Expressions, Equations, and Relationships>Describing the Volume Formula of a Cylinder as V = Bh(TEKS.Math.8.6.A)

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Texas 8th Grade Math › Expressions, Equations, and Relationships>Describing the Volume Formula of a Cylinder as V = Bh(TEKS.Math.8.6.A)

Questions 1 - 3
1

A mailing tube has diameter 6 in and height 8 in. Using $V = \pi r^2 h$, what is the volume, rounded to the nearest tenth? Use $\pi \approx 3.14$.

169.6 in^3

72.0 in^3

904.3 in^3

226.1 in^3

Explanation

For a cylinder, $V = Bh$ where $B = \pi r^2$. The diameter is 6 in, so $r = 3$ in. Compute $B = \pi r^2 = 3.14 \times 3^2 = 3.14 \times 9 = 28.26$. Then $V = Bh = 28.26 \times 8 = 226.08 \approx 226.1$. The volume is 226.1 in^3.

2

A candle jar has diameter 6 cm and height 15 cm. Using $V = \pi r^2 h$, what is the volume, rounded to the nearest tenth? Use $\pi \approx 3.14$.

423.9 cm^3

1695.6 cm^3

135.0 cm^3

339.1 cm^3

Explanation

For a cylinder, $V = Bh$ where $B = \pi r^2$. The diameter is 6 cm, so $r = 3$ cm. Compute $B = \pi r^2 = 3.14 \times 3^2 = 3.14 \times 9 = 28.26$. Then $V = Bh = 28.26 \times 15 = 423.9$. The volume is 423.9 cm^3.

3

A paint can has diameter 6 cm and height 20 cm. Using $V = \pi r^2 h$, what is the volume, rounded to the nearest tenth? Use $\pi \approx 3.14$.

565.2 cm^3

2260.8 cm^3

180.0 cm^3

169.6 cm^3

Explanation

For a cylinder, $V = Bh$ where $B = \pi r^2$. The diameter is 6 cm, so $r = 3$ cm. Compute $B = \pi r^2 = 3.14 \times 3^2 = 3.14 \times 9 = 28.26$. Then $V = Bh = 28.26 \times 20 = 565.2$. The volume is 565.2 cm^3.