup, regroup incorrectly, don't understand borrowing from zero, or make arithmetic mistakes. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones (7 + 8 = 15 ones = 1 ten + 5 ones), combine tens (4 + 2 + 1 = 7 tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
Add $24 + 35$. What is the total?
49
59
69
510
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: 47 + 28 → 7 + 8 = 15, write 5 and carry 1 → 4 + 2 + 1 = 7 → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: 63 - 27 → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → 13 - 7 = 6, 5 - 2 = 3 → answer is 36). Describe strategies: Place value strategy: Break numbers into tens and ones, add or subtract separately, combine (47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, the student must add 24 + 35 to find the total. To solve, add ones: 4 + 5 = 9 (no carry), add tens: 2 + 3 = 5, answer 59. Choice C is correct because adding 24 + 35 correctly—4 + 5 = 9, 2 + 3 = 5, giving 59. This correctly applies addition without regrouping. Choice A represents a specific error: carried unnecessarily (4 + 5 = 9 but perhaps thought it was 9 + carry to get 69). This error typically happens when students regroup incorrectly, make arithmetic mistakes, or confuse place values. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones (7 + 8 = 15 ones = 1 ten + 5 ones), combine tens (4 + 2 + 1 = 7 tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
Use place value to solve $46 + 27$.
63
72
73
83
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: 47 + 28 → 7 + 8 = 15, write 5 and carry 1 → 4 + 2 + 1 = 7 → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: 63 - 27 → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → 13 - 7 = 6, 5 - 2 = 3 → answer is 36). Describe strategies: Place value strategy: Break numbers into tens and ones, add or subtract separately, combine (47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, student must add 46 + 27 using place value. To solve, break into tens and ones: (40 + 20) + (6 + 7) = 60 + 13 = 73, or add ones: 6 + 7 = 13 (write 3, carry 1), add tens: 4 + 2 + 1 = 7, answer 73. Choice B is correct because adding 46 + 27 correctly—6 + 7 = 13 (write 3, carry 1), 4 + 2 + 1 = 7, giving 73. This correctly applies addition with regrouping. Choice D represents not carrying when regrouping in addition (6 + 7 = 13 but wrote 63 instead of carrying to get 73, or basic fact error 6 + 7 = 12, giving 72). This error typically happens when students forget to regroup or make arithmetic mistakes. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones (7 + 8 = 15 ones = 1 ten + 5 ones), combine tens (4 + 2 + 1 = 7 tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
There were 78 students. 26 went home. How many are left?
42
52
54
62
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: 47 + 28 → 7 + 8 = 15, write 5 and carry 1 → 4 + 2 + 1 = 7 → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: 63 - 27 → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → 13 - 7 = 6, 5 - 2 = 3 → answer is 36). Place value strategy: Break numbers into tens and ones, add or subtract separately, combine (47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, there were 78 students and 26 went home, a word problem requiring subtraction to find how many are left. To solve, subtract 78 - 26: ones 8 - 6 = 2 (no borrow needed), tens 7 - 2 = 5, answer 52, or use place value: 70 - 20 = 50, 8 - 6 = 2, total 52. Choice C is correct because subtracting 78 - 26 correctly—8 - 6 = 2, 7 - 2 = 5, giving 52, or in context: 78 total, 26 left, 52 remain. This correctly applies subtraction without regrouping to the word problem. Choice B represents a wrong operation (perhaps added 78 + 26 = 104 but that's not an option, or miscalculated as 62 by borrowing unnecessarily or arithmetic error). This error typically happens when students confuse operations (add instead of subtract), make arithmetic mistakes, or don't understand word problem keywords like 'left'. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones (7 + 8 = 15 ones = 1 ten + 5 ones), combine tens (4 + 2 + 1 = 7 tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
Ben scored $$38$$ points in his first game and $$27$$ points in his second game. Sarah scored $$19$$ more points than Ben's total. How many points did Sarah score?
$$84$$ points because she scored more than Ben's total
$$46$$ points because she scored more than Ben's first game
$$57$$ points because she scored more than Ben's second game
$$76$$ points because she scored more than Ben's total
Explanation
Ben's total points: 38 + 27 = 65. Sarah scored 19 more than Ben's total: 65 + 19 = 84 points. Choice B incorrectly calculates Sarah's score as 19 more than Ben's first game only: 38 + 19 = 57, but shows 46 due to calculation error. Choice C results from miscalculating Ben's total as 38 + 27 = 57, then adding 19: 57 + 19 = 76. Choice D calculates 19 more than Ben's second game only: 27 + 19 = 46, but shows 57.
Maya has 52 beads and gets 19 more. How many now?
