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This deck focuses on Using Matrices To Represent Manipulate Data, giving you a quick way to review the definitions, rules, and examples that matter most for Precalculus.
Study Using Matrices To Represent Manipulate Data in Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Identify whether AB is defined if A is 2×3 and B is 2×2.
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Not defined, since 3=2 for the inner dimensions. Column count of A doesn't match row count of B.
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This deck focuses on Using Matrices To Represent Manipulate Data, giving you a quick way to review the definitions, rules, and examples that matter most for Precalculus.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Not defined, since 3=2 for the inner dimensions. Column count of A doesn't match row count of B.
Answer: [−20610]. Multiply each entry by 2: 2(−1)=−2, 2(3)=6, 2(0)=0, 2(5)=10.
Answer: AB is m×p. Product dimensions: outer dimensions of the factors.
Answer: In column e: −1 at row u, +1 at row v, and 0 elsewhere. Shows edge direction: −1 at source, +1 at destination.
Answer: A−1=ad−bc1[d−c−ba]. Formula uses determinant ad−bc and swapped/negated entries.
Answer: [02]. 1(2)+2(−1)=0 and 3(2)+4(−1)=2.
Answer: aij is the value in row i and column j of A. Standard matrix notation: row index first, column index second.
Answer: In has 1 on the diagonal; AIn=InA=A. Identity matrix acts as multiplicative identity for square matrices.
Answer: pij is the payoff when Player 1 uses strategy i and Player 2 uses strategy j. Row player's payoff for their strategy choice against column player's choice.
Answer: The identity matrix I: IA=A and AI=A. Identity matrix acts as multiplicative identity element.
Answer: AB=[11]. 1×3+2×4=3+8=11.
Answer: (AT)ij=aji. Row j, column i of A becomes row i, column j of AT.
Answer: Row sum of row i equals the out-degree of node i. Counts edges leaving node i.
Answer: [610812]. Add corresponding entries: 1+5=6, 2+6=8, 3+7=10, 4+8=12.
Answer: AT=[aji]. Transpose swaps row and column indices.
Answer: It swaps dimensions: AT is n×m. Rows become columns and columns become rows.
Answer: Column sum of column j equals the in-degree of node j. Counts edges entering node j.
Answer: If A is m×n and B is n×p. Inner dimensions must match for matrix multiplication.
Answer: aij is the value in row i, column j of A. Standard notation for matrix entries uses row-column indexing.
Answer: c12=7. Row 1 of A dot column 2 of B: 2(4)+1(−1)=7.
Answer: A1=[36]. Multiplying by ones vector sums each row.
Answer: (A+B)ij=aij+bij. Add corresponding entries from the same position in each matrix.
Answer: cij=∑k=1naikbkj. Row i of A dot column j of B gives entry (i,j).
Answer: Non-invertible when ad−bc=0. Determinant zero means matrix is singular.
Answer: Expected payoff is rTPc. Weighted average of payoffs using probability vectors.
Answer: Px gives expected payoffs for each row strategy (given column mix x). Weighted average of payoffs based on opponent's strategy probabilities.
Answer: (kA)ij=kaij. Multiply every entry by the scalar k.
Answer: 1−20534. Swap rows and columns: first row becomes first column, etc.
Answer: There exists A−1 with AA−1=I and A−1A=I. Inverse undoes multiplication from either side.
Answer: Dimensions are m×n. Matrix size is always expressed as rows × columns.
Answer: A weighted combination of columns of A (a linear combination). Each column is weighted by corresponding entry in x.
Answer: They must have the same dimensions m×n. Matrix addition requires element-wise operations, so dimensions must match.
Answer: aij=1 means an edge from node i to node j (else 0). Binary indicator: 1 if directed edge exists, 0 otherwise.
Answer: −1 leaves node, +1 enters node, 0 not incident. Signs indicate edge direction relative to node.
Answer: cij=∑k=1naikbkj. Dot product of row i from A with column j from B.
Answer: pij is the payoff to the specified player for outcome (i,j). Entry shows reward/cost for strategy combination.
Answer: The inner dimensions must match: A has n columns and B has n rows. Number of columns in first matrix must equal rows in second.
Answer: (AB)T=BTAT. Order reverses when transposing a product.