SSAT Upper Level Quantitative · Question of the Day

SSAT Upper Level Quantitative Question of the Day

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Tuesday, August 18, 2026

A map has a scale where 1.51.5 inches represents 1212 miles. If two cities are 8.58.5 inches apart on the map, and a car travels between them at an average speed of 5151 miles per hour, how long will the trip take?

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Question of the Day

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A map has a scale where 1.51.5 inches represents 1212 miles. If two cities are 8.58.5 inches apart on the map, and a car travels between them at an average speed of 5151 miles per hour, how long will the trip take?

  1. 11 hour 2020 minutes (correct answer)
  2. 11 hour 4040 minutes
  3. 22 hours 1010 minutes
  4. 22 hours 4040 minutes

Explanation: First, find the actual distance: 8.5 inches1.5 inches×12 miles=8.5×121.5=1021.5=68\frac{8.5 \text{ inches}}{1.5 \text{ inches}} \times 12 \text{ miles} = \frac{8.5 \times 12}{1.5} = \frac{102}{1.5} = 68 miles. Then find the time: 68 miles51 mph=6851=43=113\frac{68 \text{ miles}}{51 \text{ mph}} = \frac{68}{51} = \frac{4}{3} = 1\frac{1}{3} hours =1= 1 hour 2020 minutes. Choice B uses incorrect scale calculation (8.5×12=1028.5 \times 12 = 102 miles directly). Choice C incorrectly calculates 6852\frac{68}{52} instead of 6851\frac{68}{51}. Choice D uses 8.5×1.5×12=1538.5 \times 1.5 \times 12 = 153 miles.