How to multiply variables - SSAT Middle Level Quantitative

In order to figure out who has the most money, we must organize the data we have. Since Shaun has more money than Jessica, let us use Jessica as our baseline. So, if the money that Jessica has is represented by , the money Shaun has will be because he has twice as much money as Jessica.

Jessica =

Shaun =

Next, we know that Jessica has one third as much money as Chris. In other words, Chris has three times as much money as Jessica. This can be represented by . We then learn that Shaun has half as much money as Carmen or, in other words, Carmen has two times the amount of money Shaun has. Since Shaun has dollars, that must mean Carmen has dollars because . So, by comparing everyone side-by-side, we can see that Carmen has the most money as she has four times the amount of money that Jessica has.

Jessica =

Shaun =

Chris =

Carmen =

Carmen is the answer.

Apply the distributive property:

The answer shows that the 3 in front of the has been cancelled, but not removed from the denomitator for the .

Apply the distributive property:

Apply the distributive property:

Apply the distributive property:

refers to the product of the three variables: .

To solve, you can use the commutative and associative properties of multiplication to group like-terms together.

The 4 and 3 should be first multiplied, resulting in 12.

Next should be multiplied by , giving us .

12 times is equal to .

Therefore, the correct answer is .

When simplifying this expression, the first step is to apply the distributive property.

Next, we assert whether the expression can be reduced further. It cannot, as there are no like-terms to combine.

Therefore, the correct answer is .

is fifty-five subtracted from .

is the product of nine and a number.

Subsequently, is "fifty-five subtracted from the product of nine and a number".

By the order of operations, the operation inside grouping symbols, which here is addition, takes precendence, followed by, in order, squaring and multiplication.

In modulo 8 arithmetic, a number is congruent to the remainder of the divison of that number by 8. Since

and

then

.

The correct response is 4.

When multiplying like variables, the constants are multiplied together.

For the exponents, when you multply variable exponents you have to add the exponents together.

and so that gives you an answer of .

When multiplying variables with exponents, add the exponents.

The correct answer is

When multiplying variables with exponents the exponents are added.

The correct answer is

The answer shows that the 3 in front of the has been cancelled, but not removed from the denomitator for the .

Apply the distributive property:

Apply the distributive property:

Apply the distributive property: