SAT Math Flashcards: Solving Nonlinear Functions

Study Solving Nonlinear Functions in SAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

SAT Math

Solving Nonlinear Functions

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QUESTION
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Identify the axis of symmetry for y=x2+6x+5y = x^2 + 6x + 5.

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ANSWER

x=3x = -3. Use formula x=b2a=62(1)=3x = -\frac{b}{2a} = -\frac{6}{2(1)} = -3.

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This deck focuses on Solving Nonlinear Functions, giving you a quick way to review the definitions, rules, and examples that matter most for SAT Math.

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Flashcard 1: Identify the axis of symmetry for y=x2+6x+5y = x^2 + 6x + 5.

Answer: x=3x = -3. Use formula x=b2a=62(1)=3x = -\frac{b}{2a} = -\frac{6}{2(1)} = -3.

Flashcard 2: What is the effect of a<0a < 0 in y=a(xh)2+ky = a(x-h)^2 + k?

Answer: Parabola opens downward. Negative coefficient makes parabola open downward.

Flashcard 3: Identify the roots of x26x+9=0x^2 - 6x + 9 = 0.

Answer: x=3x = 3. Perfect square: (x3)2=0(x-3)^2 = 0 has repeated root.

Flashcard 4: What is the effect of a>0a > 0 in y=a(xh)2+ky = a(x-h)^2 + k?

Answer: Parabola opens upward. Positive coefficient makes parabola open upward.

Flashcard 5: What does the discriminant b24acb^2 - 4ac indicate about roots?

Answer: Number and type of roots. Determines number of real roots and their nature.

Flashcard 6: Which form is y=a(xh)2+ky = a(x-h)^2 + k?

Answer: Vertex form. Form that shows vertex (h,k)(h,k) and transformations.

Flashcard 7: Convert the quadratic y=2x2+8x+6y = 2x^2 + 8x + 6 to vertex form.

Answer: y=2(x+2)22y = 2(x+2)^2 - 2. Complete the square: factor out 2, then add/subtract 4.

Flashcard 8: If y=x2+2x+1y = x^2 + 2x + 1, what is the axis of symmetry?

Answer: x=1x = -1. Perfect square: (x+1)2(x+1)^2, so axis is x=1x = -1.

Flashcard 9: Convert y=x2+6x+9y = x^2 + 6x + 9 to vertex form.

Answer: y=(x+3)2y = (x+3)^2. Perfect square: (x+3)2=x2+6x+9(x+3)^2 = x^2 + 6x + 9.

Flashcard 10: What is the solution to 4x24x+1=04x^2 - 4x + 1 = 0?

Answer: x=12x = \frac{1}{2}. Perfect square: (2x1)2=0(2x-1)^2 = 0 gives x=12x = \frac{1}{2}.

Flashcard 11: Find the roots of x25x+6=0x^2 - 5x + 6 = 0 using factoring.

Answer: x=2,x=3x = 2, x = 3. Factors as (x2)(x3)=0(x-2)(x-3) = 0, so x=2x = 2 or x=3x = 3.

Flashcard 12: State the relationship between roots and factors of a quadratic.

Answer: Roots are solutions; factors are (xr1)(xr2)(x - r_1)(x - r_2). If roots are r1,r2r_1, r_2, then factors are (xr1)(xr2)(x-r_1)(x-r_2).

Flashcard 13: What is the solution for 4x2=164x^2 = 16?

Answer: x=2x = 2 or x=2x = -2. Divide by 4: x2=4x^2 = 4, so x=±2x = \pm 2.

Flashcard 14: State the quadratic formula.

Answer: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Standard formula for solving quadratic equations.

Flashcard 15: What is the discriminant in the quadratic formula?

Answer: b24acb^2 - 4ac. Expression under the square root that determines root types.

Flashcard 16: Convert y=x2+4x+4y = x^2 + 4x + 4 to vertex form.

Answer: y=(x+2)2y = (x+2)^2. Complete the square: (x+2)2=x2+4x+4(x+2)^2 = x^2 + 4x + 4.

