Model Electric and Magnetic Fields
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Physics › Model Electric and Magnetic Fields
A proton enters a region of uniform magnetic field $\vec B$ directed into the page ($\otimes$). Its initial velocity $\vec v$ is upward in the plane of the page. Neglecting gravity, what path will the proton follow while it remains in the field?
A straight line upward at constant speed
A straight line that speeds up
A circular path that spirals inward because magnetic force does work
A circular path in the plane of the page
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. A magnetic field B exists around magnets and current-carrying wires and is defined by the force it exerts on moving charges: F = qvB sin(θ), measured in Tesla (T). Unlike electric fields which can have isolated sources (single charges), magnetic field lines always form closed loops with no beginning or end (no magnetic monopoles exist), emerging from the north pole and entering the south pole of magnets, or circling around current-carrying wires as determined by right-hand rules. A proton (positive charge) with initial velocity upward in a magnetic field directed into the page experiences force perpendicular to both v and B, causing circular motion in the plane of the page, as the force continuously changes direction but not speed. Choice B is correct because it properly identifies that the magnetic force is always perpendicular to velocity, leading to a circular path in the plane of the page. Choice D incorrectly shows magnetic field lines with starting or ending points (magnetic monopoles), when actually all magnetic field lines must form closed loops—field lines emerge from the north pole, enter the south pole, and continue through the magnet from south to north, completing the loop; additionally, it wrongly suggests magnetic force does work, but since F ⊥ v, speed remains constant without spiraling. When modeling fields and their effects: for magnetic fields, (1) identify source (permanent magnet or current), (2) use right-hand rule for direction (thumb = current, fingers curl = field for wire; or just remember N to S outside magnet), (3) recognize field lines always form closed loops (no monopoles), and (4) force on moving charge is F = qvB perpendicular to both v and B (right-hand rule: fingers = B, thumb = v, palm = F). Common mistakes to avoid: (d) thinking magnetic field lines start and stop like electric ones (magnetic field lines are always closed loops), (e) assuming magnetic force is parallel to field or velocity (it's perpendicular to both), and (f) assuming magnetic force can change particle speed (F ⊥ v means no work, speed constant).
Two point charges lie on the $x$-axis: $Q_1=+4.0,\mu\text{C}$ at $x=-0.20,\text{m}$ and $Q_2=-4.0,\mu\text{C}$ at $x=+0.20,\text{m}$. At the origin ($x=0$), what is the direction of the net electric field $\vec E$ due to these charges?
To the right (positive $x$ direction)
Upward (positive $y$ direction)
Zero (no net electric field)
To the left (negative $x$ direction)
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. An electric field E exists in the region around a charge or group of charges and is defined as the force per unit charge that a positive test charge would experience at each point: E = F/q, measured in N/C (Newtons per Coulomb). The field direction is the direction a positive charge would be pushed (away from positive source charges, toward negative source charges), and field magnitude for a point charge is E = kQ/r², decreasing with the square of distance from the source charge Q. With charge 1: positive +4.0 μC at x=-0.20 m and charge 2: negative -4.0 μC at x=+0.20 m, the electric field at the origin is the vector sum of fields from both charges; charge 1 creates field E₁ pointing to the right (positive x) with magnitude E₁ = k|Q₁|/r₁² = $(9×10⁹)(4×10^{-6}$)/(0.2)² = $9×10^5$ N/C, and charge 2 creates field E₂ pointing to the right (toward negative charge) with magnitude E₂ = $9×10^5$ N/C; the net field is E_net = E₁ + E₂ = $1.8×10^6$ N/C pointing to the right. Choice B is correct because it properly identifies the electric field direction as to the right (positive x direction) by accurately adding the vector fields from both sources to find the net field direction. Choice A reverses the electric field direction, showing it pointing to the left when actually the fields from both charges reinforce to the right: the positive charge pushes positive test charge right, and the negative charge pulls it right. When modeling fields and their effects: for electric fields, (1) identify source charges and their signs, (2) remember field points away from positive charges and toward negative charges, (3) calculate magnitude using E = kQ/r² for point charges, (4) for multiple sources add fields as vectors (considering directions), and (5) force on test charge is F = qE in field direction if q positive, opposite if q negative. Critical distinctions: electric fields can do work on charges (F parallel to motion possible, changes kinetic energy), electric field from stationary charges (no motion needed), electric field lines can start or end on charges—these differences make electric and magnetic fields fundamentally different, though both follow superposition principle (net field is vector sum from all sources) and both decrease with distance from sources.
