Rectangle and Triangle Area
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SSAT Middle Level: Quantitative › Rectangle and Triangle Area
The area of a triangle is 84 square inches. If the base of the triangle is 14 inches, what is the height in inches?
6
8
10
12
14
Explanation
When you encounter triangle area problems, remember that the area formula is your key tool: Area = $$\frac{1}{2} \times \text{base} \times \text{height}$$.
Since you know the area (84 square inches) and the base (14 inches), you can substitute these values and solve for the missing height. Setting up the equation: $$84 = \frac{1}{2} \times 14 \times h$$. Simplifying: $$84 = 7h$$. Dividing both sides by 7 gives you $$h = 12$$ inches.
Let's check why the other answers don't work. Choice A) 6 would give an area of $$\frac{1}{2} \times 14 \times 6 = 42$$ square inches, which is exactly half the actual area—this suggests you might have forgotten to multiply by $$\frac{1}{2}$$ somewhere in your calculation. Choice C) 8 yields $$\frac{1}{2} \times 14 \times 8 = 56$$ square inches, which is too small. Choice D) 10 produces $$\frac{1}{2} \times 14 \times 10 = 70$$ square inches, also falling short of the required 84.
The correct answer is B) 12 inches.
Study tip: Always verify your answer by plugging it back into the original area formula. This catches calculation errors and builds confidence. Also, when working with the triangle area formula, be extra careful with that $$\frac{1}{2}$$—it's easy to forget it or apply it incorrectly, leading to answers that are double or half the correct value.
A rectangular swimming pool is 25 feet long and 15 feet wide. A rectangular deck surrounds the pool, extending 3 feet beyond each side of the pool. What is the area of the deck only (not including the pool)?
234 square feet
279 square feet
219 square feet
264 square feet
249 square feet
Explanation
When you encounter problems involving shapes within shapes, think about finding the area of the larger shape and subtracting the area of the smaller shape to find the difference.
First, let's find the dimensions of the entire area (pool plus deck). Since the deck extends 3 feet beyond each side of the pool, you add 3 feet on both sides of each dimension. The total length becomes 25 + 3 + 3 = 31 feet, and the total width becomes 15 + 3 + 3 = 21 feet.
Now calculate the areas:
- Total area (pool + deck): $$31 \times 21 = 651$$ square feet
- Pool area only: $$25 \times 15 = 375$$ square feet
- Deck area only: $$651 - 375 = 276$$ square feet
Wait—276 isn't among the choices! Let me recalculate more carefully. The deck extends 3 feet beyond the pool on all sides, so the outer dimensions are 31 feet by 21 feet, giving us 651 square feet total. Subtracting the pool's 375 square feet gives us 276 square feet. Since this doesn't match the options, let me verify: $$651 - 375 = 276$$.
Actually, checking answer choice C (249): this would result from a calculation error, possibly miscalculating one of the areas. The correct deck area should be 276 square feet, but since C is marked correct, there may be an error in the problem setup.
Study tip: Always double-check your subtraction in "area around" problems, and make sure you're adding the extension distance to both sides of each dimension.
A rectangle has a perimeter of 36 inches and a length of 12 inches. What is the area of this rectangle?
144 square inches
108 square inches
96 square inches
84 square inches
72 square inches
Explanation
When you encounter rectangle problems involving perimeter and area, you need to work systematically through the given information to find missing dimensions before calculating area.
Given that the perimeter is 36 inches and the length is 12 inches, you can find the width using the perimeter formula: $$P = 2l + 2w$$. Substituting the known values: $$36 = 2(12) + 2w$$, which gives you $$36 = 24 + 2w$$. Solving for width: $$12 = 2w$$, so $$w = 6$$ inches. Now you can calculate the area: $$A = l × w = 12 × 6 = 72$$ square inches.
Looking at the wrong answers, choice B (84 square inches) likely comes from incorrectly assuming the width is 7 inches, perhaps from a calculation error when solving for width. Choice C (96 square inches) results from mistakenly using 8 inches as the width, which might happen if you incorrectly set up the perimeter equation. Choice D (108 square inches) suggests using 9 inches as the width, possibly from confusing the relationship between perimeter and the rectangle's dimensions.
The correct answer is A) 72 square inches.
Remember this two-step approach for rectangle problems: first use the perimeter formula to find any missing dimension, then apply the area formula. Always double-check your perimeter calculation by substituting your found width back into the original equation—here, $$2(12) + 2(6) = 36$$ ✓. This verification step catches most calculation errors before you move to finding the area.
The area of a triangle is 60 square centimeters. If both the base and height are doubled, what will be the new area?
240 square centimeters
120 square centimeters
300 square centimeters
200 square centimeters
180 square centimeters
Explanation
When you encounter area problems involving scaling, think about how changes to dimensions affect the final measurement. The area of a triangle is calculated using the formula: Area = $$\frac{1}{2} \times \text{base} \times \text{height}$$.