Flashcard 17: What is the solution for 4x2=164x^2 = 16?

Answer: x=2x = 2 or x=2x = -2. Divide by 4: x2=4x^2 = 4, so x=±2x = \pm 2.

Flashcard 18: What is the standard form of a quadratic equation?

Answer: ax2+bx+c=0ax^2 + bx + c = 0. General form with degree 2 polynomial set to zero.

Flashcard 19: Determine the nature of roots for x2+2x+5=0x^2 + 2x + 5 = 0.

Answer: Complex. Discriminant 420=16<04 - 20 = -16 < 0 means complex roots.

Flashcard 20: What is the vertex of y=x22x+1y = x^2 - 2x + 1?

Answer: (1,0)(1, 0). Perfect square: (x1)2(x-1)^2 has vertex at (1,0)(1,0).

Flashcard 21: Identify the discriminant of x2+4x+4=0x^2 + 4x + 4 = 0.

Answer: 00. Calculate b24ac=1616=0b^2 - 4ac = 16 - 16 = 0.

Flashcard 22: Convert y=x2+4x+4y = x^2 + 4x + 4 to vertex form.

Answer: y=(x+2)2y = (x+2)^2. Complete the square: (x+2)2=x2+4x+4(x+2)^2 = x^2 + 4x + 4.

Flashcard 23: Solve for xx: x2+9=0x^2 + 9 = 0.

Answer: x=3ix = 3i or x=3ix = -3i. Take square root: x2=9x^2 = -9, so x=±3ix = \pm 3i.

Flashcard 24: Which form is y=a(xp)(xq)y = a(x-p)(x-q)?

Answer: Factored form. Shows roots pp and qq directly as factors.

Flashcard 25: What is a nonlinear function?

Answer: A function that is not a straight line. Graph is not a straight line (degree > 1).

Flashcard 26: Solve for xx: x2+6x+9=0x^2 + 6x + 9 = 0 using the square root method.

Answer: x=3x = -3. Perfect square trinomial: (x+3)2=0(x+3)^2 = 0, so x=3x = -3.

Flashcard 27: Find the discriminant of x24x+4=0x^2 - 4x + 4 = 0.

Answer: 00. Calculate b24ac=1616=0b^2 - 4ac = 16 - 16 = 0.

Flashcard 28: Identify the maximum or minimum value of y=(x2)2+5y = (x-2)^2 + 5.

Answer: Minimum: 55. Since a>0a > 0, parabola opens up with minimum at vertex.

Flashcard 29: What is the sum of the roots of ax2+bx+c=0ax^2 + bx + c = 0?

Answer: ba-\frac{b}{a}. Vieta's formula for sum of roots.

Flashcard 30: Identify the discriminant of x2+4x+4=0x^2 + 4x + 4 = 0.

Answer: 00. Calculate b24ac=1616=0b^2 - 4ac = 16 - 16 = 0.

Flashcard 31: Determine the nature of roots for x2+2x+5=0x^2 + 2x + 5 = 0.

Answer: Complex. Discriminant 420=16<04 - 20 = -16 < 0 means complex roots.

Flashcard 32: Find the vertex of y=x2+6x9y = -x^2 + 6x - 9.

Answer: (3,0)(3, 0). Perfect square: (x3)2-(x-3)^2 has vertex at (3,0)(3,0).

Flashcard 33: State the quadratic formula used to solve ax2+bx+c=0ax^2 + bx + c = 0.

Answer: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Derived by completing the square on the general quadratic form.

Flashcard 34: What is the solution to 4x24x+1=04x^2 - 4x + 1 = 0?

Answer: x=12x = \frac{1}{2}. Perfect square: (2x1)2=0(2x-1)^2 = 0 gives x=12x = \frac{1}{2}.

Flashcard 35: What is the vertex of y=2(x+3)2+4y = -2(x+3)^2 + 4?

