Precalculus Flashcards: Matrix Transformations Of Vectors

Study Matrix Transformations Of Vectors in Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Precalculus

Matrix Transformations Of Vectors

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QUESTION
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What is the result of applying AA then BB to a vector v\vec{v}, written as one matrix times v\vec{v}?

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ANSWER

B(Av)=(BA)vB(A\vec{v})=(BA)\vec{v}. Composition of transformations equals product of matrices.

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This deck focuses on Matrix Transformations Of Vectors, giving you a quick way to review the definitions, rules, and examples that matter most for Precalculus.

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Flashcard 1: What is the result of applying AA then BB to a vector v\vec{v}, written as one matrix times v\vec{v}?

Answer: B(Av)=(BA)vB(A\vec{v})=(BA)\vec{v}. Composition of transformations equals product of matrices.

Flashcard 2: What is the output type of multiplying a matrix AA by a column vector v\vec{v} (with compatible dimensions)?

Answer: A column vector (a matrix of size m×1m\times 1). Matrix-vector multiplication preserves the column structure.

Flashcard 3: What is A(11)A\begin{pmatrix}1\\1\end{pmatrix} if A=(2143)A=\begin{pmatrix}2&-1\\4&3\end{pmatrix}?

Answer: (17)\begin{pmatrix}1\\7\end{pmatrix}. 2(1)+(1)(1)=12(1)+(-1)(1)=1; 4(1)+3(1)=74(1)+3(1)=7.

Flashcard 4: What is Ae2A\vec{e}_2 for A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix} and e2=(01)\vec{e}_2=\begin{pmatrix}0\\1\end{pmatrix}?

Answer: (bd)\begin{pmatrix}b\\d\end{pmatrix}. Multiplying by e2\vec{e}_2 selects second column of AA.

Flashcard 5: What is Ae1A\vec{e}_1 for A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix} and e1=(10)\vec{e}_1=\begin{pmatrix}1\\0\end{pmatrix}?

Answer: (ac)\begin{pmatrix}a\\c\end{pmatrix}. Multiplying by e1\vec{e}_1 selects first column of AA.

Flashcard 6: Compute AxA\vec{x} for A=(30012)A=\begin{pmatrix}3&0\\0&\frac{1}{2}\end{pmatrix} and x=(28)\vec{x}=\begin{pmatrix}2\\8\end{pmatrix}.

Answer: (64)\begin{pmatrix}6\\4\end{pmatrix}. 3(2)+0(8)=63(2)+0(8)=6; 0(2)+12(8)=40(2)+\frac{1}{2}(8)=4.

Flashcard 7: What is (3003)(14)\begin{pmatrix}3&0\\0&3\end{pmatrix}\begin{pmatrix}-1\\4\end{pmatrix}?

Answer: (312)\begin{pmatrix}-3\\12\end{pmatrix}. Scalar matrix multiplies all components by 3.

Flashcard 8: What is (0110)(83)\begin{pmatrix}0&1\\1&0\end{pmatrix}\begin{pmatrix}8\\-3\end{pmatrix}?

Answer: (38)\begin{pmatrix}-3\\8\end{pmatrix}. Swaps xx and yy components.

Flashcard 9: What is (1k01)(xy)\begin{pmatrix}1&k\\0&1\end{pmatrix}\begin{pmatrix}x\\y\end{pmatrix} in terms of x,y,kx,y,k?

Answer: (x+kyy)\begin{pmatrix}x+ky\\y\end{pmatrix}. Shear transformation adds kk times yy to xx.

Flashcard 10: What is the standard matrix for the transformation T(x,y)=(ax+by,cx+dy)T(x,y)=(ax+by,cx+dy)?

Answer: (abcd)\begin{pmatrix}a&b\\c&d\end{pmatrix}. Coefficients form columns: (a,c)(a,c) and (b,d)(b,d).

Flashcard 11: What is the 2×22\times 2 matrix that swaps coordinates, reflecting across the line y=xy=x?

Answer: (0110)\begin{pmatrix}0&1\\1&0\end{pmatrix}. Swaps xx and yy coordinates.

Flashcard 12: What is the 2×22\times 2 matrix for a counterclockwise rotation by angle θ\theta in R2\mathbb{R}^2?

Answer: (cosθsinθsinθcosθ)\begin{pmatrix}\cos\theta&-\sin\theta\\sin\theta&\cos\theta\end{pmatrix}. Standard rotation matrix using trig functions.

Flashcard 13: What is the 2×22\times 2 matrix that reflects points across the xx-axis in R2\mathbb{R}^2?

