Quadratic Systems - Pre-Calculus
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Which of the following could NOT be a possible number of solutions of a system of quadratic and linear equations?
Which of the following could NOT be a possible number of solutions of a system of quadratic and linear equations?
Recall that the solution of a system of equations is given by the intersection points of the graphs. Thus, this question is really asking how many times a parabola and a line can intersect. Visualize a parabola and a line. For this purpose, let's say that the parabola is facing up. If a line is drawn horizontally under the vertex, then it would not intersect the parabola at all, so the system would have no solutions. If the line is tangent to, or just skims the edge, of the parabola then it would only intersect once and the system would have one solution. If the line goes straight through the parabola, then it would intersect twice. There is no other option for the orientation of the line and parabola. Thus, there cannot be three solutions.
Recall that the solution of a system of equations is given by the intersection points of the graphs. Thus, this question is really asking how many times a parabola and a line can intersect. Visualize a parabola and a line. For this purpose, let's say that the parabola is facing up. If a line is drawn horizontally under the vertex, then it would not intersect the parabola at all, so the system would have no solutions. If the line is tangent to, or just skims the edge, of the parabola then it would only intersect once and the system would have one solution. If the line goes straight through the parabola, then it would intersect twice. There is no other option for the orientation of the line and parabola. Thus, there cannot be three solutions.
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Find the coordinate of intersection, if possible: 
and 
.
Find the coordinate of intersection, if possible:
To solve for x and y, set both equations equal to each other and solve for x.
Substitute 
into either parabola.
The coordinate of intersection is 
.
To solve for x and y, set both equations equal to each other and solve for x.
Substitute
The coordinate of intersection is
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Find the intersection(s) of the two parabolas: 
, 
Find the intersection(s) of the two parabolas:
Set both parabolas equal to each other and solve for x.
Substitute both values of 
into either parabola and determine 
.
The coordinates of intersection are:
and 
Set both parabolas equal to each other and solve for x.
Substitute both values of
The coordinates of intersection are:
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Find the points of intersection:
; 
Find the points of intersection:
To solve, set both equations equal to each other:
To solve as a quadratic, combine like terms by adding/subtracting all three terms from the right side to the left side:
This simplifies to
Solving by factoring or the quadratic formula gives the solutions 
and 
.
Plugging each into either original equation gives us:
Our coordinate pairs are 
and 
.
To solve, set both equations equal to each other:
To solve as a quadratic, combine like terms by adding/subtracting all three terms from the right side to the left side:
This simplifies to
Solving by factoring or the quadratic formula gives the solutions
Plugging each into either original equation gives us:
Our coordinate pairs are
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Give the coordinate pairs that satisfy the system of equations.
Give the coordinate pairs that satisfy the system of equations.
To solve, set the two quadratics equal to each other and then combine like terms:
subtract everything on the right from both sides to combine like terms.
Solving by factoring or using the quadratic formula gives us the solutions 
and 
.
To find the y-coordinates, plug these into either equation:
To solve, set the two quadratics equal to each other and then combine like terms:
Solving by factoring or using the quadratic formula gives us the solutions
To find the y-coordinates, plug these into either equation:
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Give the 
, 
coordinate pairs that satisfy the two equations.
Give the
To solve, first re-write the second one so that y is isolated on the left side:
Now set the two quadratics equal to each other:
add/subtract all of the terms from the right side so that this is a quadratic equal to zero.
combine like terms.
Using the quadratic formula or by factoring, we get the two solutions 
and 
.
To get the y-coordinates, plug these numbers into either function:
To solve, first re-write the second one so that y is isolated on the left side:
Now set the two quadratics equal to each other:
Using the quadratic formula or by factoring, we get the two solutions
To get the y-coordinates, plug these numbers into either function:
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Find the coordinate pairs satisfying both polynomials:
Find the coordinate pairs satisfying both polynomials:
To solve, set the two polynomials equal to each other:
add/subtract all of the terms from the right side from both sides.
combine like terms.
Solving with the quadratic formula or by factoring gives us the solutions 5 and -3.
To get the y-coordinates, plug these numbers into either of the original equations:
To solve, set the two polynomials equal to each other:
Solving with the quadratic formula or by factoring gives us the solutions 5 and -3.