Answer: (3,4)(-3, 4). Vertex form shows (h,k)=(3,4)(h,k) = (-3,4) directly.

Flashcard 36: What is the standard form equation of a quadratic function?

Answer: ax2+bx+c=0ax^2 + bx + c = 0. General form where a0a \neq 0 defines any quadratic equation.

Flashcard 37: State the quadratic formula.

Answer: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Standard formula for solving quadratic equations.

Flashcard 38: Find the roots of x25x+6=0x^2 - 5x + 6 = 0 using factoring.

Answer: x=2,x=3x = 2, x = 3. Factors as (x2)(x3)=0(x-2)(x-3) = 0, so x=2x = 2 or x=3x = 3.

Flashcard 39: Identify the axis of symmetry for y=x2+6x+5y = x^2 + 6x + 5.

Answer: x=3x = -3. Use formula x=b2a=62(1)=3x = -\frac{b}{2a} = -\frac{6}{2(1)} = -3.

Flashcard 40: State the relationship between roots and factors of a quadratic.

Answer: Roots are solutions; factors are (xr1)(xr2)(x - r_1)(x - r_2). If roots are r1,r2r_1, r_2, then factors are (xr1)(xr2)(x-r_1)(x-r_2).

Flashcard 41: Find the roots of x25x+6=0x^2 - 5x + 6 = 0.

Answer: x=2x = 2 or x=3x = 3. Factor: (x2)(x3)=0(x-2)(x-3) = 0 gives roots.

Flashcard 42: Which form is y=a(xp)(xq)y = a(x-p)(x-q)?

Answer: Factored form. Shows roots pp and qq directly as factors.

Flashcard 43: Solve for xx: x29=0x^2 - 9 = 0.

Answer: x=3x = 3 or x=3x = -3. Difference of squares: (x3)(x+3)=0(x-3)(x+3) = 0.

Flashcard 44: What are the roots of x21=0x^2 - 1 = 0?

Answer: x=1x = 1 or x=1x = -1. Difference of squares: (x1)(x+1)=0(x-1)(x+1) = 0.

Flashcard 45: Solve for xx: x24=0x^2 - 4 = 0.

Answer: x=2x = 2 or x=2x = -2. Factor as difference of squares: (x2)(x+2)=0(x-2)(x+2) = 0.

Flashcard 46: Solve for xx: x2+6x+9=0x^2 + 6x + 9 = 0 using the square root method.

Answer: x=3x = -3. Perfect square trinomial: (x+3)2=0(x+3)^2 = 0, so x=3x = -3.

Flashcard 47: Identify the roots of x26x+9=0x^2 - 6x + 9 = 0.

Answer: x=3x = 3. Perfect square: (x3)2=0(x-3)^2 = 0 has repeated root.

Flashcard 48: Identify the vertex form of a quadratic function.

Answer: y=a(xh)2+ky = a(x-h)^2 + k. Shows vertex (h,k)(h,k) and stretch factor aa explicitly.

Flashcard 49: What is the product of the roots of ax2+bx+c=0ax^2 + bx + c = 0?

Answer: ca\frac{c}{a}. Vieta's formula for product of roots.

Flashcard 50: Convert the quadratic y=2x2+8x+6y = 2x^2 + 8x + 6 to vertex form.

Answer: y=2(x+2)22y = 2(x+2)^2 - 2. Complete the square: factor out 2, then add/subtract 4.

Flashcard 51: Which method can solve x2+4x+4=0x^2 + 4x + 4 = 0 besides factoring?

Answer: Completing the square. Transforms equation to perfect square trinomial form.

Flashcard 52: Find the value of xx in x2+4x+4=0x^2 + 4x + 4 = 0.

Answer: x=2x = -2. Perfect square: (x+2)2=0(x+2)^2 = 0 gives x=2x = -2.

Flashcard 53: What does a positive discriminant indicate about a quadratic's roots?

Answer: Two distinct real roots. When b24ac>0b^2 - 4ac > 0, the parabola crosses the x-axis twice.