61
70
71
81
Explanation
This question tests 2nd grade understanding of adding and subtracting within 100, including using regrouping (carrying and borrowing) when necessary (CCSS 2.NBT.B.5: Fluently add and subtract within 100 using strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; CCSS 2.NBT.B.7: Add and subtract within 1000, using strategies and algorithms based on place value—focus here on within 100). When adding two-digit numbers, add ones first, then tens. If the ones sum is 10 or more, regroup: write the ones digit and carry 1 ten to the tens column (example: $47 + 28$ → $7 + 8 = 15$, write 5 and carry 1 → $4 + 2 + 1 = 7$ → answer is 75). When subtracting, subtract ones first, then tens. If the ones digit in the top number is smaller than the ones digit in the bottom number, regroup (borrow): take 1 ten from the tens column and add 10 to the ones (example: $63 - 27$ → can't do 3 - 7, so regroup 6 tens 3 ones into 5 tens 13 ones → $13 - 7 = 6$, $5 - 2 = 3$ → answer is 36). Place value strategy: Break numbers into tens and ones, add or subtract separately, combine ($47 + 28 = 40 + 20 + 7 + 8 = 60 + 15 = 75$). Number line: Start at first number, jump by tens then ones to add, or jump backward to subtract. In this problem, Maya has 52 beads and gets 19 more, a word problem requiring addition. To solve, add $52 + 19$: ones $2 + 9 = 11$ (write 1, carry 1), tens $5 + 1 + 1 = 7$, answer 71, or use place value: $50 + 10 = 60$, $2 + 9 = 11$, total 71. Choice B is correct because adding $52 + 19$ correctly—$2 + 9 = 11$ (write 1, carry 1), $5 + 1 + 1 = 7$, giving 71, or in context: Maya had 52, got 19 more, total 71. This correctly applies addition with regrouping to the word problem. Choice A represents not carrying in addition ($5 + 1 = 6$, $2 + 9 = 11$ but wrote 61 without proper carry or misadded). This error typically happens when students forget to regroup, make arithmetic mistakes, or confuse the operation in the word problem. To help students: Teach regrouping explicitly with place value understanding. For addition: 'When ones add to 10 or more, we have too many ones. Group 10 ones into 1 ten. Write the remaining ones, carry the 1 ten.' Use base-ten blocks: 4 tens + 7 ones + 2 tens + 8 ones → combine ones ($7 + 8 = 15$ ones = 1 ten + 5 ones), combine tens ($4 + 2 + 1 = 7$ tens) → 75. For subtraction: 'If top ones < bottom ones, we need more ones. Borrow 1 ten (= 10 ones) from tens column.' Show with blocks: 6 tens 3 ones, need to subtract 7 ones (can't), so trade 1 ten for 10 ones (5 tens 13 ones), now can subtract. Practice standard algorithm vertically—align place values, work ones first then tens. Teach number line strategy: to add, jump forward; to subtract, jump backward. For word problems, identify operation: 'got more, combine, total' = add; 'gave away, left, how many more' = subtract. Practice mental math strategies: break apart by tens and ones, use friendly numbers. Watch for: not regrouping when needed, regrouping incorrectly (carrying/borrowing wrong amount), place value errors, wrong operation for context, basic arithmetic mistakes.
Maya has $$37$$ stickers. She gives away $$19$$ stickers to her friends, then finds $$25$$ more stickers in her backpack. How many stickers does Maya have now?
$$43$$ stickers
$$81$$ stickers
$$41$$ stickers
$$45$$ stickers
Explanation
Start with 37 stickers. After giving away 19: 37 - 19 = 18 stickers. After finding 25 more: 18 + 25 = 43 stickers. Choice B results from calculating 37 - 19 + 23 (adding 23 instead of 25). Choice C results from 37 - 17 + 25 (subtracting 17 instead of 19). Choice D results from adding all numbers: 37 + 19 + 25 = 81.
A box contains $$63$$ crayons. Children take out $$28$$ crayons for their project. Then $$16$$ crayons are added back to the box. How many crayons are in the box now?
$$47$$ crayons remain in the box after all changes
$$51$$ crayons remain in the box after all changes
$$107$$ crayons remain in the box after all additions
$$35$$ crayons remain in the box after taking them out
Explanation
Start with 63 crayons. After taking out 28: 63 - 28 = 35 crayons. After adding 16 back: 35 + 16 = 51 crayons. Choice B gives the number after taking out crayons but before adding any back. Choice C results from adding all numbers: 63 + 28 + 16 = 107. Choice D results from miscalculating: 63 - 28 = 35, then 35 + 12 = 47 (adding 12 instead of 16).