Expressions, Equations, and Relationships>Applying the Pythagorean Theorem and Its Converse to Solve Problems(TEKS.Math.8.7.C)
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Texas 8th Grade Math › Expressions, Equations, and Relationships>Applying the Pythagorean Theorem and Its Converse to Solve Problems(TEKS.Math.8.7.C)
A ladder leans against a wall. The ladder is 13 feet long, and the base is 5 feet from the wall. How high up the wall does the ladder reach?
12 feet
13 feet
5 feet
14 feet
Explanation
The ladder is the hypotenuse, and the wall height and ground distance are the legs. Use $a^2 + b^2 = c^2$ with $c = 13$ and a leg $a = 5$. Then $b = \sqrt{13^2 - 5^2} = \sqrt{169 - 25} = \sqrt{144} = 12$ feet. This models a common construction setup for checking heights safely.
A rectangular field is 60 meters by 80 meters. What is the diagonal distance across the field?
140 meters
100 meters
60 meters
80 meters
Explanation
The diagonal is the hypotenuse of a right triangle with legs 60 and 80. $d = \sqrt{60^2 + 80^2} = \sqrt{3600 + 6400} = \sqrt{10000} = 100$ meters. This is useful in surveying and planning straight paths across rectangular lots.
A triangle has side lengths 8 units, 15 units, and 17 units. Is this triangle a right triangle?
Yes, because 8 + 15 = 17
No, because $8^2 + 15^2 \ne 17^2$
Yes, because $8^2 + 15^2 = 17^2$
Cannot be determined without angles
Explanation
Use the converse of the Pythagorean Theorem. Compute $8^2 + 15^2 = 64 + 225 = 289$ and $17^2 = 289$. Since $8^2 + 15^2 = 17^2$, the triangle is right. Builders use this idea (like a 8–15–17 or 3–4–5 triangle) to check square corners.
A triangle has side lengths 10 units, 12 units, and 15 units. Is this triangle a right triangle?
Yes, because 10 + 12 = 22
Yes, because $10^2 + 12^2 = 15^2$
Cannot be determined
No, because $10^2 + 12^2 \ne 15^2$
Explanation
Check the converse: compute $10^2 + 12^2 = 100 + 144 = 244$ and $15^2 = 225$. Because $244 \ne 225$, $a^2 + b^2 \ne c^2$, so it is not a right triangle. This kind of check helps verify whether a corner is square in design and construction.
A hiker walks 9 kilometers east and then 12 kilometers north. How far is the hiker from the starting point, in a straight line?
21 kilometers
15 kilometers
3 kilometers
13 kilometers
Explanation
The path forms a right triangle with legs 9 and 12. The straight-line distance is $d = \sqrt{9^2 + 12^2} = \sqrt{81 + 144} = \sqrt{225} = 15$ kilometers. This models navigation using straight-line distance (displacement).