A proton enters a region of uniform magnetic field with its velocity perpendicular to $\vec{B}$. Which best describes its subsequent motion in the magnetic field (neglecting gravity and electric fields)?
It speeds up in the direction of $\vec{B}$
It moves in a circle at constant speed
It moves in a straight line at constant speed
It slows down because the magnetic field does negative work
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. A magnetic field B exists around magnets and current-carrying wires and is defined by the force it exerts on moving charges: F = qvB sin(θ), measured in Tesla (T). When a proton enters a uniform magnetic field with velocity perpendicular to B, it experiences a magnetic force F = qvB perpendicular to both v and B. Since the force is always perpendicular to velocity, it acts as a centripetal force, changing the direction but not the magnitude of velocity, causing the proton to move in a circular path at constant speed (F = mv²/r = qvB, so r = mv/qB). Choice C is correct because it recognizes that magnetic force is always perpendicular to velocity, providing centripetal acceleration that causes circular motion at constant speed—the magnetic field changes direction of motion but cannot change speed since F ⊥ v means no work is done. Choice D claims the magnetic field does negative work and slows the particle down, when actually the magnetic force F = qvB is always perpendicular to both v and B (given by right-hand rule), which means the force is perpendicular to displacement, so no work is done (W = F·d = 0) and kinetic energy remains constant. When modeling fields and their effects: for magnetic fields, (1) identify source (permanent magnet or current), (2) use right-hand rule for direction (thumb = current, fingers curl = field for wire; or just remember N to S outside magnet), (3) recognize field lines always form closed loops (no monopoles), and (4) force on moving charge is F = qvB perpendicular to both v and B (right-hand rule: fingers = B, thumb = v, palm = F). Critical distinctions: electric fields can do work on charges (F parallel to motion possible, changes kinetic energy), magnetic fields cannot do work (F always perpendicular to v, changes direction only, not speed), electric field from stationary charges (no motion needed), magnetic field from moving charges or magnets (motion or intrinsic magnetic dipoles), electric field lines can start or end on charges, magnetic field lines must form closed loops—these differences make electric and magnetic fields fundamentally different, though both follow superposition principle (net field is vector sum from all sources) and both decrease with distance from sources.
Two point charges lie on the x-axis: $Q_1=+2.0,\mu\text{C}$ at $x=-0.20,\text{m}$ and $Q_2=+2.0,\mu\text{C}$ at $x=+0.20,\text{m}$. Point $P$ is at the origin. What is the net electric field $\vec{E}_{\text{net}}$ at point $P$?
Zero (the fields cancel)
To the left (in the $-x$ direction)
Upward (in the $+y$ direction)
To the right (in the $+x$ direction)
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. An electric field E exists in the region around a charge or group of charges and is defined as the force per unit charge that a positive test charge would experience at each point: E = F/q, measured in N/C (Newtons per Coulomb). The field direction is the direction a positive charge would be pushed (away from positive source charges, toward negative source charges), and field magnitude for a point charge is E = kQ/r², decreasing with the square of distance from the source charge Q. With charge 1: positive +2.0 μC at x=-0.20 m and charge 2: positive +2.0 μC at x=+0.20 m, the electric field at point P at the origin is the vector sum of fields from both charges; charge 1 creates field E₁ pointing to the right (+x) with magnitude E₁ = kQ₁/r₁² = $(9×10⁹)(2×10^{-6}$)/(0.20)² = $4.5×10^5$ N/C, and charge 2 creates field E₂ pointing to the left (-x) with magnitude E₂ = kQ₂/r₂² = $4.5×10^5$ N/C; the net field is E_net = E₁ + E₂ = $+4.5×10^5$ + $(-4.5×10^5$) = 0 N/C (fields cancel due to symmetry), and a positive test charge at P would experience no net force. Choice A is correct because it accurately applies vector addition for multiple sources to find net field direction and recognizes cancellation. Choice B adds the field magnitudes without considering directions (vector addition), calculating E_net = |E₁| + |E₂| when actually E_net requires vector addition: if fields point in opposite directions they partially cancel, not add. When modeling fields and their effects: for electric fields, (1) identify source charges and their signs, (2) remember field points away from positive charges and toward negative charges, (3) calculate magnitude using E = kQ/r² for point charges, (4) for multiple sources add fields as vectors (considering directions), and (5) force on test charge is F = qE in field direction if q positive, opposite if q negative; critical distinctions: electric fields can do work on charges (F parallel to motion possible, changes kinetic energy), magnetic fields cannot do work (F always perpendicular to v, changes direction only, not speed), electric field from stationary charges (no motion needed), magnetic field from moving charges or magnets (motion or intrinsic magnetic dipoles), electric field lines can start or end on charges, magnetic field lines must form closed loops—these differences make electric and magnetic fields fundamentally different, though both follow superposition principle (net field is vector sum from all sources) and both decrease with distance from sources.