Answer: (1001)\begin{pmatrix}1&0\\0&-1\end{pmatrix}. Negates yy-coordinate while keeping xx unchanged.

Flashcard 14: What is the definition of a matrix transformation TT associated with a matrix AA acting on vectors?

Answer: T(v)=AvT(\vec{v})=A\vec{v} for each vector v\vec{v}. Matrix transforms vectors by multiplication.

Flashcard 15: Compute AxA\vec{x} for A=(1401)A=\begin{pmatrix}1&4\\0&1\end{pmatrix} and x=(12)\vec{x}=\begin{pmatrix}1\\-2\end{pmatrix}.

Answer: (72)\begin{pmatrix}-7\\-2\end{pmatrix}. 1(1)+4(2)=71(1)+4(-2)=-7; 0(1)+1(2)=20(1)+1(-2)=-2.

Flashcard 16: What is the formula for AvA\vec{v} when A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix} and v=(xy)\vec{v}=\begin{pmatrix}x\\y\end{pmatrix}?

Answer: Av=(ax+bycx+dy)A\vec{v}=\begin{pmatrix}ax+by\\cx+dy\end{pmatrix}. Each component is the dot product of a row with the vector.

Flashcard 17: What dimension must a matrix AA have to multiply a vector v\vec{v} of size n×1n\times 1 on the left?

Answer: AA must be m×nm\times n so AvA\vec{v} is m×1m\times 1. Matrix cols must match vector rows for multiplication.

Flashcard 18: What is (1001)(62)\begin{pmatrix}-1&0\\0&1\end{pmatrix}\begin{pmatrix}6\\-2\end{pmatrix}?

Answer: (62)\begin{pmatrix}-6\\-2\end{pmatrix}. Reflects xx-component across origin, keeps yy unchanged.

Flashcard 19: What dimension must an m×nm\times n matrix AA have to multiply a vector x\vec{x} of size n×1n\times 1?

Answer: AA must be m×nm\times n so AxA\vec{x} is defined. Number of columns in AA must equal rows in x\vec{x} for multiplication.

Flashcard 20: What is (2003)(41)\begin{pmatrix}2&0\\0&3\end{pmatrix}\begin{pmatrix}4\\-1\end{pmatrix}?

Answer: (83)\begin{pmatrix}8\\-3\end{pmatrix}. Diagonal matrix scales each component independently.

Flashcard 21: What is (1001)(39)\begin{pmatrix}1&0\\0&1\end{pmatrix}\begin{pmatrix}-3\\9\end{pmatrix}?

Answer: (39)\begin{pmatrix}-3\\9\end{pmatrix}. Identity matrix leaves vectors unchanged.

Flashcard 22: What is the 2×22\times 2 matrix for scaling by factor kk in both directions in R2\mathbb{R}^2?

Answer: (k00k)\begin{pmatrix}k&0\\0&k\end{pmatrix}. Diagonal matrix with kk scales both coordinates by kk.

Flashcard 23: Compute AxA\vec{x} for A=(1234)A=\begin{pmatrix}1&2\\3&4\end{pmatrix} and x=(15)\vec{x}=\begin{pmatrix}-1\\5\end{pmatrix}.

Answer: (917)\begin{pmatrix}9\\17\end{pmatrix}. 1(1)+2(5)=91(-1)+2(5)=9; 3(1)+4(5)=173(-1)+4(5)=17.

Flashcard 24: What is the 2×22\times 2 matrix that reflects points across the yy-axis in R2\mathbb{R}^2?

Answer: (1001)\begin{pmatrix}-1&0\\0&1\end{pmatrix}. Negates xx-coordinate while keeping yy unchanged.

Flashcard 25: Identify the dimension error: Can (123456)(78)\begin{pmatrix}1&2&3\\4&5&6\end{pmatrix}\begin{pmatrix}7\\8\end{pmatrix} be computed?

Answer: No; inner dimensions 33 and 22 do not match. Matrix has 3 columns but vector has 2 rows.

Flashcard 26: What is (1230)(51)\begin{pmatrix}1&-2\\3&0\end{pmatrix}\begin{pmatrix}5\\1\end{pmatrix}?

Answer: (315)\begin{pmatrix}3\\15\end{pmatrix}. First row: 1(5)+(2)(1)=31(5)+(-2)(1)=3; second row: 3(5)+0(1)=153(5)+0(1)=15.

Flashcard 27: What is the dimension of the product AxA\vec{x} if AA is m×nm\times n and x\vec{x} is n×1n\times 1?

Answer: AxA\vec{x} is m×1m\times 1. Result has rows of AA and columns of x\vec{x}.

