PSAT Math Flashcards: Systems Of Polynomial Equations

Study Systems Of Polynomial Equations in PSAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

PSAT Math

Systems Of Polynomial Equations

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What is the elimination step when two equations are equal to yy, such as y=f(x)y=f(x) and y=g(x)y=g(x)?

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ANSWER

Subtract to get f(x)g(x)=0f(x)-g(x)=0. This creates a single equation to find where curves intersect.

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This deck focuses on Systems Of Polynomial Equations, giving you a quick way to review the definitions, rules, and examples that matter most for PSAT Math.

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Flashcard 1: What is the elimination step when two equations are equal to yy, such as y=f(x)y=f(x) and y=g(x)y=g(x)?

Answer: Subtract to get f(x)g(x)=0f(x)-g(x)=0. This creates a single equation to find where curves intersect.

Flashcard 2: What should you do after finding possible xx-values from substitution in a system?

Answer: Substitute back to find yy and verify. Find corresponding yy-values and check both equations are satisfied.

Flashcard 3: Identify the best first step to solve y=2x+1y=2x+1 and x2+y2=5x^2+y^2=5 using substitution.

Answer: Substitute y=2x+1y=2x+1 into x2+y2=5x^2+y^2=5. Replace yy in the circle equation to get a quadratic in xx.

Flashcard 4: Solve the system y=x21y=x^2-1 and y=0y=0; what are the solution points?

Answer: (1,0)(1,0) and (1,0)(-1,0). Set x21=0x^2-1=0: (x1)(x+1)=0(x-1)(x+1)=0, so x=pm1x=pm 1.

Flashcard 5: Solve the system y=x2y=x^2 and x+y=6x+y=6 for (x,y)(x,y).

Answer: (2,4)(2,4) and (3,9)(-3,9). Substitute y=6xy=6-x into y=x2y=x^2 to get x2+x6=0x^2+x-6=0.

Flashcard 6: What are the intersection points of y=x2+1y=x^2+1 and y=2x+1y=2x+1?

Answer: (0,1)(0,1) and (2,5)(2,5). Set x2+1=2x+1x^2+1=2x+1, which gives same xx-values as x2=2xx^2=2x.

Flashcard 7: Solve the system x2+y2=4x^2+y^2=4 and x=0x=0 for all solutions (x,y)(x,y).

Answer: (0,2)(0,-2) and (0,2)(0,2). Substitute x=0x=0 into circle equation: y2=4y^2=4, so y=±2y=\pm 2.

Flashcard 8: What substitution step is used if a system includes y=f(x)y=f(x) and another equation in xx and yy?

Answer: Replace yy with f(x)f(x) in the other equation. This substitution eliminates yy to solve for xx first.

Flashcard 9: What is the substitution method for a system like y=f(x)y=f(x) and y=g(x)y=g(x)?

Answer: Set f(x)=g(x)f(x)=g(x), solve for xx, then find yy. Since both equal yy, set right sides equal to eliminate yy.

Flashcard 10: Identify the intersection points of y=x2y=x^2 and y=x+2y=x+2.

Answer: (1,1)(-1,1) and (2,4)(2,4). Substitute to get x2=x+2x^2=x+2; solve x2x2=0x^2-x-2=0.

Flashcard 11: Solve the system y=x2+1y=x^2+1 and y=2xy=2x; what are the solutions?

Answer: (1,2)(1,2). x2+1=2xx^2+1=2x gives x22x+1=0x^2-2x+1=0, so (x1)2=0(x-1)^2=0.

Flashcard 12: Find kk so the system y=x2y=x^2 and y=2x+ky=2x+k has exactly one real solution.

Answer: k=1k=-1. Line tangent to parabola when discriminant of x22xk=0x^2-2x-k=0 equals zero.

Flashcard 13: Solve the system y=x2y=x^2 and y=xy=-x; what are the solutions?

Answer: (0,0)(0,0) and (1,1)(-1,1). x2=xx^2=-x gives x2+x=0x^2+x=0, so x(x+1)=0x(x+1)=0.