To get the y-coordinates, plug these numbers into either of the original equations:
Compare your answer with the correct one above
Which of the following could NOT be a possible number of solutions of a system of quadratic and linear equations?
Which of the following could NOT be a possible number of solutions of a system of quadratic and linear equations?
Recall that the solution of a system of equations is given by the intersection points of the graphs. Thus, this question is really asking how many times a parabola and a line can intersect. Visualize a parabola and a line. For this purpose, let's say that the parabola is facing up. If a line is drawn horizontally under the vertex, then it would not intersect the parabola at all, so the system would have no solutions. If the line is tangent to, or just skims the edge, of the parabola then it would only intersect once and the system would have one solution. If the line goes straight through the parabola, then it would intersect twice. There is no other option for the orientation of the line and parabola. Thus, there cannot be three solutions.
Recall that the solution of a system of equations is given by the intersection points of the graphs. Thus, this question is really asking how many times a parabola and a line can intersect. Visualize a parabola and a line. For this purpose, let's say that the parabola is facing up. If a line is drawn horizontally under the vertex, then it would not intersect the parabola at all, so the system would have no solutions. If the line is tangent to, or just skims the edge, of the parabola then it would only intersect once and the system would have one solution. If the line goes straight through the parabola, then it would intersect twice. There is no other option for the orientation of the line and parabola. Thus, there cannot be three solutions.
Compare your answer with the correct one above
Find the coordinate of intersection, if possible: and .
Find the coordinate of intersection, if possible:
To solve for x and y, set both equations equal to each other and solve for x.
Substitute into either parabola.
The coordinate of intersection is .
To solve for x and y, set both equations equal to each other and solve for x.
Substitute
The coordinate of intersection is
Compare your answer with the correct one above
Find the intersection(s) of the two parabolas: ,
Find the intersection(s) of the two parabolas:
Set both parabolas equal to each other and solve for x.
Substitute both values of into either parabola and determine .
The coordinates of intersection are:
and
Set both parabolas equal to each other and solve for x.
Substitute both values of
The coordinates of intersection are:
Compare your answer with the correct one above
Find the points of intersection:
;
Find the points of intersection:
To solve, set both equations equal to each other:
To solve as a quadratic, combine like terms by adding/subtracting all three terms from the right side to the left side:
This simplifies to
Solving by factoring or the quadratic formula gives the solutions and .
Plugging each into either original equation gives us:
Our coordinate pairs are and .
To solve, set both equations equal to each other:
To solve as a quadratic, combine like terms by adding/subtracting all three terms from the right side to the left side:
This simplifies to
Solving by factoring or the quadratic formula gives the solutions
Plugging each into either original equation gives us:
Our coordinate pairs are
Compare your answer with the correct one above
Give the coordinate pairs that satisfy the system of equations.
Give the coordinate pairs that satisfy the system of equations.
To solve, set the two quadratics equal to each other and then combine like terms:
subtract everything on the right from both sides to combine like terms.
Solving by factoring or using the quadratic formula gives us the solutions and .
To find the y-coordinates, plug these into either equation:
To solve, set the two quadratics equal to each other and then combine like terms:
Solving by factoring or using the quadratic formula gives us the solutions
To find the y-coordinates, plug these into either equation:
Compare your answer with the correct one above
Give the , coordinate pairs that satisfy the two equations.
Give the
To solve, first re-write the second one so that y is isolated on the left side:
Now set the two quadratics equal to each other:
add/subtract all of the terms from the right side so that this is a quadratic equal to zero.
combine like terms.
Using the quadratic formula or by factoring, we get the two solutions and .
To get the y-coordinates, plug these numbers into either function:
To solve, first re-write the second one so that y is isolated on the left side:
Now set the two quadratics equal to each other:
Using the quadratic formula or by factoring, we get the two solutions
To get the y-coordinates, plug these numbers into either function:
Compare your answer with the correct one above
Find the coordinate pairs satisfying both polynomials:
Find the coordinate pairs satisfying both polynomials:
To solve, set the two polynomials equal to each other:
add/subtract all of the terms from the right side from both sides.
combine like terms.
