Practice Test 11

A particle with charge $q=-3.0,\mu\text{C}$ moves upward at speed $v=2.0\times10^5,\text{m/s}$ through a uniform magnetic field $B=0.40,\text{T}$ directed to the right. What is the magnitude of the magnetic force on the particle? (Assume $\vec{v}\perp\vec{B}$.)

A uniform electric field of magnitude $E=2.5\times10^3,\text{N/C}$ points to the right. A particle with charge $q=+1.6\times10^{-19},\text{C}$ is released from rest in this field. What is the direction of its acceleration?

A particle with charge $q=-3.0,\mu\text{C}$ moves upward at speed $v=2.0\times10^5,\text{m/s}$ through a uniform magnetic field $B=0.40,\text{T}$ directed to the right. What is the magnitude of the magnetic force on the particle? (Assume $\vec{v}\perp\vec{B}$.)

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