Flashcard 14: What does it mean if substitution gives a contradiction such as 0=50=5?

Answer: No solution. The equations contradict each other, so no point satisfies both.

Flashcard 15: What is the elimination method for a polynomial system when terms can be canceled by adding equations?

Answer: Multiply as needed, then add or subtract equations to eliminate a variable. Scale equations so matching terms cancel when combined.

Flashcard 16: What method solves a system by adding or subtracting equations to eliminate a variable?

Answer: Elimination. Add/subtract equations to cancel out a variable.

Flashcard 17: Find the solutions to the system y=x+1y=x+1 and y2=4y^2=4.

Answer: (3,2)(-3,-2) and (1,2)(1,2). From y2=4y^2=4, y=pm2y=pm^2, then find xx values.

Flashcard 18: Solve the system y=x24x+3y=x^2-4x+3 and y=0y=0; what are the solutions?

Answer: (1,0)(1,0) and (3,0)(3,0). Factor: (x1)(x3)=0(x-1)(x-3)=0 gives x=1,3x=1,3 with y=0y=0.

Flashcard 19: Identify the intersection points of y=x2y=x^2 and y=4y=4.

Answer: (2,4)(2,4) and (2,4)(-2,4). Set x2=4x^2=4, so x=pm2x=pm 2 with y=4y=4 for both.

Flashcard 20: What is the solution to the system x2+y2=25x^2+y^2=25 and y=0y=0?

Answer: (5,0)(-5,0) and (5,0)(5,0). Circle intersects xx-axis where x2+02=25x^2+0^2=25.

Flashcard 21: What equation represents the xx-coordinates of intersection points of y=f(x)y=f(x) and y=g(x)y=g(x)?

Answer: Solve f(x)g(x)=0f(x)-g(x)=0 for xx. Rearranging gives the equation whose roots are x-coordinates.

Flashcard 22: What does it mean if two polynomial equations have no real solution as a system?

Answer: Their graphs have no real intersection points. The curves don't touch or cross in the real coordinate plane.

Flashcard 23: What is the standard elimination step if you have p(x,y)=0p(x,y)=0 and q(x,y)=0q(x,y)=0 and one equation is linear in yy?

Answer: Solve the linear equation for yy and substitute into the other. This reduces the system to a single-variable equation.

Flashcard 24: Solve the system x2+y2=25x^2+y^2=25 and y=0y=0; what are the solution points?

Answer: (5,0)(-5,0) and (5,0)(5,0). Circle intersects xx-axis where x2+02=25x^2+0^2=25.

Flashcard 25: What are the xx-values of intersection for y=x2y=x^2 and y=4y=4?

Answer: x=2x=-2 and x=2x=2. Solve x2=4x^2=4 to get x=pm2x=pm 2.

Flashcard 26: What does each solution (x,y)(x,y) of a polynomial system represent on a graph?

Answer: An intersection point of the graphs. Solutions occur where the curves meet.

Flashcard 27: What is the degree of the equation formed by substituting a linear equation into a cubic?

Answer: Degree 33 (a cubic in one variable). Linear substituted into cubic yields cubic.

Flashcard 28: What is the first step to solve y=x2+1y=x^2+1 and y=2x+1y=2x+1 by substitution?

Answer: Set x2+1=2x+1x^2+1=2x+1. Since both equal yy, set the right sides equal.

Flashcard 29: Identify the solution set of {y=2x+1y=x2+1\begin{cases}y=2x+1\\y=x^2+1\end{cases}.

Answer: {(0,1),(2,5)}\{(0,1),(2,5)\}. Set 2x+1=x2+12x+1=x^2+1: x22x=0x^2-2x=0, factor to x(x2)=0x(x-2)=0.

Flashcard 30: What is the standard substitution step after solving one equation for yy in a system?

Answer: Replace yy in the other equation with that expression, then solve for xx. Substitution eliminates one variable by replacement.

Flashcard 31: What is the result of substituting y=2x3y=2x-3 into x2+y2=13x^2+y^2=13 (single equation in xx)?

