Computing and Comparing Averages

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SSAT Middle Level: Quantitative › Computing and Comparing Averages

Questions 1 - 4
1

A teacher calculated that her class average on a test was 78 points. After discovering that one student's score of 65 was incorrectly recorded as 56, she recalculated the average. If there are 24 students in the class, what is the new average?

78.5 points

79.125 points

78.25 points

79.25 points

78.375 points

Explanation

When you encounter questions about correcting errors in averages, you need to understand how changes to individual data points affect the overall average. The key insight is that you don't need to recalculate everything from scratch—you can work with the change directly.

Start with what you know: the original average was 78 points with 24 students, so the total points for all students was $$78 \times 24 = 1,872$$ points. When the error is corrected, one student's score changes from 56 to 65, adding $$65 - 56 = 9$$ points to the class total.

The new total becomes $$1,872 + 9 = 1,881$$ points. With 24 students, the new average is $$\frac{1,881}{24} = 78.375$$ points.

Looking at the wrong answers: Choice A (78.25) likely comes from adding only 6 points instead of 9, perhaps from miscalculating the difference. Choice C (78.5) might result from rounding errors or adding exactly 12 points (0.5 × 24). Choice D (79.125) is too large and suggests either doubling the correction or making an error in the division.

For average correction problems, remember this efficient approach: find the total change in points, add it to the original total (original average × number of items), then divide by the number of items. This saves time compared to listing all individual scores and avoids arithmetic errors from handling large datasets.

2

A quality control inspector measured the weights of 15 packages. The first 10 packages had an average weight of 2.4 pounds each. The remaining 5 packages weighed 2.1, 2.8, 2.6, 2.3, and 2.7 pounds respectively. What was the overall average weight of all 15 packages?

2.53 pounds

2.55 pounds

2.50 pounds

2.45 pounds

2.47 pounds

Explanation

When you encounter questions about finding the overall average of combined groups, you need to work with total weights rather than just averaging the given averages.

To find the overall average weight, you must first calculate the total weight of all packages, then divide by the total number of packages.

For the first 10 packages with an average of 2.4 pounds each:

Total weight = $$10 \times 2.4 = 24$$ pounds

For the remaining 5 packages:

Total weight = $$2.1 + 2.8 + 2.6 + 2.3 + 2.7 = 12.5$$ pounds

Combined total weight = $$24 + 12.5 = 36.5$$ pounds

Overall average = $$\frac{36.5}{15} = 2.466...$$ pounds, which rounds to 2.47 pounds.

Looking at the wrong answers: Choice A (2.45 pounds) is too low and might result from calculation errors in adding the individual weights. Choice C (2.50 pounds) could come from incorrectly averaging the two group averages (2.4 and 2.5) without considering that the groups have different sizes. Choice D (2.53 pounds) is too high and might result from errors in the initial calculations or rounding mistakes.

The key strategy here is remembering that you cannot simply average two averages when the groups are different sizes. Always convert to totals first, then find the overall average. This weighted average concept appears frequently on standardized tests, so practice identifying when group sizes differ.

3

A baseball player's batting averages for each month of the season were: April 0.285, May 0.312, June 0.298, July 0.276, August 0.334, and September 0.291. If batting average represents hits per at-bat, and the player had 85 at-bats each month, what was his overall batting average for the season?

0.296

0.299

0.302

0.305

0.308

Explanation

When you encounter batting average problems, remember that batting average is calculated as total hits divided by total at-bats. The key insight here is that you can't simply average the monthly batting averages—you need to work with the actual hits and at-bats.

First, calculate the total hits for each month by multiplying each batting average by 85 at-bats:

  • April: $$0.285 × 85 = 24.225$$ hits
  • May: $$0.312 × 85 = 26.52$$ hits
  • June: $$0.298 × 85 = 25.33$$ hits
  • July: $$0.276 × 85 = 23.46$$ hits
  • August: $$0.334 × 85 = 28.39$$ hits
  • September: $$0.291 × 85 = 24.735$$ hits

Total hits: $$24.225 + 26.52 + 25.33 + 23.46 + 28.39 + 24.735 = 152.66$$

Total at-bats: $$85 × 6 = 510$$

Overall batting average: $$\frac{152.66}{510} = 0.299$$

The correct answer is B) 0.299.

Answer A) 0.296 would result from calculation errors in the hit totals. Answer C) 0.302 and D) 0.305 likely come from incorrectly averaging the six monthly averages ($$\frac{0.285 + 0.312 + 0.298 + 0.276 + 0.334 + 0.291}{6} ≈ 0.299$$), but this approach ignores the weighted nature of the calculation.

Remember: When dealing with rates or averages across different time periods, always work with the underlying totals rather than averaging the rates directly, especially when the sample sizes are equal across periods.

4

A fitness trainer recorded the number of push-ups completed by 8 clients: 25, 32, 28, 35, 30, 26, 33, and 29. The trainer wants to compare this group's average to the gym's overall average of 31 push-ups. By how much does this group's average differ from the gym average?

1.0 push-ups below gym average

2.25 push-ups below gym average

Exactly matches the gym average

1.25 push-ups below gym average

0.5 push-ups above gym average

Explanation

When you encounter average comparison problems, you need to calculate the group's mean and then find the difference from the reference value.

To find this group's average, add all the push-up counts and divide by 8: $$\frac{25 + 32 + 28 + 35 + 30 + 26 + 33 + 29}{8} = \frac{238}{8} = 29.75$$ push-ups.

Now compare this to the gym's overall average of 31 push-ups: $$31 - 29.75 = 1.25$$. Since the group's average (29.75) is less than the gym average (31), the group performed 1.25 push-ups below the gym average.

Looking at the wrong answers: Choice A (2.25 below) likely comes from a calculation error, perhaps miscounting the sum or dividing incorrectly. Choice C (1.0 below) might result from rounding 29.75 to 30 before comparing, which loses important precision. Choice D (0.5 above) represents a sign error—getting the magnitude wrong or mistakenly thinking the group performed better than average.

The key trap here is precision. Many students rush through the division or round prematurely, leading to incorrect differences. Always carry your decimal calculations through to the end before rounding, and pay careful attention to whether the difference represents "above" or "below" the reference value. When working with averages, double-check your arithmetic since small errors in addition or division create noticeably wrong final answers.