Study Add Vectors In Different Ways in Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: What is the component-wise sum formula for ⟨ a , b ⟩ + ⟨ c , d ⟩ \langle a,b\rangle+\langle c,d\rangle ⟨ a , b ⟩ + ⟨ c , d ⟩ ? Answer: ⟨ a + c , b + d ⟩ \langle a+c,\,b+d\rangle ⟨ a + c , b + d ⟩ . Add corresponding components: first with first, second with second.
Flashcard 2: Find the magnitude ∥ ⟨ 5 , 12 ⟩ ∥ \|\langle 5,12\rangle\| ∥ ⟨ 5 , 12 ⟩ ∥ . Answer: 13 13 13 . 5 2 + 12 2 = 25 + 144 = 169 = 13 \sqrt{5^2+12^2}=\sqrt{25+144}=\sqrt{169}=13 5 2 + 1 2 2 = 25 + 144 = 169 = 13 .
Flashcard 3: What is the commutative property of vector addition written with vectors u ⃗ \vec{u} u and v ⃗ \vec{v} v ? Answer: u ⃗ + v ⃗ = v ⃗ + u ⃗ \vec{u}+\vec{v}=\vec{v}+\vec{u} u + v = v + u . Order doesn't matter in vector addition.
Flashcard 4: What does it mean to add vectors end-to-end (head-to-tail) in geometry? Answer: Place tail of v ⃗ \vec{v} v at head of u ⃗ \vec{u} u ; sum is tail-to-head. Connect vectors tip-to-tail; resultant goes from start to end.
Flashcard 5: Find ∥ ⟨ 6 , 8 ⟩ ∥ \lVert\langle 6,8\rangle\rVert ∥⟨ 6 , 8 ⟩∥ . Answer: 10 10 10 . Use 6 2 + 8 2 = 36 + 64 = 100 = 10 \sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10 6 2 + 8 2 = 36 + 64 = 100 = 10 .
Flashcard 6: What property states that u ⃗ + v ⃗ \vec{u}+\vec{v} u + v equals v ⃗ + u ⃗ \vec{v}+\vec{u} v + u ? Answer: Commutative property of vector addition. Vector addition order doesn't matter, like regular addition.
Flashcard 7: What is the additive identity for vectors (the vector 0 ⃗ \vec{0} 0 ) in R 2 \mathbb{R}^2 R 2 ? Answer: 0 ⃗ = ⟨ 0 , 0 ⟩ \vec{0}=\langle 0,0\rangle 0 = ⟨ 0 , 0 ⟩ . The zero vector has both components equal to zero.
Flashcard 8: If u ⃗ = ⟨ 2 , 1 ⟩ \vec{u}=\langle 2,1\rangle u = ⟨ 2 , 1 ⟩ and v ⃗ = ⟨ − 1 , 5 ⟩ \vec{v}=\langle -1,5\rangle v = ⟨ − 1 , 5 ⟩ , find u ⃗ + v ⃗ \vec{u}+\vec{v} u + v . Answer: ⟨ 1 , 6 ⟩ \langle 1,\,6\rangle ⟨ 1 , 6 ⟩ . Add components: ⟨ 2 + ( − 1 ) , 1 + 5 ⟩ = ⟨ 1 , 6 ⟩ \langle 2+(-1), 1+5\rangle = \langle 1, 6\rangle ⟨ 2 + ( − 1 ) , 1 + 5 ⟩ = ⟨ 1 , 6 ⟩ .
Flashcard 9: If u ⃗ = ⟨ 4 , 0 ⟩ \vec{u}=\langle 4,0\rangle u = ⟨ 4 , 0 ⟩ and v ⃗ = ⟨ 0 , 3 ⟩ \vec{v}=\langle 0,3\rangle v = ⟨ 0 , 3 ⟩ , find ∥ u ⃗ + v ⃗ ∥ \lVert\vec{u}+\vec{v}\rVert ∥ u + v ∥ . Answer: 5 5 5 . First add to get ⟨ 4 , 3 ⟩ \langle 4,3\rangle ⟨ 4 , 3 ⟩ , then 4 2 + 3 2 = 25 = 5 \sqrt{4^2+3^2}=\sqrt{25}=5 4 2 + 3 2 = 25 = 5 .
Flashcard 10: What is the additive inverse of v ⃗ = ⟨ a , b ⟩ \vec{v}=\langle a,b\rangle v = ⟨ a , b ⟩ ? Answer: − v ⃗ = ⟨ − a , − b ⟩ -\vec{v}=\langle -a,-b\rangle − v = ⟨ − a , − b ⟩ . Negate both components to get the opposite vector.