Answer: x2+(2x3)2=13x^2+(2x-3)^2=13. Direct substitution expands to x2+4x212x+9=13x^2+4x^2-12x+9=13.

Flashcard 32: What is the discriminant condition for exactly one intersection of y=ax2+bx+cy=ax^2+bx+c and y=mx+ny=mx+n?

Answer: After setting equal, discriminant Δ=0\Delta=0. One solution means the resulting quadratic has discriminant zero.

Flashcard 33: What is the solution to the system y=x24y=x^2-4 and y=0y=0?

Answer: (2,0)(-2,0) and (2,0)(2,0). Find where parabola crosses xx-axis by solving x24=0x^2-4=0.

Flashcard 34: Identify the solution set of {y=x2y=x+2\begin{cases}y=x^2\\y=x+2\end{cases}.

Answer: {(1,1),(2,4)}\{(-1,1),(2,4)\}. Set x2=x+2x^2=x+2: x2x2=0x^2-x-2=0, factor to (x2)(x+1)=0(x-2)(x+1)=0.

Flashcard 35: Find the solutions to the system x+y=5x+y=5 and xy=6xy=6.

Answer: (2,3)(2,3) and (3,2)(3,2). Solve quadratic x25x+6=0x^2-5x+6=0 from substitution.

Flashcard 36: What is the degree of the equation formed by eliminating yy between a line and a parabola?

Answer: Degree 22. Line has degree 1, parabola has degree 2; product is 2.

Flashcard 37: What are the intersection points of y=x2y=x^2 and y=4y=4?

Answer: (2,4)(-2,4) and (2,4)(2,4). Substitute x=pm2x=pm 2 into either equation to get y=4y=4.

Flashcard 38: What are the intersection points of y=x2y=x^2 and y=x2+1y=x^2+1?

Answer: No solution (it would require 0=10=1). Parallel parabolas never intersect.

Flashcard 39: What is the maximum possible number of real intersections of a line and a quadratic?

Answer: At most 22 real intersection points. A line crosses a parabola at most twice.

Flashcard 40: What do you do after finding an xx-value from f(x)=g(x)f(x)=g(x) in a system y=f(x)y=f(x), y=g(x)y=g(x)?

Answer: Substitute xx into either equation to find the matching yy. Use the xx-value in either original equation to get yy.

Flashcard 41: Solve the system x2+y2=1x^2+y^2=1 and y=0y=0 for all solutions (x,y)(x,y).

Answer: (1,0)(-1,0) and (1,0)(1,0). Substitute y=0y=0 into circle equation: x2=1x^2=1, so x=±1x=\pm 1.

Flashcard 42: What method solves a system by adding multiples of equations to eliminate a variable?

Answer: Elimination (linear combination). Add/subtract equations to cancel out a variable term.

Flashcard 43: Identify the maximum number of real intersection points of a line and a parabola.

Answer: 22. A line can intersect a parabola at most twice.

Flashcard 44: What are the solution points to y=x2y=x^2 and y=1y=-1?

Answer: No real solutions. Since x20x^2 \geq 0, it can never equal 1-1.

Flashcard 45: Identify the solution set of {y=x24y=0\begin{cases}y=x^2-4\\y=0\end{cases}.

Answer: {(2,0),(2,0)}\{(-2,0),(2,0)\}. Set x24=0x^2-4=0: x2=4x^2=4, so x=±2x=\pm 2.

Flashcard 46: Solve the system y=x2y=x^2 and y=x2+1y=x^2+1; how many solutions are there?

Answer: 00 solutions. Parallel parabolas (same shape, shifted vertically) never intersect.

Flashcard 47: What is the first step to solve the system y=x2y=x^2 and y=2x+3y=2x+3 algebraically?

Answer: Set x2=2x+3x^2=2x+3. Since both equal yy, equate the right-hand sides.

Flashcard 48: What are the solutions to the system y=x2y=x^2 and y=2xy=2x?

Answer: (0,0)(0,0) and (2,4)(2,4). Substitute x=0x=0 and x=2x=2 into either equation for yy.

Flashcard 49: What are the solution points to y=x2+1y=x^2+1 and y=1y=1?