Flashcard 54: What is the vertex form of a quadratic function?

Answer: y=a(xh)2+ky = a(x-h)^2 + k. Shows vertex (h,k)(h,k) and vertical shifts/stretches.

Flashcard 55: What is the discriminant in the quadratic formula?

Answer: b24acb^2 - 4ac. Expression under the square root that determines root types.

Flashcard 56: What is the standard form of a quadratic equation?

Answer: ax2+bx+c=0ax^2 + bx + c = 0. General form with degree 2 polynomial set to zero.

Flashcard 57: What is a nonlinear function?

Answer: A function that is not a straight line. Graph is not a straight line (degree > 1).

Flashcard 58: For y=3(x4)27y = 3(x-4)^2 - 7, what is the vertex?

Answer: (4,7)(4, -7). Vertex form shows (h,k)=(4,7)(h,k) = (4,-7) directly.

Flashcard 59: Convert y=x2+6x+9y = x^2 + 6x + 9 to vertex form.

Answer: y=(x+3)2y = (x+3)^2. Perfect square: (x+3)2=x2+6x+9(x+3)^2 = x^2 + 6x + 9.

Flashcard 60: Find the vertex of y=x2+6x9y = -x^2 + 6x - 9.

Answer: (3,0)(3, 0). Perfect square: (x3)2-(x-3)^2 has vertex at (3,0)(3,0).

Flashcard 61: Solve for xx: x24=0x^2 - 4 = 0.

Answer: x=2x = 2 or x=2x = -2. Factor as difference of squares: (x2)(x+2)=0(x-2)(x+2) = 0.

Flashcard 62: What is the degree of a quadratic function?

Answer:

  1. Highest power of variable is 2.

Flashcard 63: What type of solutions does a quadratic have if the discriminant is negative?

Answer: Complex solutions. Negative discriminant means no real roots.

Flashcard 64: What does a positive discriminant indicate about a quadratic's roots?

Answer: Two distinct real roots. When b24ac>0b^2 - 4ac > 0, the parabola crosses the x-axis twice.

Flashcard 65: What is the vertex of y=2(x+3)2+4y = -2(x+3)^2 + 4?

Answer: (3,4)(-3, 4). Vertex form shows (h,k)=(3,4)(h,k) = (-3,4) directly.

Flashcard 66: What is the effect of a<0a < 0 in y=a(xh)2+ky = a(x-h)^2 + k?

Answer: Parabola opens downward. Negative coefficient makes parabola open downward.

Flashcard 67: Find the vertex of y=2(x3)2+4y = 2(x - 3)^2 + 4.

Answer: Vertex: (3,4)(3, 4). In vertex form, (h,k)(h,k) gives the vertex coordinates directly.

Flashcard 68: For y=(x1)2+3y = (x-1)^2 + 3, identify the vertex.

Answer: (1,3)(1, 3). Vertex form shows (h,k)=(1,3)(h,k) = (1,3) directly.

Flashcard 69: If y=x2+2x+1y = x^2 + 2x + 1, what is the axis of symmetry?

Answer: x=1x = -1. Perfect square: (x+1)2(x+1)^2, so axis is x=1x = -1.

Flashcard 70: Find the roots of x25x+6=0x^2 - 5x + 6 = 0.

Answer: x=2x = 2 or x=3x = 3. Factor: (x2)(x3)=0(x-2)(x-3) = 0 gives roots.

Flashcard 71: Convert y=x24x+6y = x^2 - 4x + 6 to vertex form.

Answer: y=(x2)2+2y = (x-2)^2 + 2. Complete the square: (x2)2=x24x+4(x-2)^2 = x^2 - 4x + 4.

Flashcard 72: What are the roots of x21=0x^2 - 1 = 0?

Answer: x=1x = 1 or x=1x = -1. Difference of squares: (x1)(x+1)=0(x-1)(x+1) = 0.

Flashcard 73: Find the vertex of y=2(x3)2+4y = 2(x - 3)^2 + 4.