A wire segment carries conventional current to the right through a region where a uniform magnetic field $\vec{B}$ points upward. What is the direction of the magnetic force on the wire segment?
To the right (same as the current)
Out of the page ($\odot$)
Into the page ($\otimes$)
Upward (same as $\vec{B}$)
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. A magnetic field B exists around magnets and current-carrying wires and is defined by the force it exerts on moving charges: F = qvB sin(θ), measured in Tesla (T). Unlike electric fields which can have isolated sources (single charges), magnetic field lines always form closed loops with no beginning or end (no magnetic monopoles exist), emerging from the north pole and entering the south pole of magnets, or circling around current-carrying wires as determined by right-hand rules. For a wire carrying current I to the right in magnetic field B upward, the force is F = I L × B, where L is in direction of I; using right-hand rule (fingers in B upward, thumb in I right, palm pushes out of page), the force is out of the page (⊙), potentially causing the wire to move in that direction if free. Choice A is correct because it accurately applies right-hand rule for magnetic force on current-carrying wire. Choice B misapplies the right-hand rule for the magnetic field, using left hand or pointing thumb in wrong direction, which leads to predicting force direction opposite to correct. When modeling fields and their effects: for magnetic fields, (1) identify source (permanent magnet or current), (2) use right-hand rule for direction (thumb = current, fingers curl = field for wire; or just remember N to S outside magnet), (3) recognize field lines always form closed loops (no monopoles), and (4) force on moving charge is F = qvB perpendicular to both v and B (right-hand rule: fingers = B, thumb = v, palm = F); common mistakes to avoid: (c) using left hand instead of right for right-hand rules (gives opposite result), (e) assuming magnetic force is parallel to field or velocity (it's perpendicular to both).
A point charge $Q=-3.0,\mu\text{C}$ is fixed. Point $P$ is $0.50,\text{m}$ away from the charge. Using $E = k|Q|/r^2$ with $k=9.0\times10^9,\text{N},\text{m}^2/\text{C}^2$, what is the magnitude of the electric field at $P$?
$5.4\times10^5,\text{N/C}$
$1.1\times10^4,\text{N/C}$
$1.1\times10^5,\text{N/C}$
$5.4\times10^4,\text{N/C}$
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. An electric field E exists in the region around a charge or group of charges and is defined as the force per unit charge that a positive test charge would experience at each point: E = F/q, measured in N/C (Newtons per Coulomb). The field direction is the direction a positive charge would be pushed (away from positive source charges, toward negative source charges), and field magnitude for a point charge is E = kQ/r², decreasing with the square of distance from the source charge Q. For a negative point charge Q = -3.0 μC, the electric field magnitude at distance r = 0.50 m is calculated using E = k|Q|/r² = $(9×10⁹)(3×10^{-6}$)/(0.50)² = $(9×10⁹)(3×10^{-6}$)/0.25 = $(2.7×10^4$)/0.25 = $1.08×10^5$ ≈ $1.1×10^5$ N/C, and the direction is radially inward for negative charge; a positive test charge q placed at this point would experience force F = qE toward the charge, while a negative test charge would experience equal magnitude force in the opposite direction. Choice A is correct because it correctly calculates field strength using E = k|Q|/r² with proper values and units. Choice B claims a lower magnitude by possibly using r instead of r² in the denominator or miscalculating the exponent, when actually the inverse square law requires division by r², leading to a stronger field closer to the charge. Common mistakes to avoid: (a) assuming electric field points from negative to positive (it's opposite: from + to -), (b) forgetting that force on negative charge is opposite to field direction (F = qE with q < 0 reverses direction), (c) using left hand instead of right for right-hand rules (gives opposite result), (d) thinking magnetic field lines start and stop like electric ones (magnetic field lines are always closed loops), (e) assuming magnetic force is parallel to field or velocity (it's perpendicular to both), and (f) adding field vectors as scalars without considering direction (vector addition requires accounting for whether fields reinforce or cancel based on directions).
