SSAT Upper Level Quantitative Flashcards: Percent Increase And Decrease

What this deck covers

This deck focuses on Percent Increase And Decrease, giving you a quick way to review the definitions, rules, and examples that matter most for SSAT Upper Level Quantitative.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: State the formula for the percent change from an original value $O$ to a new value $N$.

Answer: $\frac{N-O}{O}\times 100\%$. Calculates the relative change by dividing the difference by the original value and multiplying by 100 to express as a percentage.

Flashcard 2: A price is discounted $30\%$ and then discounted $20\%$. What single discount percent is equivalent?

Answer: $44\%$. The equivalent single discount is $100\% - (0.7 \times 0.8) \times 100\%$, yielding 44%.

Flashcard 3: What percent decrease takes $120$ down to $96$?

Answer: $20\%$. Divide the decrease by the original value and multiply by 100 to determine the percentage reduction.

Flashcard 4: State the multiplier for increasing a value by $p\%$.

Answer: $1+\frac{p}{100}$. Represents the factor by which the original value is scaled to include the percentage increase.

Flashcard 5: A $35\%$ discount is followed by a $35\%$ markup on the discounted price. What is the net percent change?

Answer: $-12.25\%$. The overall multiplier $0.65 \times 1.35 = 0.8775$ indicates a 12.25% decrease from the original.

Flashcard 6: What is the percent decrease from $90$ to $72$?

Answer: $20\%$. Divide the decrease by the original value and multiply by 100 to find the percentage change.

Flashcard 7: What is the final value after increasing $200$ by $15\%$ and then increasing the result by $10\%$?

Answer: $253$. Successive application of multipliers $1.15$ and $1.1$ to the original value gives the final result.

Flashcard 8: What discount percent from original price $O$ to sale price $S$? (Express in terms of $O$ and $S$.)

Answer: $\frac{O-S}{O}\times 100\%$. Discount percentage is the reduction relative to the original price, computed as the difference over original times 100%.

Flashcard 9: What is the percent increase from $50$ to $65$?

Answer: $30\%$. Divide the increase by the original value and multiply by 100 to find the percentage change.

Flashcard 10: What percent increase takes $40$ up to $50$?

Answer: $25\%$. Divide the increase by the original value and multiply by 100 to determine the percentage growth.

Flashcard 11: A quantity decreases from $y$ to $0.6y$. What is the percent decrease?

Answer: $40\%$. The decrease of $0.4y$ relative to the original $y$ corresponds to a 40% change.

Flashcard 12: A quantity increases from $x$ to $1.5x$. What is the percent increase?

Answer: $50\%$. The increase of $0.5x$ relative to the original $x$ corresponds to a 50% change.

Flashcard 13: What is the new value if $80$ is increased by $25\%$?

Answer: $100$. Apply the multiplier $1.25$ to the original value to compute the increased amount.

Flashcard 14: A shirt costs $48 after a $20\%$ discount. What was the original price?

Answer: $60. Divide the discounted price by the retention rate $0.8$ to recover the original price.

Flashcard 15: What markup percent from cost $C$ gives selling price $S$? (Express in terms of $C$ and $S$.)

Answer: $\frac{S-C}{C}\times 100\%$. Markup percentage is the profit relative to cost, computed as the difference over cost times 100%.

Flashcard 16: A price is increased by $10\%$ and then decreased by $10\%$. What is the net percent change?

Answer: $-1\%$. The successive multipliers $1.1$ and $0.9$ yield an overall factor of $0.99$, indicating a 1% decrease.

Flashcard 17: After a $25\%$ decrease, a value is $150$. What was the original value?

Answer: $200$. Divide the decreased value by the retention rate $0.75$ to find the original value.

Flashcard 18: A price is increased $30\%$ and then increased $20\%$. What single increase percent is equivalent?

Answer: $56\%$. The equivalent single increase is $(1.3 \times 1.2 - 1) \times 100\%$, yielding 56%.

Flashcard 19: What is the overall percent change after increases of $20\%$ and $30\%$ applied successively?

Answer: $56\%$. The combined multiplier $1.2 \times 1.3 = 1.56$ corresponds to a 56% increase from the original.

Flashcard 20: A value is multiplied by $1.2$ and then by $0.75$. What is the overall percent change?

Answer: $-10\%$. The product of the multipliers $1.2$ and $0.75$ is $0.9$, representing a 10% decrease overall.

Flashcard 21: A number is decreased by $20\%$ and then increased by $25\%$. What is the net percent change?

Answer: $0\%$. The multipliers $0.8$ and $1.25$ product to $1$, resulting in no net percentage change.

Flashcard 22: What is the new value if $60$ is decreased by $15\%$?

Answer: $51$. Apply the multiplier $0.85$ to the original value to compute the decreased amount.

Flashcard 23: A value becomes $84$ after a $40\%$ increase. What was the original value?

Answer: $60$. Divide the new value by the growth factor $1.4$ to find the original value before the increase.

Flashcard 24: State the multiplier for decreasing a value by $p\%$.

Answer: $1-\frac{p}{100}$. Represents the factor by which the original value is scaled to account for the percentage decrease.

Flashcard 25: What is the overall percent change after decreases of $20\%$ and $30\%$ applied successively?

Answer: $-44\%$. The combined multiplier $0.8 \times 0.7 = 0.56$ corresponds to a 44% decrease from the original.