Flashcard 11: Find the magnitude ∥ ⟨ 6 , 8 ⟩ ∥ \|\langle 6,8\rangle\| ∥ ⟨ 6 , 8 ⟩ ∥ . Answer: 10 10 10 . 6 2 + 8 2 = 36 + 64 = 100 = 10 \sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10 6 2 + 8 2 = 36 + 64 = 100 = 10 .
Flashcard 12: What inequality relates ∥ u ⃗ + v ⃗ ∥ \|\vec{u}+\vec{v}\| ∥ u + v ∥ to ∥ u ⃗ ∥ \|\vec{u}\| ∥ u ∥ and ∥ v ⃗ ∥ \|\vec{v}\| ∥ v ∥ (triangle inequality)? Answer: ∥ u ⃗ + v ⃗ ∥ ≤ ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \|\vec{u}+\vec{v}\|\le \|\vec{u}\|+\|\vec{v}\| ∥ u + v ∥ ≤ ∥ u ∥ + ∥ v ∥ . The magnitude of a sum never exceeds the sum of magnitudes.
Flashcard 13: What is the associative property of vector addition for u ⃗ \vec{u} u , v ⃗ \vec{v} v , and w ⃗ \vec{w} w ? Answer: ( u ⃗ + v ⃗ ) + w ⃗ = u ⃗ + ( v ⃗ + w ⃗ ) (\vec{u}+\vec{v})+\vec{w}=\vec{u}+(\vec{v}+\vec{w}) ( u + v ) + w = u + ( v + w ) . Grouping doesn't affect the result.
Flashcard 14: What is the magnitude formula for v ⃗ = ⟨ a , b ⟩ \vec{v}=\langle a,b\rangle v = ⟨ a , b ⟩ ? Answer: ∥ v ⃗ ∥ = a 2 + b 2 \lVert\vec{v}\rVert=\sqrt{a^2+b^2} ∥ v ∥ = a 2 + b 2 . Apply the Pythagorean theorem to the components.
Flashcard 15: What property states that ( u ⃗ + v ⃗ ) + w ⃗ = u ⃗ + ( v ⃗ + w ⃗ ) (\vec{u}+\vec{v})+\vec{w}=\vec{u}+(\vec{v}+\vec{w}) ( u + v ) + w = u + ( v + w ) ? Answer: Associative property of vector addition. Grouping doesn't affect the result when adding multiple vectors.
Flashcard 16: What inequality relates ∥ u ⃗ + v ⃗ ∥ \lVert\vec{u}+\vec{v}\rVert ∥ u + v ∥ to ∥ u ⃗ ∥ \lVert\vec{u}\rVert ∥ u ∥ and ∥ v ⃗ ∥ \lVert\vec{v}\rVert ∥ v ∥ ? Answer: ∥ u ⃗ + v ⃗ ∥ ≤ ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \lVert\vec{u}+\vec{v}\rVert\le\lVert\vec{u}\rVert+\lVert\vec{v}\rVert ∥ u + v ∥ ≤ ∥ u ∥ + ∥ v ∥ . The triangle inequality: sum magnitude ≤ magnitude sum.
Flashcard 17: Find ⟨ 3 , − 2 ⟩ + ⟨ − 5 , 4 ⟩ \langle 3,-2\rangle+\langle -5,4\rangle ⟨ 3 , − 2 ⟩ + ⟨ − 5 , 4 ⟩ . Answer: ⟨ − 2 , 2 ⟩ \langle -2,\,2\rangle ⟨ − 2 , 2 ⟩ . Add components: 3 + ( − 5 ) = − 2 3+(-5)=-2 3 + ( − 5 ) = − 2 and − 2 + 4 = 2 -2+4=2 − 2 + 4 = 2 .
Flashcard 18: What is the component-wise subtraction formula for ⟨ a , b ⟩ − ⟨ c , d ⟩ \langle a,b\rangle - \langle c,d\rangle ⟨ a , b ⟩ − ⟨ c , d ⟩ ? Answer: ⟨ a − c , b − d ⟩ \langle a-c,\,b-d\rangle ⟨ a − c , b − d ⟩ . Subtract corresponding components: first minus first, second minus second.
Flashcard 19: Identify the correct statement about magnitudes: ∥ u ⃗ + v ⃗ ∥ \lVert\vec{u}+\vec{v}\rVert ∥ u + v ∥ vs. ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \lVert\vec{u}\rVert+\lVert\vec{v}\rVert ∥ u ∥ + ∥ v ∥ . Answer: Typically ∥ u ⃗ + v ⃗ ∥ ≠ ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \lVert\vec{u}+\vec{v}\rVert\ne\lVert\vec{u}\rVert+\lVert\vec{v}\rVert ∥ u + v ∥ = ∥ u ∥ + ∥ v ∥ . Triangle inequality shows sum magnitude usually less than magnitude sum.