A uniform electric field of magnitude $E=800,\text{N/C}$ points to the right. A charge $q=-2.0,\mu\text{C}$ is placed in this field. What is the direction of the electric force on the charge?
Upward
Downward
To the right (same direction as $\vec{E}$)
To the left (opposite $\vec{E}$)
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. An electric field E exists in the region around a charge or group of charges and is defined as the force per unit charge that a positive test charge would experience at each point: E = F/q, measured in N/C (Newtons per Coulomb). The field direction is the direction a positive charge would be pushed (away from positive source charges, toward negative source charges), and field magnitude for a point charge is E = kQ/r², decreasing with the square of distance from the source charge Q. A negative charge q = -2.0 μC in electric field E = 800 N/C pointing right experiences force F = qE = $(-2×10^{-6}$)(800) = $-1.6×10^{-3}$ N (negative sign indicates opposite to E, so to the left), giving acceleration a = F/m in the left direction if mass is known, causing the charge to accelerate to the left. Choice B is correct because it correctly determines force direction on test charge using F = qE with sign of charge considered. Choice A confuses the force direction on a negative charge with the field direction—the electric field direction is defined by the force on a positive charge, so a negative charge experiences force opposite to the field direction: if E points right, then F on negative charge points left (F = qE with q < 0 gives negative/opposite direction). When modeling fields and their effects: for electric fields, (1) identify source charges and their signs, (2) remember field points away from positive charges and toward negative charges, (3) calculate magnitude using E = kQ/r² for point charges, (4) for multiple sources add fields as vectors (considering directions), and (5) force on test charge is F = qE in field direction if q positive, opposite if q negative; for magnetic fields, (1) identify source (permanent magnet or current), (2) use right-hand rule for direction (thumb = current, fingers curl = field for wire; or just remember N to S outside magnet), (3) recognize field lines always form closed loops (no monopoles), and (4) force on moving charge is F = qvB perpendicular to both v and B (right-hand rule: fingers = B, thumb = v, palm = F).
A positive charge moves with velocity $\vec{v}$ to the right in a uniform magnetic field $\vec{B}$ directed out of the page ($\odot$). What is the direction of the magnetic force on the charge?
Upward
To the right (same direction as $\vec{v}$)
Into the page ($\otimes$)
Downward
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. A magnetic field B exists around magnets and current-carrying wires and is defined by the force it exerts on moving charges: F = qvB sin(θ), measured in Tesla (T). Unlike electric fields which can have isolated sources (single charges), magnetic field lines always form closed loops with no beginning or end (no magnetic monopoles exist), emerging from the north pole and entering the south pole of magnets, or circling around current-carrying wires as determined by right-hand rules. A positive charge q in magnetic field B directed out of the page (⊙) with velocity v to the right experiences force F = q (v × B), perpendicular to both v and B; using the right-hand rule (fingers in B direction out, thumb in v direction right, palm pushes downward), the force is downward, causing the charge to curve in that direction. Choice B is correct because it correctly determines force direction on test charge using F = q v × B with right-hand rule applied. Choice D claims the force on a charge in a magnetic field is parallel to either the velocity or the field, when actually the magnetic force F = qvB is always perpendicular to both v and B (given by right-hand rule: fingers = B, thumb = v, palm = F), which is why magnetic fields change direction of motion but don't change speed. When modeling fields and their effects: for magnetic fields, (1) identify source (permanent magnet or current), (2) use right-hand rule for direction (thumb = current, fingers curl = field for wire; or just remember N to S outside magnet), (3) recognize field lines always form closed loops (no monopoles), and (4) force on moving charge is F = qvB perpendicular to both v and B (right-hand rule: fingers = B, thumb = v, palm = F).
