Application Problems - Pre-Calculus

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Question

The amount of phosphorus present in a sample at a given time is given by the following equation:

Where is in days, is the amount of phosphorus after days, and is the initial amount of phosphorus at the beginning of the first day. What percent of the initial amount of phosphorus is left after days of decay?

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Answer

The problem asks us for the percent that the amount of phosphorus after t days is of the original amount of phosphorus. If we think of this percentage with respect to the variables present in the equation, we can see that the following fraction expresses the amount of phosphorus after t days as a percentage of the initial amount of phosphorus:

So if this is the fraction we want to solve for, we should divide both sides of the equation by to obtain this fraction on the left side of the equation:

We now have the fraction we want to solve for in terms of just one variable, , for which we plug in 25 days to find the percentage of phosphorus left of the initial amount after 25 days:

So after 25 days of decay, the amount of phosphorus is 47% of the initial amount.

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