Solving with the quadratic formula or by factoring gives us the solutions 5 and -3.
To get the y-coordinates, plug these numbers into either of the original equations:
To solve, set the two polynomials equal to each other:
Solving with the quadratic formula or by factoring gives us the solutions 5 and -3.
To get the y-coordinates, plug these numbers into either of the original equations:
Compare your answer with the correct one above
Which of the following could NOT be a possible number of solutions of a system of quadratic and linear equations?
Which of the following could NOT be a possible number of solutions of a system of quadratic and linear equations?
Recall that the solution of a system of equations is given by the intersection points of the graphs. Thus, this question is really asking how many times a parabola and a line can intersect. Visualize a parabola and a line. For this purpose, let's say that the parabola is facing up. If a line is drawn horizontally under the vertex, then it would not intersect the parabola at all, so the system would have no solutions. If the line is tangent to, or just skims the edge, of the parabola then it would only intersect once and the system would have one solution. If the line goes straight through the parabola, then it would intersect twice. There is no other option for the orientation of the line and parabola. Thus, there cannot be three solutions.
Recall that the solution of a system of equations is given by the intersection points of the graphs. Thus, this question is really asking how many times a parabola and a line can intersect. Visualize a parabola and a line. For this purpose, let's say that the parabola is facing up. If a line is drawn horizontally under the vertex, then it would not intersect the parabola at all, so the system would have no solutions. If the line is tangent to, or just skims the edge, of the parabola then it would only intersect once and the system would have one solution. If the line goes straight through the parabola, then it would intersect twice. There is no other option for the orientation of the line and parabola. Thus, there cannot be three solutions.
Compare your answer with the correct one above
Find the coordinate of intersection, if possible: and .
Find the coordinate of intersection, if possible:
To solve for x and y, set both equations equal to each other and solve for x.
Substitute into either parabola.
The coordinate of intersection is .
To solve for x and y, set both equations equal to each other and solve for x.
Substitute
The coordinate of intersection is
Compare your answer with the correct one above
Find the intersection(s) of the two parabolas: ,
Find the intersection(s) of the two parabolas:
Set both parabolas equal to each other and solve for x.
Substitute both values of into either parabola and determine .
The coordinates of intersection are:
and
Set both parabolas equal to each other and solve for x.
Substitute both values of
The coordinates of intersection are:
Compare your answer with the correct one above
Find the points of intersection:
;
Find the points of intersection:
To solve, set both equations equal to each other:
To solve as a quadratic, combine like terms by adding/subtracting all three terms from the right side to the left side:
This simplifies to
Solving by factoring or the quadratic formula gives the solutions and .
Plugging each into either original equation gives us:
Our coordinate pairs are and .
To solve, set both equations equal to each other:
To solve as a quadratic, combine like terms by adding/subtracting all three terms from the right side to the left side:
This simplifies to
Solving by factoring or the quadratic formula gives the solutions
Plugging each into either original equation gives us:
Our coordinate pairs are
Compare your answer with the correct one above
Give the coordinate pairs that satisfy the system of equations.
Give the coordinate pairs that satisfy the system of equations.
To solve, set the two quadratics equal to each other and then combine like terms:
subtract everything on the right from both sides to combine like terms.
Solving by factoring or using the quadratic formula gives us the solutions and .
To find the y-coordinates, plug these into either equation:
To solve, set the two quadratics equal to each other and then combine like terms:
Solving by factoring or using the quadratic formula gives us the solutions
To find the y-coordinates, plug these into either equation:
Compare your answer with the correct one above
Give the , coordinate pairs that satisfy the two equations.
Give the
To solve, first re-write the second one so that y is isolated on the left side:
Now set the two quadratics equal to each other:
add/subtract all of the terms from the right side so that this is a quadratic equal to zero.
combine like terms.
Using the quadratic formula or by factoring, we get the two solutions and .
To get the y-coordinates, plug these numbers into either function:
To solve, first re-write the second one so that y is isolated on the left side:
Now set the two quadratics equal to each other:
Using the quadratic formula or by factoring, we get the two solutions
To get the y-coordinates, plug these numbers into either function:
Compare your answer with the correct one above