Multiplication and Division - Pre-Algebra

Since , we can convert as follows:

A fraction bar in an expression acts as both a division symbol and a grouping symbol, so we evaluate the numerator first. Within the numerator, there is a multplication, a subtraction, and an addition, so, by order of operations, we multiply first. Addition and subtraction are carried out right to left; the subtraction is left of the addition, so we subtract next, then add. Finally, we divide the numerator by the denominator.

In summary: Multiply, subtract, add, divide

If Beck has 5 pairs of shoes, that means he has 10 shoes because there are 2 shoes in a pair.

Since each shoe has 6 buttons, that means that there are 60 buttons in the collection.

If we use the foil method we get the following:
First:

Inner:

Outer:

Last:

If that is simplified we're left wiht

The whole operation is squared, so to better understand how to solve it it can be rewritten as:

Using order of operations we get the following:
First:

Inner:

Outer:

Last:

When this is simplified we have

The equation can be rewritten as

First the foil method should be used, leaving us with:

Then the 2 can be distributed to each of the factors inside the parentheses. Leaving the solution:

results in when simplifying with the foil method as follows:
First:

Inner:

Outer:

Last:

When simplified using the FOIL method results in the following:

First:

Inner:

Outer:

Last:

When the 2 is distributed and the expression simplified we are left with

The total sale price of the cars he sells will be

.

12% of $125,000 is

,

which is the salesman's commission.

To reduce any fraction, you must find the greatest common factor (GCF) of both the numerator and denominator. In this case, the biggest number that can be divided into both 18 and 24 evenly is 6. Divide both 18 and 24 by 6 to solve.

The solution is .

Simplify the numerator and denominator by cancelling out common factors.

Then follow suit and multiply the denominator with denominator and numerator with numerator.

Multiply the ones digits together.

The ones digit of the final answer is .

Carry over the to the next calculuation.

Multiply the with the tens digit of the first number, and add the carryover .

The answer is:

Eliminate the absolute value sign before proceeding to multiply all the terms.

A value inside the absolute value will result into a positive value.

From here, first multiply , when doing so remember when a negative number is multiplied by a positive number the resulting product is negative.

Therefore we get,

.

Now we will need to multiply with .

First multiply six with nine to get . Keep the four in the ones place and carry the five to the tens place. Now multply nine with three . Since we carried the five over we need to add . Combine this value with the value that was found for the ones spot to get, . Finally, place a negative sign in front of it to arrive at the final answer.

.

Multiply the ones digits.

The is the ones digit of the final answer. The will be the carryover for the next calculation.

Multiply the tens digit of with with the carryover.

There are no further calculuations. Combine the numbers.

The answer is:

Multiply the ones digit of with .

Multiply the tens digit of with .

Since this number is 10 or greater, use this tens digit as the carry over for the next calculation.

Multiply the hundreds digit of with with the carry over.

Combine this number with the ones digit of the previous calculations.

The correct answer is:

The numbers are positive. We just multiply. Answer is .

We have one positive and one negative number.

When multipled, our answer is negative.

The product is .

We have two negative numbers. When multiplied, the answer is positive.

The product is .

There is a negative number and zero. Regardless whether the number is positive or negative, anything multiplied by zero is always zero. Answer is .