Flashcard 20: Find u ⃗ + v ⃗ \vec{u}+\vec{v} u + v if u ⃗ \vec{u} u goes from ( 0 , 0 ) (0,0) ( 0 , 0 ) to ( 2 , − 1 ) (2,-1) ( 2 , − 1 ) and v ⃗ \vec{v} v goes from ( 0 , 0 ) (0,0) ( 0 , 0 ) to ( − 3 , 4 ) (-3,4) ( − 3 , 4 ) . Answer: ⟨ − 1 , 3 ⟩ \langle -1,\,3\rangle ⟨ − 1 , 3 ⟩ . u ⃗ = ⟨ 2 , − 1 ⟩ \vec{u}=\langle 2,-1\rangle u = ⟨ 2 , − 1 ⟩ and v ⃗ = ⟨ − 3 , 4 ⟩ \vec{v}=\langle -3,4\rangle v = ⟨ − 3 , 4 ⟩ sum component-wise.
Flashcard 21: What is the additive inverse of v ⃗ = ⟨ a , b ⟩ \vec{v}=\langle a,b\rangle v = ⟨ a , b ⟩ ? Answer: − v ⃗ = ⟨ − a , − b ⟩ -\vec{v}=\langle -a,\,-b\rangle − v = ⟨ − a , − b ⟩ . Negate each component to get the opposite vector.
Flashcard 22: What is the triangle (end-to-end) rule for adding u ⃗ \vec{u} u and v ⃗ \vec{v} v ? Answer: Place tail of v ⃗ \vec{v} v at head of u ⃗ \vec{u} u ; sum is tail-to-head. Connect vectors tip-to-tail; resultant goes from start to end.
Flashcard 23: What is the additive identity vector, written as a component vector in R 2 \mathbb{R}^2 R 2 ? Answer: ⟨ 0 , 0 ⟩ \langle 0,0\rangle ⟨ 0 , 0 ⟩ . The zero vector leaves any vector unchanged when added.
Flashcard 24: If v ⃗ = ⟨ a , b ⟩ \vec{v}=\langle a,b\rangle v = ⟨ a , b ⟩ , what is v ⃗ + ( − v ⃗ ) \vec{v}+(-\vec{v}) v + ( − v ) ? Answer: 0 ⃗ \vec{0} 0 . A vector plus its negative always gives the zero vector.
Flashcard 25: Find ⟨ 3 , − 2 ⟩ + ⟨ − 5 , 4 ⟩ \langle 3,-2\rangle + \langle -5,4\rangle ⟨ 3 , − 2 ⟩ + ⟨ − 5 , 4 ⟩ using component-wise addition. Answer: ⟨ − 2 , 2 ⟩ \langle -2,\,2\rangle ⟨ − 2 , 2 ⟩ . 3 + ( − 5 ) = − 2 3+(-5)=-2 3 + ( − 5 ) = − 2 and − 2 + 4 = 2 -2+4=2 − 2 + 4 = 2 .
Flashcard 26: When does ∥ u ⃗ + v ⃗ ∥ = ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \|\vec{u}+\vec{v}\|=\|\vec{u}\|+\|\vec{v}\| ∥ u + v ∥ = ∥ u ∥ + ∥ v ∥ hold exactly? Answer: When u ⃗ \vec{u} u and v ⃗ \vec{v} v point in the same direction. Parallel vectors with same orientation achieve equality.
Flashcard 27: What is the component-wise addition formula for ⟨ a , b ⟩ + ⟨ c , d ⟩ \langle a,b\rangle + \langle c,d\rangle ⟨ a , b ⟩ + ⟨ c , d ⟩ ? Answer: ⟨ a + c , b + d ⟩ \langle a+c,\,b+d\rangle ⟨ a + c , b + d ⟩ . Add corresponding components: first with first, second with second.
Flashcard 28: Find the vector A B → \overrightarrow{AB} A B for A ( 1 , − 3 ) A(1,-3) A ( 1 , − 3 ) and B ( 6 , 2 ) B(6,2) B ( 6 , 2 ) . Answer: ⟨ 5 , 5 ⟩ \langle 5,\,5\rangle ⟨ 5 , 5 ⟩ . Calculate ⟨ 6 − 1 , 2 − ( − 3 ) ⟩ = ⟨ 5 , 5 ⟩ \langle 6-1, 2-(-3)\rangle = \langle 5, 5\rangle ⟨ 6 − 1 , 2 − ( − 3 )⟩ = ⟨ 5 , 5 ⟩ .