Answer: Vertex: (3,4)(3, 4). In vertex form, (h,k)(h,k) gives the vertex coordinates directly.

Flashcard 74: What type of solutions does a quadratic have if the discriminant is negative?

Answer: Complex solutions. Negative discriminant means no real roots.

Flashcard 75: What is the product of the roots of ax2+bx+c=0ax^2 + bx + c = 0?

Answer: ca\frac{c}{a}. Vieta's formula for product of roots.

Flashcard 76: Identify the maximum or minimum value of y=(x2)2+5y = (x-2)^2 + 5.

Answer: Minimum: 55. Since a>0a > 0, parabola opens up with minimum at vertex.

Flashcard 77: Which form is y=a(xh)2+ky = a(x-h)^2 + k?

Answer: Vertex form. Form that shows vertex (h,k)(h,k) and transformations.

Flashcard 78: State the quadratic formula used to solve ax2+bx+c=0ax^2 + bx + c = 0.

Answer: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Derived by completing the square on the general quadratic form.

Flashcard 79: Find the value of xx in x2+4x+4=0x^2 + 4x + 4 = 0.

Answer: x=2x = -2. Perfect square: (x+2)2=0(x+2)^2 = 0 gives x=2x = -2.

Flashcard 80: Find the axis of symmetry for y=2x2+4x+1y = 2x^2 + 4x + 1.

Answer: x=1x = -1. Use x=b2a=42(2)=1x = -\frac{b}{2a} = -\frac{4}{2(2)} = -1.

Flashcard 81: Solve for xx: x2+9=0x^2 + 9 = 0.

Answer: x=3ix = 3i or x=3ix = -3i. Take square root: x2=9x^2 = -9, so x=±3ix = \pm 3i.

Flashcard 82: For y=(x1)2+3y = (x-1)^2 + 3, identify the vertex.

Answer: (1,3)(1, 3). Vertex form shows (h,k)=(1,3)(h,k) = (1,3) directly.

Flashcard 83: For y=3(x4)27y = 3(x-4)^2 - 7, what is the vertex?

Answer: (4,7)(4, -7). Vertex form shows (h,k)=(4,7)(h,k) = (4,-7) directly.

Flashcard 84: What is the vertex form of a quadratic function?

Answer: y=a(xh)2+ky = a(x-h)^2 + k. Shows vertex (h,k)(h,k) and vertical shifts/stretches.

Flashcard 85: What is the degree of a quadratic function?

Answer:

  1. Highest power of variable is 2.

Flashcard 86: What does the discriminant b24acb^2 - 4ac indicate about roots?

Answer: Number and type of roots. Determines number of real roots and their nature.

Flashcard 87: What is the effect of a>0a > 0 in y=a(xh)2+ky = a(x-h)^2 + k?

Answer: Parabola opens upward. Positive coefficient makes parabola open upward.

Flashcard 88: What is the vertex of y=x22x+1y = x^2 - 2x + 1?

Answer: (1,0)(1, 0). Perfect square: (x1)2(x-1)^2 has vertex at (1,0)(1,0).

Flashcard 89: Identify the vertex form of a quadratic function.

Answer: y=a(xh)2+ky = a(x-h)^2 + k. Shows vertex (h,k)(h,k) and stretch factor aa explicitly.

Flashcard 90: Find the discriminant of x24x+4=0x^2 - 4x + 4 = 0.

Answer: 00. Calculate b24ac=1616=0b^2 - 4ac = 16 - 16 = 0.

Flashcard 91: For y=x24x+4y = x^2 - 4x + 4, determine the axis of symmetry.

Answer: x=2x = 2. Axis of symmetry is x=b2a=42(1)=2x = -\frac{b}{2a} = -\frac{-4}{2(1)} = 2.

Flashcard 92: What is the sum of the roots of ax2+bx+c=0ax^2 + bx + c = 0?

Answer: ba-\frac{b}{a}. Vieta's formula for sum of roots.