How to multiply - SSAT Upper Level Quantitative

First multiply the fraction in the numerator.

$\frac{1}{2}$times $\frac{1}{3}$=\frac{1times 1}{2times 3}$=\frac{1}{6}$

Now we have $\frac{frac{1}{6}$}{$\frac{1}{9}$}

Never divide fractions. We multiply the numerator by the reciprocal of the denominator.

$\frac{frac{1}{6}$}{$\frac{1}{9}$}=\frac{1}{6}$div $\frac{1}{9}$=\frac{1}{6}$times $\frac{9}{1}$=\frac{1times 9}{6times 1}$=\frac{9}{6}$=\frac{3}{2}$

The easiest way to see that all four are equivalent is to convert each to a decimal product, noting that twenty percent and one-fifth are equal to , and twenty-five percent and one fourth are equal to .

One fourth of 0.2:

One fifth of 0.25:

Twenty-five percent of one fifth:

Twenty percent of one fourth:

When three negative numbers are multiplied together, the product will be negative as well. All the other expressions are true.

Scientific notation is used to simplify exceptionally complex numbers and to quickly present the number of significant figures in a given value. The value is converted to an exponent form using base ten, such that only a single-digit term with any given number of decimal places is used to represent the significant figures of the given value. Non-significant zeroes can be omitted from the leading term, and represented only in the base ten exponent.

The given number has three significant figure () so we write out number as

You must move the decimal place two places to the right, or in other words multiply by . When you move the decimal place to the right, you multiply the number by , so it is .

The answer is .

The problem is asking for a number whose product with 5 yields a number congruent to 3 in modulo 6 arithmetic - that is, a number which, when divided by 6, yields remainder 3. We multiply 5 by each choice and look for a product with this characteristic.

;

;

;

;

;

The only choice whose product with 5 yields a number congruent to 3 modulo 6 is 3, so this is the correct choice.

The problem is asking for a number whose product with 6 yields a number congruent to 5 in modulo 12 arithmetic - that is, a number which, when divided by 12, yields remainder 6.

However, 6 multiplied by any odd number yields a number which, when divided by 12, yields remainder 6, as is demonstrated using our choices:

Each of the choices yields a product congruent to 6 modulo 12, so none of them is a correct choice.

We can write 2 pounds, 5 ounces as just ounces as follows:

Multiply:

Divide by 16, noting quotient and remainder, to get pounds and ounces:

Therefore, the correct response is 13 pounds, 14 ounces.

First multiply the fraction in the numerator.

$\frac{1}{2}$times $\frac{1}{3}$=\frac{1times 1}{2times 3}$=\frac{1}{6}$

Now we have $\frac{frac{1}{6}$}{$\frac{1}{9}$}

Never divide fractions. We multiply the numerator by the reciprocal of the denominator.

$\frac{frac{1}{6}$}{$\frac{1}{9}$}=\frac{1}{6}$div $\frac{1}{9}$=\frac{1}{6}$times $\frac{9}{1}$=\frac{1times 9}{6times 1}$=\frac{9}{6}$=\frac{3}{2}$

The easiest way to see that all four are equivalent is to convert each to a decimal product, noting that twenty percent and one-fifth are equal to , and twenty-five percent and one fourth are equal to .

One fourth of 0.2:

One fifth of 0.25:

Twenty-five percent of one fifth:

Twenty percent of one fourth:

When three negative numbers are multiplied together, the product will be negative as well. All the other expressions are true.

Scientific notation is used to simplify exceptionally complex numbers and to quickly present the number of significant figures in a given value. The value is converted to an exponent form using base ten, such that only a single-digit term with any given number of decimal places is used to represent the significant figures of the given value. Non-significant zeroes can be omitted from the leading term, and represented only in the base ten exponent.

The given number has three significant figure () so we write out number as

You must move the decimal place two places to the right, or in other words multiply by . When you move the decimal place to the right, you multiply the number by , so it is .

The answer is .

The problem is asking for a number whose product with 5 yields a number congruent to 3 in modulo 6 arithmetic - that is, a number which, when divided by 6, yields remainder 3. We multiply 5 by each choice and look for a product with this characteristic.

;

;

;

;

;

The only choice whose product with 5 yields a number congruent to 3 modulo 6 is 3, so this is the correct choice.

The problem is asking for a number whose product with 6 yields a number congruent to 5 in modulo 12 arithmetic - that is, a number which, when divided by 12, yields remainder 6.

However, 6 multiplied by any odd number yields a number which, when divided by 12, yields remainder 6, as is demonstrated using our choices:

Each of the choices yields a product congruent to 6 modulo 12, so none of them is a correct choice.

We can write 2 pounds, 5 ounces as just ounces as follows:

Multiply:

Divide by 16, noting quotient and remainder, to get pounds and ounces:

Therefore, the correct response is 13 pounds, 14 ounces.

First multiply the fraction in the numerator.

$\frac{1}{2}$times $\frac{1}{3}$=\frac{1times 1}{2times 3}$=\frac{1}{6}$

Now we have $\frac{frac{1}{6}$}{$\frac{1}{9}$}

Never divide fractions. We multiply the numerator by the reciprocal of the denominator.

$\frac{frac{1}{6}$}{$\frac{1}{9}$}=\frac{1}{6}$div $\frac{1}{9}$=\frac{1}{6}$times $\frac{9}{1}$=\frac{1times 9}{6times 1}$=\frac{9}{6}$=\frac{3}{2}$

The easiest way to see that all four are equivalent is to convert each to a decimal product, noting that twenty percent and one-fifth are equal to , and twenty-five percent and one fourth are equal to .

One fourth of 0.2:

One fifth of 0.25:

Twenty-five percent of one fifth:

Twenty percent of one fourth:

When three negative numbers are multiplied together, the product will be negative as well. All the other expressions are true.

Scientific notation is used to simplify exceptionally complex numbers and to quickly present the number of significant figures in a given value. The value is converted to an exponent form using base ten, such that only a single-digit term with any given number of decimal places is used to represent the significant figures of the given value. Non-significant zeroes can be omitted from the leading term, and represented only in the base ten exponent.

The given number has three significant figure () so we write out number as

You must move the decimal place two places to the right, or in other words multiply by . When you move the decimal place to the right, you multiply the number by , so it is .