Answer: (0,1)(0,1). Solve x2+1=1x^2+1=1: only x=0x=0 works.

Flashcard 50: What does it mean if f(x)g(x)f(x)-g(x) has no real roots when solving f(x)=g(x)f(x)=g(x)?

Answer: No real intersection points; the system has no real solutions. The curves never meet in the real plane.

Flashcard 51: What are the intersection points of y=x2y=x^2 and y=xy=-x?

Answer: (0,0)(0,0) and (1,1)(-1,1). Solve x2=xx^2=-x to get x2+x=0x^2+x=0, so x(x+1)=0x(x+1)=0.

Flashcard 52: What method solves a system by replacing one variable using an equation like y=x2y=x^2?

Answer: Substitution. Replace one variable with its expression from another equation.

Flashcard 53: What are the intersection points of y=x2y=x^2 and y=2xy=2x?

Answer: (0,0)(0,0) and (2,4)(2,4). Substitute x=0x=0 and x=2x=2 into either equation to find yy.

Flashcard 54: Solve the system y=(x1)2y=(x-1)^2 and y=x+1y=x+1 for (x,y)(x,y).

Answer: (1,2)(1,2) and (4,5)(4,5). Expand and set (x1)2=x+1(x-1)^2=x+1; solve x23x=0x^2-3x=0.

Flashcard 55: Solve the system y=x21y=x^2-1 and y=0y=0; what are the solutions?

Answer: (1,0)(1,0) and (1,0)(-1,0). x21=0x^2-1=0 gives x=±1x=\pm 1, then y=0y=0 for both.

Flashcard 56: Solve the system y=x2y=x^2 and y=xy=x for all solutions (x,y)(x,y).

Answer: (0,0)(0,0) and (1,1)(1,1). Set x2=xx^2=x to get x(x1)=0x(x-1)=0, so x=0x=0 or x=1x=1.

Flashcard 57: Solve the system y=2xy=2x and y=x2y=x^2 for all real solutions.

Answer: (0,0)(0,0) and (2,4)(2,4). Set 2x=x22x=x^2: x22x=x(x2)=0x^2-2x=x(x-2)=0, so x=0x=0 or x=2x=2.

Flashcard 58: Find the solution points to y=x2y=x^2 and y=2xy=2x.

Answer: (0,0)(0,0) and (2,4)(2,4). Solve x2=2xx^2=2x: x(x2)=0x(x-2)=0, giving x=0,2x=0,2.

Flashcard 59: What does it mean if f(x)g(x)f(x)-g(x) is the zero polynomial when solving f(x)=g(x)f(x)=g(x)?

Answer: Infinitely many solutions; the equations represent the same curve. The two equations describe identical curves.

Flashcard 60: Find the solutions to the system xy=1x-y=1 and x2y2=5x^2-y^2=5.

Answer: (3,2)(3,2). Factor as (x+y)(xy)=5(x+y)(x-y)=5 with xy=1x-y=1.

Flashcard 61: Solve the system y=x2+2y=x^2+2 and y=2x+2y=2x+2 for all solutions (x,y)(x,y).

Answer: (0,2)(0,2) and (2,6)(2,6). Set x2+2=2x+2x^2+2=2x+2 to get x22x=0x^2-2x=0, so x=0x=0 or x=2x=2.

Flashcard 62: What does it mean if f(x)g(x)f(x)-g(x) factors as (xa)2(x-a)^2 when solving f(x)=g(x)f(x)=g(x)?

Answer: x=ax=a is a double root; the graphs are tangent there. The curves touch but don't cross at x=ax=a.

Flashcard 63: What do the real solutions of a system f(x)=g(x)f(x)=g(x) represent on a graph?

Answer: The xx-coordinates of intersection points. Where the graphs intersect, their xx-values are the solutions.

Flashcard 64: Solve the system y=x2y=x^2 and x+y=0x+y=0; what are the solution points?

Answer: (0,0)(0,0) and (1,1)(-1,1). Substitute y=xy=-x into y=x2y=x^2: x=x2-x=x^2, so x2+x=0x^2+x=0.

