### All Precalculus Resources

## Example Questions

### Example Question #1 : Graph A Hyperbola

What is the equation of the conic section graphed below

**Possible Answers:**

**Correct answer:**

The hyperbola pictured is centered at , meaning that the equation has a horizontal shift. The equation must have rather than just x. The hyperbola opens up and down, so the equation must be the y term minus the x term. The hyperbola is drawn according to the box going up/down 5 and left/right 2, so the y term must be or , and the x term must be or .

### Example Question #2 : Graph A Hyperbola

How can this graph be changed to be the graph of

?

**Possible Answers:**

The center box should extend up to and down to , stretching the graph.

The graph should have -intercepts and not -intercepts.

The -intercepts should be at the points and .

The -intercepts should be at the points and .

The graph should be an ellipse and not a hyperbola.

**Correct answer:**

The -intercepts should be at the points and .

This equation should be thought of as .

This means that the hyperbola will be determined by a box with x-intercepts at and y-intercepts at .

The hyperbola was incorrectly drawn with the intercepts at instead.

### Example Question #3 : Graph A Hyperbola

Which of the following would NOT be true of the graph for ?

**Possible Answers:**

The graph never intersects with the -axis.

The graph opens up and down.

All of these statements are true.

The graph never intersects with the -axis.

The graph is centered at .

**Correct answer:**

The graph never intersects with the -axis.

The graph should look like this:

### Example Question #4 : Graph A Hyperbola

Which of these equations produce this graph, rotated 90 degrees?

**Possible Answers:**

**Correct answer:**

Rotated 90 degrees, this graph would be opening up and down instead of left and right, so the equation will have the y term minus the x term.

The box that the hyperbola is drawn around will also rotate. It will now be up/down 2 and left/right 3.

This makes the correct equation

.

Certified Tutor