A point charge $Q=+4.0,\mu\text{C}$ is fixed at the origin. Point $P$ is located on the +x-axis at $x=0.30,\text{m}$. What is the direction of the electric field $\vec{E}$ at point $P$ due to $Q$?
Toward the origin (in the $-x$ direction)
In the $+y$ direction
Away from the origin (in the $+x$ direction)
In the $-y$ direction
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. An electric field E exists in the region around a charge or group of charges and is defined as the force per unit charge that a positive test charge would experience at each point: E = F/q, measured in N/C (Newtons per Coulomb). The field direction is the direction a positive charge would be pushed (away from positive source charges, toward negative source charges), and field magnitude for a point charge is E = kQ/r², decreasing with the square of distance from the source charge Q. For a positive point charge Q = +4.0 μC at the origin, the electric field at point P on the +x-axis at x=0.30 m points radially outward from the charge, which is in the +x direction (away from the origin); a positive test charge at P would experience a force in the +x direction, while a negative test charge would experience force toward the origin in the -x direction. Choice C is correct because it properly identifies electric field direction as radially outward from positive charge. Choice A reverses the electric field direction, showing it pointing inward to positive when actually electric field points away from positive charges (the direction a positive test charge would be pushed) and toward negative charges (the direction a positive test charge would be pulled). When modeling fields and their effects: for electric fields, (1) identify source charges and their signs, (2) remember field points away from positive charges and toward negative charges, (3) calculate magnitude using E = kQ/r² for point charges, (4) for multiple sources add fields as vectors (considering directions), and (5) force on test charge is F = qE in field direction if q positive, opposite if q negative; for magnetic fields, (1) identify source (permanent magnet or current), (2) use right-hand rule for direction (thumb = current, fingers curl = field for wire; or just remember N to S outside magnet), (3) recognize field lines always form closed loops (no monopoles), and (4) force on moving charge is F = qvB perpendicular to both v and B (right-hand rule: fingers = B, thumb = v, palm = F).
A proton enters a region of uniform magnetic field $\vec{B}$ directed into the page ($\otimes$) with an initial velocity $\vec{v}$ upward. Neglecting gravity, what path will the proton follow while in the field?
A straight line upward at constant speed
A circular path in the plane of the page
A straight line upward with increasing speed
A circular path spiraling out of the page
Explanation
This question tests understanding of modeling electric and magnetic fields and predicting how they interact with charges or currents. A magnetic field B exists around magnets and current-carrying wires and is defined by the force it exerts on moving charges: F = qvB sin(θ), measured in Tesla (T). Unlike electric fields which can have isolated sources (single charges), magnetic field lines always form closed loops with no beginning or end (no magnetic monopoles exist), emerging from the north pole and entering the south pole of magnets, or circling around current-carrying wires as determined by right-hand rules. A positive proton charge in magnetic field B directed into the page (⊗) with initial velocity v upward experiences force F = q (v × B) always perpendicular to v, causing circular motion with radius r = mv / (qB) and constant speed since magnetic force does no work; using right-hand rule, the force initially to the right curves the path into a circle in the plane perpendicular to B. Choice B is correct because it properly recognizes that magnetic force is perpendicular to velocity, leading to uniform circular motion in the plane perpendicular to B. Choice A assumes magnetic force is parallel to field or velocity, when actually the magnetic force F = qvB is always perpendicular to both v and B (given by right-hand rule: fingers = B, thumb = v, palm = F), which is why magnetic fields change direction of motion but don't change speed. Critical distinctions: electric fields can do work on charges (F parallel to motion possible, changes kinetic energy), magnetic fields cannot do work (F always perpendicular to v, changes direction only, not speed), electric field from stationary charges (no motion needed), magnetic field from moving charges or magnets (motion or intrinsic magnetic dipoles), electric field lines can start or end on charges, magnetic field lines must form closed loops—these differences make electric and magnetic fields fundamentally different, though both follow superposition principle (net field is vector sum from all sources) and both decrease with distance from sources.