Flashcard 65: Solve the system y=x22y=x^2-2 and y=xy=x; what are the solutions?

Answer: (1,1)(-1,-1) and (2,2)(2,2). x22=xx^2-2=x gives x2x2=0x^2-x-2=0, factoring to (x+1)(x2)=0(x+1)(x-2)=0.

Flashcard 66: Solve the system y=x2y=x^2 and y=2xy=2x; what are the solution points?

Answer: (0,0)(0,0) and (2,4)(2,4). From x2=2xx^2=2x: x(x2)=0x(x-2)=0, so x=0x=0 or x=2x=2.

Flashcard 67: What does a solution (x,y)(x,y) to a system of two polynomial equations represent on a graph?

Answer: An intersection point of the two graphs. Solutions occur where both curves meet.

Flashcard 68: Solve the system x+y=5x+y=5 and x2+y2=13x^2+y^2=13; what are the solution points?

Answer: (2,3)(2,3) and (3,2)(3,2). Substitute y=5xy=5-x into circle equation and solve quadratic.

Flashcard 69: What is the maximum possible number of real solutions to a system of two quadratic equations?

Answer: 44. Two parabolas can intersect at most 4 times.

Flashcard 70: Solve the system y=x2+2y=x^2+2 and y=xy=x; how many real solutions are there?

Answer: 00 real solutions. x2+2=xx^2+2=x gives x2x+2=0x^2-x+2=0; discriminant is negative.

Flashcard 71: What is the elimination step if you have y=f(x)y=f(x) and y=g(x)y=g(x) in a system?

Answer: Set f(x)=g(x)f(x)=g(x). Since both equal yy, set the expressions equal to each other.

Flashcard 72: Identify the first step to solve y=x2y=x^2 and y=2xy=2x using substitution.

Answer: Set x2=2xx^2=2x. Since both equal yy, equate the right sides.

Flashcard 73: Identify the number of real solutions to x2+y2=1x^2+y^2=1 and y=2y=2.

Answer: 00. Line y=2y=2 is outside unit circle centered at origin.

Flashcard 74: What does it mean if a system has exactly one real solution?

Answer: The graphs intersect at exactly one real point. This is the unique solution to the system.

Flashcard 75: Identify the polynomial equation in xx after eliminating yy: y=x2+1y=x^2+1 and y=3x2y=3x-2.

Answer: x2+1=3x2x^2+1=3x-2. Set the two yy-expressions equal to eliminate yy.

Flashcard 76: What are the solution points to y=x2y=x^2 and y=x2y=x^2?

Answer: Infinitely many solutions: all points on y=x2y=x^2. Identical equations mean every point on the curve satisfies both.

Flashcard 77: What is the maximum number of real intersection points between a line and a parabola?

Answer: At most 22. A quadratic equation has at most 2 real roots.

Flashcard 78: What are the solutions to the system x2+y2=25x^2+y^2=25 and y=0y=0?

Answer: (5,0)(-5,0) and (5,0)(5,0). Circle intersects xx-axis where x2=25x^2=25.

Flashcard 79: What method solves a system by setting y=f(x)y=f(x) from both equations and equating them?

Answer: Substitution: set f(x)=g(x)f(x)=g(x) after isolating the same variable. Both equations express y in terms of x, so equate the expressions.

Flashcard 80: What is the maximum number of real intersection points of y=x2y=x^2 and y=ax+by=ax+b?

Answer: 22. A parabola and line can intersect at most twice.

Flashcard 81: What is the maximum possible number of real intersection points of y=y= quadratic and y=y= cubic?

Answer: At most 33 real intersection points. A cubic minus a quadratic yields a cubic with at most 3 roots.

Flashcard 82: What is the maximum possible number of real intersections of y=x3y=x^3 and y=mx+by=mx+b?

Answer: 33. A cubic and line can intersect at most three times.

Flashcard 83: What is the substitution step if you have y=x2y=x^2 and y=2x+3y=2x+3?

Answer: Set x2=2x+3x^2=2x+3. Substitute to eliminate yy since both expressions equal yy.