Flashcard 29: What is the vector from point A ( x 1 , y 1 ) A(x_1,y_1) A ( x 1 , y 1 ) to point B ( x 2 , y 2 ) B(x_2,y_2) B ( x 2 , y 2 ) in component form? Answer: ⟨ x 2 − x 1 , y 2 − y 1 ⟩ \langle x_2-x_1,\,y_2-y_1\rangle ⟨ x 2 − x 1 , y 2 − y 1 ⟩ . Subtract initial point coordinates from terminal point coordinates.
Flashcard 30: Compute ∥ ⟨ 4 , 0 ⟩ ∥ + ∥ ⟨ 0 , 3 ⟩ ∥ \lVert\langle 4,0\rangle\rVert+\lVert\langle 0,3\rangle\rVert ∥⟨ 4 , 0 ⟩∥ + ∥⟨ 0 , 3 ⟩∥ . Answer: 7 7 7 . Sum individual magnitudes: 16 + 9 = 4 + 3 = 7 \sqrt{16}+\sqrt{9}=4+3=7 16 + 9 = 4 + 3 = 7 .
Flashcard 31: What is the parallelogram rule statement for u ⃗ + v ⃗ \vec{u}+\vec{v} u + v ? Answer: Diagonal from common tail of adjacent sides u ⃗ \vec{u} u and v ⃗ \vec{v} v . Form parallelogram; sum is the diagonal from shared starting point.
Flashcard 32: Identify the correct statement about magnitudes: is ∥ u ⃗ + v ⃗ ∥ \|\vec{u}+\vec{v}\| ∥ u + v ∥ typically equal to ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \|\vec{u}\|+\|\vec{v}\| ∥ u ∥ + ∥ v ∥ ? Answer: No; typically ∥ u ⃗ + v ⃗ ∥ ≠ ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \|\vec{u}+\vec{v}\|\ne \|\vec{u}\|+\|\vec{v}\| ∥ u + v ∥ = ∥ u ∥ + ∥ v ∥ . Triangle inequality shows equality is rare.
Flashcard 33: Find ⟨ − 1 , 7 ⟩ − ⟨ 4 , − 3 ⟩ \langle -1,7\rangle - \langle 4,-3\rangle ⟨ − 1 , 7 ⟩ − ⟨ 4 , − 3 ⟩ using component-wise subtraction. Answer: ⟨ − 5 , 10 ⟩ \langle -5,\,10\rangle ⟨ − 5 , 10 ⟩ . − 1 − 4 = − 5 -1-4=-5 − 1 − 4 = − 5 and 7 − ( − 3 ) = 10 7-(-3)=10 7 − ( − 3 ) = 10 .
Flashcard 34: When does equality hold in ∥ u ⃗ + v ⃗ ∥ ≤ ∥ u ⃗ ∥ + ∥ v ⃗ ∥ \lVert\vec{u}+\vec{v}\rVert\le\lVert\vec{u}\rVert+\lVert\vec{v}\rVert ∥ u + v ∥ ≤ ∥ u ∥ + ∥ v ∥ ? Answer: When u ⃗ \vec{u} u and v ⃗ \vec{v} v point in the same direction. Equality occurs when vectors are parallel with same orientation.
Flashcard 35: What is the magnitude formula for a vector v ⃗ = ⟨ a , b ⟩ \vec{v}=\langle a,b\rangle v = ⟨ a , b ⟩ ? Answer: ∥ v ⃗ ∥ = a 2 + b 2 \|\vec{v}\|=\sqrt{a^2+b^2} ∥ v ∥ = a 2 + b 2 . Use the Pythagorean theorem on the components.
Flashcard 36: What is the parallelogram rule for u ⃗ + v ⃗ \vec{u}+\vec{v} u + v in geometric vector addition? Answer: Draw both from same tail; sum is diagonal of the parallelogram. Vectors form adjacent sides; sum is the diagonal.
Flashcard 37: Compute ∥ ⟨ 1 , 2 ⟩ + ⟨ 2 , 1 ⟩ ∥ \|\langle 1,2\rangle+\langle 2,1\rangle\| ∥ ⟨ 1 , 2 ⟩ + ⟨ 2 , 1 ⟩ ∥ . Answer: 18 \sqrt{18} 18 . Sum is ⟨ 3 , 3 ⟩ \langle 3,3\rangle ⟨ 3 , 3 ⟩ ; magnitude is 9 + 9 = 18 \sqrt{9+9}=\sqrt{18} 9 + 9 = 18 .