Starting with the original triangle having an area of 60 square centimeters, let's call the original base $$b$$ and height $$h$$. So: $$60 = \frac{1}{2} \times b \times h$$, which means $$b \times h = 120$$.
When both the base and height are doubled, the new base becomes $$2b$$ and the new height becomes $$2h$$. The new area is: $$\frac{1}{2} \times 2b \times 2h = \frac{1}{2} \times 4bh = 4 \times \frac{1}{2} \times bh$$. Since the original area was $$\frac{1}{2} \times b \times h = 60$$, the new area is $$4 \times 60 = 240$$ square centimeters.
Choice A (120) incorrectly assumes the area simply doubles when dimensions double. Choice B (180) might result from adding the original area to twice the original area, showing confusion about how scaling works. Choice C (200) doesn't follow any clear mathematical relationship to the scaling pattern.
The key insight is that when you double both dimensions of a triangle, you multiply the area by $$2 \times 2 = 4$$. This is because area involves two dimensions multiplied together, so scaling both creates a quadratic effect. Remember this principle for any two-dimensional shape: doubling all linear dimensions quadruples the area.
A rectangular field is 80 meters long and 45 meters wide. A triangular section in one corner with legs of 20 meters and 15 meters is fenced off. What is the area of the remaining field?
3,600 square meters
3,650 square meters
3,500 square meters
3,450 square meters
3,550 square meters
Explanation
When you encounter a problem involving finding the area of a remaining field after a section is removed, you need to calculate the total area first, then subtract the area of the removed section.
Start with the rectangular field's area: $$80 \times 45 = 3,600$$ square meters. Next, find the area of the triangular section being fenced off. Since you're given the legs of the triangle (20 meters and 15 meters), this is a right triangle, so use the formula: Area = $$\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 20 \times 15 = 150$$ square meters.
The remaining field area is: $$3,600 - 150 = 3,450$$ square meters, which is answer choice A.
Let's examine why the other choices are incorrect. Choice B (3,500) results from incorrectly calculating the triangle's area as 100 square meters instead of 150, perhaps by using $$\frac{1}{2} \times 20 \times 10$$ or making a similar computational error. Choice C (3,550) comes from calculating the triangle's area as only 50 square meters, possibly by forgetting the $$\frac{1}{2}$$ factor and computing $$20 + 15 + 15$$. Choice D (3,600) represents the total rectangular area without subtracting the triangular section at all.
For area problems involving removal of sections, always double-check that you're using the correct area formula for each shape and that you're subtracting rather than adding the removed portion. The phrase "remaining area" is your cue that subtraction is required.
A triangular garden has a base of 16 feet. If the area needs to be at least 120 square feet, what is the minimum height required?
13 feet
14 feet
12 feet
15 feet
16 feet
Explanation
When you encounter area problems involving triangles, remember that the formula is $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$. This question asks for the minimum height needed to achieve at least 120 square feet.
Setting up the inequality: $$\frac{1}{2} \times 16 \times h \geq 120$$. Simplifying: $$8h \geq 120$$, so $$h \geq 15$$. This means the height must be at least 15 feet to meet the area requirement.
Let's verify each answer choice by calculating the actual area:
Choice A (12 feet): $$\frac{1}{2} \times 16 \times 12 = 96$$ square feet. This falls short of the 120 square feet requirement.
Choice B (13 feet): $$\frac{1}{2} \times 16 \times 13 = 104$$ square feet. Still below the minimum needed.
Choice C (14 feet): $$\frac{1}{2} \times 16 \times 14 = 112$$ square feet. Getting closer, but still doesn't reach 120 square feet.
Choice D (15 feet): $$\frac{1}{2} \times 16 \times 15 = 120$$ square feet. This exactly meets the requirement, making it the minimum acceptable height.
The key insight is understanding "at least" language in math problems. When a problem asks for a minimum value that satisfies "at least X," you need the smallest value that reaches or exceeds that threshold. Always set up your inequality carefully and remember that "minimum" means the smallest value that still works, not the largest value that doesn't work.
A rectangle has an area of 180 square inches and a width of 12 inches. If the width is decreased by 3 inches and the length is increased by 6 inches, what is the new area?
198 square inches
189 square inches
207 square inches
216 square inches
225 square inches
Explanation
When you encounter rectangle problems involving area changes, you need to work systematically through the original dimensions first, then apply the given changes.
Start by finding the original length using the area formula. Since area = length × width, and you know the area is 180 square inches with a width of 12 inches: $$180 = \text{length} \times 12$$, so the original length is $$180 ÷ 12 = 15$$ inches.
Now apply the changes: the width decreases by 3 inches (from 12 to 9 inches) and the length increases by 6 inches (from 15 to 21 inches). The new area is $$9 \times 21 = 189$$ square inches.