Flashcard 28: Identify whether AxA\vec{x} is defined for AA of size 2×32\times 3 and x\vec{x} of size 2×12\times 1.

Answer: Not defined since 323\neq 2 (inner dimensions do not match). Columns of AA (3) must equal rows of x\vec{x} (2).

Flashcard 29: What is the image of e1=(10)\vec{e}_1=\begin{pmatrix}1\\0\end{pmatrix} under A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix}?

Answer: Ae1=(ac)A\vec{e}_1=\begin{pmatrix}a\\c\end{pmatrix} (the first column of AA). Multiplying by e1\vec{e}_1 extracts the first column.

Flashcard 30: What is the image of e2=(01)\vec{e}_2=\begin{pmatrix}0\\1\end{pmatrix} under A=(abcd)A=\begin{pmatrix}a&b\\c&d\end{pmatrix}?

Answer: Ae2=(bd)A\vec{e}_2=\begin{pmatrix}b\\d\end{pmatrix} (the second column of AA). Multiplying by e2\vec{e}_2 extracts the second column.

Flashcard 31: What is the 2×22\times 2 matrix for a horizontal shear with factor kk (sending (x,y)(x,y) to (x+ky,y)(x+ky,y))?

Answer: (1k01)\begin{pmatrix}1&k\\0&1\end{pmatrix}. Adds kk times yy to xx, keeping yy unchanged.

Flashcard 32: Identify whether AxA\vec{x} is defined for AA of size 3×23\times 2 and x\vec{x} of size 2×12\times 1.

Answer: Defined; the product has size 3×13\times 1. Columns of AA (2) equals rows of x\vec{x} (2).

Flashcard 33: What is (0110)(25)\begin{pmatrix}0&-1\\1&0\end{pmatrix}\begin{pmatrix}2\\5\end{pmatrix}?

Answer: (52)\begin{pmatrix}-5\\2\end{pmatrix}. Rotates vector 90° counterclockwise.

Flashcard 34: What is the entry formula for (Ax)i(A\vec{x})_i when AA is m×nm\times n and x\vec{x} is n×1n\times 1?

Answer: (Ax)i=j=1naijxj(A\vec{x})_i=\sum_{j=1}^{n}a_{ij}x_j. Row ii of AA dot product with vector x\vec{x}.

Flashcard 35: What is the linear-combination form of A(xy)A\begin{pmatrix}x\\y\end{pmatrix} using columns a1,a2\vec{a}_1,\vec{a}_2 of AA?

Answer: A(xy)=xa1+ya2A\begin{pmatrix}x\\y\end{pmatrix}=x\vec{a}_1+y\vec{a}_2. Matrix multiplication is a linear combination of columns.

Flashcard 36: Identify the correct interpretation of AxA\vec{x} in Rn\mathbb{R}^n when AA is n×nn\times n.

Answer: AxA\vec{x} is the image of x\vec{x} under the linear transformation AA. Matrix multiplication represents a linear transformation.

Flashcard 37: Compute AxA\vec{x} for A=(1001)A=\begin{pmatrix}1&0\\0&-1\end{pmatrix} and x=(64)\vec{x}=\begin{pmatrix}-6\\4\end{pmatrix}.

Answer: (64)\begin{pmatrix}-6\\-4\end{pmatrix}. 1(6)+0(4)=61(-6)+0(4)=-6; 0(6)+(1)(4)=40(-6)+(-1)(4)=-4.

Flashcard 38: What is (1001)(47)\begin{pmatrix}1&0\\0&-1\end{pmatrix}\begin{pmatrix}-4\\7\end{pmatrix}?

Answer: (47)\begin{pmatrix}-4\\-7\end{pmatrix}. Reflects yy-component across origin, keeps xx unchanged.

Flashcard 39: Compute AxA\vec{x} for A=(2103)A=\begin{pmatrix}2&-1\\0&3\end{pmatrix} and x=(42)\vec{x}=\begin{pmatrix}4\\-2\end{pmatrix}.

Answer: (106)\begin{pmatrix}10\\-6\end{pmatrix}. 2(4)+(1)(2)=102(4)+(-1)(-2)=10; 0(4)+3(2)=60(4)+3(-2)=-6.

Flashcard 40: Compute AxA\vec{x} for A=(0110)A=\begin{pmatrix}0&-1\\1&0\end{pmatrix} and x=(23)\vec{x}=\begin{pmatrix}2\\3\end{pmatrix}.

Answer: (32)\begin{pmatrix}-3\\2\end{pmatrix}. 0(2)+(1)(3)=30(2)+(-1)(3)=-3; 1(2)+0(3)=21(2)+0(3)=2.