Flashcard 84: What are the xx-values solving the system y=x2y=x^2 and y=2xy=2x?

Answer: x=0x=0 or x=2x=2. Solve x2=2xx^2=2x: x(x2)=0x(x-2)=0.

Flashcard 85: Solve the system x2+y2=25x^2+y^2=25 and y=4y=4 for (x,y)(x,y).

Answer: (3,4)(3,4) and (3,4)(-3,4). Substitute y=4y=4 into the circle equation: x2+16=25x^2+16=25.

Flashcard 86: What are the xx-values of solutions to y=x2y=x^2 and y=xy=x?

Answer: x=0x=0 or x=1x=1. Solve x2=xx^2=x: x(x1)=0x(x-1)=0.

Flashcard 87: What does it mean if two polynomial equations have infinitely many solutions as a system?

Answer: The equations define the same curve (are equivalent). One equation is a multiple of the other, so they're the same curve.

Flashcard 88: Identify the solutions to x2+y2=25x^2+y^2=25 and y=0y=0.

Answer: (5,0)(5,0) and (5,0)(-5,0). Circle intersects x-axis where x2=25x^2=25.

Flashcard 89: Solve the system y=x2+1y=x^2+1 and y=x2+1y=x^2+1; how many solutions are there?

Answer: Infinitely many solutions. Identical equations represent the same curve.

Flashcard 90: Identify the number of real intersections if x2+1=xx^2+1=x.

Answer: 00 real intersections. Rearranging gives x2x+1=0x^2-x+1=0 with negative discriminant.

Flashcard 91: What is the solution set to the system y=x2y=x^2 and y=x2y=x^2?

Answer: Infinitely many solutions: all points on y=x2y=x^2. Same equation twice means every point on curve satisfies both.

Flashcard 92: What are the solutions to the system x2+y2=1x^2+y^2=1 and y=0y=0?

Answer: (1,0)(1,0) and (1,0)(-1,0). Substitute y=0y=0 into circle equation: x2=1x^2=1.

Flashcard 93: Identify the system's solutions in the coordinate plane when y=f(x)y=f(x) and y=g(x)y=g(x) are given.

Answer: All intersection points (x,y)(x,y) of the two graphs. Solutions occur where the curves meet in the plane.

Flashcard 94: Identify the best first step to solve the system y=x2+1y=x^2+1 and y=3x+1y=3x+1.

Answer: Set x2+1=3x+1x^2+1=3x+1. Since both equal yy, set the expressions equal.

Flashcard 95: Solve the system x2+y2=25x^2+y^2=25 and y=3y=3; what are the solution points?

Answer: (4,3)(4,3) and (4,3)(-4,3). Substitute y=3y=3: x2+9=25x^2+9=25, so x2=16x^2=16, x=±4x=±4.

Flashcard 96: What are the solution points to y=x2y=x^2 and y=xy=-x?

Answer: (0,0)(0,0) and (1,1)(-1,1). Solve x2=xx^2=-x: x(x+1)=0x(x+1)=0, so x=0x=0 or x=1x=-1.

Flashcard 97: Identify the number of solutions if the system is y=x2+2x+1y=x^2+2x+1 and y=(x+1)2y=(x+1)^2.

Answer: Infinitely many solutions. Both equations represent the same parabola: (x+1)2=x2+2x+1(x+1)^2=x^2+2x+1.

Flashcard 98: Identify the degree of the equation formed after substitution: y=x2y=x^2 into y=3x+1y=3x+1.

Answer: 22 (it becomes x2=3x+1x^2=3x+1). Substituting gives x2=3x+1x^2=3x+1, which has degree 2.

Flashcard 99: Which equation in xx results from eliminating yy in x+y=5x+y=5 and xy=6xy=6?

Answer: x(5x)=6x(5-x)=6. Substitute y=5xy=5-x from first equation into second equation xy=6xy=6.

Flashcard 100: Identify the number of real solutions to y=x2y=x^2 and y=1y=1.

Answer: 22. Solve x2=1x^2=1 to get x=pm1x=pm 1.