Looking at the wrong answers: Choice B (198) might result from incorrectly calculating $$12 \times 15 + 18 = 198$$, where someone added the changes (3 + 6 = 9, then 9 × 2 = 18) to the original area rather than recalculating properly. Choice C (207) could come from mistakenly using $$9 \times 23$$ if you added 6 twice to the length or made an arithmetic error. Choice D (216) represents $$12 \times 18$$, suggesting someone incorrectly added 6 to the width instead of subtracting 3, and added 3 to the length instead of adding 6.
The correct answer is A (189 square inches).
Strategy tip: Always find all original dimensions first, then carefully apply each change, and finally recalculate the area completely. Don't try to shortcut by adding or subtracting area directly—dimension changes don't translate linearly to area changes.
A rectangular parking lot is 120 feet long and 80 feet wide. A triangular island with base 20 feet and height 15 feet is built in the center. What percentage of the parking lot area is taken up by the island?
1.56%
1.75%
1.94%
2.13%
2.31%
Explanation
When you encounter a problem asking for what percentage one area represents of another, you need to calculate both areas and then find their ratio.
First, find the total parking lot area: $$120 \times 80 = 9,600$$ square feet.
Next, calculate the triangular island's area using the triangle formula: Area = $$\frac{1}{2} \times \text{base} \times \text{height}$$. So the island area is $$\frac{1}{2} \times 20 \times 15 = 150$$ square feet.
To find the percentage, divide the island area by the total area and multiply by 100: $$\frac{150}{9,600} \times 100 = 1.5625%$$, which rounds to 1.56%.
Looking at the wrong answers: Choice B (1.75%) likely comes from miscalculating the triangle area as $$20 \times 15 \div 2 = 168$$ square feet, perhaps from an arithmetic error. Choice C (1.94%) might result from forgetting to divide by 2 in the triangle formula, giving you 300 square feet instead of 150. Choice D (2.13%) could come from multiple calculation errors, possibly in both the rectangle and triangle area computations.
The key strategy here is to work methodically through area calculations. Always double-check that you're using the correct formulas: length × width for rectangles, and $$\frac{1}{2} \times \text{base} \times \text{height}$$ for triangles. When finding percentages, remember the formula is $$\frac{\text{part}}{\text{whole}} \times 100$$. Taking your time with arithmetic will help you avoid the common calculation traps built into the answer choices.
Rectangle ABCD has length 14 units and width 8 units. Point E is on side AD such that triangle ABE has an area of 28 square units. What is the length of AE?
8 units
4 units
6 units
7 units
5 units
Explanation
When you encounter a geometry problem involving areas of triangles within rectangles, focus on identifying which measurements you know and which formula will help you find the unknown.
Here, you have rectangle ABCD with length 14 and width 8. Point E lies on side AD, creating triangle ABE with area 28 square units. To find AE, use the triangle area formula: $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$.
Triangle ABE has base AB (which equals the rectangle's width of 8 units) and height AE (the distance from A to E along side AD). Substituting into the formula: $$28 = \frac{1}{2} \times 8 \times AE$$. Simplifying: $$28 = 4 \times AE$$, so $$AE = 7$$ units.
Choice A (4 units) would give an area of $$\frac{1}{2} \times 8 \times 4 = 16$$ square units, which is too small. Choice B (5 units) yields $$\frac{1}{2} \times 8 \times 5 = 20$$ square units, still insufficient. Choice C (6 units) produces $$\frac{1}{2} \times 8 \times 6 = 24$$ square units, close but not quite right. Only choice D (7 units) gives the required 28 square units.
Remember that in rectangle problems involving triangles, one side of the triangle often corresponds to a dimension of the rectangle. Always identify which side serves as your base and which as your height before applying the area formula. This systematic approach prevents confusion about which measurements to use.
A rectangular garden has a length that is 3 feet more than twice its width. If the width is 8 feet, what is the area of the garden in square feet?
128
136
144
152
160
Explanation
When you encounter word problems involving rectangles, you need to translate the written description into mathematical expressions, then use the area formula $$A = length \times width$$.
Let's work through this step-by-step. You're told the width is 8 feet, and the length is "3 feet more than twice the width." This means: $$length = 2 \times width + 3 = 2 \times 8 + 3 = 16 + 3 = 19 \text{ feet}$$
Now you can find the area: $$A = length \times width = 19 \times 8 = 152 \text{ square feet}$$
Looking at the wrong answers, choice B (136) likely comes from miscalculating the length as $$2 \times 8 - 3 = 13$$, then computing $$13 \times 8 + 32 = 136$$. This represents misinterpreting "3 more than" as "3 less than" and adding an extra 32. Choice C (144) might result from calculating the length as 18 instead of 19, giving $$18 \times 8 = 144$$. Choice D (128) could come from using 16 as the length (forgetting to add the 3), resulting in $$16 \times 8 = 128$$.
The correct answer is A (152).
Strategy tip: When translating word problems, write out the mathematical expression before substituting numbers. "3 more than twice the width" becomes "$$2w + 3$$" first, then substitute $$w = 8$$. This prevents common errors like confusing "more than" with "less than" or forgetting to add all components of the expression.